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Simplest Full Bridge Inverter Circuit

Last Updated on March 20, 2025 by Swagatam 391 Comments

Among the different existing inverter topologies, the full bridge or the H-bridge inverter topology is considered to be the most efficient and effective. Configuring a full bridge topology could involve too many criticality, however with the advent of full bridge driver ICs these have now become one of the simplest inverters one can build.

Table of Contents
  • What's a Full-Bridge Topology
  • Circuit Operation
  • Important Calculations
    • Frequency Calculation for IRS2453 Oscillator
    • Gate Resistors
    • Power Dissipation in Gate Resistors:
    • Drain-Source Voltage (VDS):
    • Current Handling (ID):
    • Reverse Gate Diodes
    • Reverse Recovery Time:
    • Power Dissipation:
    • Load Power
    • Load Current (Iload):
    • Power Dissipation in MOSFETs:
    • Capacitor Selection
    • Bootstrap Capacitors (1 µF/25V):
    • High Voltage Feature
  • Simple H-Bridge or Full Bridge Inverter using two Half-Bridge IC IR2110
    • Parts List
    • Oscillator Circuit
    • Discrete Full Bridge Inverter using Transistor

What's a Full-Bridge Topology

A full bridge inverter also called an H-bridge inverter, is the most efficient inverter topology which work two wire transformers for delivering the required push-pull oscillating current into the primary. This avoids the use of a 3-wire center tapped transformer which are not very efficient due to their twice the amount of primary winding than a 2-wire transformer

This feature allows the use of smaller transformers and get more power outputs at the same time.Today due to the easy availability of full bridge driver ICs things have become utterly simple and making a full bridge inverter circuit at home has become a kids play.

Here I have explained a full bridge inverter circuit using the full bridge driver IC IRS2453(1)D from International Rectifiers.

The mentioned chip is an outstanding full bridge driver IC as it single handedly takes care of  all the major criticality involved with H-bridge topologies through its advanced in-built circuitry.

The assembler simply needs to connect a few handful of components externally for achieving a full fledged, working H-bridge inverter.

The simplicity of the design is evident from the diagram shown below:

Circuit Operation

NOTE: Please join the SD pin of the IC with the ground line, if it is not used for the shut down operation.

Pin14 and pin10 are the high side floating supply voltage pinouts of the IC. The 1uF capacitors effectively keep these crucial pinouts a shade higher than the drain voltages of the corresponding mosfets ensuring that the mosfet source potential stays lower than the gate potential for the required conduction of the mosfets.

The gate resistors suppress drain/source surge possibility by preventing sudden conduction of the mosfets.

The diodes across the gate resistors are introduced for quick discharging of the internal gate/drain capacitors during their non-conduction periods for ensuring optimal response from the devices.

The IC IRS2453(1)D is also featured with an in-built oscillator, meaning no external oscillator stage would be required with this chip.

Just a couple of external passive components take care of the frequency for driving the inverter.

Rt and Ct can be calculated for getting the intending 50Hz or 60 Hz frequency outputs over the mosfets.

Important Calculations

Frequency Calculation for IRS2453 Oscillator

The IRS2453 chip uses external components Rt and Ct to set the PWM frequency.

Formula:

f = 1 / (1.453 × Rt × Ct)

  • Where:
  • f = Switching frequency (Hz)
  • Rt = Timing resistor (ohms)
  • Ct = Timing capacitor (farads)

Example Calculation:

Let us Assume Rt = 33 kΩ = 33 × 10³ Ω, Ct = 1 µF = 1 × 10⁻⁶ F:

f = 1 / (1.453 × (33 × 10³) × (1 × 10⁻⁶))

f = 1 / (1.453 × 33 × 10⁻³)

f ≈ 20.9 kHz

Thus the switching frequency is approximately 20.9 kHz. So you can adjust Rt and Ct to modify the frequency as needed.

Gate Resistors

The 33ohm resistors at the MOSFET gates limit the inrush current during switching and dampen oscillations.

Power Dissipation in Gate Resistors:

Pgate = Qg × Vgate × f

  • Where:
  • Qg = Gate charge of the MOSFET (63 nC for IRF540)
  • Vgate = Gate drive voltage (10V)
  • f = Switching frequency (20.9 kHz)

Substituting values:

Pgate = 63 × 10⁻⁹ × 10 × 20.9 × 10³

Pgate ≈ 0.013 W

Each gate resistor dissipates approximately 13 mW, which is negligible.

Power MOSFET Ratings (IRF540)

Drain-Source Voltage (VDS):

The MOSFETs must withstand the full rectified supply voltage. For a 15V input, VDS(max) must be higher than 15V. The IRF540 has a VDS(max) of 100V, which is adequate.

Current Handling (ID):

Each MOSFET handles half the load current:

ID = Iload / 2

Ensure ID(max) (33A for IRF540) exceeds this value.

Reverse Gate Diodes

The 1N4148 diodes ensures instant gate capacitance discharge for the MOSFETs, which ensures efficient switching response from the MOSFETs.

Reverse Recovery Time:

The recovery time for 1N4148 is 4ns, suitable for high-frequency switching.

Power Dissipation:

Pdiode = Vf × Iload

Where Vf = Forward voltage of the diode (0.7V for 1N4148).

Load Power

The load determines the current through the MOSFETs and resistors.

Load Current (Iload):

Iload = Pload / Vsupply

For Pload = 50 W and Vsupply = 15V:

Iload = 50 / 15 = 3.33 A

Power Dissipation in MOSFETs:

PMOSFET = ID² × RDS(on)

For IRF540, RDS(on) = 0.044 Ω:

PMOSFET = (3.33 / 2)² × 0.044 = 0.122 W per MOSFET.

Capacitor Selection

Input Capacitor (100 µF/25V):

Filters the rectified AC and smooths the supply voltage. The ripple current rating should exceed the load current (Iload).

Bootstrap Capacitors (1 µF/25V):

These provide gate drive voltage for the high-side MOSFETs. Ensure the value can handle the gate charge (Qg) of the MOSFETs.

High Voltage Feature

Another interesting feature of this IC is its ability to handle very high voltages upto 600V making it perfectly applicable for transformeless inverters or compact ferrite inverter circuits.

As can be seen in the given diagram, if an externally accessible 330V DC is applied across the "+/- AC rectified lines", the configuration instantly becomes a transformerless inverter wherein any intended load can be connected directly across the points marked as "load".

Alternatively if an ordinary step-down transformer is used, the primary winding can be connected across the points marked as "load". In this case the "+AC rectified line" can be joined with pin#1 of the IC and terminated commonly to the battery (+) of the inverter.

If a battery higher than 15V is used, the "+AC rectified line" should be connected directly with the battery positive while pin#1 should be applied with a stepped down regulated 12V from the battery source using IC 7812.

Although the below shown design looks too easy to construct, the layout requires some strict guidelines to be followed, you may refer to the post for ensuring correct protection measures for proposed simple full bridge inverter circuit.

Simple H-Bridge or Full Bridge Inverter using two Half-Bridge IC IR2110

Parts List

ComponentValue / Part NumberDescription
IC1, IC2IR2110High and Low Side MOSFET Driver IC
Q1, Q2, Q3, Q4IRF540 or SimilarN-channel MOSFETs
D1, D2, D3, D41N4007General-purpose rectifier diodes (for bootstrap circuit protection)
C1, C2100nF (0.1µF)Ceramic capacitor (decoupling for IR2110)
C3, C4, C5, C6, C7, C822µF / 25VElectrolytic capacitors (bootstrap and power supply stabilization)
R1, R2, R3, R4150Ω / 0.25WGate resistors for MOSFETs
R5, R6, R7, R81KΩ / 0.25WPull-down resistors for MOSFET gates
VCC+12VPower supply for IR2110
Logic Supply+5VLogic supply for control signals
Load SupplyVDC LoadMain DC power for the load
Clock InputFrom Astable MultivibratorExternal alternating PWM signal source

The diagram above shows how to implement an effective full bridge square wave inverter design using a couple of half bridge ICs IR2110.

The ICs are full fledged half bridge drivers equipped with the required bootstrapping capacitor network for driving the high side mosfets, and a dead-time feature to ensure 100% safety for the mosfet conduction.

The ICs work by alternately switching the Q1/Q2 and Q3/Q4 mosfets in tandem, such that at any occasion when Q1 is ON, Q2 and Q3 are completely switched OF and vice versa.

The IC is able to create the above precise switching in response to the timed signals at their HIN and LIN inputs.

These four inputs needs to be triggered to ensure that at any instant HIN1 and LIN2 are switched ON simultaneously while HIN2 and LIN1 are switched OFF, and vice versa. This is done at twice the rate of the inverter output frequency. Meaning if the inverter output is required to be 50Hz, the HIN/LIN inputs should be oscillated at 100Hz rate and so on.

Oscillator Circuit

IR2110 input feed oscillator circuit

This is an oscillator circuit which is optimized for triggering the HIN/LIN inputs of the above explained full-bridge inverter circuit.

A single 4049 IC is used for generating the required frequency and also for isolating the alternating input feeds for the inverter ICs.

C1 and R1 determine the frequency required for  oscillating the half bridge devices and could be calculated using the following formula:

f = 1 /1.2RC

Alternatively, the values could be achieved through some trial and error.

Discrete Full Bridge Inverter using Transistor

So far we have studied a full bridge inverter topologies using specialized ICs, however the same could be built using discrete parts such transistors and capacitors, and without depending on ICs.

A simple diagram can be seen below:

simple transistorized full bridge inverter circuit using discrete parts

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Filed Under: Inverter Circuits Tagged With: Bridge, Full, Inverter, Simplest

About Swagatam

I am an electronics engineer and doing practical hands-on work from more than 15 years now. Building real circuits, testing them and also making PCB layouts by myself. I really love doing all these things like inventing something new, designing electronics and also helping other people like hobby guys who want to make their own cool circuits at home.

And that is the main reason why I started this website homemade-circuits.com, to share different types of circuit ideas..

If you are having any kind of doubt or question related to circuits then just write down your question in the comment box below, I am like always checking, so I guarantee I will reply you for sure!



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Reader Interactions

Questions & Answers

Total Posts: 391
Newest Oldest
brian
May 1, 2026 • 3 months ago #206205

educate me .. u is using an N Mosfet for high side switching

Reply
brian
May 4, 2026 • 3 months ago #206450

finally after reading all that is required to use P channel and N channel for high side switching , from many data sheets yes you have educated me,
much thanks
regards
Br

Reply
SwagatamAdmin
May 5, 2026 • 3 months ago #206465

Thank you, I am glad it helped you to understand the concepts better…please keep up the good work…

Reply
Majaha Masuku
February 18, 2026 • 5 months ago #201288

Hie sir, I want to make a 24v Fullbridge inverter , 12 mosfets , 3per channel , can I use transistor level shifters to drive the mosfets instead of drivers?

Reply
SwagatamAdmin
February 19, 2026 • 5 months ago #201318

Hi Majaha,
Basic level shifters will not work for N-channel h-bridge without complex circuitry, so specialized driver ICs will be required, since they can make H-bridge designs very simple and reliable, so driver ICs are recommended.

Reply
saeef
January 8, 2026 • 7 months ago #198588

Some induction furnace designs have the problem that the MOSFET or EGBT burns out quickly and its protection is very weak. I want a design that allows the EGBT to work with the drive.

Reply
Saykio
January 7, 2026 • 7 months ago #198493

Hello, I just tried to replicate your circuit in Qspice, but it’s not working. Have you ever simulated it in Qspice or LTspice, or did you just build it directly?

I’ve built a half-bridge with only one driver before, and that worked. Now I’m trying to convert the DC-DC with 30V operating voltage into a DC-AC. Any tips for me?

Reply
SwagatamAdmin
January 8, 2026 • 7 months ago #198539

Hey, the IR2110 circuit is 100% tested and a practically working design.
Make sure the HIN and LIN of the two ICs are correctly swapped….meaning the HIN of one IC joins with the LIN of the other IC and vice versa…

Reply
Saykio
January 8, 2026 • 7 months ago #198584

Thank you for your feedback. The HIN and LIN of the two ICs are connected correctly. I can see that the SPWM is correctly inverted in the four inputs. The problem is with the outputs and the voltage at the load. Yesterday, I also sent you an email with the file I created in Qspice. Have you looked at it? Thank you in advance!

Reply
SwagatamAdmin
January 9, 2026 • 7 months ago #198657

Hi, It is not possible for me to troubleshoot a simulator result…however if you build and test it practically and explain me the issue, then I can try troubleshooting it, but not a simulator result…

sorry I did not find any email of your..

Reply
Engr Bright
November 12, 2025 • 9 months ago #190286

pls can you send me a 24v low battery protection circuit diagram for my inverter using sg3524 ic. or using relay to disconnect the supply voltage from entering into the voltage regulator lm7812. with explanation pls

Reply
SwagatamAdmin
November 12, 2025 • 9 months ago #190310

Bright, you can use the following circuit and connect the pin#6 of the opamp with pin#10 of the SG3525:
Low voltage Indicator 1
Please replace the 741 with one opamp from IC LM358 and Adjust the preset appropriately to set the cut off point of the Ic.

Reply
Engr Bright
November 9, 2025 • 9 months ago #190032

I power the circuit with 48v battery it blow my high side MOSFET pls what bootstrap capacitor to use because I use 50v/10uf which work on my 24v battery before but now on 48 my MOSFET blow pls help

Reply
SwagatamAdmin
November 9, 2025 • 9 months ago #190042

Your bootstrap capacitor is OK, according to me, even for 48V….
I think you must use snubbers for the MOSFETs, and always use a series bulb initially while testing an confirming a newly built design:
https://www.homemade-circuits.com/explained-snubber-circuit-for-mosfet-h-bridge/

Reply
Engr Bright
October 27, 2025 • 9 months ago #189198

pls what are the things to change if I want to make this ir2110 h-bridge inverter work on a 48v battery. should I change the boost capacitor to what pls.

Reply
Engr Bright
October 31, 2025 • 9 months ago #189476

I made this H-bridge circuit with two ir2110, sg3524 as my oscillator and my battery voltage is 25.6v but when I put my multimeter at the load side of the mosfet for transformer, I was getting 28.0v stable, when I set the preset of sg3524 the voltage comes down to 24.2v to 21.0v and the voltage was fauctuating. pls what do I do. I want to use a transformer from a 24v 2kva inverter.

Reply
SwagatamAdmin
October 31, 2025 • 9 months ago #189485

If your meter is set to read AC, then the voltage looks OK to me, since the AC across the load side will read same as the battery voltage. If the meter is set for DC then you must see around 13V DC on your meter for a 25V battery….
If you want to be 100% sure then you may have to use an oscilloscope to check the waveform across the various points on your inverter.
Right now, you can connect and small transformer across the load side of the MOSFETs and check whether the transformer generates the 220V AC or not…

Reply
SwagatamAdmin
October 27, 2025 • 9 months ago #189220

Nothing needs to be changed except the drain side voltage for the MOSFFETs, except the bootstrap 1uF capacitor voltage, which should be 100V rated. Also consider putting snubbers across each mosfets as explained below:
https://www.homemade-circuits.com/explained-snubber-circuit-for-mosfet-h-bridge/

Reply
Engr. Bright
July 4, 2025 • 1 year ago #184151

Pls one of my MOSFET gate resistor of 33kohms spiol can I replace it with 10 ohms resistor in my inverter since it is only one

Reply
SwagatamAdmin
July 5, 2025 • 1 year ago #184161

Why did you use a 33k initially, was there any specific reason? For high frequency operation of a MOSFET through a logic gate, the resistor can be a low value such as 10 ohms. So if your MOSFET gate is connected to some logic IC then yes you can use a 10 ohm series resistor.

Reply
Engr Bright
October 26, 2025 • 9 months ago #189163

pls can I still use 10uf/50,v as boost cap on a 48v to 220v inverter

Reply
SwagatamAdmin
October 27, 2025 • 9 months ago #189218

Yes, because the circuit is still operating with 12V DC only,….the MOSFET side is operating with 48V

Reply
Engr Bright
July 3, 2025 • 1 year ago #183971

pls I want to build 24v inverter h-bridge with ir2110 MOSFET gate driver which value of capacitor to choose as bootstrap capacitor. can I choose 50v/47uf or 50v/10uf

Reply
SwagatamAdmin
July 3, 2025 • 1 year ago #183999

10uF/50V should be quite enough.

Reply
Yanior
January 26, 2025 • 1 year ago #168157

El tl494 para que sirve

Reply
SwagatamAdmin
January 26, 2025 • 1 year ago #168160

tl494 is an oscillator IC.

Reply
Yanior
January 26, 2025 • 1 year ago #168156

Gracias por ayudarme a mejorar las experiencia en electrónica

Reply
Yanior
January 26, 2025 • 1 year ago #168155

Porque los diodos de salida del inversores se calientan

Reply
SwagatamAdmin
January 26, 2025 • 1 year ago #168159

which diodes are you referring to exactly?

Reply
sayed 2000
October 24, 2024 • 2 years ago #164173

hello sir i hope you good,, i have talk with you about full h-bridge solar inverter 5.5kw and volatge from the solar is 490v and i am using SPW47N60C3 mosfet and 10 mosfet on each channel all mosfets i will use 40 mosfets ….10 on each channel i will use 2 IR2110 ic and cd4047 for pwm for 2 IR2110 ic to drive mosfets to make it full h-bridge
i have a question and thanks you for your time.
how much current the circuit need for ics to feed gate mosfets without any problem and what is the best voltage?

Reply
SwagatamAdmin
October 24, 2024 • 2 years ago #164180

Thank you Sayed,
The MOSFET gates are high impedance inputs so the current does not matter, the gates can work with microamperes also, so nothing to worry about the current. The best voltage is 12V.
The ICs might need 5 to 10mA for operating correctly.

Reply
Engr Bright
October 20, 2025 • 9 months ago #188631

pls can any h-bridge pure sine wave 12v inverter transformer work with this circuit

Reply
Engr Bright
October 24, 2025 • 9 months ago #188922

pls if I want to build this inverter to work on a 48v battery, with ir2110 driver can I use a zener/resistor to regulate the 48v from the battery to 12v and 5v to power the ic/ir2110

Reply
SwagatamAdmin
October 24, 2025 • 9 months ago #188935

Yes, you can use zener/resistor for stepping down the 48V to 12V at the VCC pin of the IC…

Reply
SwagatamAdmin
October 21, 2025 • 9 months ago #188651

Yes, any two wire primary/secondary side transformer will work…

Reply
sayed 2000
October 25, 2024 • 2 years ago #164290

okay i want ask you again and i am sorry for taking from you time.sir
i will make circut without transformer to feed the ics and gates of mosfets
12v 150 ma it will handle the gates and ics?
question two the gates takes power from the 2 IR2110 ics and cd4047 right?

Reply
SwagatamAdmin
October 25, 2024 • 2 years ago #164308

No problem Sayed,
Yes 12V 150mA will more than sufficient for the ICs and the MOSFET gates.
Your second question is also correct. However remember that the HIN pin of one IR2110 IC must connect with the LIN pin of the other IR2110 IC, and vice versa.

Reply
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