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You are here: Home / Mini Projects / Simple Solar Garden Light Circuit – With Automatic Cut Off

Simple Solar Garden Light Circuit – With Automatic Cut Off

Last Updated on September 12, 2021 by Swagatam 250 Comments

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A very simple automatic solar light system for illuminating your garden passages can be built using some LEDs, a rechargeable battery and a small solar panel. The system automatically switches ON the lamps at dusk and switches them OFF at dawn.

How it Works

The circuit design is extremely straightforward and may be understood with the following points:

As can be seen in the given circuit diagram, the design basically consists of a solar panel, a PNP transistor, few LEDs, a battery and a few resistors.

The transistor is the only active component which is positioned as a switch for preventing the battery voltage from reaching the connected LEDs during day time.

During broad day light, the solar panel produces the required amount of voltage which is applied across the rechargeable battery via the 1N4007 diode and the resistor R*. This voltage charges the battery gradually from dawn to dusk.

Selecting the Current Limiter Resistor

The resistor R* value should be adjusted as per the specs of the battery for limiting excessive current to it.

The resistor also serves as the current limiting resistor for the connected LEDs when the transistor is switched ON.

Here it has been calculated as 10 Ohms.

As long as the solar panel generates the optimal amount of power, the positive potential at the base of the transistor keeps it switched OFF.

However when dusk sets in the solar voltage begins to drop, and when it drops below the zener diode rating, the transistor slowly starts conducting, illuminating the LEds gradually.

With complete absence of sun light or when its completely dark, the transistor conducts fully with the help of the 1K resistor, and produces full brightness over the LEDs.

The next morning, the cycle repeats all over again.

The circuit can be modified in many different ways.

Circuit Diagram

simple solar LED lamp circuit

The above diagram may also be built in the following manner. It looks more sensible now as the resistor is removed from the emitter for facilitating efficient triggering of the transistor.

PCB Design

solar garden light PCB design

Pictorial Diagram

Parts List

The diagram shows an incorrect transistor number (8050), use 8550 instead.

Recommended Solar Panel Specs

6 to 8V/2 watt

Voltage - 6V

Current - 330 mA

garden light solar panel

Using a 9 V Battery and High Bright White LED

The next shows an elaborate yet simple solar garden light diagram in pictorial form

R2 is the LED current limiting resistor which can be calculated using the following formula:

R2 = Battery Voltage - LED Fwd Voltage / LED Current

R3 is the charging current limiter resistor for the battery, and it can be calculated using the following formula:

R3 = Solar Panel Voltage - Battery Voltage / 10% of Battery mAH Rating

The battery voltage must be at least 3 V higher than LED voltage.

The panel voltage must be at least 3 V higher than the battery voltage.

Using NPN Transistors

The above explained designs can be also replicated using two NPN transistors as shown in the following diagram:

Solar Pathway Light Circuit with Constant Voltage

If a Li-Ion battery is intended to be used for the above explained circuit, a constant voltage feature becomes crucial for safeguarding battery life and prolonging it.

The following circuit show how this may be done by adding a simple voltage follower regulator circuit:

current controlled LED lamp circuit

If a 3.7V Li-Ion battery is used, make sure to adjust the 10K preset to achieve precisely 4V across the output points where the battery is supposed to be connected, do this adjustment without connecting the battery.

The 4V level ensures that the battery is never overcharged (at 4.2V) and this also allows the circuit charge the battery without a constant current supply.

1.5V Solar Garden Light with Enhanced Features

The following solar powered garden light was designed by Mr. Guido which includes additional features such over charge and low charge cut off for the battery and with  a Schmidt trigger.

This ensures that the connected battery is never allowed to charge or discharge beyond unsafe levels.

The main attraction of the circuit is the use of a single rechargeable AAA penlight cell, which is able to light up a 3.3V high bright LED through an attached Joule thief circuit.

solar LED lamp with auto cut off circuit
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About Swagatam

I am an electronic engineer (dipIETE ), hobbyist, inventor, schematic/PCB designer, manufacturer. I am also the founder of the website: https://www.homemade-circuits.com/, where I love sharing my innovative circuit ideas and tutorials.
If you have any circuit related query, you may interact through comments, I'll be most happy to help!

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  1. EN says

    March 4, 2022 at 12:20 pm

    Hi Swagatam.
    There’s a question in your circuit.
    “a simple voltage follower regulator circuit”
    What does 10K preset mean in this circuit?
    Regulator? resistance?
    Additionally, I don’t have 8050 or 2N222. 135D was used. No problem?
    I’ll be waiting for your response. Thank you.

    Reply
    • Swagatam says

      March 4, 2022 at 1:48 pm

      Hi EN, the 10K is a variable resistor preset or a trimpot.

      I could not find the datasheet of 135D transistor, so I am unable to suggest whether it can be used or not.

      Reply
      • EN says

        March 7, 2022 at 2:57 pm

        Thank you for answering.
        It’s BD135 from Onsemiconductor.
        In the above quesiton circuit, do i have to use tow 1N4007? Tow letters were written, so a circuit was created, but the battery does not charge even when exposed to sunlight.

        Reply
        • Swagatam says

          March 7, 2022 at 6:30 pm

          BD135 can be used, You must adjust the 10K preset accurately so that the emitter voltage reaches the full battery charge level across the battery terminals. Measure this without connecting battery. I did not understand what you meant by “tow 1N4007”

          The solar panel current must be correctly rated as per the battery specification, only then the battery will charge.

          Reply
          • EN says

            March 8, 2022 at 6:26 am

            solar panel 6V, 0.35A, Battery 4.2V, 2550mA
            Is there a way to send pictures? Mail or another?
            Thank you

            Reply
            • EN says

              March 8, 2022 at 6:34 am

              Additionally, how do you adjust the 10K preset?
              I want to know the formula

              Reply
              • Swagatam says

                March 8, 2022 at 10:40 am

                You can use voltage divider formula to get the base voltage…

                and then add 0.6 to the result….this will be the emitter voltage.

                Base voltage = Vin (R2 / R1 + R2)
                R1 = 1k or 1000 ohms
                R2 = preset adjustment value
                Vin = 6V

                Emitter voltage = Base voltage + 0.6

                Reply
            • Swagatam says

              March 8, 2022 at 10:33 am

              Did you confirm the 0.35 A and 6 V with meter? Check it with meter it might be less than that. By the way 0.35 amps will not charge a 2550 mAh battery efficiently…it should be minimum 0.5 amps to 1 amp. Pictures are not required, values are enough.

              Reply
              • EN says

                March 8, 2022 at 12:59 pm

                In fact, solar panels are measured lower than 6V.
                I don’t know how to approach it,,, but I should study again while looking at the circuit diagram.
                Thank you.

                Reply
                • Swagatam says

                  March 8, 2022 at 8:32 pm

                  The minimum voltage can be 5V, but the current should be between 500 mA and 1 amp.

                  Reply
                  • EN says

                    March 10, 2022 at 7:17 am

                    When the actual test was conducted, the panel was measured at 4.4V and turned on only 3 hours after charging for 3 hours.
                    I have a question. Why do you use two 1N4007 diodes in the first circuit?
                    Because of the principle of operation of the transistor?
                    I ask questions because I lack a lot of knowledge.

                    Reply
                    • Swagatam says

                      March 10, 2022 at 10:24 am

                      The left side diode is actually not required, it is placed to safeguard the circuit from an accidental reversing of the solar panel polarity. If you are sure you will always connect the panel polarity correctly, then you can remove the left side diode.

                    • EN says

                      March 10, 2022 at 1:18 pm

                      Thank you for your answer.
                      If I have any questions, I’ll ask you more!
                      Have a good day.

                    • Swagatam says

                      March 10, 2022 at 1:19 pm

                      Sure, no problem.

  2. AMIT GARG says

    January 31, 2022 at 3:10 pm

    Would appreciate if you add costing of components used in the circuit.

    Reply
  3. Kris K. says

    November 29, 2021 at 4:12 am

    I tried adapting these ideas to understand how 200 blue LEDs ((3.2V, 20mA each)) can be lit from one single 1.2V NiMH battery slow-charged from a small solar cell, but I remain mystified. It’s not for any class ((I graduated college in 1979, LOL!)) but I’m wondering, because I’d like to repair 2 light strings if that’s possible. I simply haven’t been able to get from here, to there…

    Many thanks in advance for any information or links!

    Reply
    • Swagatam says

      November 29, 2021 at 5:27 pm

      Thank you for your interest in this concept. 200 nos are too many LEDs, and a NiMH might not have sufficient current to handle this. However a Li-ion cell with along with a joule thief circuit might be perhaps able to handle this load

      Reply
      • Kris K. says

        November 30, 2021 at 12:02 am

        Thank you for your reply!
        That must be why the string never worked from the start. Now that I know to not keep struggling to make the original thing work, I’ll start from the ground up so to speak.

        Reply
        • Swagatam says

          November 30, 2021 at 9:50 am

          Sure, no problem!

          Reply
  4. Dennis Eugene Rowe says

    September 27, 2021 at 9:04 pm

    Hi SM. I work for a maritime museum and we have a lighthouse which was fitted with a 120v incandescent lamp. I would like to convert this to a pulsating/breathing LED lamp. I have did some research and came across you forum. Thank you for the diagrams. My question is using a 6v agm battery what size of solar panel would be needed? I have read that to charge a 6v battery you should use a 7-9V solar cell. Also any ideas on the pulsating/blinking/breathing feature to simulate an actual lighthouse?

    Reply
    • Swagatam says

      September 28, 2021 at 9:12 am

      Hi Dennis, for a 6V battery you can try a 9 to 12V solar panel, and use a constant current and constant voltage charger. The current rating of the solar panel can be 7 to 10 times lower than the battery Ah value.

      for the rotating light effect you can probably try the following circuit

      https://www.homemade-circuits.com/police-ambulance-siren-circuit-with-rotating-beacon-light/

      Reply
  5. Eugene says

    September 24, 2021 at 4:32 pm

    hello, I found this site & followed all the steps but the LED lights could not turn off even during the day. what could be the problem

    Reply
    • Swagatam says

      September 24, 2021 at 7:25 pm

      Hello, connect the transistor base with its emitter manually and check if the LEDs shuts off, if not then your transistor is faulty.

      Reply
      • eugy says

        September 25, 2021 at 2:46 pm

        do I basically need to use specifically the transistor indicated on the diagram

        Reply
        • Swagatam says

          September 25, 2021 at 4:03 pm

          It just needs to be a PNP transistor, that’s all

          Reply
  6. Emre says

    September 11, 2021 at 10:46 pm

    In the picture whose Pictorial Diagram is given, how many volts/amperes is the panel and is the battery 9V ni-cd? Can 9V ni-mh or lithium be used instead of 9V ni-cd battery?
    In what range should the mah value of the battery be? thanks

    Reply
    • Swagatam says

      September 12, 2021 at 10:31 am

      I have updated the diagram with more details, and also provided the relevant calculations.
      The battery shown in the diagram is NiCd, Li-Ion or NiMh can be also used. For Li-Ion and NiMh batteries the 10% figure indicated in the R3 formula will change to 50%

      Reply
  7. Emre says

    September 11, 2021 at 5:56 am

    Hey, 7.4Volt 2600mah (2 serial 3.7V li-on batteries), how do I set up a circuit for a battery? Can you help me build the circuit? For example, how many volts should the panel be? can you draw a circuit diagram. Thank you

    Reply
    • Swagatam says

      September 11, 2021 at 10:31 am

      You can use a 12V 1 amp solar panel, and adjust the output voltage using a LM317 circuit to precisely 8.2V and then you can charge your series battery safely.

      Reply
  8. James says

    August 31, 2021 at 7:36 am

    Hello, I’m trying to design a solar dusk to dawn light using a 3.7v 18650 2400mah battery, a single bright white 60-80lumen light with the smallest solar cell that charges on cloudy days. The light must maintain light atleast 10 hrs at night. The led possibly could pulse at 50 cycles as to save on power and not notice blinking by the naked eye. Thank you.

    Reply
    • Swagatam says

      August 31, 2021 at 1:34 pm

      Hello, you can use a 100 mA or 50 mA straw hat type LED, and use with your battery for a 10 hour back up. The solar panel must e rated at 6V, 1 amp. You will need an auto cut off circuit for charging the battery with this solar panel.

      Reply
      • Jamed says

        September 28, 2021 at 5:06 am

        Thank you, would you have an existing circuit diagram?

        Reply
        • Swagatam says

          September 28, 2021 at 10:19 am

          You can try the last circuit from the following article:

          You may replace the P mosfet with a 2N2907 transistor, and replace the 2N6284 transistor with 2N2222

          https://www.homemade-circuits.com/battery-deep-discharge-protection-circuit/

          Reply
  9. Marko says

    August 19, 2021 at 3:01 am

    How can the pcb pictorial be done on a copper clad board? I have only an inkjet printer and want to build this circuit?

    Reply
    • Swagatam says

      August 19, 2021 at 8:25 am

      You can refer to this article for the details:

      How to Make PCB at Home

      Reply
  10. Vj sarkissian says

    June 11, 2021 at 7:02 am

    dear sir; the above constant voltage circuit designed with 6v battery and 6-8v/2w solar panel, 2 transistors and few resisters and load of (24) .5w high power leds is really great. my question is if I increase the load to (44) .5w and select the a/h of battery to 20a/h also double the the amperage of solar panel would circuit work properly? I thank you very much..

    Reply
    • Swagatam says

      June 12, 2021 at 1:03 pm

      Dear Vj, yes you can definitely upgrade the circuit by suitably modifying the parts, and the battery. You will have to use a TIP127 for the transistor, 10k resistor for the base, the charging current limiter must be adjusted to a value which allows only 1 .5 amp to 2 amp current for the battery charging.

      Reply
  11. Cheryll Robinson says

    June 9, 2021 at 8:12 pm

    I’m a 75yo woman and have no electrical background, but am willing to learn new things. I have purchased a commercial solar powered pump package with a fixed solar cell. The pump turns on with a manual pushbutton switch. The small electrical storage battery (12v) does not hold enough electricity to power the pump through the hours after the solar cell loses sunlight until the next day. Once the power supply is exhausted, the pump switches off and remains off until the manual switch is pushed again. It is in a remote area, so the pump might be off for several days until I can get back to switch it on. I am making a solar tracking unit to extend the hours that it is in sunlight, which will hopefully extend the battery service also.

    Here is my question: Is there a way to use a small solar cell to power a switch that will bypass the manual switch and turn the pump back on when the sunlight is available the next day? If one of your examples above will do that, please tell me which one to use.

    Reply
    • Swagatam says

      June 10, 2021 at 10:40 am

      You can build and implement the following concept:

      solar panel activated pump motor

      Please note that the relay of the circuit will activate ON and OFF momentarily only when the sun light has reached a reasonable peak level. If you want the circuit to activate at a lower peak level of the sun light then you can reduce the relay value to 5V, and also replace the 12V zener to a 5V zener.

      Reply
  12. Neill says

    June 9, 2021 at 1:20 pm

    Hello Swagatam,
    Firstly, top notch support for your ccts. You really are very patient with everyone. Can I ask please, I have a very low power 5v solar cell, how much current loss is caused by the simple single transistor circuit? I presume this one would be the least hungry of the ccts. At the moment I use a switch to feed the leds and automated is definitely the way forward.
    Thank you for your time and I hope you have remained healthy through the pandemic.
    Neill

    Reply
    • Swagatam says

      June 9, 2021 at 1:56 pm

      Thank you very much Neil for your kind words!
      No current would be wasted by the transistor circuit, since the transistor circuit would remain switched OFF. However, a slight current would be lost through the base resistor of the transistor, which would be in a couple of mA may be. You can definitely think of replacing the mechanical switch with a transistorized circuit, with minimal current drain.

      Reply
  13. KM says

    February 20, 2021 at 4:34 am

    Figure 1 & 2 I can’t seem to make it work at all, the same is true for the similar circuit using the 2 transistor version, 2222 & 2907, the mail issues is I can make it light with the battery but it will not shut off the led during the day / charging cycle… Checked and double checked… Help…

    Reply
    • Swagatam says

      February 20, 2021 at 9:37 am

      Please check the circuit first with a bench power supply, not with solar panel.
      With the input DC connected check the voltage across base/emitter of the transistor, it must be 0V, and it should be around 0.6V when the input supply is removed!

      With 0V across B/E, the LEDs should be switched OFF, and with 0.6V the LEDs must switch ON

      Reply
  14. NGANG says

    January 24, 2021 at 10:00 am

    Good morning Sir,
    1) What is the advantage of the circuit with the two npn transistor ? Does doubling the transistor increase brightness ?
    2) I want to use 14 LEDs (4mm leds) to run for 12hrs with good brightens, using 3.7v li-ion battery;-
    a) what should be the capacity of the battery?
    b) if I have 2watts 6v solar panels how many can I parallel to charge the battery.?
    c) which circuit can I use for this to serve as an automatic solar outdoor(landscape) security light?
    Thanks

    Reply
    • Swagatam says

      January 25, 2021 at 5:42 pm

      Hi Ngang, slight advantage is there due to better ON/OFF switching of the LEDs, and better transfer of power to the LEDs.

      A 2 watt solar panel will produce 2 / 6 = 0.33 amps or 300 mA current, which means a 4.5 V battery or a 3 V battery can be used having 2 Ah rating

      LEDs can be 3.3 V 1 watt single, or 3.3 V 20 mA up to 10 in parallel.

      Reply
  15. Frank says

    January 22, 2021 at 8:01 pm

    Hello, I have 4 garden lights each one has two 8mm white leds I would like to use only one solar panel,two service all four lamps,but dont know what
    size or wattage or voltage to use.

    I hope you can help…………Frank

    Reply
    • Swagatam says

      January 23, 2021 at 11:06 am

      Hi, assuming your LEDs are 50 mA each, and the two LEDs are in series in each of the modules, then for 4 lights the total current required will be 200 mA. Now to illuminate this 200 mA lamp for 10 hours will require a battery rated at 2 Ah or 2000 mAh.

      Your solar panel must be around 3 amps and voltage equal to 10 V, with a 7V controller

      Reply
      • frank says

        January 23, 2021 at 6:17 pm

        Thank You..

        Frank.

        Reply
  16. Ravi I. KUMAR says

    January 20, 2021 at 5:57 pm

    Hi Namaste Swagatham
    I just beginning to learn and do some hobby during Covid-19. I have solar powered pedestal light on long post. The switch failed due to water leakage. I am trying to replace the switch. But I need to replace the resister to reconnect the wires. I cannot recognise the resister. It is tiny blue resister connected to terminals. This is because the switch has three positions. Semi / Off / Full. The switch has six terminals three on each side.The resister is connected semi and off terminals. Perhaps I I could send photo, but do not know how to include in this comment. Please help. I have also other small hobby projects which I will let you know. Thank you very much. I am from UK, SENIOR CITIZEN. RAVI

    Reply
    • Swagatam says

      January 20, 2021 at 9:30 pm

      Hi Ravi, without seeing the image it can be difficult for me to understand the fault. What you can do is, upload the image on any free image hosting site online, and provide me the link, I will quickly check it out and try to solve it for you….

      Reply
  17. Tony says

    December 12, 2020 at 7:08 am

    Hi Swagatam,
    I have found several of your articles very interesting and delightful. However, I have a project that is VERY unusual and have not been able to find a circuit to solve my problem.
    I am attempting to back light a lithographed photo that is mounted on an outdoor plaque. I want to use a single white LED (or a single 5050 RGB strip light LED) to backlight the lithograph. Normally, I could use a solar powered Garden light circuit, however I need it to stay lit during the daytime AND night time and still charge a battery (1.2V NI-CD) for the nighttime use. I can use 2 solar cells, one for daylight use and the other to charge the battery for nighttime use, However, I am not sure of the best way to isolate the two solar cells so one powers the LED during the day while the other charges the battery and then at night switches to the battery. Any help would be appreciated. I am an electronics tech with some engineering (self taught) background, but this seems to be eluding me for some reason. I hope you can help. Thanks in advance.

    Reply
    • Swagatam says

      December 12, 2020 at 11:30 am

      Thank you Tony, glad you found them interesting!
      I think two alternating cells may not be necessary, instead multiple cells could be attached in parallel which may be rated to keep the LEDs lit up for 24 hours with each charge. Similarly the solar panel may be rated to ensure both the cells are optimally charged each day.

      If you provide me the LED current and voltage specifications I can provide the estimates for the solar panel and charge control specifications
      Alternatively, if you think two alternating cells would be a better choice, I can suggest an appropriate design for that also….

      Reply
  18. Eduardo says

    November 26, 2020 at 8:42 pm

    Thanks for that it’s really worth to query the designer appreciate it very much
    It’s wonderful finding you on Pinterest
    Rgrds,
    Eduardo

    Reply
    • Swagatam says

      November 27, 2020 at 2:25 pm

      It’s my pleasure and happy to help!

      Reply
  19. Eduardo Roxas says

    November 26, 2020 at 3:32 pm

    After reading I’m trying to find that zener diode describe but not available in anypart of the schematic diagram pls give details
    Thank you for sharing

    Reply
    • Swagatam says

      November 26, 2020 at 7:32 pm

      In the second last diagram, the 10k preset was not included in the original initial diagram, instead a zener was put in that area for getting a fixed output at the emitter side. If you don’t want the preset for customized adjustment you can replace it with an appropriately rated zener diode

      Reply
  20. Robert C Gillespie says

    August 16, 2020 at 9:52 pm

    I’m new to this website. It appears to be exactly what I need.
    Home / Mini Projects / Simple Solar Garden Light Circuit – With Automatic Cut Off
    This is a genius little circuit and would be perfect for my Japanese lantern. Is the PCB board available?

    Reply
    • Swagatam says

      August 17, 2020 at 8:42 am

      Hi, Thanks, and Glad you liked this website and the circuit! However, sorry I do not have ready made PCB for this project, but since the design requires very little parts you can easily assemble them over a small veroboard or a strip board.

      Reply
  21. Glynn Trow says

    July 29, 2020 at 1:22 am

    Hi. Found this site about 2 weeks ago and built the circuit. First time I have done anything similar for maybe 50 years!! I was a bit apprehensive. However the circuit works well. I am quite happy with it. One problem the LEDs light up too early. It is still light. I am using 4×1.2v Li-ion batteries. I reduced the 10 ohm resistance to 5 ohms. Is there away to prevent the LEDs lighting up before it gets dark? Thank you for firstly the circuit and secondly the time you spend answering queries

    Reply
    • Swagatam says

      July 29, 2020 at 10:48 am

      That sounds amazing and Glad you could make it successfully. The early switch ON could probably be prevented by upgrading the circuit through a couple of more transistors as shown in the following image:

      solar garden light with complete darkness switch ON

      Reply
  22. Nélio says

    July 25, 2020 at 4:08 pm

    Hi Swag,
    In this circuit, can I replace the 6 LED’s by a single of high Power, say 1W, 3W or 5W?
    If so, which changes can I made?
    Best Regards.
    Nelio.

    Reply
    • Swagatam says

      July 25, 2020 at 5:23 pm

      Hi Nelio, yes that’s possible, the formula for the series resistor is:

      R = (Battery Voltage – LED Fwd voltage) / LED Current

      Reply
      • Nélio says

        July 25, 2020 at 5:37 pm

        Hi,
        You are refering the first circuit.
        I was considering this one :
        Solar Pathway Light Circuit with Constant Voltage
        Nelio

        Reply
        • Swagatam says

          July 25, 2020 at 6:41 pm

          Yes I was referring to the first circuit, in the pathway circuit you may have to connect a resistor in series with the collector of the LED transistor. This resistor should be calculated using the previous formula

          Reply
          • Nélio says

            July 25, 2020 at 7:00 pm

            Ok.
            Thanks.
            Best Regards.
            Nelio

            Reply
            • Swagatam says

              July 25, 2020 at 10:20 pm

              Glad to help!

              Reply
  23. Dimitar says

    April 26, 2020 at 8:48 pm

    https://drive.google.com/drive/folders/1oCAPL9J53O0QZP7SXJnlNtnkq8NQ9QoY?usp=sharing

    I have reverse modeled the board. If you are curious to see it, you can find it here as .jpeg file. Most of the elements I was able to read, but not all.

    Reply
    • Swagatam says

      April 27, 2020 at 1:36 pm

      It is difficult to understand the diagram in this form, please draw it in proper schematic form with correct symbol and pin direction, I will try to figure it out.

      Reply
  24. Dimitar Kirov says

    April 24, 2020 at 6:37 pm

    Hello Swagatan,

    I found your site by accident a week ago and I`m completely hooked up.

    I have an old solar lamp that uses 1.2V Ni-CD battery and 1 piranha LED. It has an LDR to turn it ON/OFF, however I notice that even without it, it turns ON/OFF if the Solar Panel is illuminated.

    Can you reverse engineer this board, if I provide you pictures of it, as I want to make myself more of these DIY. It says 3033 on one of the elements, has SGL0047-3033 printed on it. I could not find anything on the internet about it.

    Thanks for your answer in advance.

    Reply
    • Swagatam says

      April 25, 2020 at 10:50 am

      Thanks Dimitar, I am glad I found my sire useful.

      I think an LDR is not necessary for a solar automatic LED circuit. The first circuit from the above article will also do the same. When sufficient light applied on the solar panel, the LEDs will remain OFF, and they will switch ON when the light becomes weaker.

      Reply
      • Dimitar says

        April 25, 2020 at 12:49 pm

        Thank you for your fast reply, Swagatam.

        Is the first circuit going to work at 1.2V, or must it be 4.5V, 3 NiCD/NiMH batteries in series?

        Reply
        • Swagatam says

          April 25, 2020 at 6:53 pm

          Yes it should be 4.5V. At 1.2 V the LEDs will not light up.

          Reply
          • Dimitar says

            April 26, 2020 at 1:38 am

            I understand.

            The solar lamps I have use 1x 600mAh 1.2V NiCD battery and powers a 1W warm white COB LED. I believe they are rated at 3.2V. It lasts about 5-7 hours, depending on the amount of sun during the day.

            Can you propose a way to achieve this? Do you want me to send pictures of the board? If yes, how?

            Reply
            • Swagatam says

              April 26, 2020 at 11:21 am

              Images won’t be required since it will be difficult to identify the parts and the layout from the images.

              Instead you can try the following version which uses a joule thief circuit for boosting the 1.2 V to 3 V for the LED:

              1.2 V solar charger circuit

              If the LED doesn’t light up with a 1.5 V cell, you can try swapping the terminals of the winding between the transistor base and the 1K resistor.

              Reply
            • Dimitar says

              April 26, 2020 at 4:24 pm

              Thank you for the great advice, Swagatam!

              I found the joule thief circuit on your site, but what was interesting to me is that this solar lamp uses no coil, only a couple of resistors, diodes and transistors.

              Reply
            • Dimitar says

              April 26, 2020 at 5:45 pm

              P.S. My bad, it does have an inductor, it does use a joule thief.

              Reply
              • Swagatam says

                April 26, 2020 at 6:31 pm

                OK, so in that case you can use the diagram which I suggested in my earlier comment. It has a feedback loop which will switch OFF the LED during day and switch ON during night at 1.2 V supply

                Reply
  25. Edward says

    December 5, 2019 at 6:16 am

    Sounds like great systems. I am not however looking to build a system but buy a ready made system for a large garden area where I can plug in various low voltage garden lights or Christmas lights. Any suggestions? Getting tired of the cheap solar lights from the hardware store and too far to run 120V. thanks.

    Reply
    • Swagatam says

      December 5, 2019 at 11:56 am

      Thanks, please provide the LED specifications and the connection details that you wish to use, I’ll try to figure out the required set up accordingly

      Reply
      • Dweep K Baniya says

        March 28, 2020 at 4:46 pm

        I have made 40 W street light solar circuit I m working in offline solar inverter manf company I m not getting desired output 2 V instead of 12V but cut off low & high is working properly.

        Reply
        • Swagatam says

          March 28, 2020 at 8:39 pm

          I could not understand your question.

          Reply
          • Dweep Baniya says

            April 3, 2020 at 8:37 pm

            Sir I have made a circuit with help of your diagram for 40 W solar street light circuit I m able to adjust low & high cut off but sir I m not getting Required output when solar voltage is given I m getting only 1.9 V max

            Reply
            • Swagatam says

              April 3, 2020 at 8:52 pm

              Dweep, please show me your exact schematic so that I can understand it…upload it to any free image hosting site and provide the link here….

              Reply
  26. Hannah B says

    December 4, 2019 at 11:53 am

    Hi Swagatam –

    thank you for all the information here! I’ve made some simple LED circuits before, but I’m new to solar. I am making a night light for indoors – the LED doesn’t need to be very bright, but there won’t be as much sunlight to charge it. Can I increase the size of the solar panel to maximize the charge? Would I need to worry then about overcharging the batteries if the panel got direct sunlight?

    Reply
    • Swagatam says

      December 4, 2019 at 5:12 pm

      Thank you Hannah, yes you can increase the solar panel size for maximizing the output, but stronger sunlight may harm the battery in that case. If you can provide the battery specifications, I can suggest the controller circuit for you.

      Reply
      • Hannah B says

        December 8, 2019 at 9:42 am

        Thank you! I haven’t bought my batteries yet, but I was thinking about using 2 Kentli Li-on rechargeable AAs – – they output 1.5v 2000mA. I have some flexibility in my design so I could use larger batteries, but I’m not powering much – just one standard brightness white LED. I’m mostly interested in longevity – if possible, I’d like to set things up so the light runs for at least 5 hours even if it’s not charged in direct sunlight.

        Reply
        • Swagatam says

          December 8, 2019 at 7:58 pm

          As per the given specs the battery seems to be quite powerful and has a built-in over charge cut off system so it cannot be harmed by the panel anyway.

          You can use a 6V 5 watt panel and connect its output directly to the battery for charging. Since the current is only 5 / 6 = 830 mA and will continue to drop as the sun goes down, the voltage will effectively therefore drop to the desired battery level and keep the battery topped up always.

          Reply
  27. FPoster says

    October 18, 2019 at 7:12 am

    I have a garden PV light PCB but it does not have any visible ICs, transistors, or non-LED diodes unless these components are hiding under a hard circular mound of dried adhesive or maybe heat sink material that is on the side opposite the components. I wish to understand where the conductor tracings connect but this is hidden under the mound. (I would send my photos.) I have minimal circuit analysis skills and hope this simple PCB will be instructive.

    Reply
    • Swagatam says

      October 18, 2019 at 3:46 pm

      You can upload the pics to your google drive and share the link with me here, I’ll try to figure it out

      Reply
  28. Robert Bernal says

    September 3, 2019 at 4:02 am

    Wanted to say thanks! Will an 18v panel be too high of a voltage (at really low current) for the base of the pnp? I assume the higher (than 12.8v battery) voltage is what turns it off during the day.
    Thanks!

    Reply
  29. Robert Bernal says

    September 3, 2019 at 3:06 am

    Hi,
    I’m making a 12.8v battery powered, 4 led (in series) solar light, at about 250 mA (the LEDs require only about 2.8v each and can handle over an amp)
    I just want to know if the transistor can handle 18v or so from the panel (at very small current). I’m not sure how it works. The higher voltage from the panel (which is more than battery voltage) must turn off the transistor at the base?
    Thanks.

    Reply
    • Swagatam says

      September 3, 2019 at 11:38 am

      Hi, yes the 8550 or 2N2907 will easily handle 18V. The transistor will remain switched OFF as long as the base/emitter voltages are at equal levels, meaning the difference is 0V

      Reply
  30. NGANG GODWILL says

    May 30, 2019 at 7:32 am

    Sir,
    I can’t see the updated diagram for lithium ion. is the 10 ohms resistor is eliminated in the lithium ion version?

    Reply
    • Swagatam says

      May 30, 2019 at 9:56 am

      the second last circuit can be used for Li-ion cell. yes the 10 ohm is removed otherwise the Li-ion cell will never get charged.

      Reply
      • Mudita says

        October 31, 2019 at 12:54 pm

        I am looking to make large quantity of reading lights for students in a village. I am thinking of using solar panels station at school to charge the batteries. I plan to use LEDs. I like to have the high school kids build it themselves, with some training. So, I like to find a simple circuitry based design with very few parts. I am an electrical engineer, I will be teaching them how to build them. I also need parts cheap. Any suggestions of where I can find what I am looking for.

        Reply
        • Swagatam says

          October 31, 2019 at 2:53 pm

          Please provide the specifications of all the parameters so that I can suggest a suitable design. Or you can tell me the appox budget for each light, I’ll try to figure it out!

          Reply
      • rudi says

        September 16, 2020 at 10:15 pm

        I have tried your circuit, especially in figure 5, with 24 led a battery capacity of 6 volts 4.5 Ah / 20 hours, there is a problem that I experienced, transistor tip 122, very hot, fortunately I added a cooler, I used 12 volt solar cells, what I ask, could the resistor that is 1k in size be replaced with 10 k of which leads to the bc 547 transistor and tip 122 ?, thanks for the help

        Reply
        • Swagatam says

          September 17, 2020 at 5:37 pm

          yes 1k can be replaced with 10k which will dissipate less current and heat. 10k should work since the TIP is a Darlington BJT with very high gain

          Reply
    • Mario says

      July 6, 2020 at 8:59 pm

      Hi, is there a substitute for tip122 transistor? Thanks for your input

      Reply
      • Swagatam says

        July 7, 2020 at 11:57 am

        There’s no easy substitute for TIP122

        Reply
        • Mario says

          July 7, 2020 at 4:02 pm

          I see, well I tried. Will definitely order me some of those. Can’t wait to fiddle around with these circuits. I have tried many circuits from YouTube videos but for some reason or another the lights turn on at dusk as opposed to dark, therefore draining battery way to early. I noticed on some of your circuits there being 2 IN4007 diodes. Is that accurate? Just wondering. Thanks for all you di, its awesome to see someone take the time to help out us noobs and DIYERS. Have a great one.

          Reply
          • Swagatam says

            July 7, 2020 at 7:06 pm

            The lights won’t turn ON until the solar panel voltage became 1 V or lower, that will happen at extreme dusk, but not at night. For night time switching you may have to use a delay ON timer with the circuit. Two 1N4007 is fine considering the ease of making and the solar panel being 9 V or 12 V plenty of voltage available for the 2 V drop.

            Reply
            • Mario says

              July 7, 2020 at 7:52 pm

              Got it, that explains it and makes perfect sense. The 10k preset resistor you mentioned on the 6v circuit, is that a mini potentiometer?

              Reply
              • Swagatam says

                July 7, 2020 at 8:40 pm

                That’s a preset, not a potentiometer, it is intended for a one time voltage setting.

                Reply
        • Mario says

          July 25, 2020 at 11:57 pm

          Hey, hope all is well and safe with you and yours. Just wanted to mention that I received the tip122 transistor and got busy putting that circuit together. The issue I have encountered is that the light doesn’t remain on, it turns off then when battery gets taken out and put back in it doesn’t remain on just a flicker. The solar end of it works. It does what its supposed to. What am I doing wrong. Oh, and by the way I’m using a string of-4.. 1w cob led lights in parallel and using an 8 volt battery.

          Reply
          • Swagatam says

            July 26, 2020 at 11:02 am

            Hey, please remove the solar panel and then check the response. Make sure the battery is optimally charged for the LED. If still it flickers then your transistor may be faulty, or there may be a loose connection somewhere, or the battery may be low.

            Reply
            • Mario says

              July 28, 2020 at 4:05 am

              What I encountered was when the i completly darken the panel the light simply turns on then off leaving 1.5 volts output. But if I slowly turn panel over and leave it half way light remains on and getting 3.7v output and the lights remain on and glowing nice and bright. Any suggestions. Thanks

              Reply
              • Swagatam says

                July 28, 2020 at 1:40 pm

                Please remove the solar panel completely and then check the LED response. If the LED flickers then certainly there may some problem with either the diodes or the transistor, or the resistor or the battery. If not, then you can replace the solar panel with an ordinary power supply and check again.

                Reply
            • Mario says

              August 4, 2020 at 7:13 pm

              Swag, sorry for not replying sooner. The 6v multiple schematic is working perfect now. My question is about the one with the 10k preset. Is this the correct one?
              https://drive.google.com/file/d/1bRO_ebrUBzruoMYWI98CEK4SO3ml1O5B/view?usp=drivesdk

              I am only getting 2.5v on the out for the led lights and the solar part is not working properly. I’ve checked connections over and over and still not solved it.

              Reply
              • Swagatam says

                August 4, 2020 at 9:24 pm

                Thanks Mario, which 6 V multiple schematic are you referring to? Did to check the output by removing the solar panel entirely? If it is not working after removing the solar panel, change the transistor and check again?

                Reply
              • Swagatam says

                August 4, 2020 at 9:26 pm

                …yes the preset is OK…still for confirming you can check the resistance across the pair of pins which are arranged on one end of the preset, opposite to the single pin on the other end.

                Reply
            • Mario says

              August 4, 2020 at 10:55 pm

              There was no reply option on your last post. So I’m using old cmment. Anyway, this is the schematic I’m referring to; https://drive.google.com/file/d/1bhto9JCa2C1U4eUBw-aZwhkNlDBJbpNm/view?usp=drivesdk

              Does the preset adjust the voltage coming in the solar panel by the way? Not sure why I’m only getting 2.5v coming from light output. I’m using a 7.4 2s2p 18650 with BMS. For this project.

              Reply
              • Swagatam says

                August 5, 2020 at 10:26 am

                Mario, Yes the preset is used for adjusting the voltage to the garden light circuit. The voltage must be higher than the battery voltage. You must disconnect the base of the PNP transistor and then adjust the preset to get the required charging voltage across the 1 K resistor. Once this is set you can join the PNP base with the 1K.

                And remove the BMS and connect a separate battery while testing.
                If you are geting 2.5 V then definitely there’s something wrong with your panel or the NPN circuit, or may be you are not following the instructions properly which i am suggesting here.

                Reply
  31. NGANG GODWILL says

    May 30, 2019 at 7:27 am

    Greetings Sir;
    Thanks very much for this article. I have tested it and works great.
    The problem I am facing is, even after charging the whole day, it runs down before morning. (8 hours only).
    I am using:
    1) 7Volt, 2.5wat, 0.35A solar panel,
    2) 3.7 Volt, 2600mA, 18650 Li-on battery (1 nos)
    my multi-meter reads 80mA and 3.08Volt when circuit is in operation
    Thanks

    Reply
    • Swagatam says

      May 30, 2019 at 9:55 am

      Thanks Ngang, glad to know it’s working! The 0.35A seems quite less for a 2600mA cell to charge effectively. It should be at least 1 amp at 4.2V for the cell to charge in 3 hours.

      But at 0.35 A also the cell should charge fully but it may take around 6 hours for this.

      Are you sure your 3.7V cell is getting 0.35 amps? Connect an ammeter in series with the solar panel positive to check this, I doubt the panel might not be supplying this much current at 5V.

      The best way to confirm this is by testing the panel’s short circuit current by connecting a 10 amp ammeter directly across the solar panel terminals at peak sunshine…the result will give you the data regarding the panel’s max current output

      Reply
  32. Nelio Abreu says

    January 27, 2019 at 12:15 am

    Hi Swag,
    If I use 3 batteries in parallel how many LED’s can I use?
    Best Regards
    Nélio

    Reply
    • Swag says

      January 27, 2019 at 9:11 am

      Hi Nelio it will depend on the battery Ah rating and the LED current rating. Typically the total LED watt should not exceed 50% of the Ah rating of the cell, for a Li-ion cell.

      Reply
      • Nélio Abreu says

        January 27, 2019 at 3:18 pm

        Hi Swag,
        I have 3 4.5V 1AH SLA batteries, connected in parallel which will give 4.5V 3AH total.
        Best Regards.

        Nélio Abreu

        Reply
        • Swag says

          January 27, 2019 at 5:09 pm

          Hi Nelio, since it’s an SLA battery, the load should not be more than 1 amp, therefore you can use any LEDs whose total wattage may not exceed 1 amp, and for this the transistor will need to be at least 2 amp rated… a BD140 on heatsink will do

          Reply
  33. Sparjan says

    April 30, 2018 at 3:21 pm

    Sir I not understand 8050transistor.pls explain 8050 and how its use in this ckt

    Reply
    • Swag says

      April 30, 2018 at 5:21 pm

      Please check any online datasheet of 8050 transistor for the pinouts and other details, you can also use 2N2222 instead of 8050

      Reply
  34. Vishwa mukh says

    January 31, 2018 at 6:21 pm

    Sir,
    Thanks a lot for your prompt help.

    Thanking you for your time,

    Reply
    • Swag says

      January 31, 2018 at 7:47 pm

      you are welcome!!

      Reply
  35. Vishwa Mukh Bharadwaj says

    January 31, 2018 at 2:33 pm

    Sir,

    I have compiled the part list. May I request you to please confirm if any changes are required:

    1. Solar Panel = 2V 380mA

    2. R1 = 5K

    3. T1 = BC547C

    4. R2 = 100 Ohm

    5. T3 = BC558B

    6. R3 = 1.5K

    7. T2 = BC547C

    8. R4 = 20K

    9. P1 = 20K

    10. 1.2V rechargeable cell

    11. R5 = 10K

    12. R6 = 13.2K

    13. R7 = 100k

    14. R8 = 10K

    15. T4 = BC547B

    16. R9 = 200 Ohm

    17. R10 = 10K

    18. T5 = BC547C

    19. R11 = 1K

    20. T6 = 2N3904

    21. R12 = 10K

    22. T7 = BC547C

    23. TR2 = 40

    24. R13 = 200 Ohm

    25. T8 = BC547C

    26. Cluster of 9 white lights in series.

    Can you please tell more about component at serial number 23. TR2 = 40?

    Thanking you for your time,

    Reply
    • Swag says

      January 31, 2018 at 5:09 pm

      Vishwa, it looks OK to me.

      TR2 is the boost coil. 40 is the number of turns for both primary and secondary using any super enameled copper wire which fits inside a torroid ring. For more on this you can refer to the following two articles:

      https://www.homemade-circuits.com/8x-overunity-circuit-using-joule-thief/

      https://www.homemade-circuits.com/1-watt-led-driver-using-joule-thief/

      Reply
  36. Ananta says

    December 25, 2017 at 9:15 pm

    Sir,
    I have a 3w ,6v solar panel.the maximum current = .34a as per the maufraturer & 6v/4.5ah SMF battery. I am new in electronics.pls suggest that can I go with the PCB which had provide you above without any changes.if need,what would be done.

    Reply
    • Swag says

      December 26, 2017 at 6:36 am

      Ananta, your panel and battery are OK and can be used for the mentioned circuit, but I cannot guarantee the PCB layout because it was designed by somebody else…so please verify it by comparing it with the schematic

      Reply
    • Ananta says

      January 9, 2018 at 4:52 am

      Sir
      How much led (8mm straw head
      .5w 20ma) can be used for 12 hour

      Reply
      • Swag says

        January 9, 2018 at 9:43 am

        If the battery is 1 AH rated, you can use 5 LEDs in parallel, and illuminate for 10 hours approximately.

        Reply
    • Bikash says

      January 11, 2018 at 3:55 pm

      I have 6v 3watt solara panel,6v 4AH battery,5nos 8mm straw hat led fwd voLt 3.2 to 3.4 & 150 amp.
      Please suggest for the both resistance value/ cicuit

      Reply
      • Swag says

        January 12, 2018 at 9:00 am

        your solar panel voltage should be at least 8V to 9V otherwise the 6V battery will never get charged.

        resistor value can be a 4 ohm / 2 watt

        Reply
  37. abba says

    December 10, 2017 at 12:44 am

    I want to ask again
    1. do we have to worry about over-charge when using lithium battery even-though we provided voltage regulation?

    Reply
    • Swag says

      December 10, 2017 at 10:48 am

      yes you have to worry about over charging if the output is set at the maximum charge level of the battery….if it is fixed at slightly lower than the full charge level then you can keep it connected forever, without worrying.

      Reply
  38. abba says

    December 10, 2017 at 12:35 am

    thanks a lot in advance.
    Hi swagatam I have a couple of questions
    1. do we have to care about overvoltage or current protection when using lead-acid battery ?
    2. when the battery got full during the day time, wouldn’t it affect the battery’s health and life-span due to absence of auto-cutoff feature?

    Reply
    • Swag says

      December 10, 2017 at 10:52 am

      Hi Abba, you must care about the over charging factor for all batteries and you must not keep it connected permanently with the source. In the above design we are assuming that the battery will not charge fully during the course of the entire day or rather we have to select the parameters in such a way that the battery is able to charge only upto 60 to 70% maximum during the daytime.

      Reply
  39. Mick Oude Engberink says

    August 18, 2017 at 10:46 pm

    Does a 1 Ah battery mean that the battery will provide a current of 1A over the time span of 1 hour?
    One of your earlier replies:
    1watt LED x 12 hours = 12 watt hours will be the led consumption

    12watt hours / 12V batt = 1ah battery will be sufficient, so 5ah is more than enough.

    Here you say that for 12watt hours you will only need a 1Ah battery. I'm a noob so correct me if I'm wrong but doesn't this mean the battery will give an amount of 1/12=0,83A for 12 hours?

    Reply
    • Swagatam says

      August 20, 2017 at 7:02 am

      yes that’s right, but in the most ideal conditions.

      I meant to say 1ah is correct as per the calculations, and 5 AH battery will be sufficient, practically 1 ah will not be good, although technically it may look OK

      Reply
  40. Bryan Freed says

    July 18, 2017 at 5:35 pm

    Verified Build, "Solar Garden Light Circuit with Constant Voltage". Work Great, Thank You!

    If I'm using a LI-ion battery do I need to worry about a low voltage cut off?

    Reply
    • Swagatam says

      July 19, 2017 at 2:03 am

      I am glad you could make it successfully.

      yes you will have to worry about the over discharge,in that case you can build the following concept, with the above.

      https://www.homemade-circuits.com/2016/05/solar-charger-circuit-using-transistors.html

      Reply
  41. maulik says

    July 9, 2017 at 4:51 am

    Hello Sir,

    Please suggest me the complete circuit diagram of automatic garden solar led light for:

    * Super Bright 8mm Straw Hat 0.5W/3.2V-3.6V (100-120mA) X 2 Nos.
    * Lithium Battery 18650. : 3.7V/2600 mah
    * SOLAR PANEL Cell: 5V/ 500mW

    Thanks,

    Reply
    • Swagatam says

      July 10, 2017 at 2:48 am

      Hi Maulik,

      I'll update the circuit in the above article soon….

      Reply
    • Swagatam says

      July 10, 2017 at 3:21 am

      Please see the updated diagram at the bottom of the article, you can use the concept for your application…

      Reply
  42. IT Computer says

    May 17, 2017 at 3:59 pm

    dear i want make 20w LED with solar can you please describe me which circuit and parts i use

    Reply
    • Swagatam says

      May 19, 2017 at 3:49 am

      please provide the voltage or the current specs of the LED, or both….

      Reply
  43. Albert Kravcov says

    April 13, 2017 at 10:02 am

    Could you please tell me how can I modify your circuit for my application? > wd-design.de/schaltung.png

    Reply
    • Swagatam says

      April 14, 2017 at 2:38 am

      In my circuit remove the 10 ohm.
      replace the battery points with your PCB's input (+)(-) points.

      replace the LED points with your Arduino input supply points.

      Reply
  44. Ashok Dhenge says

    January 21, 2017 at 6:08 pm

    Sir I assembled this circuit. But I assembled 3lights, providing 6volt 4.5ah battery at one place and connecting all light by cable approx 3meter distance. I used 3 no 8mm hat straw for one lights. My question is when I checked voltage at end off cable shows 3.2volt I don't get this reason. How to solve this? Because of voltage drop light illuminates very low.

    Reply
    • Swagatam says

      January 22, 2017 at 4:42 am

      Ashok, please check the voltage across the collector/ground of the circuit without the LEDs connected, if you see correct battery voltage here, then the problem could be with the current consumption of the LeDs that may be causing the drop in voltage.

      Reply
    • Swagatam says

      January 22, 2017 at 4:43 am

      …the wire resistance can also be the reason for the issue…

      Reply
  45. Navaneeth Nr says

    January 6, 2017 at 5:53 am

    Hi, Happy to see my garden light working!! Thanks a lot for the circuit.
    one query ,what is the use of LHS diode connected directly to solar? Can the circuit function efficiently without it? Since my solar panel is only 5.5V ,battery charging is seeing 2 diode voltage drop 0.7+0.7=1.4v. Is there any modification I can do?

    Reply
    • Swagatam says

      January 6, 2017 at 11:11 am

      I am glad too it's working for you!! you are welcome!!

      the LHS diode is only to protect the circuit from accidental reversal of polarity, meaning if by mistake the solar panel is connected oppositely.

      yes if you are sure you won't make the above mistake then you can definitely remove that diode…

      Reply
    • Swagatam says

      May 26, 2017 at 11:31 am

      Navaneeth, TIP127 can handle upto 5 amps, so you can easily use it for your panned application, but make sure to put a large heatsing with it…

      Reply
  46. Bruno Viegas says

    November 2, 2016 at 11:37 pm

    Hi, I have to do a similar project you make here, but I only have a 6v 140mah 0.6W solar panel, and absolutely no knowledge about how to choose components. Can you please help me out in order to make this work out with the panel I have if it's possible? Thanks in advance.

    Reply
    • Swagatam says

      November 3, 2016 at 9:10 am

      Hi, you can try the second circuit from the above article with your panel, it will definitely work.

      Reply
    • Bruno Viegas says

      November 3, 2016 at 8:55 pm

      Sorry to bother again, but I showed the system to my teacher and He said that a on-off switch will suffice instead of the automatic day-night switch, can you modify this system for me with that in mind? The solar panel is still the same I said in the first comment.
      As for the battery, I didn't find the one in your system to sell here. Do you have any suggestions for a more commom type?
      Many thanks.

      Reply
    • Swagatam says

      November 4, 2016 at 6:36 am

      In the second circuit, remove the right side diode, remove the transistor, remove the 1k resistor….now connect the switch terminals in series with the line which was going through the transistor to the positive.

      that's all

      the battery can be any battery whose voltage may be a few volts lower than the peak level of the panel…and the AH rating could be 3 or 4 times higher than the amp spec of the panel.

      Reply
  47. sunilsuth says

    October 19, 2016 at 5:04 pm

    In this circuit the led starts glowing as soon as the SP voltage drops below 4.3v ,can u modify this and make the led glow when SP VOLTAGE drops below 3v or near to that

    Reply
    • Swagatam says

      October 20, 2016 at 2:27 am

      you can add the following circuit with the panel for acquiring the mentioned feature

      https://www.homemade-circuits.com/2013/05/low-battery-indicator-circuit-using-two.html

      Reply
  48. Tuan Sathiyan says

    July 21, 2016 at 3:51 pm

    Thank you Sir.

    Reply
  49. chandraworld says

    July 17, 2016 at 1:22 pm

    Thank-you,ihave tried 8550 and it works well.but led burns before it becomes dark.kindly suggest changes to be made.

    Reply
    • Swagatam says

      July 17, 2016 at 3:17 pm

      If you have used the series resistor correctly then the LED will never burn, please make sure you have connected a correctly calculated resistor.

      Reply
  50. Swagatam says

    July 15, 2016 at 2:46 am

    BC547 will not work, it should be a PNP and rated to handle 1 amp for the power LED, you can try 8550 or 2N2907 transistor with an identical set up as given above
    you will also need a battery, preferably a 3.7 Li-ion

    Reply
  51. Navaneeth Nr says

    June 22, 2016 at 8:32 am

    Many Thanks. I agree. These type of special ICs also runs at particular frequency ( Even though the Leds blink , our eyes can't detect) there by reducing battery consumption. Can you help me in incorporating the circuit?

    Reply
    • Swagatam says

      June 23, 2016 at 2:53 am

      Thanks, the frequency is used as a part of their buck or boost converter circuit which efficiently reduce or increase the voltage to the LED as per the LED specification….that's the only purpose of the involved frequency.

      A LED will always require a constant DC with the correct V and I specs for illuminating at the optimal level…if its applied with a pulsed DC then its light will also dim or reduce proportionately

      Reply
  52. Navaneeth Nr says

    June 21, 2016 at 4:40 pm

    Could you please try designing more efficient circuit like one using qx5252 (solar driver) , where it can light longer and has battery protection form discharge and overcharge?

    Reply
    • Swagatam says

      June 22, 2016 at 4:39 am

      I already have many efficient and easy to build battery charger circuits posted in this site…you can find them under the "battery charger" category. I normally avoid using special ICs because they are mostly not available in all places and tend to get obsolete overtime.

      Reply
  53. Swagatam says

    June 20, 2016 at 1:59 am

    no changes are required…

    Reply
  54. Swagatam says

    June 19, 2016 at 12:01 pm

    you can use any other differently rated battery also, just make sure the panel and the LEDs are also appropriately matched with the battery specs

    Reply
  55. Swagatam says

    June 12, 2016 at 12:02 pm

    sure you can try it out. there is no overcharge feature in this design for the sake of simplicity…
    this is a cheap circuit so a charge controller cannot be expected for this design, although one can include it if it's felt important by the user.

    here the charging current of the panel is matched with the batt specs such that it charges the batt to around 70% until it's dark…with this consideration the charger controller is eliminated for this design

    Reply
  56. Swagatam says

    June 10, 2016 at 3:34 pm

    the indicated resistor actually acts as a limiter for the battery, not for the LEDs, because LEDs are assumed to be having the forward voltage fixed in accordance with the battery voltage so no resistor would be required for the LEDs essentially.

    But if the LED series FWD voltage is not calculated as per the battery voltage then the strings might require their own calculated limiting resistors

    Reply
  57. Swagatam says

    June 10, 2016 at 7:05 am

    correction:

    the formula should be as given under:

    R = V/I

    Reply
  58. Swagatam says

    June 10, 2016 at 7:03 am

    Hi, you can use the above circuit for your specific application without changing much….except the transistor which could be replaced with a TIP127…the resistor won't be critical with this transistor and anything between 1K and 22K would work satisfactorily.

    you can use any battery as long as its voltage is compatible with the LED string voltage…nothing will need to be changed in the design….however the 10 ohm current limiter might require a recalculation for a given battery.

    the following formula could be used for it

    V = I/R where V is the supply voltage and I is specified safe charging current rate of the battery

    Reply
  59. Unknown says

    June 7, 2016 at 4:48 am

    Hi Sir,
    Thank you for sharing this circuit?

    I have two questions
    1) is it okay to continuously charge a battery. Normally for 12v batteries we have a charge controller. I didn't find too many for batteries below 12v. Why is that ?
    2) is it possible to add a charging led indicator ?

    Reply
    • Swagatam says

      June 7, 2016 at 2:55 pm

      Hi,

      this is a cheap circuit so a charge controller cannot be expected for this design, although one can include it if it's felt important by the user.

      here the charging current of the panel is matched with the batt specs such that it charges the batt to around 70% until it's dark…with this consideration the charger controller is eliminated for this design

      Reply
  60. Rajkumar v says

    May 24, 2016 at 6:34 am

    Sir good day to you
    May I use BD140 transister. What can I do to change this circuit ? My requirement one 3w led and battery type 6v4.5 amp
    Thank you sir

    Reply
    • Swagatam says

      May 25, 2016 at 2:52 am

      Hi Rajkumar, what is the voltage rating of the 3 watt LED?

      BD140 might not work, use a TIP127 instead

      Reply
  61. satheesh k Nalluswamy says

    May 19, 2016 at 12:57 pm

    Dear sir,
    Good day to you May I use 4.5v 2A battery and 8 smd 5050 led (150ma) . what will be changes for this circuit .

    Reply
    • Swagatam says

      May 20, 2016 at 1:27 pm

      Dear Satheesh,

      4.5V 2ah will not be able to support 8nos of 150mA LEDs for too long.

      8 LEDs in parallel will consume 1.2 amps, which will drain the batt within 1 hour

      Reply
  62. Swagatam says

    May 17, 2016 at 3:48 am

    yes it will be harmful for the battery to use a higher rated panel….you can put a 7806 IC after the panel supply t0 drop the supply to 6V for the circuit and the battery

    Reply
  63. walker01 says

    May 16, 2016 at 8:35 pm

    Does it matter how high the solar panel voltage is for recharging the batteries? Will using a 12v solar panel damage the batteries when charging them if the batteries only output at like 5v?

    Thanks! awesome post

    Reply
  64. john kg says

    May 9, 2016 at 4:58 am

    good day sir
    i made the solar garden lamp and it working well i just want to know how can i increase the sensitivity of the circuit so it will light up when sunlight really fade out
    and i am using 3.7v li ion battery any problem realted to over charging since there is any control circuit
    thanks
    john

    Reply
    • Swagatam says

      May 9, 2016 at 11:37 am

      Hi John, you mean you want the LEDs to illuminate when it is almost dark? to implement that you may have to add another transistor stage with the above shown design.

      to avoid over charging we can dimension the 10 ohm resistor value such that it charges the battery almost fully by the time the sun is about to set….

      Reply
      • john kg says

        May 9, 2016 at 1:59 pm

        thankyou sir for the promt reply
        can u help what vaule of resistor to put ( i am using 8v 200 mill amp solar panel and 4x 3.7v (18650)
        in paralle)

        john

        Reply
        • Swagatam says

          May 9, 2016 at 2:47 pm

          what is the mAH rating of the cells together or for each?

          anyhow it seems the 200mA from the panel could be quite low for those cells, and no resistance should be used in order to allow some charging of the cells throughout the day….but a resistor should be included with the LEDs for safeguarding them, as per their rating

          Reply
  65. John Merten says

    March 11, 2016 at 2:32 pm

    Ahhh ok. Light bulb just came on. thank you.

    Reply
  66. Swagatam says

    March 11, 2016 at 7:58 am

    It's for biasing the transistor…so that the transistor is able to sense the voltage level from the panel and switch the LEDs ON or OFF?

    Reply
  67. John Merten says

    March 11, 2016 at 4:56 am

    Hello. I hope I'm not to late for this question period. I am a total newbie but non the less find this fascinating and confusing. What is the purpose of connecting the line with the 1K resistor from negative to the positive in the first place?? even if "It would hardly dissipate anything" How can that help anything?

    Reply
  68. Pavel Dikov says

    March 9, 2016 at 8:41 pm

    Hi, how can I modify this circuit with a timer so that the light turns on for about 3-6 hours after dusk? thanks

    Reply
    • Swagatam says

      March 10, 2016 at 11:16 am

      you can use the same configuration that's shown above with the following modifications.

      use a 4060 based timer circuit.

      remove everything from the existing base of the 8550 and connect the base of the 8550 transistor via a 1K resistor to pin3 of the IC.

      connect pin12 of the IC to ground via a 1M resistor, and connect a link from positive of the panel to pin12 of the IC.
      set the R/C values of the 4060 to get 4 hours delay.
      also connect a 1N4148 diode from pin3 to pin11..cathode to pin11

      that's all

      Reply
    • Pavel Dikov says

      March 10, 2016 at 11:57 pm

      Can you also explain the exact flow of the current from the battery to the LED's, because I'm confused where the current goes after it passes through the LED's. Does it go through the transistor and back to the battery? If not, than what is the purpose of the transistor? Thank you.

      Reply
    • Swagatam says

      March 11, 2016 at 5:04 am

      current from battery (+) enters the emitter of the transistor, comes out of the collector, enters the LEDs and returns back to the battery (-)

      Reply
  69. Unknown says

    March 9, 2016 at 8:38 pm

    Hi, how can I modify this circuit so that the light turns on at dusk for about 3-6 hours? and where would I place the timer? thanks

    Reply
  70. Maruti patil says

    January 31, 2016 at 3:04 pm

    Sir, This is exactly what I need except that I need to use a 15 watt 17 volt solar panel with an output of .89 amp. What components do I need to replace in order to run this solar panel? I'll be charging 2 or 3 18650 batteries in parallel with a 2500mah capacity each. thank you in advance.

    Reply
    • Swagatam says

      February 1, 2016 at 4:16 am

      Maruti, for charging the mentioned cells you will need to eliminate the 10 ohm resistor and short it with a wire link.

      make sure you connect the cells in series and not in parallel, since each cell is rated at 3.7V so 3 in series would require 12V to charge them fully and the 17V panel would work good since it's quite low in current compared to the required 2.5AH rating of the battery.

      the transistor and the 1K resistor are related to the load not with battery charging…so will depend on the load specs,

      Reply
    • Maruti patil says

      February 4, 2016 at 5:21 pm

      Can you share the diagram

      Reply
  71. Unknown says

    December 6, 2015 at 5:02 pm

    Hello Swagatam
    Your site is of great help.
    I have a query in above circuit.
    What is purpose of 10Ohm,1/4W resistor? How does it act as current limiting resistor?
    My understanding was resistor was added for voltage drop in battery voltage of 4.5V to LED spec voltage.

    Can you provide the voltage/current/power of LED used?

    Reply
    • Swagatam says

      December 7, 2015 at 6:19 am

      thanks unknown,

      the 10 ohm resistor is for providing some sort of current limiting to the attached battery while the solar voltage is available, and it also acts like a current limiter for the LEDs while the solar panel voltage is absent and the LEds switched ON.

      Reply
    • Swagatam says

      December 7, 2015 at 6:20 am

      the LEDs can be 5mm/ 20mA type white LeDs

      Reply
    • Kancharla Nishanth says

      December 7, 2015 at 2:18 pm

      Hello Swagatam,
      Thanks for reply.
      I am planning to use single 1 Watt LED (3.2 V, 350mA), so what should be resistance value and wattage of resistor?
      Can i use 3.6V, 1000maH battery?

      Reply
    • Swagatam says

      December 8, 2015 at 11:02 am

      Hello Nishanth,

      3.6V/1000mAh will get drained very soon with a 1 watt LED, it should be at least a 2AH battery.

      you can use a 2.5 ohm, 1/2 watt resistor

      Reply
    • Kancharla Nishanth says

      December 8, 2015 at 2:59 pm

      Hello Swagatam
      Can you explain me on how you came up with 2.5 ohm, 1/2 watt resistor?

      Reply
    • Swagatam says

      December 9, 2015 at 5:52 am

      hello Kancharla, it's calculated in this way:

      R = 4 – 3.3 / 0.3 = 2.33 ohms

      4 is the batt voltage, 3.3V is LED fwd V, 0.3 is the LED current

      watt = 4 – 3.3 x 0.3 = 0.7 x 0.3 = 0.2 watts,

      1/2 watt is selected for more safety

      Reply
  72. Swagatam says

    November 23, 2015 at 4:54 am

    .

    Reply
  73. John Dougherty says

    November 22, 2015 at 4:20 pm

    Ahh thank you I though it was a pnp transistor. But since it's not is there a way to know just by the label number if it is?

    Reply
    • Swagatam says

      November 23, 2015 at 4:56 am

      The label will not inform regarding its polarity, you may have to refer to its datasheet online to learn the details….

      Reply
  74. John Dougherty says

    November 21, 2015 at 6:34 pm

    I should also be able to include a picture if you think that would be helpful

    Reply
  75. John Dougherty says

    November 21, 2015 at 6:32 pm

    Hello, I liked your schematic because it appeared to be very straight forward, however when i went to make it for myself the LED lit up but would not turn off when light was exposed to the solar panel. when looking for transistors i could not find the exact transistor you call for but i did get a 2n2923 transistor i thought would work. since this is the only active component I'm not sure if the problem could be there or somewhere else. since we are using a battery pack for 8 double A's that should cause it to act as a 12v battery we are using a 750 resistor along with the 1K resistor. currently there is only one LED connected and I believe everything else follows the schematic exactly. Any ideas or suggestion what could be causing this problem would be greatly appreciated.

    Reply
    • Swagatam says

      November 22, 2015 at 4:03 pm

      Hello, 2N2923 is an NPN transistor, so it will simply not work, it has to be a PNP, or may be you can use two 2N2923 for getting the same results.

      Reply
  76. Vikirthi......... says

    September 21, 2015 at 8:12 am

    Hi, Can you provide a solar lamp with LDR circuit details ?, Something similar to A LTTER OF LIGHT Program.

    Reply
    • Swagatam says

      September 23, 2015 at 2:44 am

      LDR won't be required, the solar panel will itself work like a light sensor…… the concept explained in the above article is a good example

      Reply
    • Kancharla Nishanth says

      December 8, 2015 at 3:12 am

      But on cloudy day without sun light, LED will start glowing as current is zero from panel. But we may not need LED light as it is day. Will LDR help here?

      Reply
    • Swagatam says

      December 8, 2015 at 11:22 am

      Yes, it will start glowing at a proportionately dim level depending on how much overcast it may be…LDR will not help…. you will need a relay changeover instead of a battery changeover, as shown in the following circuit:

      https://www.homemade-circuits.com/2015/03/solar-led-lights-with-charger.html

      Reply
  77. Lorenzo Chow says

    August 5, 2015 at 2:35 am

    Sir, This is exactly what I need except that I need to use a 15 watt 17 volt solar panel with an output of .89 amp. What components do I need to replace in order to run this solar panel? I'll be charging 2 or 3 18650 batteries in parallel with a 2500mah capacity each. thank you in advance.

    Reply
    • Swagatam says

      August 5, 2015 at 12:29 pm

      Lorenzo, you'll need to change the transistor with a BD140, and reduce the 1K resistor value to may be 220 ohms 1 watt

      also you'll need to connect the 3.7V batts in series for making its voltage compatible with the panel output…. for more safety you can think of using a LM338 variable regulator IC at the input…..

      Reply
  78. Basavaraj Bijjal says

    February 19, 2015 at 11:50 am

    Sir
    I want one circuit diagram.and I want automatically ON & OFF the street lights by using L.D.R's and lanp which is connected to solar energy

    Reply
    • Swagatam says

      February 20, 2015 at 3:55 am

      Basavraj, you can try the following design:

      https://www.homemade-circuits.com/2012/10/automatic-40-watt-led-solar-street.html

      Reply
  79. Jit Lee says

    July 31, 2014 at 4:12 pm

    Sir, is it ok if I use 6V battery?

    Reply
    • Swagatam says

      August 2, 2014 at 4:15 am

      yes it's OK

      Reply
  80. Shiraz rizvi says

    April 17, 2014 at 9:35 pm

    Ye jo aap ne 4.5 1h ki battery use ki diagram me ager ye bttery ki jagha 12v26ah ki battery lagau to transistor kitne no ka use karu ?

    Reply
    • Swagatam says

      April 18, 2014 at 9:51 am

      use TIP127

      Reply
  81. Swagatam says

    December 31, 2013 at 9:33 am

    refer to the formula given at the bottom of the following article for calculating the resistance value:

    https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

    Reply
  82. Swagatam says

    December 31, 2013 at 9:30 am

    Here are the calculations:

    1watt LED x 12 hours = 12 watt hours will be the led consumption

    12watt hours / 12V batt = 1ah battery will be sufficient, so 5ah is more than enough.

    12/5 hours sunlight = 2.5 watt solar panel will do

    2.5/battery V = 2.5/12 = 0.208amp solar panel will be required

    the above calculations was done as per the following article:

    https://www.homemade-circuits.com/2013/05/how-to-calculate-and-match-solar-panel.html

    Reply
  83. Swagatam says

    December 30, 2013 at 3:10 pm

    An 18V, 1 amp solar panel would be OK, if only battery is charged, if LEds are also simultaneously used then you would require a 3 amp solar panel.

    the backup time will entirely depend on the battery AH and the led current, led current should be approx 1/10th of battery AH for 9hrs operation.

    Reply
  84. Monica says

    December 30, 2013 at 4:27 pm

    Thanks for the reply sir.,actually LEDs will not be used simultaneously,I want that the battery gets charged during day time and used at night. Whether a 12V(5AH) battery is sufficient or not? Also,what should be the 'Wattage' rating of the solar panel?These power LEDs are connected in series and as far as I know the 1 watt i.e. power LED requires 350 ma current.What is the value of resistance that is needed to be connected for this 5 Watt LED circuit?
    Thanks..

    Reply
  85. Monica says

    December 30, 2013 at 9:19 am

    What should be the specification of solar panel if we want to charge a 12V battery (5Ah or 2.5 Ah) for using 4-5 power LEDs ? What changes are to be made in the above circuit so that LEDs can glow for atleast 8-9 hours?
    Thanks.

    Reply
  86. azra says

    December 6, 2013 at 4:17 am

    hi, i used 4.5 v solar panel, and i used 3,7 A li-ion battery. Do i have to change anything to the circuit? thanks.

    Reply
    • Swagatam says

      December 7, 2013 at 5:43 am

      Hi, 4.5V will not do, you will need at least a 6v panel for the above circuit.

      Reply
    • Shiraz rizvi says

      April 16, 2014 at 1:35 pm

      Hi swagatam bhai ty for help
      Maine soler automatic circuit banai ager mujhe 10 watt soler 12v 7ah or 4.5v led h uske liye mujhe kya krna chahiyye help me

      Reply
    • Swagatam says

      April 16, 2014 at 4:22 pm

      Hi Shiraz bhai you can use the circuit that's shown in the above article.

      just replace the shown transistor with TIP127, connect the LED across collector/ground and battery at the given position

      please mention the LEd wattage and voltage also so that I can calculate and provide you the series resistor value for the LED

      Reply
    • Shiraz rizvi says

      April 16, 2014 at 4:42 pm

      Thanx you so much mere bhai

      Reply
    • Swagatam says

      April 17, 2014 at 6:51 am

      my pleasure bhai.

      Reply
  87. Swagatam says

    September 19, 2013 at 3:26 pm

    Please refer to the previous comment posted just above this comment..

    Reply
  88. Swagatam says

    September 19, 2013 at 3:25 pm

    If you are using the configuration that's shown in the above article then you may have to first step down the solar panel voltage to 6V to safeguard the battery.

    You can use a 7806 IC at the input of the circuit such that the panel voltage passes through the IC and then reaches the above circuit.

    You can take the help of the following post for knowing the 7806 connection details, it will exactly same as shown in the following circuit:

    https://www.homemade-circuits.com/2012/03/how-to-make-simple-dc-to-dc-cell-phone.html

    Reply
  89. Lucky Day says

    August 20, 2013 at 11:14 pm

    Just built this and tested it out and it works great.

    I'm curious though if maybe the 1k resistor can be lowered and what kind of value would be safe to make the LEDs brighter.

    I would like them extremely bright, but don't want to blow them obviously.

    At the moment they light up, and they are fairly bright, but not as bright as I've seen these LEDs get before (I'm using 8mm standard 20ma LEDs that you can get from Radioshack)

    Reply
    • Swagatam says

      August 21, 2013 at 7:45 am

      Thank you Lucky Day,

      reducing iK resistor wouldn't be a good idea, rather you can try inserting a resistor in series with each LED and remove the common 10 ohm resistor.

      the value for the individual resistors could be around 2 ohm, 1/4 watt

      Reply
  90. Swagatam says

    August 20, 2013 at 6:53 am

    It would hardly dissipate anything, you may try increasing it to 2k2.

    Reply
  91. Swagatam says

    August 18, 2013 at 1:49 pm

    Hello friend,

    With the transistor as a switch there won't be well defined switching rather the transition would be in a gradual manner.

    As long as the solar voltage is above 4.5V, the LEDs would be completely shut off, as the panel voltage begins dropping downward, the LEds would begin illuminating dimly and start getting bigger as the voltage drops further, finally when the solar voltage becomes almost zero, the LEDs would glow at their maximum rated intensity.

    Reply
  92. 2ea5c024-ebf9-11e2-95c4-000f20980440 says

    August 12, 2013 at 4:08 am

    hello SM,
    is there any chance you can work on a circuit similiar to the following ebay link? http://www.ebay.com/itm/LED-Solar-Power-Motion-Sensor-PIR-Wall-Mount-Garden-Path-Yard-Door-Light-Lamp-/310657821723

    its PIR solar light running off 3x 1.2v rechargeable batteries? Ive looks around google for a similiar circuit but no luck, so i decided to try my luck with you! plmk.

    Thanks
    G.

    Reply
    • Swagatam says

      August 12, 2013 at 1:57 pm

      Hello G,

      The above circuit and the second last design presented in the following link can be easily combined to produce identical results:

      https://www.homemade-circuits.com/2012/09/pir-controlled-led-driver-circuit.html

      Some tweaking would be required to make the design perfect, though.

      Reply
      • Temp says

        December 12, 2020 at 2:49 pm

        as per above comments as you said LDR not required then how can we use tp4056 module for battery safety ,? my request to you kindly help me to use PIR motion sensor with TP4056 module. so that i can protect battery and led , and i want light will turn on if PIR motion sensor will detect any motion otherwise light will remind off , no need to continuously on all night. this way i can get more lumens light in less battery Mah. I’m neither electrician nor engineer . I’m very curious to make solar auto on / off light by my self. i can not afford market and online products they are very costly and they don’t provide enough lumens light. I’ll follow your instruction
        i have
        1) 6v100ma (3 solar panel)
        2) 2400mah battery
        3) PIR sensor
        4) 1w (5 Led)
        5) BC547 & 2N2222

        Thanks & Regards

        Reply
        • Swagatam says

          December 12, 2020 at 9:21 pm

          I am not sure how the TP4056 module working is dependent on LDR?

          Please refer to the following article for more info on the TP4056 module

          3 Smart Li-Ion Battery Chargers using TP4056, IC LP2951, IC LM3622

          Reply
          • temp says

            December 14, 2020 at 8:28 am

            i’m sorry for bothering you. in short my question is how can we make solar pir sensor auto on/off 5w led light using tp4056? no need LDR.
            anyway thanks for your response.

            Reply
            • Swagatam says

              December 14, 2020 at 12:29 pm

              You can try this diagram:

              solar pir sensor auto on/off 5w led light using tp4056

              Reply
  93. Swagatam says

    August 10, 2013 at 2:30 am

    you are most welcome!

    Reply
  94. Swagatam says

    August 9, 2013 at 4:26 am

    The initial diagram had a zener diode at the base of the transistor which I removed later on for making the circuit more responsive and efficient.

    Reply
  95. Swagatam says

    July 26, 2013 at 2:45 pm

    I regret it if I misunderstood you, I thought you were saying that the written corrections were made immediately after listening to your suggestion.

    Correcting the image is time consuming and involves more effort therefore I put in the text form.

    Anyway, cheers!

    Reply
  96. Swagatam says

    July 23, 2013 at 4:18 pm

    Check the previous comments dated May14, June7, it's always wise to check the facts before criticizing.

    Reply
  97. Swagatam says

    July 23, 2013 at 4:02 pm

    Go and check the cached impression in Google you would know it was done a long time ago.

    Reply
  98. Swagatam says

    July 22, 2013 at 3:32 pm

    may be you did not notice the message written in BOLD letters just under the diagram

    Reply
  99. Swagatam says

    July 22, 2013 at 4:08 am

    you can modify the above circuit simply by calculating the resistor as per the given formula.

    Reply

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