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How to Make Step Down Transformers

Last Updated on January 3, 2025 by Swagatam 162 Comments

A step down transformer is a device which reduces a higher AC potential to a lower AC potential as per its winding ratio and specifications.

Table of Contents
  • Introduction
  • Basic Transformer Design
  • Calculating Primary Winding
    • Winding Data
  • Calculating Secondary Winding
    • Calculating Core size
    • Table Dimension of Transformer Stamping
      • Section 1
      • Section 2
    • Core Assembly Diagram
    • How to Assemble the Transformer
    • How to Apply Shielding
      • For Torroidal Transformer designing, you can refer to the following pdf document:
    • Additional Useful Information Regarding Transformer Winding
    • Simple Calculation of Transformers Up to 2000 Watts
    • Calculation Notes:
    • Power Calculation Example:
    • Core Cross-Section Calculation:
    • Primary Winding Turns Calculation:
    • Primary Current Calculation:
    • Wire Calculation:

In this article we are going to discuss how to design and construct a basic step down transformer which are typically applied in mains-operated power supplies.

Introduction

This will likely help electronic hobbyists to develop and build their very own transformers based on their particular demands.

Within the next pages, a simplified layout method is presented in order to achieve satisfactorily developed transformers. On the other hand, the design process may be a subject of some experimentation.

The tables I have I have explained in this article trim computations short which help the designer to find the appropriate size of wire or even core lamination.

Exclusively pertinent data and calculations are supplied here to ensure that the designer is absolutely not baffled by unwanted details.

Here we will specifically discuss about transformers which possesses 2 or more winding of insulated copper wire around an iron core. These are: one primary winding and one or maybe more secondary winding.

Each winding is electrically isolated from the other however are magnetically connected by using a laminated iron core.

Small transformers possess a shell style structure, i.e. the winding are encircled by the core as demonstrated in Fig. 1.

The power supplied by the secondary is in fact transmitted from the primary, although at a voltage level dependent on the winding ratio of the a pair of winding.

Video Interpretation

transformer parts

Basic Transformer Design

As the initial phase towards the design of a transformer, the primary and secondary voltage evaluations and the secondary ampere rating has to be distinctly expressed.

After that determine the core content to be employed: ordinary steel stamping or cold rolled grain oriented (CRGO) stamping. CRGO features a greater allowable flux density and reduced losses.

The best possible cross-sectional part of the core is roughly assigned by:

Core Area: 1.152 x √(output voltage x output current) sq cm.

With regard to transformers having several secondaries, the sum of the the output volt-amp product of each winding needs to be considered.

The quantity of turns on the primary and secondary winding is determined using the formula for turns per volt ratio as:

Turns per volt = 1/ (4.44  x 10-4 frequency x core area x flux density)

Here, the frequency is usually 50Hz for Indian household mains source. The flux density could be considered as approximately 1.0 Weber/ sq. m. intended for ordinary steel stamping and approximately 1.3 Weber/ sq. m. for CRGO stamping.

Calculating Primary Winding

The current in the primary'winding is presented by the formula:

Primary Current = Sum of o/p Volt and o/p Amp divided by Primary Volts x efficiency

The efficiency of small transformers can deviate between 0.8 to 0.§6. A value of 0.87 works extremely well for regular transformers.

The appropriate wire size needs to be determined for the winding. The wire diameter is dependent upon the current rated for the winding and also the permitted current density of the wire.

The current density could be as tall as 233 amps/ sq. cm. in small transformers and as minimal as 155 amps/ sq. cm. in big ones.

Winding Data

SWGMax. current capacity (Amp)Turns per sq. cm.
1016.608.7
1113.63810.4
1210.96112.1
138.57913.6
146.48721.5
155.25426.8
164.15135.2
173.17845.4
182.53857.3
192.01372.3
201.313106.0
211.0377132.7
220.8183167.4
230.6383210.9
240.5046265.9
250.4004334.9
260.3284415.0
270.2546523.0
280.2024659.0
290.1608830.0
300.1558881
310.1364997
320.11821137
330.10141308
340.08581608
350.07151902
360.05862286
370.04692800
380.03663542
390.02844838
400.02255595
410.01976543
420.01449337
430.011311352
440.009014392
450.007917147
460.005920223
470.004725397
480.003731605
490.002940160
500.001081242

Typically, a value of 200 amps/ sq. cm. may be considered, according to which Table#1 is created. The amount of turns in the primary winding is presented by the formula:

Primary Turns = Turns per Volt x Primary Volts

The room consumed by the winding is determined by the insulation density, technique of winding and the wire diameter.

Table#1 provides the estimated values of the turns per square cm. through which we are able to calculate the window area consumed by the primary winding.

Primary winding Area = Primary turns / Turns per sq. cm from Table#1

Calculating Secondary Winding

Considering that we have the assumed secondary current rating, we are able to determine the wire size for the secondary winding simply by going through Table#1 directly.

The quantity of turns on the secondary is calculated in the identical method when it comes to primary, but around 3% excess turns should be included to reimburse for the internal drop of secondary winding voltage of the transformer, upon loading. Hence,

Secondary turns = 1.03 (turns per volt x secondary volts)

The window area necessary for secondary winding is identified from Table#2 as

Secondary window area = Secondary turns / Turns per sq. cm. (from Table#2 below)

Calculating Core size

The principal qualifying measure in picking the core could be the total window area of winding space accessible.

Total window area = Primary window area + sum of secondary window areas + space for former & insulation.

A little extra space is necessary to support the former and insulation in between winding. The specific quantity of extra area may differ, even though 30% could be considered to begin with although this may need to be customized later on.

Table Dimension of Transformer Stamping

Section 1

Type No.Tongue width (cm.)Window area (sq. cm.)
17 (E-I)1.2701.213
12A (E-I)1.5881.897
74 (E-I)1.7482.213
23 (E-I)1.9052.723
20 (E-I)1.9053.230
15 (E-I)2.2233.230
31 (E-I)2.5883.230
11 (E-I)2.5404.839
35 (E-I)2.5404.839
14 (E-I)2.4615.645
33 (E-I)2.4615.645
11 (E-I)2.5407.259
35 (E-I)2.5407.259
3 (E-I)3.8107.562

Section 2

Type No.Tongue width (cm.)Window area (sq. cm.)
9 (U-T)2.2237.865
9A (U-T)2.2237.865
4A (E-I)3.81010.484
4 (E-I)3.81010.484
16 (E-I)3.81010.891
13 (E-I)2.38115.865
7 (E-I)2.54015.865
6 (E-I)3.81015.865
5 (E-I)3.81019.305
8 (E-I)5.08049.803

The perfect core sizes possessing a more substantial window space are generally determined from Table#2 taking into consideration the gap between lamination while stacking them (the core stacking element may be taken as 0.9), we now have

Gross core area = Core Area / 0.9 sq cm. In general, a square central limb is preferred.

For this, the width of the tongue of lamination is

Tongue width =  √Gross core area (sq.cm)

Now refer to Table#2 once again and as a final point find the appropriate core size, having adequate window area and a nearby value of the tongue width as calculated. Modify thel stack height as needed to acquire the intended core section.

Stack Height = Gross Core Area / Actual Tongue Width

The stack must not be a lot under the tongue width rather should be more. However, it must not be greater than 11/2 times the tongue width.

Core Assembly Diagram

lamination core assembly
Core lamination details

How to Assemble the Transformer

The winding are done over an insulating former or bobbin that fits on the middle pillar of the core lamination.

The primary is generally wound first, and next it is the secondary, keeping an insulation between the two layers of the winding.

One last insulating layer is applied on top of the winding to safeguard all of them from mechanical and vibration deterioration.

Whenever thin wires are employed, their particular ends needs to be soldered to heavier wires in order to bring the terminals outside the former.

The lamination are usually put together on the former by alternate lamination reversed in set up.

The lamination has to be tightly bound together through an appropriate clamping framework or by using nuts and bolts (in case through holes are supplied within the lamination assembly).

How to Apply Shielding

This can be a wise idea to utilize an electrostatic shielding between the primary and secondary winding to circumvent electrical interference from moving across to the secondary from the primary.

The shield for step down transformers can be constructed from a copper foil which can be wound between the two winding for somewhat more than a tum.

Insulation has to be presented across the entire foil and proper care taken in order that the two ends of the foil never come in contact with each other.

Additionally  a wire could be soldered with this shielding field and connected with the ground line of the circuit or with the lamination of the transformer which may be clamped with the ground line of the circuit.

For Torroidal Transformer designing, you can refer to the following pdf document:

https://www.homemade-circuits.com/wp-content/uploads/2021/04/torroidal-transformer_compressed.pdf

Additional Useful Information Regarding Transformer Winding

The following useful data related to transformer winding was kindly shared by Mr. Constantinos Mermygas. I hope the readers will find it very helpful.

copper winding data
transformer calculations

Simple Calculation of Transformers Up to 2000 Watts

Parameters:

  • V = Mains voltage
  • f = Network frequency in cycles per second
  • S = Core cross-section in square centimeters
  • B = Weber per square centimeter (Weber/cm²)
  • 4.44 = Coefficient of constant
  • N1 = Turns of primary winding
  • N2 = Turns of secondary winding
  • I1 = Primary current in Amperes
  • I2 = Secondary current in Amperes
  • W = Transformer power in Watts

Calculation Notes:

  1. Choose Bmax = 1.2 (maximum flux density).
  2. To calculate a transformer, determine the power consumption on the secondary winding and add approximately 10%.

Power Calculation Example:

  • Secondary Voltage: 24 volts
  • Current: 15 Amps
  • Transformer Power: (24 * 15) + 10% = 400 watts

Core Cross-Section Calculation:

  • Example:
    Core cross-section: √400 * 1.2 = 24 cm²
    Central trunk (tongue):
  • Width = 5 cm
  • Height = 4.8 cm
  • Add 5% for varnish, total height ≈ 5 cm

Primary Winding Turns Calculation:

  • Formula:
    N1 = V / (4.44 × B × S × f / 10,000)

Primary Current Calculation:

  • Formula:
    I1 = W / V
    Example:
    I1 = 400W / 220V = 1.818 Amperes

Wire Calculation:

  • Example:
  • Wire Diameter: 1 mm
  • Cross Section: 0.785 mm²
  • Current Strength: Up to 1.960 Amperes

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Filed Under: Power Supply Circuits Tagged With: Down, Step, Transformers

About Swagatam

I am an electronics engineer and doing practical hands-on work from more than 15 years now. Building real circuits, testing them and also making PCB layouts by myself. I really love doing all these things like inventing something new, designing electronics and also helping other people like hobby guys who want to make their own cool circuits at home.

And that is the main reason why I started this website homemade-circuits.com, to share different types of circuit ideas..

If you are having any kind of doubt or question related to circuits then just write down your question in the comment box below, I am like always checking, so I guarantee I will reply you for sure!



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Reader Interactions

Questions & Answers

Total Posts: 162
Newest Oldest
Faith
February 10, 2018 • 8 years ago #58344

This is a very interesting topic especially for me thank you for that
But what in a case i have a transformer salvage from ups and i want to redesign it how do i go about the calculationt
Thanks and best regards

And as for the sinewave inverter using spwm i’m still on it when I’m done i will share the good news
thank you once more for help God bless you real good

Reply
SwagatamAdmin
February 10, 2018 • 8 years ago #58347

Thank you Faith, for modifying a readymade transformer you may have to go in the reverse manner and first identify the core size and the other parameters then compare them with the values given in the respective tables and subsequently evaluate the wire sizes and the number of turns

Reply
cristian
February 14, 2018 • 8 years ago #58441

hello friend long time

i looking circuit for water level for up tank and down tank
down tank is whit water and up is low level turn pump on and so

and what y think i use a automotive rele 30amp to turn a 3hp 220 water pump ?

Reply
SwagatamAdmin
February 14, 2018 • 8 years ago #58446

hello cristian, you can use any set-reset circuit using IC or transistor, and use the “set” points at the bottom of the ground tank and use the “reset” points at the brim of the overhead tank, and wire the relay accordingly.

yes 220V/30 amp relay will work

Reply
cristian
February 14, 2018 • 8 years ago #58454

i show this but not look ic model

tablero con automatico para tanque cisterna listo para usar D NQ NP 675905 MLA25094466995 102016 F

Reply
SwagatamAdmin
February 15, 2018 • 8 years ago #58466

the design is correct, may be the ICs are IC 555

Reply
charan
February 17, 2018 • 8 years ago #58533

This was useful.Hope you can make a similar post on ferrite core transformers and its switching supply circuits.

Reply
SwagatamAdmin
February 18, 2018 • 8 years ago #58544

I am glad you liked it, if I happen to find the ferrite core formulas, will surely update it here…

Reply
Sherwin Baptista
March 1, 2018 • 8 years ago #58838

Dear,
Now I’ve started to build my own transformers (i’m describing an IRON CORE trafo). First i considered this difficult and never knew how to do so. Previously i had to compensate someone in the field to build as per my specs.
Now I’ve cracked the way how to build my own only after seeing this page in your blog.

I’ve got the stamping and frame ordered from Lamington road, purchased varnish and other basic materials required to build the transformer.
Till date I’ve made just one successfully.

I calculated all the electrical parameters involved in its construction and now its been constructed and working properly.

Reply
SwagatamAdmin
March 1, 2018 • 8 years ago #58842

That’s great Sherwin, I am glad you could do it so easily…keep up the good work

Reply
paaker
September 3, 2018 • 8 years ago #62807

Hi Swag,

I got some microwave oven transformers. to rewind for battery charging / inverter purpose. I try to rewind this transformers secondary line 12-0- 12 my coil gauge was SWG 10 and I have rewinding it bifilar type finally I got
8v-08v coz no more space to wind.and its working perfect. on this way I have rewind several transformers with different gauge wires.

now my question is I know how much the voltage output from this transformer. but how to check how much ampere its giving. it is possible to check a transformers output current without connecting a load?

regards.

Reply
SwagatamAdmin
September 4, 2018 • 8 years ago #62809

Hi Paaker, probably the only way to know is by connecting a correctly rated ammeter directly across the output wires of the transformer and check the measurement. Do it only for a couple of seconds, otherwise the transformer or the meter or both could start fuming.

Reply
paaker
September 6, 2018 • 8 years ago #62854

fine.
its possible to make a Battery charger with this transformer( 8v-0v-8v) to charge 12V 150A battery? I thing my transformer is around 40-45A. coz the wire I use to wind it was SWG 10.

Reply
SwagatamAdmin
September 7, 2018 • 8 years ago #62857

yes its possible. use the outer wire to get 16V, and then add a voltage regulator to stabilize at 14.2V

Reply
Paaker
September 7, 2018 • 8 years ago #62864

Fine,
can you please suggest me a perfect circuit for this purpose.

Regards.

Reply
SwagatamAdmin
September 7, 2018 • 8 years ago #62869

Here’s a simplest design:
DC motor mosfet speed manage

Replace the motor with a 1K resistor, adjust the pot to get exactly 14.2V across the 1K

That’s all…now you can connect your battery and let it charge until its terminals reach 14.2V.

For better protection connect a 0.3 ohm 25 watt resistor in series with the positive line, put this resistor over a large heatsink, and do the same to the mosfet also

Reply
Osei Kwame
May 30, 2019 • 7 years ago #67339

teacher Swagatam I was reading your article on transformer calculations
now how do I know out put current when calculating core area per your calculations. 2 is this formula applicable to E and I transformers that handle 5Kw of power thanks teacher

Reply
SwagatamAdmin
May 31, 2019 • 7 years ago #67341

Hello Osei, The formulas are applicable for 5 kW but the tables are not, they are limited to 10 amps max.

Reply
Osei Kwame
June 1, 2019 • 7 years ago #67347

Thanks teacher Swagatam

Reply
DEV DATT
June 4, 2019 • 7 years ago #67453

Sir thanks for such a good circuit diagrams & details the one thing which is very important designing the transformer for SMPS Power supplies so sir is it possible to have some help from your side related to this topic as this is a very critical.
Hope to receive the reply.
Thanks & Regards

Reply
SwagatamAdmin
June 4, 2019 • 7 years ago #67454

Thank you Dev, you can read the following post:

https://www.homemade-circuits.com/how-to-design-and-calculate-ferrite-core-transformers-for-inverters/

Reply
Victory
June 22, 2019 • 7 years ago #67861

Good day sir, is it possible to wind like 10pcs of wire at same time for primary coil to make it faster and fewer number of turns and join end to start

Reply
SwagatamAdmin
June 23, 2019 • 7 years ago #67867

Victory, the number of turns should be as per the calculations, adding more number of wires will increase the current handling capacity of the winding.

Reply
Christo
June 23, 2019 • 7 years ago #67877

Hi Swag,

As they say the truth, in simple English, shall set you free. Thank you. This is the first clear discussion I see on trafo’s, especially the relationship between changed voltages and currents. I was particularly concerned about the effect of the changes in current in step-down trafo’s. One thing that became very clear is that I can imagine any situation and start from there. I can then practice the formula’s in every way possible to understand all the effects of all the different designs. This also gives me the ability to reverse engineer existing trafo’s and understand things even better.

Thank you, I like the way you explain things that I can follow your thinking. That makes it every easy to turn my own thinking onto something real.

Reply
SwagatamAdmin
June 24, 2019 • 7 years ago #67882

Thanks Christo,
I am glad you found it useful…please keep up the good work!

Reply
Tolu
June 26, 2019 • 7 years ago #67932

I made a 78va capacity trafo inverter, i load it With 110w appliances, what may bẹ the effect technically.

Reply
SwagatamAdmin
June 26, 2019 • 7 years ago #67937

Output voltage will drop proportionately

Reply
Tolu
June 26, 2019 • 7 years ago #67933

I saw a 1.5kva/24v inverter, the trafo guage amperage was 21.2amps for the battery side and the ac output sise was 2.64amps. please explain how it is so. For this inverter, it is suppose to be 55amps for the battery side which is not feasible

Reply
SwagatamAdmin
June 26, 2019 • 7 years ago #67938

Pleas multiply the primary side voltage with its current, and the secondary side voltage with its current to get the wattages at the relevant sides of the trafo.

Reply
Sam
July 24, 2019 • 7 years ago #68725

Hi swagtam. I used the turn per voltage formula and fixed these values: 1/(4.44*10^-4*50hz*528mm^2*1.1) giving me a total of 1/12.89376, equals 0.077556895turns per voltage, please help me calculate it using my values. The 528mm^2 is the core area, and i got it from tongue width: 1.6cm * tongue depth: 3.3cm. Please help me out

Reply
SwagatamAdmin
July 24, 2019 • 7 years ago #68729

Hi Sam, we have solve it from top towards bottom, meaning start with current and the voltage of the primary and secondary and so on, it can be very difficult to do the opposite way.

Reply
Sam
July 24, 2019 • 7 years ago #68731

Please swagtam what unit is there after the 1.152 in the core area formula, help me write it out in english, my phone displayed the unit as a tiny box (my phone cannot read the unit). Thanks for the previous reply.

Reply
SwagatamAdmin
July 24, 2019 • 7 years ago #68736

Sam, That’s a square root symbol.

Reply
Sam
July 25, 2019 • 7 years ago #68740

Thanks, and also swagtam i have an e core measuring 1.6cm tongue width and 3.3 tongue depth, i use the turn per volt formula and i get 8.53turns per volt but i think its wrong. Please help me calculate the turn per volt using my details, the frequency is 50hz, i just want to know if my answer is right. Please help me calculate it.

Reply
SwagatamAdmin
July 25, 2019 • 7 years ago #68747

Hi Sam, This article is about iron-core step down transformer, it’s not for ecore.

Reply
Ceaser Molobye
September 27, 2019 • 7 years ago #70541

Good day sir
What is the acceptable gap between the lamination of a transformer unit of a 630kva oil cooled minisub and the bottom of the tank, the voltage is 6600/550v

Reply
SwagatamAdmin
September 27, 2019 • 7 years ago #70545

Good day Ceaser, sorry I have no idea about it…

Reply
Shashi Kiran
October 3, 2019 • 7 years ago #70702

What type of a transformer is used in a mosquito bat ? its a small black with yellow jacket around it.

Reply
SwagatamAdmin
October 3, 2019 • 7 years ago #70707

It is a calculated ferrite core transformer. The calculation formulas are explained in this article:

https://www.homemade-circuits.com/how-to-design-and-calculate-ferrite-core-transformers-for-inverters/

Reply
Jan
February 20, 2020 • 6 years ago #76811

Hi Swagatam,
I intend to build my own transformer winding Machine. I find it difficult to find plans to do this even on youtube. Could you perhaps suggest where I can get the necessary info.
Your assistance will be much appreciated.
Regards
Jan

Reply
SwagatamAdmin
February 21, 2020 • 6 years ago #76814

Sorry Jan, presently I do not have any information regarding transformer winding machine. If I happen to find it I’ll surely update in my blog.

Reply
Jan
February 21, 2020 • 6 years ago #76817

Thank you Swagatam

Reply
Ralph Koeniger
April 5, 2020 • 6 years ago #77689

Hello Swag,
Sincerely appreciate gentlemen like you who help tinkerers like us! I just bought a kiln requiring 208volts and my service is 242volts. The kiln manufacturer tells me I can run the kiln, but the elements will fail prematurely, replacement cost for 240 elements is $700+. Would you be so kind as to help me create a drop down transformer either for each leg of 17 or so volts or in combo of about 32 volts, please? I can make the steel core parts and wind the whole thing by hand – I am very meticulous. Have more time than money! Hahahaha!!!! I am not the best at math so doing the calcs myself without guidance from a seasoned vet like you, would not be smart on my part. I don’t want to blow up the kiln I just invested $500 in. Thank you very much – in advance!

Reply
SwagatamAdmin
April 5, 2020 • 6 years ago #77692

Thank you Ralph, A transformer based design may not be so appropriate since it will be bulky, difficult to calculate and prone to mistakes. The easiest and the ideal way to provide a controlled power to a kiln element or any resistive load is through a triac based phase chopper circuit as explained in the following article:

https://www.homemade-circuits.com/how-to-make-simplest-triac-flasher/

You can use any of the the last two designs for controlling your kiln element heat very efficiently and provide a long life to the element.

Reply
Ralph Koeniger
April 5, 2020 • 6 years ago #77710

Hey Swag,
Greatly appreciate the speedy reply. I reviewed your recommendation and think the second design would be best with just a couple increments (resistors) rather than 4, but I have some concerns of which may or may not be warranted based on my limited knowledge on the subject… namely – “minimum transients and spikes” & “generation of lots of RF.” The kiln draws 53 amps and has a digital controller that ramps up temp, holding times, etc. Will there be varied voltages, RF emissions that interfere with the controller and are the components capable of handling 53 amps? Thank you!

Reply
SwagatamAdmin
April 6, 2020 • 6 years ago #77717

Thanks Ralph, there will be RF emission when the load is operated with reduced power, and the Rf will decrease as the power on the load is increased using the potentiometer. However the L1, C1 is specifically to cancel these RF, so if these are correctly optimized, the RF emission can be expected to be minimum. The L1, C1 will also work to absorb spikes and transients.

53 amps looks very high, so the triac will need to be rated accordingly. Finding a 60 to 100 amp triacs is not easy, so this may be an issue.

To solve this a simpler design could be as shown below:

mosfet pwm kiln temperature controller circuit

This design might also work as efficiently as one can expect. The bridge rectifier will also need to be rated at 60 to 100 amps

Reply
Ralph Koeniger
April 15, 2020 • 6 years ago #77921

Hello again Swag, I contacted an electronic parts supply company, emailed the schematic you recommended and they replied:
“In order for us to locate a components on our website, please provide specification for each component on the diagram.”
So I called the tech support department and they said they need more information on the individual parts, their values, voltages, style of the caps, etc. I know I am asking a lot, but could I impose upon you for some detail on those components so the supply house can find them for me, please? Thank you.

Reply
SwagatamAdmin
April 16, 2020 • 6 years ago #77929

Hello Ralph, In general when the part numbers are without specifications that suggests any variant and type can be used.
In this circuit, resistors can be 1/4 watt 5%, pot can be any 5K or 10K linear pot, capacitors can be ceramic disc type, MOSFETs can be IRF740 10nos in parallel.

Bridge rectifier should be 70 to 100 amp rated, IC can be any IC 555

Reply
Ralph Koeinger
April 16, 2020 • 6 years ago #77939

Thank you so very much, really appreciate you going back and forth with on this. You are very kind!

Reply
SwagatamAdmin
April 16, 2020 • 6 years ago #77941

It’s my pleasure, thanks!

Reply
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