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Simplest Full Bridge Inverter Circuit

Simplest Full Bridge Inverter Circuit

Among the different existing inverter topologies, the full bridge or the H-bridge inverter topology is considered to be the most efficient and effective. Configuring a full bridge topology could involve too many criticality, however with the advent of full bridge driver ICs these have now become one of the simplest inverters one can build.

What's a Full-Bridge Topology

Full bridge inverter circuits also called the H-bridge inverter, are the truly efficient ones since these do not require a center tapped transformers and yet are able to implement the intended push-pull functions right across the entire primary winding of the attached tansformers.

This feature allows the use of smaller transformers and get more power outputs at the same time.Today due to the easy availability of full bridge driver ICs things have become utterly simple and making a full bridge inverter circuit at home has become a kids play.

Here we discuss a full bridge inverter circuit using the full bridge driver IC IRS2453(1)D from International Rectifiers.

The mentioned chip is an outstanding full bridge driver IC as it single handedly takes care of  all the major criticality involved with H-bridge topologies through its advanced in-built circuitry.

The assembler simply needs to connect a few handful of components externally for achieving a full fledged, working H-bridge inverter.

The simplicity of the design is evident from the diagram shown below:

Circuit Operation

Pin14 and pin10 are the high side floating supply voltage pinouts of the IC. The 1uF capacitors effectively keep these crucial pinouts a shade higher than the drain voltages of the corresponding mosfets ensuring that the mosfet source potential stays lower than the gate potential for the required conduction of the mosfets.

The gate resistors suppress drain/source surge possibility by preventing sudden conduction of the mosfets.

The diodes across the gate resistors are introduced for quick discharging of the internal gate/drain capacitors during their non-conduction periods for ensuring optimal response from the devices.

The IC IRS2453(1)D is also featured with an in-built oscillator, meaning no external oscillator stage would be required with this chip.

Just a couple of external passive components take care of the frequency for driving the inverter.

Rt and Ct can be calculated for getting the intending 50Hz or 60 Hz frequency outputs over the mosfets.

Calculating Frequency Determining Components

The following formula can be used for calculating the values of Rt/Ct:

f = 1/1.453 x Rt x Ct

where Rt is in Ohms and Ct in Farads.

High Voltage Feature

Another interesting feature of this IC is its ability to handle very high voltages upto 600V making it perfectly applicable for transformeless inverters or compact ferrite inverter circuits.

As can be seen in the given diagram, if an externally accessible 330V DC is applied across the "+/- AC rectified lines", the configuration instantly becomes a transformerless inverter wherein any intended load can be connected directly across the points marked as "load".

Alternatively if an ordinary step-down transformer is used, the primary winding can be connected across the points marked as "load". In this case the "+AC rectified line" can be joined with pin#1 of the IC and terminated commonly to the battery (+) of the inverter.

If a battery higher than 15V is used, the "+AC rectified line" should be connected directly with the battery positive while pin#1 should be applied with a stepped down regulated 12V from the battery source using IC 7812.

Although the below shown design looks too easy to construct, the layout requires some strict guidelines to be followed, you may refer to the post for ensuring correct protection measures for proposed simple full bridge inverter circuit.

NOTE: Please join the SD pin of the IC with the ground line, if it is not used for the shut down operation.

Circuit Diagram

Full bridge inverter using IC IRS2453(1)D

Simple H-Bridge or Full Bridge Inverter using two Half-Bridge IC IR2110

Full bridge inveter using 2 half bridge ICs

Courtesy: http://tahmidmc.blogspot.com/2013/01/using-high-low-side-driver-ir2110-with.html

The diagram above shows how to implement an effective full bridge square wave inverter design using a couple of half bridge ICs IR2110.

The ICs are full fledged half bridge drivers equipped with the required bootstrapping capacitor network for driving the high side mosfets, and a dead-time feature to ensure 100% safety for the mosfet conduction.

The ICs work by alternately switching the Q1/Q2 and Q3/Q4 mosfets in tandem, such that at any occasion when Q1 is ON, Q2 and Q3 are completely switched OF and vice versa.

The IC is able to create the above precise switching in response to the timed signals at their HIN and LIN inputs.

These four inputs needs to be triggered to ensure that at any instant HIN1 and LIN2 are switched ON simultaneously while HIN2 and LIN1 are switched OFF, and vice versa. This is done at twice the rate of the inverter output frequency. Meaning if the inverter output is required to be 50Hz, the HIN/LIN inputs should be oscillated at 100Hz rate and so on.

Oscillator Circuit

IR2110 input feed oscillator circuit

This is an oscillator circuit which is optimized for triggering the HIN/LIN inputs of the above explained full-bridge inverter circuit.

A single 4049 IC is used for generating the required frequency and also for isolating the alternating input feeds for the inverter ICs.

C1 and R1 determine the frequency required for  oscillating the half bridge devices and could be calculated using the following formula:

f = 1 /1.2RC

Alternatively, the values could be achieved through some trial and error.

Discrete Full Bridge Inverter using Transistor

So far we have studied a full bridge inverter topologies using specialized ICs, however the same could be built using discrete parts such transistors and capacitors, and without depending on ICs.

A simple diagram can be seen below:

simple transistorized full bridge inverter circuit using discrete parts


About the Author

I am an electronic engineer (dipIETE ), hobbyist, inventor, schematic/PCB designer, manufacturer. I am also the founder of the website: https://www.homemade-circuits.com/, where I love sharing my innovative circuit ideas and tutorials. If you have any circuit related query, you may interact through comments, I'll be most happy to help!

145 thoughts on “Simplest Full Bridge Inverter Circuit”

  1. sir i want to use IR2153 with inbuilt programmable oscillator having formula for f = 1/(1.4 x (Rt + 75ohm) x Ct. if i calculate the switching frequency of oscillator using its low & high pulse for mosfet driving as 50Hz. will it not be the same as the output frequency provided to the load?

    • Sheraz, the high pulses across Ct switches the high side and the low side outputs of the IC sequentially, therefore for completing each cycle (high + low switching) at the output, the Ct frequency will need to be 100 Hz, as per my understanding.

  2. dear sir! what will be the switching frequency of the mosfets or IGBTs produce by ic IR2453 for 50Hz output wave or it is 50Hz determined by calculating Rt & Ct pins of the ic?

  3. Please sir ur digram is correct but it was not a without center tap project… I am purchase this transformer(without center tap) sir…. Please recommend other sir.. In ur inverter project i show many inverter project in which using ic 555 and without centre tap… Except two batteries project… Can i choose one of them… Sir… And also suggest me which one is…

    • Apurva, IC 555 or any similar oscillator IC will always require a center tap transformer for an inverter configuration, unless two batteries are used.

      • Ok sir… I am agree with ur rply but sir can u provide me without ic 555 and without centre tap transformer project. Even it has complex than also i can tryfor make it.. But their parts will common which are found in my place…. I send u one cricuit diagram in ur email id see it and clarify it it best for me or not… And also give me some knowledge about that circuit… Please sir i always believe on u sir… Please help me

  4. This ic not present in my place. Sir
    Other two ic whivh have same configuration i search in Google but they also not found in my place sir… Please recommend common full bridge drivers ic aur if other suitable diagram which have using ic 555.. Please send me… Please sir i am very happy if u can do for me… Please sir

  5. Sir i show in ups box 600va/360w where we can take this transformer…. And i can check it with 2 bulb100w but time will be to not measure… How much will be glow it

  6. It contain ac power supply for run this this project… But i want run only battery power supply sir.. And used of without centre tape transformer… Because these item would be purchased… Now

    • You can run it with battery also. Just connect the pin#1 of the IC with the upper line, and then you can use 12V battery across the upper line and the lower line.

            • When I have already said that with 12V 7Ah battery you can operate only 50 watt load, then how can 2 100watt work? Please learn the basics first ans then attempt these complex circuits.

            • If i want generate 500w from this cricuit… How much amp battery used with this ups transformer… And also clarify me Can this ups transformer oprate 500w output power… When i introduced ur recommended amp battery…

            • But sir… When this transformer present in ups which are operate by 12v 7ah battery and produce 360watt output how it is possible sir…

            • did you practically put 360 watt and check? 360 watt will draw 30 amp current… from where will the battery will bring 30 amp? 7Ah can produce maximum 7 amp current, and at this rate it will be flat and destroyed within 30 minutes. Even at full 7 amp the max power will be 7 x 12 = 84 watts

  7. Hello.
    I am discovering your blog and i have a question about your
    f = 1/1.453 x Rt x Ct where Rt is in Ohms and Ct in Farads.

    I thought f=1/2piRC

    What did I miss?

  8. Sir
    I want to make a 150v dc to 110v ac invertor . So can i give 150v dc directly inthe +AC and -AC . Or should i make any changes inthe ckt befor it ??

  9. Sir I make this circuit,at 50hz if 24vdc apply on bridge at load point 15v ac but if 50v or more voltage apply ic and MOSFET damaged.we use bootstrap capacitor 104 if use 105 no drive volt

    • yogesh, as you can see, the mosfet positive is separate from the rectified line, the IC will need to be separately powered through a 15V source, while the mosfet rectified line from the intended high voltage source.

      the mosfets should be rated accordingly to prevent damage.

  10. I will investigate that circuit and try to design something. Also I will check on your circuit, but maybe I will need some modifications, as the “battery” in my case are the rectified 220VAC. Let me investigate and I will be back on you as I have some to share. Thanks for your reply sir. Have a nice day Swag! ๐Ÿ™‚

  11. Dear Swagatam, I sent to you a message in this page a few days ago. At the beginning it said “comment under approval” or something like that. Now I can’t see my message. I’m wondering if you have an automatic spam filter who thinks I’m a robot or whatever. Sorry for this message if cause any bother to you. Thank you! Regards!

    • Hi faktorqm, sorry, did you have too many links in the comment, then may be I might have accidentally marked it as Spam….no problem please repeat your question, if you have links you can post them but after replying I may edit those links and delete them.

      • Thanks for your reply sir! I will post only one thought. I want to construct something like a universal dimmer for all kind of loads (resistive, inductive) using the pwm pure sine technique. My main goal is to dimm, for example, filament light bulbs or leds lamps (in my country there are dimmable electronic transformers with dimmable led lights) or CFL lamps (only on/off without dimm). I found this link with a circuit but there are no values, and I don’t have an actual idea about how components value I need to start testing.


        Thank you very much for your time sir!!

          • Hi Swagatam, thanks for your reply. I didn’t figured it out but as far as I saw the igbt acts just like a on/off switch, which operated correctly, supposedly, it will deliver the square wave at figure 7 on that link. Then the next network with two igbt’s I don’t know, and the L-C circuit it looks like to be a chebyshev low pass filter with order 2 to obtain a “sine” wave after the igbt modulation. (same as the beginning of the circuit network). I have tried to simulate over proteus just the first igbt, with a square wave on the gate, 50% duty cycle, but the result is not what I expected. Maybe I need to setup the entire circuit with thumb rule component values and… cross my fingers ๐Ÿ˜›

            Regarding the circuit you pointed me out, I have one question, In this one https://homemade-circuits.com/2016/05/h-bridge-mains-voltage-stabilizer.html you used an autotransformer at the “exit”. Is this necessary for a dimmer?

            Thanks for your time sir!!!

            • Hi faktorqm, I tried to simulate the circuit in my mind and it seems the first IGBT will work correctly, however its gate voltage will need to be equal to the required output level, because since the output will be following the gate, the gate level will determine the output level. The other two IGbts probably are configured to function like high power switching diodes which work with the coil to form a buck converter kind of network, not entirely sure though.

              So technically even if the entire network of the inductor and the two IGBTs are removed still the design could be used to produce a pulsed sinewave by feeding a pulsed sinewave at the gate of the first IGBT, as per my assumption.

              In the circuit suggested by me, the coil is used for stepping up the voltage to some desired higher level during the low voltage conditions, in your case this trafo can be ignored and eliminated….

  12. yes, the high voltage rectified -DC will be the common ground for the -15V also, you ca use 1K or even 10K for keeping the SD pin grounded

  13. you can keep floating or a better keep it connected to ground via a high value resistor, because nothing is specifically mentioned in the datasheet, except that anything above 2v will enable the shut down feature on this pinout

  14. Hi, yes that's correct, since the rectified bus voltage to the full bridge would be a DC, the frequency from the ferrite core trafo wouldn't have any impact on it.

    yes, 150V to the BUS line would allow you to get around 100V AC from the full bridge circuit, at a frequency determined by Rt/Ct

  15. Hello dear sir
    Happy new year first
    I'm enjoying your creations thank you
    I would like to ask you the circuit of a transformer less inverter my batteries can be from 12v-48v 200Ah
    Preferably 6kw-10kw 220volts AC 50hz
    I know you said to connect more MOSFETs to the above circuit but I cannot understand how my knowledge is limited
    So please I need the full circuit for as it should be
    Thank you very much in advance

    • Happy New year to you demiliza,

      to make a 220V transformerless inverter you must have a DC input supply of 330V DC….a 12V or 48V will not work.

    • OK, then you could go for the circuit which is explained in the above article….feed the 330V DC across the indicated AC rectified lines…and use a more number of mosfets in parallel to the existing one to achieve the required 10kW.

      you could try IRF450 fets for this….

  16. Sir, im currently working with this inverter circuit. At first Im thinking on using 2 ir2111 for the driver but now im planning to use the above circuit. What im asking is, is it safe to use ir540n as the switching component with ac rectified input 310v ? Because i've read the datasheet of irf540n and it says 100v pls help me

  17. is it a tested design? I would like to do a pcb of this if it is. I know i would have to increase battery AH but for the transformer I would need 6000W so thats 20amps on the 300v secondary, can those output Fets manage that kind of power?

    • It is a standard design suggested by the datasheet of the IC.

      the output fets will need to be selected as per the current and voltage of the transformer and the output load, if needed more numbers can be added in parallel

    • ofcourse it's my own design.

      it's a pure sine wave design so can be used with any equipment

      wattage will depend on trafo wattage rating and battery AH rating

  18. Dear sir, I am currently working on a wireless charger and have adopted roughly the same type of circuit as shown above, but with a few changes.
    Freq: 100 KHz
    Bootstrap cap: 1.0 uF
    Mosfets: IRF540
    Series gate resistor: 10 ohm
    Gate to source resistance: 470 Kohm

    The LO1 and LO2 are connected to a 2N2907 transistor and a 1N5818 diode and then given to the low side mosfets. The output is a 17.3 AC voltage but the output from HO1 and HO2 have very bad negative and positive voltage spikes. It would be real helpful if i can bit of clarification regarding the spikes and how i can further improve the circuit.

    • Dear 932, why don't you build it exactly as per the above diagram? I don't think the 2N2907 are actually required.

      how much voltage are you using for the Vdd pin of the IC?

      make sure it's around 12V, if possible make it 12V and check the response.

      I hope you have positioned the reverse diodes across the mosfet gate resistors?

      other the these modifications, I don't see any other possible remedies for the preventing the spikes.

      and make sure the mosfets are connected as close as possible to the IC output pins.

  19. – What is the maximum frequency of the driver?
    Is it 100 kHz?
    For my wireless charger application, the frequency is 200 kHz?
    can you suggest me another driver if the mentioned one does not work
    Thank you

    • you can easily achieve 200kHz from the above shown design because the maximum range is a lot higher than that.

      if your application is not based on full bridge then you can try a 555 also for the purpose

  20. sir can u give me inverter circuit diagram that can convert 20v dc to 20v ac. i try many inverter circuit but still no get ac output and sinusoidal waveform. please help me

  21. okay sir thank you in fact i don't know how much i can thank you but all i have to you is may the good lord who knows much than we can imaging bless you may you lived long thank you hope to hear from you soon

  22. thank you sir for respond me,sir please my grandfather is un orange farmer and he is having a problem with thief's so he ask me to do something that to protect the farm or anything that can alert him when any thief's or any person try to take away any thing from the farm so i decided to install a CCTV camera,so i need a circuit without a camera or if you can help me out sir i have said this but you can create something that can help me out thank you hope to hear from you soon

    • thanks Daniel, presently I am working on a similar concept which uses a laser beam to monitor a field premise, I'll post it soon and you can apply it for your cause too..

  23. hi sir please i want you to explain this for me, my question is how can i calculate home appliance with battery i mean if i have 12v 1000watt inverter and 12v 100ah battery how can i calculate to get the hours i should calculate the battery with the appliance or the inverter wattage,it should be division or multiplication thank you hope to hear from you soon

    • Daniel, the inverter power is not relevant, it's the connected load which needs to be taken into account.

      Assuming it to be 1000 watt, then by dividing 1000 by 12 gives = 83 amps…so you would require 83 amps with a 12V supply for satisfying a 1000 watt load.

      your battery is 100H rated meaning if it's discharged at 100ah rate it will last for 1 hour….but that's possible only in a hugely ideal situation, practically you can assume it to be just for 20 minutes.

      so at 100 amp your "fully charged" battery lasts for 20 minutes….therefore for 83 amps it will last for:

      100/83 = 20/t

      t = 16 minutes only…after this it will be dead flat….and if you continue to discharge it at this high rate within days your battery will be permanently dead.

      at 83 amp discharge rate the battery must be rated at 1000 AH

    • Swagatam Majumdar is correct if the manufacturer of the battery rates the battery at a 10Hr discharge rate. Some manufactures rate their battery's at a 20hr rate. So it's buyer beware on battery's, make sure what the AH rate is based, on 10 hours or 20

  24. okay sir but i cant see which one you are referring its a lots of 555 circuit there please sir help me with this i have 555 with 4017 okay when i put on the circuit it chop 340v dc but i don't get 220v ac i got 142v ac at out put of full bridge i use 103nf in between pin2 and 6 i got 142v ac 50hz 100k pot but if i replace 103 with 102nf,104nf 101nf i got 220 but i don't get proper frequency if i regulate the 100k pot i 5175hz i cannot take even a bulb please sir guide with this please my English is not good thank you looking forward to hear from you son

    • Google "PWM 555 motor speed controller circuit" remove the mosfet and the motor from the design and the rest can be used for your purpose…

  25. thank you for respond me sir but 555 pwm circuit it come with only one out put so what should i do because i want to use it to drive most fets by IR2110 or if you can help me to get 555 pwm to fed any ic so that it can drive high voltage 315,320,or 340v dc thank you

  26. hi sir thank you for this full bridge inverter circuit,sir please i have a inverter circuit 12v DC to 340V DC but now im looking another circuit can chop 340v DC to 220v AC can you please help me one i have ir2110 i don't do programmer so i need that one don't use pic micro chip thank you hope to hear from you soon

    • Hi Daniel,

      you can use any standard 555 PWM circuit and feed it at the base of the driver transistor for controlling the RMS voltage, or alternatively you can simply drop the 12V to 9V using rectifier diodes in series with the battery positive for the same.

    • Hi Imraan,

      I have no idea about it, you may have to calculate it using the given formula or determine through a practical experiment and a digital frequency meter.

  27. Hello sir
    Is it completely safe to apply pwm to only low side of MOSFETs in full bridge only especially in this circuit where I would like to use your pwm circuit.?
    I am asking because i have been studying other drivers like the ir2110 which is another IC I am thinking of using as a back up if I can't find ir2453
    Now the thing is to implement full bridge using ir2110 I will need to use two of the IC's and then connect the lowside input LIN of ic1(ir2110) to the the high side input HIN of ic2(ir2110) so that that way diagonally they botje turn on causing current to flow but the catch here is that both inputs will receive PWM pulses( chopped 50hz pulses) so this means using the ir2110 the high side output will trigger the high side MOSFET as well as the low side mosfet with this pulses but I want to know it it will be suitable to drive the high side sufficiently.
    With this simple ir2453 we can just leave the high side pulse at line frequency (50hz) while we just pass PWM to low side only whixh is why I find it desirable as it saves lots of space and stress.
    But my main queation again is will both techniques be ok . just increasing my options.

    • Hello Michael, you can isolate the PWMs by adding a diode and a resistor across the respective LIN pinouts of the both half-bridge ICs, or alternatively you can prefer applying the PWMs at the gates of the low side mosfets for the same.

  28. Hello Sir
    That means that the only down side to the h bridge would be that I would require double the amount of MOSFETs I would use for a push pull config.
    Example if I use these four N channel on push pull by using two per each side of push pull then at 300w per MOSFET then I would have 600w output. But for h bridge when diagonal are conducting the two diagonal are only supplying 300w when individually they can give 300w each and this is due to the series connection so to get 600w in h bridge I would use 8 n channel MOSFETs.
    Is my calculation correct according to your explanation?

    • Michael, you are correct….but the H bridge trafo can be significantly smaller compared to a center tap topology…so it wins here, moreover you have the option of using higher voltages (upto even 60V or 100V) and get massive power outputs (kvas) without adding a single mosfet to the existing 4.

    • Hello sir,
      The thing is I can afford to get two 12v batteries that's why I am planning to use 24v input but you just mentioned using higher voltage like 60v or up to 100 but that would mean I have two options
      1) using more batteries which I don't want to as more is expensive
      2)using a DC to DC converter
      Now If I use option 2 as option 1 is ruled out, it means more components added as I have to use oscillator like sg3524 and a small ferrite trafo (puah pull converter) which honestly means component count is getting higher.I don't want that as I want simplicity
      A) So I was thinking are there DC to DC converters that employ minimal components only and yet so simple and effective that I can use to convert 24v to 48v.?
      B) so if (A) is possible then I connect it to the h bridge, since diagonal high and low side MOSFETs conduct then when at full power the low MOSFETs will conduct a lot of current but my question is since the high side will also conduct current will the transformerless DC to DC converter withstand such current draw at full load to adequately complement its diagonal low side MOSFET.

      Hope you get where am coming from.I have seen h bridge inverters using push pull DC to DC converters whose output powers the drain of the mosfets high side but since the transformers are small yet current will flow through them when conducting.
      So basically it seems the DC to DC has to be able to output certain amount of current?

    • Hello sir
      If complications arise I will stick to 24v direct from battery input and use as much MOSFETs as possible.I don't want complicated process.
      Unless you have a transformer less solution with stable output voltage. Ha ha

    • Hello Michael,

      using a DC DC converter would be like using two inverters in series which could make the system inefficient….moreover to produce 25 amps from the DC t DC converter could be a complex affair as it would require heavy duty coils and mosfets involved.

      so it's better to go with a 24V battery directly with the designed inverter and use more mosfdets if required.

  29. Hello Sir
    Just to be clear, if i have an N channel MOSFET that gives out 300w.then I use four of this on h bridge config.(2 on high and 2 on low side) then my total output should be 1200w right?

    • Hello micahel, no all the 4 together will help to produce 300 watts only, because the diagonal ones are conducting in series, so no question of power addition, while the left and the right diagonal pairs are conducting alternately.. so again no chance of power adding up.

    • .
      Remember Power=Voltage times current
      If the Voltage across the FET is 1 Volt when on and the current rating is 300 amps that's 300 watts per FET that is on, at a 50% duty cycle, and if the output source is 12 volts after you subtract the FET voltage drops, that's 3600 watts output. total power consumption from source supply is ~ 4200 watts.

  30. Hello sir,
    I now understand am gratefull.
    I have one more question
    In push pull config, if I wanted more power output say from 500w to 2000w output I simply add more MOSFETs in parallel and its easier since we only deal with low side switching but now since full bridge uses four MOSFETs,
    Once I have my trafo say 0-12/2000w ready,
    How do I increase power output using h bridge (full bridge topology)
    Basically what do I so to increase power from say 500w to 2000w?
    Do I add MOSFETs to both low and high?

    • Hello Michael, for an Hbridfge also you will need to add mosfets in parallel for multiplying power output…the rule is same…however you can alternatively decide on a higher voltage trafo…like a 48V primary trafo, and a 48V battery for the boosting power without having to use more number of mosfets.

  31. Also sir pls I still don't get how full bridge works fully.
    Could you explain what happens during the low and high side in terms of conducting. I think the low side MOSFET switch according to wave form at its gate but high side?

    • the diagonal mosfets pairs are switched ON simultaneously, while the left and the right pairs switch ON alternately, generating the required AC across the connected trafo primary.

      while the diagonal mosfet switch ON, the high side mosfet is applied with an excess of 5 to 10V than its drain voltage so that it's able to switch ON fully and compliments the low side mosfet, making the conduction complete and full.

  32. Also sir one important question.
    Now using pwm we make it as close to a sine wave as possible but for a 12 supply we would need a 0-12/220v trafo but for pwm should it still be 0-12/220 or 0-7/220v to make up for the PWM sectioj just like in the center tap sine wave pwm inverters you have.

  33. Hello sir
    His ic seems powerful and I think we can add pwm to the low side of the driver going to the gates but my question is this.
    You said that the gate voltage has to be at least 5v higher than drain voltage for the high side to function properly so now if I power the drain with a +24vdc supply and then use a 12v regulator to power the IC at pin 1, will sufficient voltage come out at the pin 13 and 9 high side output.? To work sufficiently.
    2)Also when using a 24vdc supply and 12 DC at pin 1 of the IC the 1uf/25v caps at 14 and 10 can it be increase to a higher capacitance/voltage?

    • Hello Michael,

      with a 12V as the supply to the IC the output at the high side pin would be 36V, which would imply an efective12V at the respective mosfet gate, which would be sufficient for driving the gate optimally.

      the capacitor voltage rating is relevant to the supply voltage so I think it can be selected to be 25V

      capacitance value are OK, no need of increasing it.

  34. I wonder why there are no snubber circuits? Most kinds of electronic high power switches I've seen have snubbers to protect the FET's or IGBT's.

  35. Thank you for your quick reply.
    But can you pls give me a simple circuit on PWMs that needs tobe connected to the lower gates of the mosfets.

  36. Hello
    Is the above inverter circuit diagram modified sinewave or pure sinewave
    inverter. And also, is it possible to power inductive and sophiscated
    device without problem?

    • Hello Raphael,

      it's a simple square wave inverter, it can be converted into a sine wave by inducing PWMs at the gates of the lower mosfets.

  37. Sir if i am using a 230 / 12-0-12 300W transformer and one car battery 12 V 35 Ah for producing a minimum of 230 V AC at 60 Hz having power rating minimum to 100 W. So…

    1). Could it be possible to connect this with the above circuit ?

    2). Will i get a minimum wattage of 100 W by doing these ?

    3). Can the output ac voltage finally produced be used to drive any sophisticated equipments ?

    My purpose is that to make a pure sine wave inverter suitable for operating the HOME THEATER in my CAR without making any humming noise while operating the System…
    I am not interested to make modified inverters based on PWM concepts, since they require a better mean such as OSCILLOSCOPE to display and analyze the wave forms formed…

    • Arun,
      for the above design you will need a two wire transformer not a center tap type…0-12V will do, or 0-9V

      Without PWMs, a sine wave is not possible.

      you can try putting a 1uF/400V capacitor and a 3amp 1mH inductor approx at the output of a square inverter for reducing the hum.

      wattage of an inverter solely depends on the transformer wattage and the battery AH, driver circuits have nothing to do with it.

    • Presently I do not have any info regarding the equivalents, but yes any type of driver with similar specs will do.


    If it can be , CAN I USE 1N4007 for this purpose or should i have to use any other diodes ?
    Also what is about filtering ? Can a pi-section filter do that purpose ?

  39. will these types of inverters capable of driving sophisticated devices ???

    How to get + and – AC rectified lines ?? You haven't mention about it

    • yes it's suitable for all types of equipment

      first step up 12V to 220V AC using a square wave inverter, next rectify and filter this 220V Ac to 310V DC. then apply this DC across the "rectified AC line" of the above circuit.

  40. hello sir
    I wanted the output power to be equal to 2kW. how do I achieve that.

    Also I want the output current frequency equal to 40 kHZ . How to achieve that.

    Is it possible to vary the output power of the inverter?

  41. hi Swagatam Majumdar,
    i want automatic switch for interchanging main supply (220 volts, 50 Hz) and stationary generator, actually i want to control my loads through computer with HMI, so i am facing problem as..
    if main supply turns off that definitely my pc turns off, and also generator takes time to start so
    Is it possible to start generator in such a way that my pc should not turns off and also my loads run without any interrupt?
    thanks in advane

    • Hi Mengal,

      I am sorry that won't be possible with a generator, because generators will always take sometime to start. You can opt for an UPS instead.

    • Hello Sir, I think the design you have mentioned here uses the high frequency ferrite inverter rectified line usually above 300v. So, this bridge produces the full cycle once again at 50Hz to make output usable. If so, then please let me know that why above 300v is required? why only 280-290v is not enough? and also i designed another schematic for driving H bridge let me know if its OK. here it is :

    • Hello Carmen, Actually it should be 310V, because our home mains 220V AC has a peak level of 310V, while the RMS value is 220V, therefore we have to make sure that in our inverter output too the peaks are at 310V, while the RMS is set at 220V

      sorry your design will not work,,,where's the bootstrapping network? ๐Ÿ™‚

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