The post explains how an ordinary IC 555 astable multivibrator could be used to make an inverter without involving complex stages.
The idea was requested by Mr. ningrat_edan.
The Circuit Design
Referring to the shown diagram, a single IC 555 can be seen configured in its standard astable mode, wherein its pin#3 is used as the oscillator source for implementing the inverter function.
Using IC 555 as the Astable Oscillator
In an astable mode the pin#3 of IC 555 generates an alternating high/low pulses at a particular frequency rate depending on the values of the resistors and capacitor across its pin#7, Pin#6, 2 etc.
As per the diagram this pin#3 oscillating is fed to a couple of BC547/BC557 buffer driver stages, where one of the stages receives an oppositely oscillating frequency due to the inclusion of an extra BC547 inverter stage.
This ensures that when the left side BC547/BC557 responds to a positive pulse from pin#3 of the IC, the other BC547/BC557 stage is inhibited from the pulse, and their bases are grounded with the aid of the intermediate BC547 conduction.
The above flip-flop functioning of the two BJT stages in turn allow the attached power mosfets to conduct alternately and activate the associated transformer winding with a push-pull current from the battery.
The response allows the transformer to generate the required AC across its secondary winding and implement the intended IC 555 inverter circuit functioning.
The zener diodes at the gates of the mosfets introduce a slight delay time or dead time between the mosfet conduction and inhibits any possibility of both mosfets getting engaged together even for a fraction of a second.
Simplified Version for the above IC 555 Inverter Design
The above shown design can be actually made simpler by removing the BC547/BC557 buffer stages as shown below:
Technical Specifications:
Power Output: Unlimited, can be between 100 watt to 5000 watts
Transformer: As per preference, Wattage will be as per the Output Load wattage requirement
Battery: 12V, and Ah rating should be 10 times more than the current selected for the transformer.
Waveform: Square Wave
Frequency: 50 Hz, or 60 Hz as per country code.
Output Voltage: 220V or 120V as per country code
Video Clip:
Waveform Image:
IC 555 Full Bridge Inverter Circuit
The idea presented belowcan be considered as the simplest IC 555 based full bridge inverter circuit which is not only simple and cheap to build but is also significantly powerful. The power of the inverter may be increased to any reasonable limits y suitably modifying the number of mosfets at the output stage.
How the Circuit Works
The circuit of a simplest full bridge power inverter explained requires a single IC 555, a couple of the mosfets and a power transformer as the top ingredients.
As shown in the figure, the IC 555 has been wired as usual in the an astable multivibrator form. The resistors R1 and R2 decides the duty cycle of the inverter.
R1 and R2 must be adjusted and calculated precisely for getting a 50% duty cycle, otherwise the inverter output may generate unequal waveform, which may lead to unbalanced AC output, dangerous for the appliances and also the mosfets will tend to dissipate unevenly giving rise to multiple issues in the circuit.
The value of the C1 must be chosen such that the output frequency comes to about 50 Hz for 220V specs and 60 Hz for 120V specs.
The mosfets can be any power mosfets, capable of handling huge currents, may be upto 10 amps or more.
Here since the operation is a full bridge type without any full bridge driver ICs, two batteries are incorporated instead of one for supplying the ground potential for the transformer and in order to make the transformer secondary winding responsive to both positive and negative cycles from the mosfet operations.
The idea has been designed by me, however it has not been yet tested practically so kindly take this issue into consideration while making it.
Assumably the inverter should be able to handle upto 200 watts of power easily with great efficiency.
The output will be a square wave type.
Parts List
R1 and R2 = See Text,
C1 = See text,
C2 = 0.01uF
R3 = 470 Ohms, 1 watt,
R4, R5 = 100 Ohms,
D1, D2 = 1N4148
Mosfets = see text.
Z1 = 5.1V 1 watt zener diode.
Transformer = Asper power requirement,
B1, B2 = two 12 volts batteries, AH will be as per preference.
IC = 555
Designing a Compact Ferrite Core IC 555 Inverter
The above concept is based on an iron core transformer, in order to convert it into a compact ferrite cored IC 555 inverter circuit, the iron transformer could be replaced with a ferrite EE core transformer consisting of 9 + 9 turns for the primary, and 300 turns for the secondary, using 0.8mm wire for the primary and 0.3 mm wire for the secondary.
This will also need the 555 frequency to be increased to around 50kHz, instead of the 50Hz assigned for the orin core transformer.
IC 555 Pinout
IC IRS2453 Pinouts
For a Ferrite Core Compact Version
Also, for implementing a ferrite core inverter, the output from the transformer will need to be rectified using a bridge rectifier and the resulting DC fed to a 50Hz full bridge or H-bridge processor, as shown below:
In this processor circuit the IC 555 functions as an adjustable PWM generator while IRS2453 constitutes the full bridge driver circuit, together the stages execute a pure sine sine wave waveform for the proposed IC 555 inverter circuit.
For more info you may feel free to express your queries through comments.
KABIR ABDULRAZAK says
BUT how dose the ofset Adjust work in the given link and how to adjust it ?
Swag says
you can correct the offset null issue by connecting a 10K preset across pin#1,5,4 of the IC, connect the outer leads of the preset with pin# 1 and pin#5, and connect the center lead with pin#4
KABIR ABDULRAZAK says
OK SIR THANKS
KABIR ABDULRAZAK says
Good day sir,
Please the circuit shown above for 555 timer inverter if I convert it DC TO DC Boost, by replacing with ferrite transformer, and make it at 12v input to achieve 310v output, sir you can see at the time of running the H-bridge inverter the input voltage to dc to dc will ten to decrease to say 11v, likewise the rectified DC of 310v will ten to decrease also, so in this case how do I make a feedback voltage with 555 to increase the pwm automatically to achieve exactly 310v at the state of 11v decrease from 12v input to dc to dc boost?
Swag says
Kabir, you may have to employ the concept which is used in the last diagram from this article
https://homemade-circuits.com/simple-solar-mppt-circuit-using-ic555/
build the IC1, IC2 and the 741 stage only, and replace this over the existing IC 555 pwm in the above article.
the pwm from pin#3 then can be used for controlling the inverter output.
the 741 input can be acquired by creating a resistive divider across the inverter 220V output such that around 12V is sent to the 741 input and this must correspond to 220V across the inverter output, now if the 220V tends to rise, the PWM will be forced to get narrower and vice versa.
Michael says
Dear Swagatam,
Thank you so many for your prompt answer, and for all you do in this site. Are you saying that the output of the second circuit is a square waveform? (you wrote in the description of the circuit that it generates a sine waveform, which I interpret as a PWM image of a sine waveform) ?
Swag says
Dear Michael,
PWM is standard digital method for creating pure sinewave in all sinewave inverters. But ideally it is an SPWM which interprets into perfect sinewave at the output.
However that may be true only if a transformer is used or through the use of inductors and capacitors.
Having said this, even without inductors or filters When an SPWM is used the load will ultimately interpret the input as a sinewave, although a slightly crude one.
Therefore, the second circuit should ideally have an SPWM input instead of a uniform PWM, as shown in the diagram.
Michael says
Dear swagatam,
In the second circuit, I don’t understand how the IC 555 can causes the circuit to generate a pure sine wave, that is, how it generates the correct PWM. Can you explain that?
Swag says
Dear Michael, since no trafo is used a pure-sine would be difficult to obtain, however you can add an LC filter across the output to actually carve the waveform into a sinewaveform, you can refer to the following similar concept which will help to understand the waveform transformation at the trafo output side.
https://homemade-circuits.com/modified-sine-wave-inverter-circuit-2/
Satyavijay Durgule says
Please tell how zener diode works to achieve dead time.
Swag says
zener diode ensures that the transistor conducts only once the trigger voltage crosses the zener value, until then the transistor remains switched OFF
Satyavijay says
Thanks for your very prompt reply. Your circuit are very useful and helpful. Your ideas use simple circuits but it does very fantastic job.
Swag says
You are most welcome satyavijay, I’m glad you found it useful
Reitz says
Dear Swagatam,
Thank you so much for your reply. Yes, you are so right. The lift didn’t go to to the top floor before, but now my H-bridge light is finally switched on.
Regards, Reitz
Swag says
You are most welcome Reitz!
Reitz says
Dear Swagatam
I have a question about the centre tap of the primary winding. I understand how and why the transformer is working. Noting the following from your design explanation:
” The zener diodes at the gates of the mosfets introduce a slight delay time or dead time between the mosfet conduction and inhibits any possibility of both mosfets getting engaged together even for a fraction of a second.”
As the mosfets cannot conduct together, would it then be possible to use this circuit on a coil without a centre tap, connecting the drains of both the mosfets to one side of the coil and the other side of the coil to +12V? I’m asking because I’m contemplating a 12VAC circuit to drive a de-magnetising/degaussing coil. I have a core from a old 12VDC auto solenoid handy which I want to use. Probably would have to up the frequency somewhat.
Thank you for a great site. I learned a lot from reading the comments and your replies
Reitz
Swag says
Thank you Reitz,
The method that you have imagined can be simply applied using a single mosfet and a single output oscillator such an IC 555, however that will not produce a push-pull effect, which becomes rather the main purpose of using full bridge networks.
by using a single mosfet, single winding topology you can eliminate the center tap mess, but the output from the secondary will be a one-sided waveform, and not an AC waveform.
I hope you got the point.
kabir Abdulrazak says
THE PWM 555 IN THE LOWER DIAGRAM, WHICH HELP THE IC IRS2453D TO PRODUCE SINE WAVE
Swagatam says
It should be set to minimum 200Hz, 55Hz will not give correct result
kabir Abdulrazak says
Sir what is the effect if to say I leave it around 50Hz to 55HZ for the 555 timer at pin3 and the IC IRS2453D kept at 50HZ?
Swagatam says
Kabir, which 555 IC you are referring to? the first 555 or the PWM 555 in the lower diagram?
kabir Abdulrazak says
Sir,
I have change the 1k and c2 and successfully achieved 50HZ; but the problem is that the frequency is not staying at 50HZ fixed, its fluctuating to 55HZ When ever power is switch off and switch on again, when you measure again you will see it change from 50HZ to around 55Hz. therefore you have to reset it again. Help.
Swagatam says
Kabir, where did you measure the frequency? please check it at the 555 IC pin#3….or you can replace the preset with a fixed resistor for permanently fixing the value.
kabir Abdulrazak says
Sir,I have refer to the link; If I replace the zener with 15v, does the resistor 10k 1/2watt need to be change or not? or that 9v 1watt zner will give me 15v out put?
Swagatam says
Kabir, the output voltage at emitter will be around 0.6V less than the zener value.
the 15K can be used for 15V zener also….this resistor determines the emitter current and a safe operating current for the zener.
kabir Abdulrazak says
Sir, how can I get 12v out of 60v from solar panel to drive my circuit, as you used 33k 10watt R in the full bridge side and get 15v? I have used 33k 10watt but the supply voltage is 60v, therefore I got 15v out, when I connect to the circuit the voltage dropped to 1v and the circuit did not function, I suspect the supply voltage differences that result in to this, Help.
Swagatam says
Kabir, you can do it using a BC546 emitter follower transistor as shown in the following figure:
https://homemade-circuits.com/2014/11/48-v-inverter-circuit.html
kabir Abdulrazak says
Sir, so at which frequency for the 555 timer suppose to give to the full bridge state for acquiring 5HZ output?
Swagatam says
It will be the same frequency, that is 50Hz which needs to be set for the IC 555, preferably at a 50% duty cycle.
this duty cycle can be changed for adjusting the RMS value of the output AC
Swagatam says
Kabir, both the pots are for PWM setting, the adjoining 1K resistors and the C2 cap can be tweaked for adjusting frequency.
kabir Abdulrazak says
Sir,
in the full bridge side, there is 2 pot, please which one is for setting the frequency, and how to set the other one for duty cycle? already I have frequency meatre .
kabir Abdulrazak says
May Allah bless you and protect you from unforeseen menace amen.
Thank you Very Much.
Swagatam says
you are welcome, and may God bless you too!
kabir Abdulrazak says
SORRY FOR MY TOO MUCH QUESTION .
CAN I USED BUCK CONVERTER TO MAXIMIZED THE OUTPUT CURRENT AND STABILIZED THE VOLTAGE TO THE REQUIRE VOLTAGE LEVEL OF MY FERRITE CORE BEFORE FEEDING IT TO FULL BRIDGE SECTION?
Swagatam says
buck converter is not required, reduce the output winding appropriately…..
kabir Abdulrazak says
THANKS FOR YOUR REPLIES :And That is very correct Sir.
I have change the Zen diode from 7v to 3.5v, and it successfully drive my IRFP450, and for the Trf winding I have change the SWG to 30swg 10 (strand) 5o tune for primary and made 40 tune 5 (strand) for the secondary with thinking that the output voltage will reduce, but nevertheless the voltage remained as its (230v dc WHEN I APPLY 12V INPUT) And if I move to 24v the output increase to 430. and my intention is to Apply direct 60v from solar panel.that is at this stage when I apply 60v the output will be up to thousand voltage. but in your 555 timer booster, your primary tune is 50 and the secondary tune is 200. and that is exactly for my first winding and achieve 320v dc when I apply 12v, that is why I change the secondary winding to 40 tune with intention to reduce the voltage. HELP
Swagatam says
the primary winding should be preferably equal to the supply voltage…for 60V you must use 60 turns. for reducing the output voltage you can reduce the the turns in the output winding.
kabir Abdulrazak says
Thank you Sir,
Sir, if I change the capacitor value at the output of my Ferrite trsf,that is from 22uf/400 to 2200uf/450 What will be the effect of my output; its capacitance change or there should be a modification in the output load?
Swagatam says
Kabir, The output response will improve if the filter capacitor value is increased, but the output voltage might increase because of this which will need to be corrected using the PWM adjustment. the output load will not require any change.
kabir Abdulrazak says
Sir, I have noticed my problem, that IRF547 In the circuit, I have replaced it with IRFP450, which prevent the circuit to work; later I just refer back to your 555 timer DC to DC boost converter, I just eliminated that 10k and 9v z from the circuit and the circuit is now working perfectly. But I tested it with 12v battery and achieved 320v DC out put. Sir my question is when I use 60v input from the solar panel, the output voltage will change or not? My ferrite core primary winding is 50 tune with 5 strand 20swg and the secondary 200 tune with single 20swg. You can see that I have altered your specification OF SWG in the circuit; this is because I determined the output load of my inverter and maximum current for the wire gauge, that 0.5mm seem like can not carry high load of current, and that 1.00mm can not carry high input current. But if I when wrong base on my assumption please correct me.
Swagatam says
Hi Kabir, the 9V zener could be reduced to some lower value, say 4.7V etc because the zeners help to achieve a dead time which is important for the inveter's safe functioning…anyway for a 60V input, the tafo will need to be dimensioned accordingly and the winding could be altered to get any desired output from the design.
instead of using single thick wire it's better to use many thin wires in parallel for a much efficient response….instead of 20SWG, try a few strands of 30SWG in parallel.
….and make sure that the IC 555 gets 12V for operating and not 60V.
rest everything may be OK.
Swagatam says
instead of 5 strands of 20SWG try 10 strands of 30SWG etc…
kabir Abdulrazak says
please sir help me as urgent,
I have build the first circuit but before testing i will like to insure the curret polarity of the zener diode, as you said the mosfit will conduct base on the negative and positive pulse of the 555 timer, so by looking at the circuit you can see that the zener diode is facing positive all of them to the mosfit, that is at a positive pulse one of the mosfit will not conduct. or the are as it is. Help
Swagatam says
Kabir, the zener diodes in the first circuit are correctly placed.
the positives from the emitters of the BC547s will enter through the zener cathodes and reach the mosfet gates.
Swagatam says
zener diodes do not work like rectifier diodes.
Asad Ahmed Miki says
thanks for ur reply sir, hope u r doing well.i have some questions .which circuit should i use ? what is the transformer & battery ratings ? is that a sine wave or square wave inverter??
Swagatam says
if you integrate the second circuit, then it will become a sinewave.
transformer and battery rating can be as per your inverter power requirement…
Asad Ahmed Miki says
sir, i have made this on proteus but haven't got the desired output yet could u check it plz ?? i have to make an 100 watt inverter for my university project .need ur help sir
Swagatam says
asad, sorry I cannot verify a software interpretation, but I can guarantee that this inverter will perform as specified when built practically without errors..
eric maduku says
Hello sir, can you pls help me with 12v dc to 60v dc 100w circuit diagram please. Thanks
Swagatam says
Hello ERic, you can try the second circuit concept from the following article
https://homemade-circuits.com/2014/05/generating-electricity-from-road-speed.html
ningrat_edan says
hello sir,
Best wishes
sir, can you help me make an inverter circuit with an ac voltage pulsed out of 500watt, so if out burdened by 500watt light the lamp may blink and blink rhythm can be set using a potentiometer with a frequency of at least 50Hz maximum out 100hz.
thank my regards
Swagatam says
hello ningrat, sorry I could not properly understand your requirement and the application need of the circuit
ningrat_edan says
Sorry sir if it is so contrary to you due to certain factors, actually I wanted to create a series of electrofishing to output a pulsed ac voltage, …
once again please forgive me if my request is contrary to your
my regards
Swagatam says
Ningrat, you mean to say you want a 220V generator circuit having a variable frequency adjustment??
Swagatam says
Chucks, you can use 2N2222 in place of 2N3053
chucks ichoku says
hello sir, I do not see ur reply in post, please reply me here so that I will carry on my project thanks
ningrat_edan says
Sir
if the email you have received from my
Swagatam says
Ningrat, I did not get any email,
please send it again or post it in the following forum
http://makingcircuits.com/forums/forum/electronic-circuit-discussions
in this forum I am the admin.
chucks ichoku says
hello sir, pls I need ur assistance
i'm designing a digital display circuit, ther was a component I can't find in ma country such as 2N3053 transitor. is ther any other transistor use to replace and also gv me the same configuration it does???? thanks
Swagatam says
I have already replied to the same comment in the other post
Swagatam says
you can use a 2N2222 instead
ningrat_edan says
Hello, sir
I hope you are always healthy, ..
sir if i can send an email to you because I want to discuss a scheme and I find it difficult to attach the scheme in this forum
Swagatam says
Hello Ningrat, for a long term consultation you can signup and start posting here
http://makingcircuits.com/forums/forum/electronic-circuit-discussions
or for brief discussion you an use my email admin @ homemade-circuits.com
ningrat_edan says
Sir,
maybe you have recommendations dc converter circuit 12volt to 300volt DC and converted into 220volt AC
Swagatam says
you can try the circuit explained in this article, you can replace the IC with the above 555 circuit stage
https://homemade-circuits.com/2013/09/half-bridge-mosfet-driver-ic-irs21531d.html
ningrat_edan says
I tried to replace the transistor with s8550 -s8050 and a series of work thank you very much sir
my regards
Swagatam says
that's great Ningrat, congrats to you
ningrat_edan says
Thank you very much sir,
sir if I could replace the transistor BC547 and bc557 with other types may BD139 and BD140 or s8550 and s8050? if it can do I need to change the value of the other components?
my regards
Swagatam says
Yes you can but it will be unnecessarily costlier….
Swagatam says
no other components will need to be changed.
ningrat_edan says
I need a circuit standby automatic charger for charging 12volt battery with a maximum current of 2 amperes, this circuit will be installed in the inverter.
Automatic question is:
1. The automatic cut off the charging current when the battery is in full condition
2. The inverter will turn on automatically when power outage
3. The inverter will automatically turn off when the power flame back.
Thank you so much my regards
Swagatam says
Ningrat, you can try the second circuit from the following article
https://homemade-circuits.com/2011/12/how-to-make-simple-low-battery-voltage.html
the charging input can be acquired from any suitable power supply source…
ningrat_edan says
Hello, sir
Can you help me again, I have to stand by charger circuit using ferrite transformer would I plug the inverter circuit that I have made.
I had been using stand by charger which uses iron transformer I think if the circuit uses ferrite transformer would facilitate.
Thank you so much my regards
Swagatam says
Ningrat, Please give the technical specifications of your charger
ningrat_edan says
a pressing issue, why I wanted to make this inverter because in the area I frequent power cuts in 4 hours
and if it's quite possible it will greatly help me
ningrat_edan says
I'm very sorry sir, too many of my questions got me so confused
actually i need a simple circuit using a transformer ferritte inverter that can be used to supply domestic appliances such as water pump, fan, TV and other types of induction motors.
The circuit may be able to use ic TL494, NE555 because the component is very easy to be in my area, there are some circuit which uses components that are very difficult in the can in my area wide ic3524,3525, IR2153, and other types
Swagatam says
Ningrat, you can try the above explained IC 555 based ferrite circuit, it will certainly serve the purpose as desired by you….
Swagatam says
or you can try the following design also
https://homemade-circuits.com/2013/10/modified-sine-wave-inverter-circuit.html
ningrat_edan says
Sir,
series such as what is used for converting high frequency to low frequency
Swagatam says
the four mosfets are toggled at the low frequency 50 Hz for executing the 50 Hz AC on the load
ningrat_edan says
if the output of the circuit is converted into a dc voltage using a diode bridge and then a dc voltage is converted back into an ac voltage what it could be?
series such as what can turn into a dc voltage low frequency ac voltage in this issue?
Swagatam says
ferrite core can be operated only with high frequency, that's why initially high frequency is used for stepping up the battery voltage to 220V and then it is converted back to low frequency for our home appliances.
ningrat_edan says
if we change the value of Rt and Ct to get 50Hz whether it could be applied in the ferrite transformer?
I mean a string of additional output transformer that will turn into a 50Hz 50kHz frequency
Swagatam says
ferrite transformer is supposed to be connected with the first diagram which has 50 Khz frequency, the lower circuit needs to be set at 50 Hz….
the load or appliance can be directly connected the lower circuit mosfet.
the 50 khz from the top circuit is fed to the second circuit through the bridge rectifier
ningrat_edan says
sir, this circuit produces high frequency ac voltage 50kHz whether it can converted into low frequency ac voltage between 50Hz – 60Hz
Swagatam says
Ningrat, the Rt, Ct values in the second circuit determines the 50Hz frequency for the load.
you can get the formula in the datasheet of the IC
ningrat_edan says
Thank you sir,
I am having trouble finding diodes past 10 amperes, .. is there a best solution for it
Swagatam says
you can try 6A4 diodes, see if they work alright?
ningrat_edan says
hello sir,
I'm very grateful you have deigned to answer my questions by posting an inverter circuit NE555 ic that works on ferrite transformer, I really hope you do not get bored if I will be asking a lot more about this circuit.
I pray that God bless your family
Swagatam says
You are welcome Ningrat!!you can feel free to post new comments
bashir abdulkadir says
My another Qestion Sir, for instant if i want to modify an low watt inverter less said 50watt please what and what do i going to change or to add. may i going to change height voltage transformer or i am going to add more transistor in pararal please which one should i going to do??
Swagatam says
what modifications do you want to make??
bashir abdulkadir says
thank u sir
bashir abdulkadir says
amps = 1W / 230V
= 0.004348A ??
Swagatam says
yes that's correct. current is measured in amps.
bashir abdulkadir says
is current the same with amp?
bashir abdulkadir says
thank sir may GOD expand ur idea more again
bashir abdulkadir says
If i get u for example if my current is 9 watt and my battery is 100AH THE ANSWER IS 100/9=11.1*0.6=6.6 hours ??
Swagatam says
It should be load current, not load wattage….your procedure was correct but in place of 9 watt you must apply current.
current can be found by dividing 9 watt with load voltage.
bashir abdulkadir says
Please Sir help me as you are doing to us. please guide me how i am going to calculate battery mAH . Assume that the battery is 12v 100mAH and connected with 500watt inverter if i connect 7 phone chager each is 6 watt and 9 watt CFL how many are hours may the battery's charging take before the it finish
Swagatam says
I guess you meant to say 100AH battery??
you simply have to divide the battery AH with the load current, and multiply the result with 0.6, that will give you the approx battery back up time.
chucks ichoku says
hello sir swagattam, I designed an inverter, it is working perfectly. but my problem is '' the heatsink ther was not fan connected to it and it is hot so much. I need an automatic fan circuit for cooling of the heatsink whenever it start heating the fan will automatically blowing, and whenever it stop heating the fan will automatically stop…. thanks
Swagatam says
hello chucks, you can try the following concept
https://homemade-circuits.com/2015/03/fan-speed-controller-for-heatsink.html
gogutu says
Domnule Swagatam Majumdar,va rog sa-mi spuneti daca acest invertor poate fi folosit la o pompa electronica pentru centrala termica,atunci cand reteaua de curent a cazut.pompa consuma 40w.daca nu ce modificari trebuie aduse.Scuze ca nu vorbesc engleza.pls raspundeti.tank you
Swagatam says
da, acesta poate fi folosit pentru orice aplicație preferată ca pe alegerea ta
chucks ichoku says
sir what is dis chopper all about. is it a circuit. if yes can u upload it, let me take a look at it. thanks
Swagatam says
you can learn the details here
https://homemade-circuits.com/2013/04/how-to-modify-square-wave-inverter-into.html
john omaba says
Is the citcuit square wave or sine wave? If square wave where to attach chopper to it and make it modified sine wave? Thanks
Swagatam says
it's square wave, add chopper to the bases of the NPN/PNP
bashir abdulkadir says
I am using a simple transformer. When I press ctrl+E, but tell me that how can i calculate these values like primary inductance, secondary inductance etc. Can you suggest me some calculator for this purpose?. My requirements are below: primary voltage: 220V, 50Hz secondary voltage: 12V, 1A
Swagatam says
I have already discussed how to design an inverter transformer in this website, you can refer to that article. you can find it through the search box above or by Google search..
bashir abdulkadir says
sir can i connect the above circuit with 6-0-6 ? and how the watt be ?
Swagatam says
it can be used if the battery is also 6V
chucks ichoku says
I av 12v 0 12v to 230v AC, will it work on the cirvuit above? sir
Swagatam says
yes ti will work
chucks ichoku says
sir can the circuit above power a fan without a noise???
Swagatam says
you can connect a capacitor with the fan to reduce noise
chucks ichoku says
sir what are the appliances does the circuit above will power ?
Swagatam says
It will power most of the equipment which use internal SMPS
eric maduku says
pls sir, can you help me with the diagram of IC 4047 and fets 1kw diagram since thats the only ic i can get around. Thanks
Swagatam says
Eric, you can try the following design
https://homemade-circuits.com/2014/11/48-v-inverter-circuit.html
you can replace the BJTs with FETs, and use 100 ohm resistor with their gates
bashir abdulkadir says
i am greatfull so much and i am very appritiate for your site
Davis Kakumba says
hi swagatam for the first diagram what is the rating of the transformer
Swagatam says
Hi Davis, it can be as per your own desired specification….
bashir abdulkadir says
Please can u help me and tell me how may i know the transformer WATT because i have UPS transformer but i don't know it WATT?
Swagatam says
apply mains AC across its mains side and then using an AC ammeter measure the current directly across the other side wire ends…then multiply the reading with the voltage specification of those wires
bashir abdulkadir says
Please sir what is the Watt of this inverter ?
Swagatam says
Will depend on the trafo wattage and the battery AH capacity.