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The post explains the how IC 555 works, its basic pinout details and how to configure the IC in its standard or popular astable, bistable, and monostable circuit modes. The post also details the various formulas for calculating the IC 555 parameters.

Contents

Introduction

Our hobby world would be less interesting without IC 555. It would be one of our first IC to use in electronics. In this article we are going to look back at history of IC555, their 3 operating modes and some of their specifications.

IC 555 was introduced in 1971 by a company called “Signetics”; it was designed by Hans R. Camenzind. It was estimated that about 1 billion units is manufactured every year.

That’s one IC 555 for every 7 people in the world. The Signetics Company is owned by Philips Semiconductor. If we look at the internal block diagram of IC 555 we can see three 5K ohm resistors connected in series, so we got name as 555 timer. But some hypothesis claims that it was arbitrary.

How IC 555 Works

A standard IC555 consist of 25 transistors, 15 resistors and 2 diodes integrated on a silicon die. There are two versions of the IC available namely military and civilian grade 555 timer.

The NE555 is a civilian grade IC and has operating temperature range of 0 to +70 degree Celsius. The SE555 is military grade IC and has operating temperature range of -55 to +125 degree Celsius.

You will also find the CMOS version of timer known as 7555 and TLC555; these consume less power compared to standard 555 and operate less than 5V.

CMOS version timers consist of MOSFETs rather than bipolar transistor, which is efficient and consume less power.

IC555 PIN DIAGRAM:

• Pin 1: Ground or 0V.
• Pin 2: Trigger or input.
• Pin 3: Output.
• Pin 4: Reset.
• Pin 5: Control.
• Pin 6: Threshold.
• Pin 7: Discharge.
• Pin 8: Vcc Supply input between 5 V and 15 V.

3 Modes of timer:

1. Bistable or Schmitt trigger
2. Monostable or one shot
3. Astable

Bistable Mode:

When the IC555 is configured in bistable mode it works as a basic flip-flop. In other words when the input trigger is given, it toggles the output stateON or OFF.

Normally #pin2 and #pin4 are connected to pull-up resistors in this mode of operation.

When the #pin2 is grounded for short duration, the output at #pin3 goes high; to reset the output, #pin4 is momentarily shorted to ground, and then the output goes low.

There is no need for a timing capacitor here, but connecting a capacitor (0.01uF to 0.1uF) across #pin5 and ground is recommended. #pin7 and #pin6 can be left unconnected in this configuration.

Here is a simple bistable circuit:

When the set button is depressed the output goes high and when reset button is depressed the output goes to low state.R1 and R2 may be 10k ohm, the capacitor may be anywhere between the specified value.

Monostable Mode:

Another useful application of the IC 555 timer is in the form of a one-shot or monostable multivibrator circuit, as shown in the figure below.

As soon as the input trigger signal becomes negative, the one-shot mode is activated, causing the output pin 3 to go high at the Vcc level. The time period of the output high condition can be calculated suing the formula:

Thigh = 1.1 RAC

As seen in the figure, the negative edge of the input forces the comparator 2 to toggle the flip-flop. This action causes the output at pin 3 to go high.

Actually in this process the capacitor C is charged toward VCC via the resistor RA. While the capacitor charges, the output is held high at the Vcc level.

When the voltage across the capacitor acquires the threshold level of 2VCC/3, comparator 1 triggers the flip-flop, forcing the output to change state and go low.

This subsequently turns the discharge low, causing the capacitor to discharge and maintain at around 0 V until the next input trigger.

The figure above shows the entire procedure when the input is triggered low, leading to an output waveform for a monostable one shot action of the IC 555.

The timing of the output for this mode can range from microseconds to many seconds, allowing this operation to become ideally useful for a range of different applications.

Simplified Explanation for the Newbies

Monostable or one-shot pulse generators are widely used in many electronic applications, where a circuit needs to be switched ON for pre-determined time after a trigger. The output pulse width at #pin3 can be determined by using this simple formula:

T = 1.1RC

Where

T is the time in Seconds

R is resistance in ohm

The output pulse falls when the voltage across the capacitor equals to 2/3 of the Vcc. The input trigger between two pulses must be greater than RC time constant.

Here is a simple Monostable circuit:

Solving a Practical Monostable Application

Find out the period of the output waveform for the circuit example shown below when it is triggered by a negative edge pulse.

Solution:

Thigh = 1.1 RAC = 1.1(7.5 x 103)(0.1 x 10-6) = 0.825 ms

How Astable Mode Works:

Referring to the figure below, the Capacitor C is charged towards VCC  level through the two resistors RA and RB. The capacitor is charged until it reaches above 2VCC/3. This voltage becomes the threshold voltage on pin 6 of the IC. This voltage operates comparator 1 to trigger the flip-flop, which causes so  the output at pin 3 to become low.

Along with this, the discharge transistor is switched ON, resulting in the pin 7 output discharging the capacitor via resistor RB.

This causes the voltage inside the capacitor to fall until finally it drops below the trigger level (VCC/3). This action instantly triggers the flip flop stage of the IC, causing the output of the IC to go become high, turning OFF the discharge transistor. This yet again enables the capacitor to get charged via resistors RA and RB toward VCC.

The time intervals which is responsible for turning the output high and low can be calculated using the relations

Thigh ≈ 0.7(RA + RB)C

Tlow ≈ 0.7 RBC

The total period is

T = period = Thigh + Tlow

Simplified Explanation for the Newbies

This is the most commonly used multivibrator or AMV design, and this would be one of our first circuit implemented for IC 555 as a hobbyist (remember alternate blinker LED?).

When IC555 configured as astable multivibrator, it gives out continuous rectangular shaped pulses at #pin3.

The frequency and pulse width can be regulated by R1, R2 and C1.The R1 is connected between Vcc and discharge #pin7, R2 is connected between #pin7 and #pin2 and also #pin6. The #pin6 and #pin2 are shorted.

The capacitor is connected between #pin2 and ground.

The frequency for Astable multivibrator can be Calculated by using this formula:

F = 1.44/((R1+R2*2)*C1)

Where,

F is the frequency in Hertz

R1 and R2 is resistors in ohms

The high time for each pulse given by:

High= 0.693(R1+R2)*C

Low time is given by:

Low= 0.693*R2*C

All ‘R’ is in ohms and ‘C’ is in ohms.

Here is a basic astable multivibrator circuit:

For 555 IC timers with bipolar transistors, R1 with low value must be avoided so that the output stays saturated near ground voltage during discharge process, else the ‘low time’ could be unreliable and we may see greater values for low time practically than calculated value.

Solving an Astable Example Problem

In the following figure find the frequency of the IC 555 and draw the output waveform results.

Solution:

Waveform images can be seen below:

PWM Circuit

If you want the output less than 50% duty cycle i.e. shorter high time and longer low time, a diode can be connected across R2 with cathode on the capacitor side. It's also called the PWM mode for the 555 IC timer.

You can also design a 555 PWM circuit with variable duty cycle two diodes as shown in the above figure.

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11 thoughts on “IC 555 Pinouts, Application Circuits and Calculations”

1. Please how can I design bistable 555 circuit to get 400hz .

• Please how can I design bistable 555 circuit to get 400hz .

• It is not bistable, it is an astable that will give you a frequency

2. Hi Swagatam,
I have a circuit that uses a ne555p astable timer that is on for 240 seconds(4-min) and is off for 1 second, then on for 240 sec, etc. My problem is the timing is off (about 1.5 times) for the first cycle when I power up the circuit. Is there a way to make the power up timing cycle be the same as the other cycles? Thanks!
Norman

• Hi Norman,

you can correct it by configuring the reset pin appropriately, so that each time power is switched ON the IC begins from the start.

for this you may connect the pin#4 of the IC with the positive line through a 10K resistor, and a add a 10uF capacitor across pin#4 and the negative supply line.

also make sure to add a 10k resistor across the positive and the negative supply lines.
hope this corrects the issue…

• Hi Swagatam, I recently ask you about a problem of my timing circuit using 555 timer was not correct at initial start up. You suggested I add a 10k resistor to ground and a 10k resistor to voltage and a 10uF cap to ground from pin 4 of the 555 timer. I did that with no effect. The initial cycle time is about 5 min. 45 sec. and all other cycles are 4 min as I designed. I have attached a partial circuit showing the timing part of the circuit. Any other suggestions would be appreciated. Thanks!
Norman
You system will not accept my schematic.

• Hi Norman,

I have replied to your email

3. check the soldering connections properly, you might have made some mistake…

4. you are most welcome!

5. If you search my blog you may find a few of them , however if you have specific questions , I can clarify them for you separately….

6. Hi, current sensing transformer would be unnecessarily complex to calculate and build, instead an opamp or resistive network could be applied for the same results with perfect accuracy.

for sensing current a simple series resistor could be used