Among the different existing inverter topologies, the full bridge or the H-bridge inverter topology is considered to be the most efficient and effective. Configuring a full bridge topology could involve too many criticality, however with the advent of full bridge driver ICs these have now become one of the simplest inverters one can build.
What's a Full-Bridge Topology
Full bridge inverter circuits also called the H-bridge inverter, are the truly efficient ones since these do not require a center tapped transformers and yet are able to implement the intended push-pull functions right across the entire primary winding of the attached tansformers.
This feature allows the use of smaller transformers and get more power outputs at the same time.Today due to the easy availability of full bridge driver ICs things have become utterly simple and making a full bridge inverter circuit at home has become a kids play.
Here we discuss a full bridge inverter circuit using the full bridge driver IC IRS2453(1)D from International Rectifiers.
The mentioned chip is an outstanding full bridge driver IC as it single handedly takes care of all the major criticality involved with H-bridge topologies through its advanced in-built circuitry.
The assembler simply needs to connect a few handful of components externally for achieving a full fledged, working H-bridge inverter.
The simplicity of the design is evident from the diagram shown below:
Simulation and Working
Pin14 and pin10 are the high side floating supply voltage pinouts of the IC. The 1uF capacitors effectively keep these crucial pinouts a shade higher than the drain voltages of the corresponding mosfets ensuring that the mosfet source potential stays lower than the gate potential for the required conduction of the mosfets.
The gate resistors suppress drain/source surge possibility by preventing sudden conduction of the mosfets.
The diodes across the gate resistors are introduced for quick discharging of the internal gate/drain capacitors during their non-conduction periods for ensuring optimal response from the devices.
The IC IRS2453(1)D is also featured with an in-built oscillator, meaning no external oscillator stage would be required with this chip.
Just a couple of external passive components take care of the frequency for driving the inverter.
Rt and Ct can be calculated for getting the intending 50Hz or 60 Hz frequency outputs over the mosfets.
Calculating Frequency Determining Components
The following formula can be used for calculating the values of Rt/Ct:
f = 1/1.453 x Rt x Ct where Rt is in Ohms and Ct in Farads.
High Voltage Feature
Another interesting feature of this IC is its ability to handle very high voltages upto 600V making it perfectly applicable for transformeless inverters or compact ferrite inverter circuits.
As can be seen in the given diagram, if an externally accessible 330V DC is applied across the "+/- AC rectified lines", the configuration instantly becomes a transformerless inverter wherein any intended load can be connected directly across the points marked as "load".
Alternatively if an ordinary step-down transformer is used, the primary winding can be connected across the points marked as "load". In this case the "+AC rectified line" can be joined with pin#1 of the IC and terminated commonly to the battery (+) of the inverter.
If a battery higher than 15V is used, the "+AC rectified line" should be connected directly with the battery positive while pin#1 should be applied with a stepped down regulated 12V from the battery source using IC 7812.
Although the below shown design looks too easy to construct, the layout requires some strict guidelines to be followed, you may refer to the post for ensuring correct protection measures for proposed simple full bridge inverter circuit.
Circuit Diagram
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naseef says
sir
can u suggest any outher h bridge driver ic for high voltage operation . so these ic is not availble in my location
Swag says
Naseef, you can Google search for “full bridge driver IC datasheet” you may find a few alternatives online…
Alexanian says
Hello.
I am discovering your blog and i have a question about your
f = 1/1.453 x Rt x Ct where Rt is in Ohms and Ct in Farads.
I thought f=1/2piRC
What did I miss?
Regards
Swag says
Hello, the formula is specific to the IC’s internal configuration, it is suggested in the datasheet of the IC on Page#9
https://www.infineon.com/dgdl/irs2153d.pdf?fileId=5546d462533600a401535676951e27c3
Naseef Vs says
Sir
I want to make a 150v dc to 110v ac invertor . So can i give 150v dc directly inthe +AC and -AC . Or should i make any changes inthe ckt befor it ??
Thanks
Swag says
yes you can do that, make sure to supply the IC Vcc with a separate 15V
Naseef Vs says
What should do sd pin (5). Thre is any connection .
Swag says
as per the technical specs of the IC it can be kept unconnected, still to be entirely confirmed you can ground it through a 10K resistor….because only a high logic can enable a shut down on this pin….
yogesh says
Sir I make this circuit,at 50hz if 24vdc apply on bridge at load point 15v ac but if 50v or more voltage apply ic and MOSFET damaged.we use bootstrap capacitor 104 if use 105 no drive volt
Swag says
yogesh, as you can see, the mosfet positive is separate from the rectified line, the IC will need to be separately powered through a 15V source, while the mosfet rectified line from the intended high voltage source.
the mosfets should be rated accordingly to prevent damage.
faktorqm says
I will investigate that circuit and try to design something. Also I will check on your circuit, but maybe I will need some modifications, as the “battery” in my case are the rectified 220VAC. Let me investigate and I will be back on you as I have some to share. Thanks for your reply sir. Have a nice day Swag! 🙂
Swag says
OK, no problem! wish you all the best!
faktorqm says
Dear Swagatam, I sent to you a message in this page a few days ago. At the beginning it said “comment under approval” or something like that. Now I can’t see my message. I’m wondering if you have an automatic spam filter who thinks I’m a robot or whatever. Sorry for this message if cause any bother to you. Thank you! Regards!
Swag says
Hi faktorqm, sorry, did you have too many links in the comment, then may be I might have accidentally marked it as Spam….no problem please repeat your question, if you have links you can post them but after replying I may edit those links and delete them.
faktorqm says
Thanks for your reply sir! I will post only one thought. I want to construct something like a universal dimmer for all kind of loads (resistive, inductive) using the pwm pure sine technique. My main goal is to dimm, for example, filament light bulbs or leds lamps (in my country there are dimmable electronic transformers with dimmable led lights) or CFL lamps (only on/off without dimm). I found this link with a circuit but there are no values, and I don’t have an actual idea about how components value I need to start testing.
https://homemade-circuits.com/wp-content/uploads/2017/09/20080901103954123.jpg
Thank you very much for your time sir!!
Swag says
I checked the article, but I am not able to understand how the last designs are designed to operate…according to me there’s no way the IGBTs would be able to implement the dimming function or even power the output, are you able to figure it out??
alternatively you can probably try the following concept for achieving the results
https://homemade-circuits.com/2016/04/solar-inverter-circuit-for-15-ton-ac.html
faktorqm says
Hi Swagatam, thanks for your reply. I didn’t figured it out but as far as I saw the igbt acts just like a on/off switch, which operated correctly, supposedly, it will deliver the square wave at figure 7 on that link. Then the next network with two igbt’s I don’t know, and the L-C circuit it looks like to be a chebyshev low pass filter with order 2 to obtain a “sine” wave after the igbt modulation. (same as the beginning of the circuit network). I have tried to simulate over proteus just the first igbt, with a square wave on the gate, 50% duty cycle, but the result is not what I expected. Maybe I need to setup the entire circuit with thumb rule component values and… cross my fingers 😛
Regarding the circuit you pointed me out, I have one question, In this one https://homemade-circuits.com/2016/05/h-bridge-mains-voltage-stabilizer.html you used an autotransformer at the “exit”. Is this necessary for a dimmer?
Thanks for your time sir!!!
Swag says
Hi faktorqm, I tried to simulate the circuit in my mind and it seems the first IGBT will work correctly, however its gate voltage will need to be equal to the required output level, because since the output will be following the gate, the gate level will determine the output level. The other two IGbts probably are configured to function like high power switching diodes which work with the coil to form a buck converter kind of network, not entirely sure though.
So technically even if the entire network of the inductor and the two IGBTs are removed still the design could be used to produce a pulsed sinewave by feeding a pulsed sinewave at the gate of the first IGBT, as per my assumption.
In the circuit suggested by me, the coil is used for stepping up the voltage to some desired higher level during the low voltage conditions, in your case this trafo can be ignored and eliminated….
Anonymous says
Hi,
For the shutdown pin, do I leave it floating or do I need to ground it?
Swagatam says
you can keep floating or a better keep it connected to ground via a high value resistor, because nothing is specifically mentioned in the datasheet, except that anything above 2v will enable the shut down feature on this pinout
Anonymous says
A 1k resistor to ground should be ok? And also, can the full-bridge share a common ground with my DC-DC converter? I'm alittle mixed up with the connections. So the + AC rectified line is the output from my DC-DC Converter and the – AC rectified line is from the ground of my DC-DC converter right? So am I right to say that the – AC rectified line becomes my common ground for the setup?
Then for the Vcc of 15V to the chip, I can just connect the -ve portion to the – AC recified line as well right? Thanks.
Swagatam says
yes, the high voltage rectified -DC will be the common ground for the -15V also, you ca use 1K or even 10K for keeping the SD pin grounded
Anonymous says
Hi,
If say I am using a DC-DC converter using high freq ferrite of 100Khz to get the 325V DC to the AC rectified line, it doesn't matter what switching freq i am using for the DC-DC converter right? As long as for the bridge driver IC, I configure it to 50Hz using the R/C values.
Also, if I just need 100VAC instead of 230VAC, can I just feed 150VDC which is the RMS equivalent of 100VAC? It can work with that value right?
Swagatam says
Hi, yes that's correct, since the rectified bus voltage to the full bridge would be a DC, the frequency from the ferrite core trafo wouldn't have any impact on it.
yes, 150V to the BUS line would allow you to get around 100V AC from the full bridge circuit, at a frequency determined by Rt/Ct
Anonymous says
Hi,
Just wondering. In your circuit example above. U used IRF540 which is a 100V n-channel mosfet from the datasheet. If I am working with about 180V DC to the AC rectified line, am I right to say that I cant use IRF540 in this case since it is rated only 100V? I need something like 300V to be safe?
Swagatam says
yes you are right, the max input supply should be always less than the device's max Drain/Source rating
Anonymous says
Hi, i am trying to build a square wave 230V AC, 50Hz inverter circuit. To get 50 Hz, i just need to adjust the R/C values according to the formula provided in the datasheet right? So for the 230V AC, I will need to supply a 325V DC to the AC rectified line right? Since 230V RMS is 325 peak equivalent in DC. Also, for the input to the driver chip, if I use 12V it should be fine too right? Datasheet seems to be from 11-15.6V typical values. The output would be 230V AC square waves?
Swagatam says
Hi, yes all your mentioned assumptions are correct! You can go ahead with them!
oyeledun bukola says
SIR SEND ME YOUR EMAIL OR EMAIL ME AT 'OYELEDUNBUKOLA@GMAIL.COM' VERY IMPORTANT SIR!!!
demiliza says
Can you please draw me the schematic diagram with the parallel MOSFETs because I don t want to make mistake thank u
demiliza says
Hello dear sir
Happy new year first
I'm enjoying your creations thank you
I would like to ask you the circuit of a transformer less inverter my batteries can be from 12v-48v 200Ah
Preferably 6kw-10kw 220volts AC 50hz
I know you said to connect more MOSFETs to the above circuit but I cannot understand how my knowledge is limited
So please I need the full circuit for as it should be
Thank you very much in advance
Swagatam says
Happy New year to you demiliza,
to make a 220V transformerless inverter you must have a DC input supply of 330V DC….a 12V or 48V will not work.
demiliza says
Thank you for the fast reply if I had the 220v how would the circuit be in order to achieve 6-10kw
Thank you
Swagatam says
OK, then you could go for the circuit which is explained in the above article….feed the 330V DC across the indicated AC rectified lines…and use a more number of mosfets in parallel to the existing one to achieve the required 10kW.
you could try IRF450 fets for this….
uddy ardiaksa says
Sir, im currently working with this inverter circuit. At first Im thinking on using 2 ir2111 for the driver but now im planning to use the above circuit. What im asking is, is it safe to use ir540n as the switching component with ac rectified input 310v ? Because i've read the datasheet of irf540n and it says 100v pls help me
Swagatam says
Uddy, it is not safe because IRF540 is not rated to handle 300V, you can go for IRF840, IRF450 or other similar mofets.
Ainsworth Lynch says
is it a tested design? I would like to do a pcb of this if it is. I know i would have to increase battery AH but for the transformer I would need 6000W so thats 20amps on the 300v secondary, can those output Fets manage that kind of power?
Swagatam says
It is a standard design suggested by the datasheet of the IC.
the output fets will need to be selected as per the current and voltage of the transformer and the output load, if needed more numbers can be added in parallel
Ainsworth Lynch says
this is another version for the circuit you did, where the iron core transformer is you can put a ferrite core with 9+9 turns and secondary 300 turns I am not sure if this is one of your designs though.
https://drive.google.com/drive/folders/0B0N-CQJdWSP0NmJwZTc3ZmVQUGc?usp=sharing
What kinda wattage can I get from this and is the wave good enough for sensitive electronics?
Swagatam says
ofcourse it's my own design.
it's a pure sine wave design so can be used with any equipment
wattage will depend on trafo wattage rating and battery AH rating
kingsley obinna says
Must there be a load on the output of the h bridge for it to properly function?
932 says
Dear sir, I am currently working on a wireless charger and have adopted roughly the same type of circuit as shown above, but with a few changes.
Freq: 100 KHz
Bootstrap cap: 1.0 uF
Mosfets: IRF540
Series gate resistor: 10 ohm
Gate to source resistance: 470 Kohm
The LO1 and LO2 are connected to a 2N2907 transistor and a 1N5818 diode and then given to the low side mosfets. The output is a 17.3 AC voltage but the output from HO1 and HO2 have very bad negative and positive voltage spikes. It would be real helpful if i can bit of clarification regarding the spikes and how i can further improve the circuit.
Thanks
Swagatam says
Dear 932, why don't you build it exactly as per the above diagram? I don't think the 2N2907 are actually required.
how much voltage are you using for the Vdd pin of the IC?
make sure it's around 12V, if possible make it 12V and check the response.
I hope you have positioned the reverse diodes across the mosfet gate resistors?
other the these modifications, I don't see any other possible remedies for the preventing the spikes.
and make sure the mosfets are connected as close as possible to the IC output pins.
Hamada Almasalma says
– What is the maximum frequency of the driver?
Is it 100 kHz?
For my wireless charger application, the frequency is 200 kHz?
can you suggest me another driver if the mentioned one does not work
Thank you
Swagatam says
you can easily achieve 200kHz from the above shown design because the maximum range is a lot higher than that.
if your application is not based on full bridge then you can try a 555 also for the purpose
Daniel Adusei says
okay sir thanks
Swagatam says
Please check it out here:
https://homemade-circuits.com/2015/12/laser-alarm-circuit-for-protecting.html
Shahril Shah says
sir can u give me inverter circuit diagram that can convert 20v dc to 20v ac. i try many inverter circuit but still no get ac output and sinusoidal waveform. please help me
Swagatam says
Shahril, you can easily convert 20V DC to 20 V AC with square waves, but making it into sine wave can be difficult.
Daniel Adusei says
okay sir thank you in fact i don't know how much i can thank you but all i have to you is may the good lord who knows much than we can imaging bless you may you lived long thank you hope to hear from you soon
Swagatam says
You are most welcome Daniel, I'll let you know when it's posted.
Daniel Adusei says
thank you sir for respond me,sir please my grandfather is un orange farmer and he is having a problem with thief's so he ask me to do something that to protect the farm or anything that can alert him when any thief's or any person try to take away any thing from the farm so i decided to install a CCTV camera,so i need a circuit without a camera or if you can help me out sir i have said this but you can create something that can help me out thank you hope to hear from you soon
Swagatam says
thanks Daniel, presently I am working on a similar concept which uses a laser beam to monitor a field premise, I'll post it soon and you can apply it for your cause too..
Daniel Adusei says
hi sir please i want you to explain this for me, my question is how can i calculate home appliance with battery i mean if i have 12v 1000watt inverter and 12v 100ah battery how can i calculate to get the hours i should calculate the battery with the appliance or the inverter wattage,it should be division or multiplication thank you hope to hear from you soon
Swagatam says
Daniel, the inverter power is not relevant, it's the connected load which needs to be taken into account.
Assuming it to be 1000 watt, then by dividing 1000 by 12 gives = 83 amps…so you would require 83 amps with a 12V supply for satisfying a 1000 watt load.
your battery is 100H rated meaning if it's discharged at 100ah rate it will last for 1 hour….but that's possible only in a hugely ideal situation, practically you can assume it to be just for 20 minutes.
so at 100 amp your "fully charged" battery lasts for 20 minutes….therefore for 83 amps it will last for:
100/83 = 20/t
t = 16 minutes only…after this it will be dead flat….and if you continue to discharge it at this high rate within days your battery will be permanently dead.
at 83 amp discharge rate the battery must be rated at 1000 AH
Raymond Borowiak says
Swagatam Majumdar is correct if the manufacturer of the battery rates the battery at a 10Hr discharge rate. Some manufactures rate their battery's at a 20hr rate. So it's buyer beware on battery's, make sure what the AH rate is based, on 10 hours or 20
Daniel Adusei says
okay sir but i cant see which one you are referring its a lots of 555 circuit there please sir help me with this i have 555 with 4017 okay when i put on the circuit it chop 340v dc but i don't get 220v ac i got 142v ac at out put of full bridge i use 103nf in between pin2 and 6 i got 142v ac 50hz 100k pot but if i replace 103 with 102nf,104nf 101nf i got 220 but i don't get proper frequency if i regulate the 100k pot i 5175hz i cannot take even a bulb please sir guide with this please my English is not good thank you looking forward to hear from you son
Swagatam says
Google "PWM 555 motor speed controller circuit" remove the mosfet and the motor from the design and the rest can be used for your purpose…
Daniel Adusei says
thank you for respond me sir but 555 pwm circuit it come with only one out put so what should i do because i want to use it to drive most fets by IR2110 or if you can help me to get 555 pwm to fed any ic so that it can drive high voltage 315,320,or 340v dc thank you
Swagatam says
you can terminate the pin3 of the 555 IC with two diodes and configure them with the inverter output devices as shown in the following article:
https://homemade-circuits.com/2013/04/how-to-modify-square-wave-inverter-into.html
in the above link a transistor astable is shown instead of a 555 astable.
Daniel Adusei says
hi sir thank you for this full bridge inverter circuit,sir please i have a inverter circuit 12v DC to 340V DC but now im looking another circuit can chop 340v DC to 220v AC can you please help me one i have ir2110 i don't do programmer so i need that one don't use pic micro chip thank you hope to hear from you soon
Swagatam says
Hi Daniel,
you can use any standard 555 PWM circuit and feed it at the base of the driver transistor for controlling the RMS voltage, or alternatively you can simply drop the 12V to 9V using rectifier diodes in series with the battery positive for the same.
Imraan says
Hi Mr Majumdar
What are the most appropriate Rt and Ct values to use for 50hz frequency at the output?
Swagatam says
Hi Imraan,
I have no idea about it, you may have to calculate it using the given formula or determine through a practical experiment and a digital frequency meter.
mexzony says
Hello sir
Is it completely safe to apply pwm to only low side of MOSFETs in full bridge only especially in this circuit where I would like to use your pwm circuit.?
I am asking because i have been studying other drivers like the ir2110 which is another IC I am thinking of using as a back up if I can't find ir2453
Now the thing is to implement full bridge using ir2110 I will need to use two of the IC's and then connect the lowside input LIN of ic1(ir2110) to the the high side input HIN of ic2(ir2110) so that that way diagonally they botje turn on causing current to flow but the catch here is that both inputs will receive PWM pulses( chopped 50hz pulses) so this means using the ir2110 the high side output will trigger the high side MOSFET as well as the low side mosfet with this pulses but I want to know it it will be suitable to drive the high side sufficiently.
With this simple ir2453 we can just leave the high side pulse at line frequency (50hz) while we just pass PWM to low side only whixh is why I find it desirable as it saves lots of space and stress.
But my main queation again is will both techniques be ok . just increasing my options.
Swagatam says
Hello Michael, you can isolate the PWMs by adding a diode and a resistor across the respective LIN pinouts of the both half-bridge ICs, or alternatively you can prefer applying the PWMs at the gates of the low side mosfets for the same.
mexzony says
Hello sir,
I forgot to mention that I sent you a mail.
Swagatam says
I'll check it as soon as i finish with my website's pending assignments…
mexzony says
Hello Sir
That means that the only down side to the h bridge would be that I would require double the amount of MOSFETs I would use for a push pull config.
Example if I use these four N channel on push pull by using two per each side of push pull then at 300w per MOSFET then I would have 600w output. But for h bridge when diagonal are conducting the two diagonal are only supplying 300w when individually they can give 300w each and this is due to the series connection so to get 600w in h bridge I would use 8 n channel MOSFETs.
Is my calculation correct according to your explanation?
Swagatam says
Michael, you are correct….but the H bridge trafo can be significantly smaller compared to a center tap topology…so it wins here, moreover you have the option of using higher voltages (upto even 60V or 100V) and get massive power outputs (kvas) without adding a single mosfet to the existing 4.
mexzony says
Hello sir,
The thing is I can afford to get two 12v batteries that's why I am planning to use 24v input but you just mentioned using higher voltage like 60v or up to 100 but that would mean I have two options
1) using more batteries which I don't want to as more is expensive
2)using a DC to DC converter
Now If I use option 2 as option 1 is ruled out, it means more components added as I have to use oscillator like sg3524 and a small ferrite trafo (puah pull converter) which honestly means component count is getting higher.I don't want that as I want simplicity
A) So I was thinking are there DC to DC converters that employ minimal components only and yet so simple and effective that I can use to convert 24v to 48v.?
B) so if (A) is possible then I connect it to the h bridge, since diagonal high and low side MOSFETs conduct then when at full power the low MOSFETs will conduct a lot of current but my question is since the high side will also conduct current will the transformerless DC to DC converter withstand such current draw at full load to adequately complement its diagonal low side MOSFET.
Hope you get where am coming from.I have seen h bridge inverters using push pull DC to DC converters whose output powers the drain of the mosfets high side but since the transformers are small yet current will flow through them when conducting.
So basically it seems the DC to DC has to be able to output certain amount of current?
mexzony says
Hello sir
If complications arise I will stick to 24v direct from battery input and use as much MOSFETs as possible.I don't want complicated process.
Unless you have a transformer less solution with stable output voltage. Ha ha
Swagatam says
Hello Michael,
using a DC DC converter would be like using two inverters in series which could make the system inefficient….moreover to produce 25 amps from the DC t DC converter could be a complex affair as it would require heavy duty coils and mosfets involved.
so it's better to go with a 24V battery directly with the designed inverter and use more mosfdets if required.
mexzony says
Hello Sir
Just to be clear, if i have an N channel MOSFET that gives out 300w.then I use four of this on h bridge config.(2 on high and 2 on low side) then my total output should be 1200w right?
Swagatam says
Hello micahel, no all the 4 together will help to produce 300 watts only, because the diagonal ones are conducting in series, so no question of power addition, while the left and the right diagonal pairs are conducting alternately.. so again no chance of power adding up.
Raymond Borowiak says
.
Remember Power=Voltage times current
If the Voltage across the FET is 1 Volt when on and the current rating is 300 amps that's 300 watts per FET that is on, at a 50% duty cycle, and if the output source is 12 volts after you subtract the FET voltage drops, that's 3600 watts output. total power consumption from source supply is ~ 4200 watts.
mexzony says
Hello sir,
I now understand am gratefull.
I have one more question
In push pull config, if I wanted more power output say from 500w to 2000w output I simply add more MOSFETs in parallel and its easier since we only deal with low side switching but now since full bridge uses four MOSFETs,
Once I have my trafo say 0-12/2000w ready,
How do I increase power output using h bridge (full bridge topology)
Basically what do I so to increase power from say 500w to 2000w?
Do I add MOSFETs to both low and high?
Confused.
Swagatam says
Hello Michael, for an Hbridfge also you will need to add mosfets in parallel for multiplying power output…the rule is same…however you can alternatively decide on a higher voltage trafo…like a 48V primary trafo, and a 48V battery for the boosting power without having to use more number of mosfets.
Swagatam says
…yes add more number of mosfets with each of the four existing mosfets
mexzony says
Also sir pls I still don't get how full bridge works fully.
Could you explain what happens during the low and high side in terms of conducting. I think the low side MOSFET switch according to wave form at its gate but high side?
Swagatam says
the diagonal mosfets pairs are switched ON simultaneously, while the left and the right pairs switch ON alternately, generating the required AC across the connected trafo primary.
while the diagonal mosfet switch ON, the high side mosfet is applied with an excess of 5 to 10V than its drain voltage so that it's able to switch ON fully and compliments the low side mosfet, making the conduction complete and full.
mexzony says
Also sir one important question.
Now using pwm we make it as close to a sine wave as possible but for a 12 supply we would need a 0-12/220v trafo but for pwm should it still be 0-12/220 or 0-7/220v to make up for the PWM sectioj just like in the center tap sine wave pwm inverters you have.
Swagatam says
for a PWM insertion, the trafo voltage should be lower than the supply voltage to compensate the PWM range
mexzony says
Hello sir
His ic seems powerful and I think we can add pwm to the low side of the driver going to the gates but my question is this.
You said that the gate voltage has to be at least 5v higher than drain voltage for the high side to function properly so now if I power the drain with a +24vdc supply and then use a 12v regulator to power the IC at pin 1, will sufficient voltage come out at the pin 13 and 9 high side output.? To work sufficiently.
2)Also when using a 24vdc supply and 12 DC at pin 1 of the IC the 1uf/25v caps at 14 and 10 can it be increase to a higher capacitance/voltage?
Swagatam says
Hello Michael,
with a 12V as the supply to the IC the output at the high side pin would be 36V, which would imply an efective12V at the respective mosfet gate, which would be sufficient for driving the gate optimally.
the capacitor voltage rating is relevant to the supply voltage so I think it can be selected to be 25V
capacitance value are OK, no need of increasing it.
Robet Mandala says
hello, swatagam majundar, inverter circuit on the waveform what? sine or square and how the power output?
thank you.
Swagatam says
hello Robet, it's squarewave
Raymond Borowiak says
I wonder why there are no snubber circuits? Most kinds of electronic high power switches I've seen have snubbers to protect the FET's or IGBT's.
Swagatam says
the fets alerady have in-built snubbers, but you can always add more externally for reinforcing the inbuilt ones…
Raphael Hlordzi says
Thank you for your quick reply.
But can you pls give me a simple circuit on PWMs that needs tobe connected to the lower gates of the mosfets.
Swagatam says
You can use the PWM design which is shown in the second diagram of the following link
https://homemade-circuits.com/2013/04/how-to-modify-square-wave-inverter-into.html
The section consisting of T5/T6 is the PWM stage.
Raphael Hlordzi says
Hello
Eng,Swagatam.
Is the above inverter circuit diagram modified sinewave or pure sinewave
inverter. And also, is it possible to power inductive and sophiscated
device without problem?
Swagatam says
Hello Raphael,
it's a simple square wave inverter, it can be converted into a sine wave by inducing PWMs at the gates of the lower mosfets.
TarekJ says
where did you buy the IRS2453(1)D? because I can not find it.
Arun Dev says
Sir if i am using a 230 / 12-0-12 300W transformer and one car battery 12 V 35 Ah for producing a minimum of 230 V AC at 60 Hz having power rating minimum to 100 W. So…
1). Could it be possible to connect this with the above circuit ?
2). Will i get a minimum wattage of 100 W by doing these ?
3). Can the output ac voltage finally produced be used to drive any sophisticated equipments ?
My purpose is that to make a pure sine wave inverter suitable for operating the HOME THEATER in my CAR without making any humming noise while operating the System…
I am not interested to make modified inverters based on PWM concepts, since they require a better mean such as OSCILLOSCOPE to display and analyze the wave forms formed…
Swagatam says
Arun,
for the above design you will need a two wire transformer not a center tap type…0-12V will do, or 0-9V
Without PWMs, a sine wave is not possible.
you can try putting a 1uF/400V capacitor and a 3amp 1mH inductor approx at the output of a square inverter for reducing the hum.
wattage of an inverter solely depends on the transformer wattage and the battery AH, driver circuits have nothing to do with it.
Arun Dev says
Any equivalent ICs for IRS2453(1)D ?
Can any type of MOSFET driver ic be used ?
Swagatam says
Presently I do not have any info regarding the equivalents, but yes any type of driver with similar specs will do.
Arun Dev says
UPTO SQUARE WAVE INVERTER IS OK.
BUT AFTER THAT HOW TO RECTIFY AND FILTTER THAT 220 V AC TO 310 V AC ?
IS IT POSSIBLE WITH A BRIDGE RECTIFIER CONFIGURATION ?
If it can be , CAN I USE 1N4007 for this purpose or should i have to use any other diodes ?
Also what is about filtering ? Can a pi-section filter do that purpose ?
Swagatam says
yes rectify the output through a bridge network…the diodes could be 1N5402 or 6A4..the filter capacitor could be just a single 10uF/400V capacitor.
Swagatam says
pi filter is not required
Arun Dev says
will these types of inverters capable of driving sophisticated devices ???
How to get + and – AC rectified lines ?? You haven't mention about it
Swagatam says
yes it's suitable for all types of equipment
first step up 12V to 220V AC using a square wave inverter, next rectify and filter this 220V Ac to 310V DC. then apply this DC across the "rectified AC line" of the above circuit.
akshay says
hello sir
I wanted the output power to be equal to 2kW. how do I achieve that.
Also I want the output current frequency equal to 40 kHZ . How to achieve that.
Is it possible to vary the output power of the inverter?
Swagatam says
hello akshay,
you can achieve 2kva by applying V x I = 2000 across the mosfet drain/source
Rt/Ct may be appropriately selected for achieving any desired frequency
Swagatam says
….output power can be varied by applying a varying PWM at the "shutdown" pin of the IC.
Swagatam says
correction: sorry SD pin cannot be used for PWM application
nitin gondliya says
hi sir u r amazing…how many output watt in this circuit……plzz provide full specification….thank u .
Swagatam says
thanks, total power will depend on trafo watts and battery ah.
Mengal Arif Ali says
hi Swagatam Majumdar,
i want automatic switch for interchanging main supply (220 volts, 50 Hz) and stationary generator, actually i want to control my loads through computer with HMI, so i am facing problem as..
if main supply turns off that definitely my pc turns off, and also generator takes time to start so
Is it possible to start generator in such a way that my pc should not turns off and also my loads run without any interrupt?
thanks in advane
Swagatam says
Hi Mengal,
I am sorry that won't be possible with a generator, because generators will always take sometime to start. You can opt for an UPS instead.
Salman Usman says
Hello Mr. Swagatam,
Vs1 and Vs2 isn't connected to out put directly even with high voltage.
Swagatam says
Hello Mr.Salman, those pinouts are correctly connected as per the datasheet.
Carmen B Gavin LATA says
Hello Sir, I think the design you have mentioned here uses the high frequency ferrite inverter rectified line usually above 300v. So, this bridge produces the full cycle once again at 50Hz to make output usable. If so, then please let me know that why above 300v is required? why only 280-290v is not enough? and also i designed another schematic for driving H bridge let me know if its OK. here it is :
i66.tinypic.com/110vzb8.jpg
Swagatam says
Hello Carmen, Actually it should be 310V, because our home mains 220V AC has a peak level of 310V, while the RMS value is 220V, therefore we have to make sure that in our inverter output too the peaks are at 310V, while the RMS is set at 220V
sorry your design will not work,,,where's the bootstrapping network? 🙂
kumail al-qadi says
Hello
I used ir2153 but when I applied power the ic gets hot
can you help me ?
Swagatam says
IC should be operated with 12V, what voltage did you use.