In this article I have explained a couple of inverter circuits featuring an automatic feedback control for ensuring that the output does not exceed the normal specified AC output level, and also does not exceed the specified overload conditions.
What is Feedback Control in Inverters
A feedback control in inverter is generally incorporated to control the output voltage and output current and prevent it from exceeding beyond dangerous limits.
In this system, the output AC mains voltage is first dropped to a proportionately lower level, and fed to the shut down pin of the control IC. The stepped down feedback voltage now follows the output AC and varies up/down accordingly, in a proportionate manner.
The control ICs shut down circuitry comares and monitors this feedback signal with a fixed ference derived from the battery volatge of the inverter.
In an event that the output voltage tends to rise above the predetermined value, and increase beyond the reference level, it activates the error amplifier, which shuts down the inverter output PWM. Once this happens, the output voltage instantly dips, causing the feedback signal to decrease below the reference value. This situation prompts the shut down feature of the IC to get disabled, and the IC starts working normally again.
If the output yet again tries to rise beyond the unsafe level, the above process is repeated in the identical manner, and this goes on continuously and rapidly, ensuring that the output voltage is never allowed to surpass the specified unsafe level.
Feedback Control in SG2524/SG3524 Inverters
The first example circuit belw shows how an automatic feedback control can be added to a SG2524 inverter circuit. The same concept can be also applied to all the other inverter versions, using the IC SG3524, and SG3525.

You can refer to the following two datasheets for exactly knowing how the pinouts of the IC SG2524 IC are designed to function:
The feedback control loop is configured in the following can be understood with the following points:
The 220V AC output is first rectified using a 4 diode bridge rectifier circuit.
The rectified high voltage DC is dropped to a lower DC level, at around 5V to 10V through the voltage divider network built using the 220K resistors and the 10K preset.
The 10K preset is used to adjust the feedback voltage until the output voltage is controlled just at the right level.
The feedback is taken from the 10K preset's center arm and fed to the error amplifier's non-inverting input pin#1 of the IC 2524.
This error amplifier is nothing but an opamp set internal to the IC for controlling the PWM of the output pin#11 and Pin#14.
The inverting or the (+) input pin#2 of the op amp is clamped at a fixed reference level of +2.5V through the couple of voltage divider resistors configured around the pin#2 and pin#16 of the IC. The +5V reference potential is derived from pin#16 of the IC and then dropped to 2.5V using the two voltage divider resisters.
Since the pin#2 of the error amplifier is fixed at 2.5V reference, means that if the pin#1 of the opamp rises above the 2.5V level would instantly trigger the PWM feature of the IC, causing narrowing of the output PWM to the transistors.
The feedback 10k preset is adjusted in a such a way that feedback voltage at pin#1 reaches the 2.6 V mark as soon as the output voltage reaches the specified unsafe high voltage level.
In such situations, when the pin#1 receives a 2.6 V, it will cause the internal error amp to activate, narrowing the output PWMs to the transistors, which will in turn cause the output voltage to reduce to the safe lower levels, appropriately.
Simple Voltage Feedback Control for SG3525 Inverters

This is simple non isolated direct feedback circuit for SG3525 inverter. First high voltage 220 AC comes from inverter output. Then four 1N4007 diodes convert this AC into DC.
After that 220k resistor drops high voltage and 10uF four hundred volt capacitor smooths out DC ripple. Now 10k preset is used as voltage divider to set output voltage to220 or 120 volt. Sampled voltage directly goes to Pin number one of SG3525 IC.
Between Pin number 1 and Pin number 9 there is 470k resistor and 68nF capacitor network for error amplifier compensation to stop oscillation.
Also 10nF capacitor is connected from Pin number 9 to ground for extra filtering. When output AC voltage increases, voltage at Pin number 1 also goes up.
Since Pin 2 is supposed to be at fixed reference, high voltage at Pin 1 forces internal error amp to reduce duty cycle and output voltage comes back to normal level.
Main warning is that this whole circuit shares common ground with AC output, so it is not isolated and touching any part can give dangerous electric shock.
Adding Feedback in IC 555 Inverter
You might have already gone through the post which explains how to build simple 555 based inverters.
Although all these inverters are decently designed and will produce the intended 220 V or 120 V from an easy IC 555 set up, these do not have a built-in feedback system for ensuring a constant output voltage.
The following figure shows how an ordinary IC 555 inverter could be transformed into an enhanced inverter through an easy feedback loop control network.

In this circuit also, we find that the 220V output from the transformer is first rectified to a DC level, and then it is stepped down through a resistive network comprising of a 220K resistor and a 10k preset.
The 10k preset center lead is configured with the NPN transistor BC547, whose collector can be seen connected with the pin#5 of the IC which is control input of the IC.
We know that normally when pin#5 is open, the PWM at the output pin#3 of the IC has a maximum PWM, however, as the potential at pin#5 is reduced, the output PWM also gets reduced proportionately.
Grounding the pin#5 causes the output PWM at pin#3 to become very narrow, with almost zero average voltage at this pinout.
In the IC 555 feedback circuit, when the output voltage tends to rise above the unsafe high voltage threshold, as per the setting of the 10k preset, the base of the BC547 slowly starts getting biased. When this happens, the BC547 begins conducting and causes the pin#5 of the IC to get gradually grounded. The grounding of the pin#5 of the IC causes the output PWM at pin#3 to get narrower, which in turns causes the output voltage to drop to the normal levels.



Questions & Answers
Hi sir, why is the feedback unstable? https://drive.google.com/file/d/1P1nT4NOcAflLR0wgv5w38ztkRjtSKv-W/view?usp=drivesdk
Johan, please make your circuit in this way, and then check:

I’ve checked but the voltage goes up and down https://drive.google.com/file/d/1PNzcsLdni5UE8shq1UUlGXNEHCU1RZ7i/view?usp=drivesdk
The feedback circuit which I gave is correct, I think the problem could be in your inverter circuit, please build the following circuit and check again:

is it possible to achieve overload and shortcircuit protection using current transformer and op-amp in an inverter? If yes please help with a circuit diagram
Sure….Please refer to the following article:
https://www.homemade-circuits.com/load-current-control-through-current-sensing-transformer/
Swatan.. I don’t know where to ask,,, I would like a circuit to make an inverted welder of at least 120 Amp to 250 Amp, I have type E ferrite cores from televisions, also the circular or round ones from vehicle audio amplifiers,,, but I need a diagram if possible checked
Hi, a TV ferrite core or an audio amplifier ferrite core will not be able to produce 200 amp current.
Unfortunately, I do not seem to have sufficient information about the details of this transformer at the moment..
Good sir. I have a problem with my sg3524 circuit.
I built this inverter with feedback voltage correction circuitry but when power it, its actually working is giving out 220v as i set it but while working the mosfet is extremely hot. I try everything i could but could not rectify the problem but when ever i remove the feedback topology and return it back to the normal switching circuitry, it doesn’t hot at all but am not ok with the output as soon i inserted a load to it. It will drop from 220 to 140v.
I actually use 7.2v center tap transformer.
Hello Abdul,
Please add a snubber network across the MOSFETs as discussed in the following article, and also add a reverse diode across the gate resistors of the MOSFETs, and add a 10k resistor between gate and source of the MOSFETs, and check the results:
https://www.homemade-circuits.com/explained-snubber-circuit-for-mosfet-h-bridge/
https://www.homemade-circuits.com/rc-snubber-calculator-for-mosfets-relay-contacts-and-triacs/
https://www.homemade-circuits.com/mosfet-protection-basics-explained-is/
swatan,,,, pregunto si tendrías algún circuito que pueda hacer para un soldador tipo invertir, para hacer si me das un esquema y detalles lo haré soy experto en electrónica..
Felix, I have answered to your question previously, but no problem I will answer it again.
Designing Inverter type welding circuit is possible, but 250 amps is huge, I have no idea which ferrite core would be required for such high current application.
https://drive.google.com/file/d/1HJ1BjVdX1m5d9tyioweUeXkwcNFR9wXL/view?usp=drivesdk
this is what i finally did,the feedback is working,but there is catch under capacitive load the output increases e.g phone charger, capacitor etc.,but if I put a 40w resistive load (incandescent bulb) and then plug any capacitive load it remains stable and don’t increase, pls what is the cause?,apart from this it is working fine my MosFets are not getting warm too quickly.i also want to add battery low circuit and fuse pls any idea?sport for so many resend I don’t know if you will see this one.
Capacitive loads like phone chargers or plain capacitors mostly pull reactive power, not real power. Because of this, the inverter thinks there is not much load so voltage can rise or go unstable, mostly if the feedback is not properly designed. Now when you connect a resistive load like a bulb, it pulls real power continuously so inverter starts regulating voltage properly. After that even if you add capacitive loads, still the voltage stays stable because real load keeps things balanced.
So you can try adding a 1k resistor at the output and check the results…
that is the issue if am going to use a resistor for the real load then I should be prepared for how to reduce the heat it is going to generate,pls what should I do about that?,also if am to use 1k pls what Watt should I use?and can even get it here cause it is not available.
Instead of a resistive method, please try connecting a 10uF capacitor across the output of the bridge rectifier and check the results.
By the way your MOSFET driver section looks bad…you must use the methods which I had suggested earlier.
can 30uf/450v Ac capacitor and AC circuit breaker be used to stabilize inverter output voltage?
Please show me the circuit diagram, I will try to figure it out….
https://drive.google.com/file/d/1sDAfqSz0v9xgZB20mmUiM3PCMeF3gXIt/view?usp=drivesdk
what will happen if you remove the 10k resistor from the oscillator pin ,with it affect the performance,cause when I want to add the totem pole driver I remove mine and my inverter was misbehave was it responsible for that?
Whether or not you connect a 10k between the oscillator output and ground does not make any difference, and will not have not any kind of effect on the inverter performance.
sir, when I implemented circuit 1 into my oscillator,it worked, but then my feedback was affected,my inverter started Misbehaving the output was no longer stable again.was could be the cause?also my inverter is sensitive to capacitor at it output or even at feedback so what could be the cause?
Jerry, please do not associate any capacitor with the feedback network, however connecting a capacitor at the output of the inverter should not affect the inverter performance. Make sure the capacitor is a non-polar PPC or MKT type such a 2.2uF/400V PPC etc. Moreover you need this capacitor mostly when you are using a modified PWM or SPWM sinewave inverters topologies, otherwise it is not required.
good evening, sir. happy new year. it been a while like a year since I work on my diy inverter, since am in school, but few day ago, while reading a course called power electronics, where I was drawing the waveform of bridge rectifier, I realized I never understood them cause I used ur circuit to design my feedback circuit for my diy inveter although the oscillator circuit is different, the issues was I always thought that the anode if a diode is the positive terminal and cathode for gnd, this was the idea I had while designing the feedback for my diy inverter, I mentioned earlier that when I implemented it at first it work even with capacitive load, after neating and coupling the inverter it misbehaved, this use due to me connecting my positive of my feedback voltage to gnd and negative or gnd through the voltage divider to pin 1, I never released this till after a year, I tried my best to find the issues, till I don’t even remember what I did that made the while system work with the feedback, but still misbehaves with capacitive load, although after my exam if I go home I would open everything and inspect what I did, cause hmmm, until after a year that I realized how bridge rectifier works, and the anode of the diode will be your ground, I pray I don’t just chastise myself when I see all my connection in the inverter. about the driver I will fix them using 4 npn transistor(the second method you show me), am also thinking of rebuild the whole osillator surcuit using your circuit entirely, that will be for maybe a second inverter and lastly thanks for all the help and advice it really helped, alot!!. the website update is nice also👌👌.
pardon me if you see this message more than once, I don’t even know if it is sent or not, that is the reason for the multiple resend
I would like to add that a thought came to me, that I can utilize your transistor driver which drine the primary winding directly, but instead used it to drive the gate of a mosfet instead, is this also ok?
Thank you Jerry for your kind and honest feedback…I appreciate it very much.
If you want to use a BJT driver for the MOSFET gates then make they are two of them connected in inverting mode, or in a totem pole mode.
Morning, sir. i am happy to announce that my inverter is up and running and these are the modification i made.

Thank you Jerry, it looks great, thank you for updating your tested design here…much appreciated.
what I was trying to say is that before I implemented the totem pole driver I already added feedback and it is working,when I power capacitive load with it it handles them also,but I noticed my mosfet got warm to quickly that is why I added the totem pole driver and on doing that the my inverter output stated misbehaving it was not stable going from 100v to 200v to and fro,but yesterday I added those 2 10k I mentioned to gnd and then I was able to finetune my feedback,but I added capacitive load and all of a sudden the voltage started fluctuating again,pls what is happening? thanks for your effort on me.
Then I think you should remove the totem pole and try the other driver configuration which I had suggested you using two NPN transistors. Make sure to connect each and every resistor correctly, otherwise it will not work:

when I return my circuit to old no (totem pole driver) ,I was able to retune my feedback again and capacitor no longer disturb it ouput,so pls what went wrong that if I add the totem pole is disturb my feedback?,cause I remove a 10k resistor from pin11 to gnd and another 10k from pin 14 to gnd.
Using totem pole for the MOSFETs should have no effect on the performance of the inverter, in fact it might only improve…
Since you have used the feedback with pin#10 of the IC so again no problems with that.
You can try connecting a 10k directly between the gate and source of the MOSFETs and check the response…
https://drive.google.com/file/d/1JLNH2vQWX9U98APID09i_wgj8zC9WCYZ/view?usp=drivesdk
pls sir is it ok to add a 10k resistor to the mosfet like this?
The resistor between the emitter and ground of the totem pole BJTs is not required, instead you can connect the 10k directly between the gate and source of the MOSFETs.
I have 4 MOSFETs in Parallel with each other and another 4 parallel MOSFETs for driving my transformer,the thing if I am to add the resistor from gate to source I will need to do that for all of my MOSFETs,and I already the mosfet,to add the resistor will the somehow stressful,the thing is the 10k resistor is already connected to MOSFET like this for each side of transformer and only one 10k was used for each side.
For connecting MOSFETs in parallel, just join their 3 relevant pins together, in parallel…
Good evening sir I actually implemented the feedback and it’s worked but lasted for like maybe 30 minutes this is the things sir the circuit I actually use was still my old oscillator circuit what I just did was use another external transformer and I try to use a voltage divider to implement the feedback but this is the thing when I tested it at first and it worked there was no voltage drop but when I realize that my battery was low ,I went to charge it but on retesting it again the inverter started to misbehave(output got to above 300v ,so I’ve been trying to figure out the issue that I was wrong with it,but my thought is maybe my voltage divider somehow is not right or my total feedback voltage(6v DC) was too low,I just want to ask that what could be the cause of this? I implemented the feedback it worked I captured the testing on camera and then on coupling the inverter and retesting after I recharge my battery,the inverter started misbehaving.
Hello Jerry,
Please provide me with the following details, I will try to figure out the issue.
1) Battery Ah value
2) Transformer voltages and wattage or current specifications.
3) Load wattage which is causing the voltage drop.
4) Battery voltage value at the time when the inverter output voltage is dropping.
For adjusting the feedback, you can simply do it by connecting an AC voltmeter to the output of the inverter transformer and then adjust the feedback preset until the output voltage settles down to the correct required output voltage level…
good morning,I have successfully implemented the feedback now and it is working,the issue before was the if I add capacitor for filtering either the output or feedback voltage the inverter misbehave so I remove all capacitor except from the oscillator circuit and it worked I added snubber circuit to the output though.now I have another question I noticed my MOSFETs warms up quickly when my feedback is now working,is it because I did not use a transistor at pin 11 and pin 14 like to function as a MOSFETs driver?,cause I have I seen two YouTuber did it but never explained why.
Hi, I am glad you could solve the problem so fast.
A driver transistor may be required for a MOSFET if the load is a high current load, otherwise not.
So for small inverters below 200 watt, driver transistor may not be required.
Just make sure to use gate resistors of small value, and put reverse diodes across these resistors.
good morning,pls do you have the schematic for the this so I can follow it?
Hi, you can try the arrangement as done in the following concept:

https://drive.google.com/file/d/1g1A6ua4Bw9Fxl_I96uJ_gGRwwCDPNap6/view?usp=drivesdk
what about this?
You can access it now,sir
but,sir I already bought component for circuit 1
No problem Jerry, You can use circuit 1 also, it will also work fine.
It is telling me to request access, please check your email ID.
my MOSFETs already has a 10k resistor from it source joined to another 10ohm resistor that goes to it gate and the junction where the two resistor joins together is where the Signal is sent to,so is the resistor connection not discharge?

The gate current from 10 ohm has to pass through the high resistances of 10k and the 1k to reach ground for discharging, which is not good. The 10ohm end must have direct access to ground during the off periods of the oscillator output.
Please use one of the two configurations which I showed you previously.
It is not opening…please get the link in the “shared” mode..
https://drive.google.com/file/d/1y_k110TcAp0FD7MXUTDEkyjjEcE14hvS/view?usp=drivesdk
which is more efficient among the two sir you gaver sir?,pls sir is there any component am missing out?
Both the designs are good, but the bottom one is better since it connects the MOSFETs gates directly to ground during the off switching periods. Your second design had a few mistakes, i have corrected them now:

it is working now sir.
Yes, now I can see the diagram, but your concept is not very efficient, because discharging the MOSFET gate through the 1k can be slow and dangerous for the MOSFETs. Instead you can use a totem pole design, as given in the 2nd diagram below.


Good morning,the feedback is not boosting the output voltage,it just makes the output stable under load,but what happened is the when my input is 12.99v or 13v the inverter misbehave and the ouput get to 324v and it drwas too much current ams asking that does this happen because I use a 6v 0 6v to 240v transformer?
Ok, earlier you were discussing feedback for overload voltage drop, so I was referring to that issue. Yes, the high voltage is due to a 6V trafo and a 12 V battery, you can try a 9-0-9V transformer instead and check the response…
good afternoon I made an inverter using an sg3524n,although the oscillator is different from yours,which I still don’t understand the way the oscillator is yet,cause i got it from a spoilt inverter where the transformer of the inverter got burnt but when I actually use it to make my own inverter the issue was that there was no feedback and when Ioad is connected to the output it will varies depending on the load so I tried to implement feedback by using a 220v to 6v battery charger that utilize a transformer which the output is rectified to get 6v then I used a 10k fixed resistor and a 20K pot and I connected in such a way that when I measure the voltage at the mid terminal of the pot with respect to ground I get around 2.99v so I connected the positive of the feedback to ground of the battery the mid terminal of the pot to pin 1 of the sg3524n, but what happened is that when I turn on the inverter it does not output any voltage so I try removing the the positive of the feedback that was connected to the ground of the battery its comes on but when I connect the positive of the feedback voltage to the ground of the battery the inverter turns off,pls what could be the cause of this? is it that the feedback voltage is too much or I’m not doing something right?
Hi, If you have used pin#1 for implementing the shut down, then the inverter output PWM will shut down when the pin#1 voltage exceeds the pin#2 reference voltage.
So can you please what reference you have set at pin#2 of the IC?
So basically, you must adjust the feedback preset such that at the desired high output voltage (above 250V), the preset output has a potential that just exceeds the pin#2 potential, and then this feedback voltage can be connected with the pin#1 for inducing the quick shut down when the inverter output goes above the unsafe high output AC voltage.
thank you for the quick reply,sir.My goal is to prevent the inverter’s output from dropping under load by implementing feedback. I realized the shutdown issue was due to the output reaching 289V. I’ll set the inverter to shut down only if the voltage exceeds 240V.pls Will enabling this feedback shutdown feature also prevent voltage drops under load? Or do I need a different approach? I’ll check the reference voltage and update you tomorrow.”
That is not possible through any means, except upgrading the inverter power.
If your inverter voltage is dropping due to overload, that means your inverter and battery are not rated to handle the specific amount of load, which means this issue cannot be solved through a feedback facility.
To solve it, you may have to consider upgrading your inverter and battery power.
good day sir. i made the sg3524 circuit, i can vary the output but when i add a load of 10watt the voltage drops to about150v
Good Morning Hillary, You must verify the output voltage without the feedback connected. Check if it drops or not. If it does then either the transformer or the battery or the PWM setting may be malfunctioning.
the transformer i used was a 6v 0 6v to 220v that I got from an old ups I also need to tell you something about the oscillator,when I try to measure the reference voltage with respect to ground I was reading around 0.49 volts which I know something is wrong so I’m trying to see if I can send you the schematic of the oscillator if maybe you can advise me to build another one and I will just get some components.
You can send the schematic or you can refer to the following post, and check if you have built your inverter as per the given configurations or not.
https://www.homemade-circuits.com/sg3525-pure-sinewave-inverter-circuit/
I also want to ask what should be the maximum feedback voltage I mean when you rectify your AC I got sending it through your voltage divider what should be the maximum voltage is it that my maximum feedback voltage should be around 5 volts before it gets to the feedback I tried voltage divider
I don’t know if u have seen the schematic, although with it help I was able fix it and implement feedback.the output does not drop anyhow any longer.but when I connect a fully charged battery 12.99v to the inverter,it draws too much current and the transformer makes a loud noise, although under 12v its behave normally,also I noticed the inverter still work at 8v and I know the battery is already low.pls those this happen because I used a 6v 0 6v to 240v transformer?
A feedback will not boost the output voltage if your voltage is dropping due to overload.
If it is working, then your inverter problem is not due to an overload.
I think you must follow a standard design as shown below for implementing a good standard SG3525 inverter circuit.
will this work pls???
It is correct and will work….
ok sir, thanks you sir.
the ic am using is sg3524n
Pic 18f2431 is it better than 16f72 and dsppic30f2010 in its ability to drive the fet/igbt effectively.
Hay its me again, is it possible to add an sg2524 to an ZVS circuit. I have had somewhat of a working ZVS circuit. I am trying to make it more stable. When it works it works well, but some time later it blows up. The best mosfets that have worked for me is the hy3408 only problem is they can handle voltage to 80. The irf260n which the circuit calls for very tempemental and costly. Thanks for your time.
ART
Thanks Art, I think it is possible, however the crucial part is calculating the buck converter section. I am not well versed with ZVS technology, let me investigate more and then I can try to add more explanation…
Hi. I have made this circuit but when i change the preset, the frequency of the ic changes instead of the duty cycle
Hi, In the 555 circuit the frequency might also slightly change when the 100k preset is adjusted.

If you want to change only the PWM, you can replace the 555 stage with the following stage:
i mean sg3524 not 555
If you adjust the feedback 10k preset the frequency cannot change because that preset has no connection with frequency.
When feedback is adjusted the PWM is narrowed or widened, frequency remains the same.
Please measure the frequency across the CT capacitor.
Pls if I connect the feedback circuit to ic4047 as indicated can it still shutdown the inverter on a high load more than the inverter power as some inverter do. Pls I want to know
No, the previous circuit is only for regulating high output voltage, it is not an over load protector…
Can I connect a 12v transformer to the inverter output before going to the bridge rectifier and the 220k, 10k preset for the feedback
If you use a small 12v step-down transformer for the feedback, then the 220k/10k divider will not be required.
Pls how can I add a feedback circuit to my cd4047 inverter that I build pls
you can try the following circuit:

connect the collector of BC547 to the Ct pin of the 4047 IC.
Thanks but what will be the minimum voltage the battery must get to indicate it is a low battery and can I replace the transistor with MOSFET.
A 12V battery may be considered low when its terminal voltage reaches 11V or 10.5V. Yes you can replace the BJTs with MOSFETs
I mean for 6v06v transformers I want to use u said I should used 9v battery max.but at what voltage will 9v battery be low
It will be around 8V…
Can I use a 6v06v to 220v transformer from old ups instead
You can use it but then the battery will need to be around 7V or max 9V.
What if instead of rectifying the output voltage for the feedback you just use a mobile charger that produce 5v for the feedback.pls will work?
No it will not work, because mobile phone will produce a fixed 5V and not a varying voltage.
Ok thanks
Hay me again looking for my last post found this topic on feedback circuit. Well first off the two boost converters work great paralleled I used , 2x. .
0.1 ohm 10-watt resisters one on each positive leg. When I got to about 2000 watts they got very hot. I guess that’s ok since that is why I used 10 watts. I also saw that a diode was used instead of the resister, could you explain the difference and in my case it would have to be a big diode of high current. I also saw your feedback circuit, going to put that to use. Thank you have the best web site, you cover everything, no need to go any place else.
ART
Thanks for updating the results. Glad the idea is working for you.
You last comment was posted under this article:
https://www.homemade-circuits.com/inverter-circuit-with-feedback-control/
Can you please tell me where is the diode placed in your boost converter circuit?
The function of the diodes could be to provide isolation across the outputs of the two boost converters.
You are most welcome, I am always happy to help!
Hi senior Swagatam, I’ve been following your post for years. My question is, can a square wave inverter power a submersive pump machine? I’ve made one of your circuit using SG3525 3kv. I recoil the transformer 48 0 48. I used 48v battery. Everything worked fine but the transformer is overheating. The output MOSFETs, I used 6 pairs (12pcs) of irf260n
good day boss, please can you share the circuit you used?
Thank you so much Barry, for being a dedicated reader of this blog.

An appropriately rated square wave inverter can power a submersive pump motor, but the motor might make a lot of noise and heat up.
So you have to make sure your inverter is at least a modified sine wave inverter with a capacitor filter at the secondary side of the inverter transformer.
Here is an example design which you can effectively employ for the same;
You can change the transformer specifications accordingly to improve power efficiency.
Can this circuit withstand refrigerator
That will depend on the transformer, MOSFET and battery capacities.