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Patient Drip Empty Warning Indicator Circuit

Last Updated on January 3, 2024 by Swagatam 40 Comments

In this post I have explained about a simple mechanism, and a circuit which will enable a patient's IV drip bottle system to sound an alarm whenever it gets almost empty, and needs a replacement.

Table of Contents
  • How it Works
  • Simple Mechanical Approach

The warning circuit will help doctors and the concerned employees to concentrate on other important matters while the drip systems are active, since after installing this unit they won't have to frequently check and be bothered about the level of the liquid inside drip bottles attached with the patients.

Set up Configuration

The proposed IV drip bottle empty alert warning indicator is configured using a mechanical spring stage attached with an electronic stage as shown below:

drip

In the figure above we can see the following things:

An appropriately selected spring mechanism attached on the upper surface of a plastic enclosure.

The lower end of the spring is appropriately terminated outside the enclosure with a hook for hanging the drip bottle.

Within the enclosure, the spring end can be seen attached with a permanent magnet, such that under no load the magnet stays in the indicated position, and in the presence of a load which can be a drip bottle filled with the drip liquid, the magnet is displaced to a lower position and away from its original position.

We can also visualize a reed switch positioned near the magnet at its initial no load position.

The reed switch terminals can be seen wired with a circuit assembled over a PCB, and the PCB bolted inside the enclosure as shown in the design.

There are two additional items in the form of a reset push button, a buzzer, and an LED which become the external protruding parts of the PCB.

In the following section I have explained how the above set up works in conjunction with the warning buzzer circuit, inside the enclosure.

How it Works

electronicselectorswitchcircuit

The working principle of the drip warning indicator is actually very simple:

Referring to the image above, initially without a filled drip bottle hung, and the circuit powered ON, the circuit stays inactive, but gets into a standby position.

In this position, the magnet stays near the reed switch in the closed position which causes a positive supply at pin#14 of the IC 4017. However this does not force the IC 4017 to shift its output logic sequence, because simultaneously the supply also resets the pin#15 of the IC through the attached 0.1uF capacitor.

Now, when the drip bottle is attached to the hook, the spring is pulled downward, causing a displacement of the magnet away from the reed switch.

The reed switch instantly opens, removing the positive supply from pin#14 of the IC 4017.

The output of IC 4017 still retains its initial condition, that is the logic stays at the unused pin#3 pinout, due to the negative supply from the 1M resistor.

Let's assume the drip fluid gets used up by the patient, and gradually nears the empty condition.

As soon as this reaches the empty level, the magnet now once again positions itself in its original point where it meets the reed switch.

The reed contacts now closes yet again, causing a positive pulse on pin#14 of IC  4017.

This time the IC reacts to this signal and shifts the high logic from its unused pin#3 to pin#2.

The transistor at pin#2 now activates, and switches ON the buzzer alarm, alerting the concerned member in the vicinity regarding the empty drip bottle. The LED being in series with the transistor base also lights up providing additional warning indication.

The buzzer continues to buzz and is held in the activated position until the concerned member comes and presses the reset button to revert the circuit in its earlier standby position.

In this position the unit allows the replacement of the empty drip bottle with a  fresh filled drip bottle, so that the cycle is able to continue yet again as explained in the above paragraphs.

Simple Mechanical Approach

The idea is very simple. The upper enclosure consists of a buzzer, battery assembly with a series reed relay and an ON/OFF switch. The reed relay is positioned at one of the bottom corners of the enclosure.

A spring mechanism is attached at the lower end of the enclosure with a magnet, such that when no drip is hung, the magnet aligns itself at a close proximity to the internal reed relay.

Initially the ON/OFF switch is held in the switched OFF condition, and is switched ON once the drip is hung and the spring is pulled downward moving the magnet away from the reed switch.

Now, as the drip liquid empties its weight decreases and it begins moving upwards due to spring tension, until finally the liquid almost gets over moving the magnet close to the reed. The reed switch now closes switching ON the buzzer.

mechanical drip alarm buzzer

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About Swagatam

I am an electronics engineer with over 15 years of hands-on experience. I am passionate about inventing, designing electronic circuits and PCBs, and helping hobbyists bring their projects to life. That is why I founded homemade-circuits.com, a website where I share innovative circuit ideas and tutorials. Have a circuit related question? Leave a comment.... I guarantee a reply!

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Reader Interactions

Comments

  1. Jedidiah says

    October 9, 2024 at 1:32 am

    Hello Sir.
    I acquired a load cell sensor but I can’t obtain the output. The only way I find is to use an Arduino board.

    Reply
    • Swagatam says

      October 9, 2024 at 8:30 am

      Hi Jedidiah
      I think you can try the instructions provided in the following video, for the all the required details:

      https://www.youtube.com/watch?v=sxzoAGf1kOo

      Let me know if you any further questions.

      Reply
      • Swagatam says

        October 9, 2024 at 8:34 am

        You can also investigate using a Force Sensing resistor, which looks cheaper than a load cell:

        https://www.homemade-circuits.com/force-sensing-resistor-explained/

        Reply
  2. Jedidiah says

    September 23, 2024 at 11:02 pm

    Do you have a circuit for this please Sir?

    Reply
    • Swagatam says

      September 24, 2024 at 12:13 pm

      Jedidiah, I have not used a load cell so far, so I am not sure how its output responds to a load.
      So I would suggest you to first buy a load cell and check its output response to a varying load, if you provide me with this information then I will be able to design an appropriate circuit as per your requirements.

      Reply
  3. Jedidiah says

    September 23, 2024 at 2:42 am

    Hello Sir.
    Can this drip monitoring unit be equipped with LCD displays and alarm functionality systems to offer real-time monitoring of drip rates and fluid level to alert clinicians in case of deviations from the prescribed drip rate ensuring timely intervention?

    Reply
    • Swagatam says

      September 23, 2024 at 8:41 am

      Hi Jedidiah,
      That may be possible if a load cell is used for the drip liquid weight detection and interfaced with an LCD.

      Reply
  4. Rodgers says

    December 4, 2021 at 12:04 pm

    I think the alarm system will disturb the patient how about finding a way that the alrm will only notify the nurses instead of the patient to hear the noise

    Reply
    • Swagatam says

      December 4, 2021 at 1:52 pm

      The alarm would be in the form of a small beeping buzzer, not a loud alarm. A remote controlled system can make the unit very expensive and complex.

      The patient must actually also know that the drip is about to finish.

      Reply
  5. ezekiel says

    January 15, 2021 at 9:03 pm

    hi, is please i need help if you can modify the same circuit so that it can alert the nurse when drip is about to finish (Not empty) also automatic stop pumping water/blood to avoid blood to flow back to the drip

    Reply
    • Swagatam says

      January 16, 2021 at 1:12 pm

      Hi, for that you just have to adjust the magnet position appropriately to get the alarm at the desired point

      Reply
      • ezekiel says

        January 17, 2021 at 3:10 am

        Thank you, but also i need your advice what can i do when the desired point have reached then the drip will automatically stop pumping the water

        Reply
        • Swagatam says

          January 17, 2021 at 11:41 am

          Sorry could not understand your question, from where will the water come?

          Reply
          • ezekiel says

            January 17, 2021 at 11:20 pm

            yeah from where the water will come, means when the desired point is reached it wi;; sound an alarm then stop water/blood

            Reply
            • Swagatam says

              January 18, 2021 at 8:07 am

              An electrical valve system will need to be introduced near the opening of the IV package, this valve can be then switched ON/OFF with the help of the above circuit

              Reply
  6. ezekiel says

    December 19, 2020 at 6:58 pm

    i am trying to implement the Patient Drip Empty Warning Indicator Circuit but i am having trouble drawing the circuit in the proteus because IC 4017 do not show pin 8 and pin 16. What should i do

    Reply
    • Swagatam says

      December 20, 2020 at 8:46 pm

      I do not use simulators so I can’t suggest about much them…..I would recommend you to build it practically to see it actually working

      Reply
  7. Barasakevindidi says

    July 15, 2019 at 5:20 pm

    Hi sir, am using 10k resistor in series with the led, and 9v battery but its just giving beeps but not lighting

    Reply
    • Swagatam says

      July 15, 2019 at 6:24 pm

      Hi kevin, you can try reducing the resistor to 4k7, if still the LED does not light, then your LED may be faulty.

      Reply
  8. Daniel Armughan says

    March 27, 2019 at 5:59 pm

    what you did not used the pin 16 for input?

    Reply
  9. Daniel Armughan says

    March 27, 2019 at 5:50 pm

    can’t you help me soon? please…clear me 2 things !
    is that 4017 circuit is successfully tested?

    and confirm me where to give the voltage supplies, please
    i’ll be thankful to you.

    Reply
    • Swagatam says

      March 27, 2019 at 6:22 pm

      Give positive to the places where +12V is written, give negative to the points indicated with earthing symbol. Pin16 is on the left side of pin15

      Reply
      • Daniel Armughan says

        March 27, 2019 at 6:40 pm

        Can i use 9 volt battery?
        And there is not any mention for pin 16 dear.that why em confused.

        Reply
        • Swagatam says

          March 27, 2019 at 6:43 pm

          yes 9V batt can be used, please see my previous comment for pin16 location…

          Reply
          • Daniel Armughan says

            March 27, 2019 at 6:47 pm

            Yup okie Sir…
            Thank you so much for your help ..
            I found out the pin 16 location..actually i was not mention so i got confused..i will try again..hope for good..

            Reply
            • Swagatam says

              March 27, 2019 at 7:40 pm

              Sure! wish you all the best!

              Reply
          • Daniel Armughan says

            March 29, 2019 at 1:01 am

            Can
            i use 6v zener diodd insread of 3v?

            Reply
            • Swagatam says

              March 29, 2019 at 6:19 am

              Use a 1N4007 diode. The line side of the diode will go to the reed, other side to positive

              Reply
      • Daniel Armughan says

        March 28, 2019 at 6:34 pm

        Can i use polarized capacitor of 1 uf?

        Reply
        • Swagatam says

          March 28, 2019 at 7:29 pm

          yes that’s fine, please use it also for the pin#15 capacitor, 0.1uF is too small

          Reply
      • Daniel Armughan says

        March 29, 2019 at 1:00 am

        Sir.
        I tried but it was unsuccessful…

        Please send me circuit diagram.

        Reply
        • Swagatam says

          March 29, 2019 at 6:20 am

          Daniel, “unsuccessful” is impossible. It will work if you do it as shown. Diagram is already given.

          Reply
  10. Daniel Armughan says

    March 27, 2019 at 5:30 pm

    Hello Sir, Can You Please Provide Me the More Accurate Circuit Diagram, Its Just Because I am Beginner, And kindly Clear me 1 thing that, Both Negative And positive supply Will be given at @ 2 point? for example negative supply at transistor and at Pin# 13 and 8. right?

    Reply
    • Swagatam says

      March 27, 2019 at 5:39 pm

      Hello Daniel, Yes you are right, I’ll try to update a clearer diagram soon, by the way if you are a beginner then you must go for the second design at the bottom instead.

      Reply
  11. BARAKA MARK BRIGHT says

    July 6, 2018 at 8:26 pm

    Thanks for sharing your ideas. I tried building the patient drip warning indicator basing on the circuit you provided above but it has failed to work. Any help?
    Thanks in advance

    Reply
    • Swagatam says

      July 7, 2018 at 6:47 am

      Hi thanks, the concept is so simple and straightforward that it can never fail..please take the assistance of somebody who has good knowledge of electronics and try it again

      Reply
      • BARAKA MARK BRIGHT says

        July 8, 2018 at 1:06 am

        Oh I forgot to tell you that the circuit finally worked. Thanks for sharing the idea.

        Reply
        • Swagatam says

          July 8, 2018 at 9:41 am

          I am glad it worked it, thanks for sharing the info.

          Reply
  12. Ali Baig says

    December 24, 2017 at 1:45 am

    I am very interested is a IGBT Based, Transformer less AC to AC Stabilizer design.
    If you can, please reply.
    Ali Baig
    CEO
    Future Technologies.
    +923332109966
    SKYPE: ali.baig25

    Reply
    • Swagatam says

      December 24, 2017 at 10:56 am

      one related design can be found at the end of this post, which you can study

      https://www.homemade-circuits.com/smps-mains-voltage-stabilizer-circuit/

      Reply

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