A step down transformer is a device which reduces a higher AC potential to a lower AC potential as per its winding ratio and specifications.
In this article we are going to discuss how to design and construct a basic step down transformer which are typically applied in mains-operated power supplies.
Introduction
This will likely help electronic hobbyists to develop and build their very own transformers based on their particular demands.
Within the next pages, a simplified layout method is presented in order to achieve satisfactorily developed transformers. On the other hand, the design process may be a subject of some experimentation.
The tables I have I have explained in this article trim computations short which help the designer to find the appropriate size of wire or even core lamination.
Exclusively pertinent data and calculations are supplied here to ensure that the designer is absolutely not baffled by unwanted details.
Here we will specifically discuss about transformers which possesses 2 or more winding of insulated copper wire around an iron core. These are: one primary winding and one or maybe more secondary winding.
Each winding is electrically isolated from the other however are magnetically connected by using a laminated iron core.
Small transformers possess a shell style structure, i.e. the winding are encircled by the core as demonstrated in Fig. 1.
The power supplied by the secondary is in fact transmitted from the primary, although at a voltage level dependent on the winding ratio of the a pair of winding.
Video Interpretation

Basic Transformer Design
As the initial phase towards the design of a transformer, the primary and secondary voltage evaluations and the secondary ampere rating has to be distinctly expressed.
After that determine the core content to be employed: ordinary steel stamping or cold rolled grain oriented (CRGO) stamping. CRGO features a greater allowable flux density and reduced losses.
The best possible cross-sectional part of the core is roughly assigned by:
Core Area: 1.152 x √(output voltage x output current) sq cm.
With regard to transformers having several secondaries, the sum of the the output volt-amp product of each winding needs to be considered.
The quantity of turns on the primary and secondary winding is determined using the formula for turns per volt ratio as:
Turns per volt = 1/ (4.44 x 10-4 frequency x core area x flux density)
Here, the frequency is usually 50Hz for Indian household mains source. The flux density could be considered as approximately 1.0 Weber/ sq. m. intended for ordinary steel stamping and approximately 1.3 Weber/ sq. m. for CRGO stamping.
Calculating Primary Winding
The current in the primary'winding is presented by the formula:
Primary Current = Sum of o/p Volt and o/p Amp divided by Primary Volts x efficiency
The efficiency of small transformers can deviate between 0.8 to 0.§6. A value of 0.87 works extremely well for regular transformers.
The appropriate wire size needs to be determined for the winding. The wire diameter is dependent upon the current rated for the winding and also the permitted current density of the wire.
The current density could be as tall as 233 amps/ sq. cm. in small transformers and as minimal as 155 amps/ sq. cm. in big ones.
Winding Data
| SWG | Max. current capacity (Amp) | Turns per sq. cm. |
|---|---|---|
| 10 | 16.60 | 8.7 |
| 11 | 13.638 | 10.4 |
| 12 | 10.961 | 12.1 |
| 13 | 8.579 | 13.6 |
| 14 | 6.487 | 21.5 |
| 15 | 5.254 | 26.8 |
| 16 | 4.151 | 35.2 |
| 17 | 3.178 | 45.4 |
| 18 | 2.538 | 57.3 |
| 19 | 2.013 | 72.3 |
| 20 | 1.313 | 106.0 |
| 21 | 1.0377 | 132.7 |
| 22 | 0.8183 | 167.4 |
| 23 | 0.6383 | 210.9 |
| 24 | 0.5046 | 265.9 |
| 25 | 0.4004 | 334.9 |
| 26 | 0.3284 | 415.0 |
| 27 | 0.2546 | 523.0 |
| 28 | 0.2024 | 659.0 |
| 29 | 0.1608 | 830.0 |
| 30 | 0.1558 | 881 |
| 31 | 0.1364 | 997 |
| 32 | 0.1182 | 1137 |
| 33 | 0.1014 | 1308 |
| 34 | 0.0858 | 1608 |
| 35 | 0.0715 | 1902 |
| 36 | 0.0586 | 2286 |
| 37 | 0.0469 | 2800 |
| 38 | 0.0366 | 3542 |
| 39 | 0.0284 | 4838 |
| 40 | 0.0225 | 5595 |
| 41 | 0.0197 | 6543 |
| 42 | 0.0144 | 9337 |
| 43 | 0.0113 | 11352 |
| 44 | 0.0090 | 14392 |
| 45 | 0.0079 | 17147 |
| 46 | 0.0059 | 20223 |
| 47 | 0.0047 | 25397 |
| 48 | 0.0037 | 31605 |
| 49 | 0.0029 | 40160 |
| 50 | 0.0010 | 81242 |
Typically, a value of 200 amps/ sq. cm. may be considered, according to which Table#1 is created. The amount of turns in the primary winding is presented by the formula:
Primary Turns = Turns per Volt x Primary Volts
The room consumed by the winding is determined by the insulation density, technique of winding and the wire diameter.
Table#1 provides the estimated values of the turns per square cm. through which we are able to calculate the window area consumed by the primary winding.
Primary winding Area = Primary turns / Turns per sq. cm from Table#1
Calculating Secondary Winding
Considering that we have the assumed secondary current rating, we are able to determine the wire size for the secondary winding simply by going through Table#1 directly.
The quantity of turns on the secondary is calculated in the identical method when it comes to primary, but around 3% excess turns should be included to reimburse for the internal drop of secondary winding voltage of the transformer, upon loading. Hence,
Secondary turns = 1.03 (turns per volt x secondary volts)
The window area necessary for secondary winding is identified from Table#2 as
Secondary window area = Secondary turns / Turns per sq. cm. (from Table#2 below)
Calculating Core size
The principal qualifying measure in picking the core could be the total window area of winding space accessible.
Total window area = Primary window area + sum of secondary window areas + space for former & insulation.
A little extra space is necessary to support the former and insulation in between winding. The specific quantity of extra area may differ, even though 30% could be considered to begin with although this may need to be customized later on.
Table Dimension of Transformer Stamping
Section 1
| Type No. | Tongue width (cm.) | Window area (sq. cm.) |
|---|---|---|
| 17 (E-I) | 1.270 | 1.213 |
| 12A (E-I) | 1.588 | 1.897 |
| 74 (E-I) | 1.748 | 2.213 |
| 23 (E-I) | 1.905 | 2.723 |
| 20 (E-I) | 1.905 | 3.230 |
| 15 (E-I) | 2.223 | 3.230 |
| 31 (E-I) | 2.588 | 3.230 |
| 11 (E-I) | 2.540 | 4.839 |
| 35 (E-I) | 2.540 | 4.839 |
| 14 (E-I) | 2.461 | 5.645 |
| 33 (E-I) | 2.461 | 5.645 |
| 11 (E-I) | 2.540 | 7.259 |
| 35 (E-I) | 2.540 | 7.259 |
| 3 (E-I) | 3.810 | 7.562 |
Section 2
| Type No. | Tongue width (cm.) | Window area (sq. cm.) |
|---|---|---|
| 9 (U-T) | 2.223 | 7.865 |
| 9A (U-T) | 2.223 | 7.865 |
| 4A (E-I) | 3.810 | 10.484 |
| 4 (E-I) | 3.810 | 10.484 |
| 16 (E-I) | 3.810 | 10.891 |
| 13 (E-I) | 2.381 | 15.865 |
| 7 (E-I) | 2.540 | 15.865 |
| 6 (E-I) | 3.810 | 15.865 |
| 5 (E-I) | 3.810 | 19.305 |
| 8 (E-I) | 5.080 | 49.803 |
The perfect core sizes possessing a more substantial window space are generally determined from Table#2 taking into consideration the gap between lamination while stacking them (the core stacking element may be taken as 0.9), we now have
Gross core area = Core Area / 0.9 sq cm. In general, a square central limb is preferred.
For this, the width of the tongue of lamination is
Tongue width = √Gross core area (sq.cm)
Now refer to Table#2 once again and as a final point find the appropriate core size, having adequate window area and a nearby value of the tongue width as calculated. Modify thel stack height as needed to acquire the intended core section.
Stack Height = Gross Core Area / Actual Tongue Width
The stack must not be a lot under the tongue width rather should be more. However, it must not be greater than 11/2 times the tongue width.
Core Assembly Diagram


How to Assemble the Transformer
The winding are done over an insulating former or bobbin that fits on the middle pillar of the core lamination.
The primary is generally wound first, and next it is the secondary, keeping an insulation between the two layers of the winding.
One last insulating layer is applied on top of the winding to safeguard all of them from mechanical and vibration deterioration.
Whenever thin wires are employed, their particular ends needs to be soldered to heavier wires in order to bring the terminals outside the former.
The lamination are usually put together on the former by alternate lamination reversed in set up.
The lamination has to be tightly bound together through an appropriate clamping framework or by using nuts and bolts (in case through holes are supplied within the lamination assembly).
How to Apply Shielding
This can be a wise idea to utilize an electrostatic shielding between the primary and secondary winding to circumvent electrical interference from moving across to the secondary from the primary.
The shield for step down transformers can be constructed from a copper foil which can be wound between the two winding for somewhat more than a tum.
Insulation has to be presented across the entire foil and proper care taken in order that the two ends of the foil never come in contact with each other.
Additionally a wire could be soldered with this shielding field and connected with the ground line of the circuit or with the lamination of the transformer which may be clamped with the ground line of the circuit.
For Torroidal Transformer designing, you can refer to the following pdf document:
https://www.homemade-circuits.com/wp-content/uploads/2021/04/torroidal-transformer_compressed.pdf
Additional Useful Information Regarding Transformer Winding
The following useful data related to transformer winding was kindly shared by Mr. Constantinos Mermygas. I hope the readers will find it very helpful.



Simple Calculation of Transformers Up to 2000 Watts
Parameters:
- V = Mains voltage
- f = Network frequency in cycles per second
- S = Core cross-section in square centimeters
- B = Weber per square centimeter (Weber/cm²)
- 4.44 = Coefficient of constant
- N1 = Turns of primary winding
- N2 = Turns of secondary winding
- I1 = Primary current in Amperes
- I2 = Secondary current in Amperes
- W = Transformer power in Watts
Calculation Notes:
- Choose Bmax = 1.2 (maximum flux density).
- To calculate a transformer, determine the power consumption on the secondary winding and add approximately 10%.
Power Calculation Example:
- Secondary Voltage: 24 volts
- Current: 15 Amps
- Transformer Power: (24 * 15) + 10% = 400 watts
Core Cross-Section Calculation:
- Example:
Core cross-section: √400 * 1.2 = 24 cm²
Central trunk (tongue): - Width = 5 cm
- Height = 4.8 cm
- Add 5% for varnish, total height ≈ 5 cm
Primary Winding Turns Calculation:
- Formula:
N1 = V / (4.44 × B × S × f / 10,000)
Primary Current Calculation:
- Formula:
I1 = W / V
Example:
I1 = 400W / 220V = 1.818 Amperes
Wire Calculation:
- Example:
- Wire Diameter: 1 mm
- Cross Section: 0.785 mm²
- Current Strength: Up to 1.960 Amperes




Questions & Answers
Hi
I followed a circuit instruction to wind a step up transformer 15 winds on the primary side 45 on the other. I used 0.6mm insulated hook up wire.
I connected the primary to a wall wart , a volt meter to the secondary and got nothing on the volt meter. the windings are on opposite sides of 20mm x 1.6 mm box section 12mm wide. Resistance test doesn’t indicate broken wires or contact with the box section former. Why doesn’t my transformer work?
Hi, if you did everything correctly then your transformer should have started working immediately. There must some winding issue or lamination core issue which may be causing an error. You can read the following article for more info:
https://www.homemade-circuits.com/how-transformers-work/
A Stranger CUBE 80 model amplispeaker mains transformer was burnt. Due to the burnt, the winding turns cannot be counted anymore. The bobbin area core is 1.2 x 1.2 sq inch (3.2 x 3.2 sq cm or 32mm x 32mm). The 220 volt primary secondary winding uses 32 SWG copper wire. Also the output secondary winding for 0 – 40 volt winding uses 32 SWG. The output of 9 – 0 – 9 volts uses 30 SWG. Another output of 25 – 0 – 25 volt uses 22 SWG. Please calculate for me the number of turns of winding of the (1) 220 volt primary, and (2) for the 40 volts. Thank you, Sir.
Momin, I will try to solve it for you once I am free from my pending assignments, in the meantime you can also try calculating using the procedures given above…
Hello Swagatam
Thanks for your reply.
Now inverter 24v to 230v. 900va
CA=35cm2
TPV=1.0
Primary turns=24nos. 40amp 8swg
Sec turns=. 230nos. 4amp. 18swg
Now which bobbin and crgo EI core should I choose for the best result?
Hope you best
Happy New year
Hello JK,
I think only a transformer expert would be able to suggest you correctly about the exact dimensions.
Basically, Use a bobbin that matches the EI core size. For a 35cm^2 core area, the EI core size would likely be between EI 96 and EI 120.
Hello. Swagatam
Hope you fine
Core area,= 1.152 sqrt (VA)
HOW this formula is derived?
Thanks
Hi JK,
Output Voltage (V) is the voltage that comes out of the transformer’s secondary side.
Output Current (A) is the current that flows out of the transformer’s secondary side.
√(Output Voltage * Output Current) shows the apparent power (VA) of the transformer.
The number 1.152 is a constant and is derived by experimenting with the following factors of an iron core transformer::
Magnetic Flux Density (B): This is a common value for iron-core transformers usually between 1.2 and 1.5 Tesla.
Frequency (f): This refers to the usual mains frequency which is either 50 or 60 Hz.
Efficiency: Transformers don’t work at 100% efficiency in real life so this number helps to factor in losses from things like core saturation, hysteresis, and eddy currents.
Practical Design Adjustments: This includes industry standards and safety margins.
No mention is made about the weight of the core itself. I thought the weight of the core in kg is an important factor in power handling of the transformer.
Hi.. Swagatam Thank you for the great works.
I think for high power designs we can either slightly decrease or increase the Bmax value or Power (watt) value to see the Cross sectional area, and then Check if it’s the same measurements with our real transformers Cross sectional area.
And with that we can knw if the transformer can deliver the actual power using the formula provided.
Thanks David, you are correct, we can try that. Appreciate your feedback.
Hi sir, thank you for the information. I would like to ask how you derive the equation of core area to get 1.152 x √(output voltage x output current) sq cm?
Hi Julian, it is a standard formula, I do not have sufficient information regarding how the formula was derived.
I see, appreciate for your help!
nice and usefull information
hello sir plz can you confirm that 1.152 is what and where you get this value.
Hello Rajiv,
The 1.152 is a constant and is permanently included in the formula.
Thank you sir
Great article but I’m still a little confused and don’t want to get it wrong. I’d like to build a transformer, 220v primary @ 60hz, 80v secondary with a max draw of 135 amps. Is that doable? I need help with core size and winding diameter. I’m assuming at 135amps it will get very hot if something is wrong.
Any input is appreciated,
Thank you
I understand your requirement, but unfortunately the Tables in the above article support only upto 10 amp transformers, so 135 amp may not be possible using the above information
Sir please meking the 1chapter choke design
thank u sir , and can u pls share 16vdc to 14vdc 2n3055 transister based regulating power supply ckt diagram once.
Try the second circuit from this article:
https://www.homemade-circuits.com/how-to-make-current-controlled-12-volt/
Hi! I have been a fan of your work and i’m from the Philippines. I know it’s rude for me to ask but can you have sample calculation for a 750 watts transformer 50/60Hz that will be use in power inverter? I just want to have a sample and it serve as a guide as well. Hoping to hear your response soon! More power! \m/
Thank you so much Diltone, I appreciate your kind words.
Yes I have a sample article which explains how to wind an inverter transformer, however the maximum current is only 10 amps. Here’s the link for the article:
https://www.homemade-circuits.com/how-to-design-your-own-inverter/
Thank you for the quick response! I just want to ask since I haven’t read the article and the link you sent me but I just want to know how much wattage that 10 amps will deliver?
You can multiply 10 amps with the battery voltage, that will be the maximum wattage achievable from the transformer.
I have a transformer 50 kva 400/11000 v, if I doubled the low voltage turns, can I connect the low voltage side of the transformer to 800 volts source to step up to 11kv
Is there any issue will appear during operation
Yes, as per the transformer standard formulas, that should be OK and possible.
great tutorial! Thanks for sharing this. Have you done a tutorial on winding a 3 phase step up/down transformer? I’d like to use a VFD single phase to 3 phase inverter, but the output is 110vac. I need to step this down.
Any suggestions would be welcome!
Thanks
Doug
Thank you!
I do not have a 3 phase transformer tutorial yet. If posible I will rty to investigate it.
For converting a 110V AC to lower levels only a step down transformer would work and can be used.
yes, the step down seemed to be the logical way to go – but doing with 1 transformer would certainly be easier than using 3, separate transformers 🙂
Thanks again for your comments and efforts.
Doug
sir how many turns will be required for both primary and secondary sides of 0-6v 50amps center tap transformer
John, the maximum current that can be used is upto 10 amps according to the above article…there’s no data given above this value in the relevant tables.
I need to make an audio transformer for an old telephone. One winding is 15 Ohms the other is 75 Ohms. Voltage supply is 3 volts.
An exisiting transformer is cylindrical and is 4 inches long by 3/4 inch in diameter with a laminated core.
Is it possible to specify wire diameter and number of turns in each coil.
Thankyou
Rod
It can be difficult to suggest the number of turns, however the wire thickness on the 75 ohm side can be around 0.3mm and on the 15 ohm ohm this can be around 0.5mm
Since you have the resistance values for the respective winding, you can wind it by some trial and error until the specified resistance values are achieved.