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Simplest 100 Watt LED Bulb Circuit

Last Updated on December 9, 2024 by Swagatam 163 Comments

In this article I have explained a very simple 100 watt LED bulb circuit using a few high voltage capacitors. The entire circuit could be built at a cost less than $25.

Table of Contents
  • Using Capacitive Power Supply
  • Analyzing the The Design
  • Circuit Diagram
  • Improved design with current control

I have already discussed many capacitive type of transformerless power supply circuits in this blog, however all these suffers from a couple of issues, namely lack of optimal current output, and surge inrush vulnerability.

Using Capacitive Power Supply

Upon studying capacitive power supplies deeply I could conclude a few crucial things regarding these configurations:

Capacitive power supplies are quite like solar panels which work efficiently, at their maximum power point specs when they are operated with their open circuit voltages, otherwise the current specs from these units go through heavy losses and produce highly inefficient results.

In simple words if we one desires to acquire high current outputs from a capacitive power supplies at will, the circuit will need to be operated with a load having a voltage requirement equal to the maximum output of the system.

For example with a 220V input, a capacitive power supply after rectification would produce an output of around 310V DC, so any load assigned with a 310V rating could be operated with full efficiency and at any required current level depending upon the requirement of the load.

If the above condition is satisfied, it also tackles the current inrush issue, since the load is specified at 310V, an inrush of full input voltage now has no effect on the load and the load remains safe even during sudden switch ON of the circuit.

Analyzing the The Design

In the proposed 100 watt LED bulb circuit we employ the same technique as discussed in the above sections.

As discussed, if the input is 220V the load would need to be rated at 310V.

With 1 watt 350mA standard LEDs this would mean adding 310/3.3 = 93 LEDs in series, that's close to 100nos.

A single 1uF/400V capacitor produces around 60mA current at the above specified 310V DC, therefore for achieving the required 350mA more such capacitors will need to be added in parallel, to be precise a total of 350/60 = 5 capacitors, that could also be a single 5uF/400V but should be a non-polar type.

An NTC thermistor may be added for extra safety, although it may not be critically required.

Similarly a resistor could be also included to provide extra bit of safety from fluctuating voltage conditions.

The resistance value may be approximately calculated as R = Us - VFd/I = 310-306/.35 = 10 ohm, 1 watt

For a 120V input, the above specs would simply need to be halved, that is use 47nos of LEDs instead of 93, and for the capacitor a 5uF/200V would be enough.

Circuit Diagram

Warning: Circuits I have explained below are not isolated from mains AC, and therefore are extremely dangerous to touch in the powered and open condition. You should be extremely careful while building and testing these circuits, and make sure to take the necessary safety precautions. The author cannot be held responsible for any mishap due to any negligence by the user.

100 watt led bulb circuit 1

The above diagram can be additionally safeguarded from surge inrush voltages, and mains fluctuations by adding a 10 ohm limiting resistors and a zener diode, as shown below.

Here the value of zener diode should be 310V, 2 watt

100 watt led bulb with NTC

Improved design with current control

The following circuit is a foolproof circuit design that will never allow the LEDs to come across a stressful condition. The mosfet and thee associated current control ensure 100% constant voltage and constant current for the connect LED bulb chain.

The number of LEDs in the chain can be adjusted as per the selected voltage, or conversely the voltage can be adjusted as per the selected number of LEDs in the chain.

LED power supply

Note: Please move the capacitor C1 from the existing position to the output terminals of the circuit. Meaning, remove the C1 from across the bridge rectifier and connect it parallel to the LED string. This will drastically eliminate excess stress of the MOSFET, yet provide a filtered DC to the LEDs, increasing the overall efficiency of the design. In this case the voltage rating of C1 can be reduced to the value that's just slightly above the total forward voltage of the series LED string.

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About Swagatam

I am an electronics engineer with over 15 years of hands-on experience. I am passionate about inventing, designing electronic circuits and PCBs, and helping hobbyists bring their projects to life. That is why I founded homemade-circuits.com, a website where I share innovative circuit ideas and tutorials. Have a circuit related question? Leave a comment.... I guarantee a reply!

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Reader Interactions

Comments

  1. Dangai Jonas says

    December 4, 2022 at 9:52 pm

    Good evening
    What would be the value of the resistor R2 for a power of 200W leds? Thanks

    Reply
    • Swagatam says

      December 5, 2022 at 9:07 am

      Hello,
      R2 = 0.7 / Maximum LED current

      Reply
      • Daouda says

        December 5, 2022 at 10:39 am

        Merci beaucoup monsieur

        Reply
  2. Daoud says

    August 16, 2021 at 2:26 pm

    Merci beaucoup Monsieur

    Reply
    • Swagatam says

      August 16, 2021 at 4:12 pm

      My pleasure!

      Reply
  3. Daoud says

    August 16, 2021 at 12:29 pm

    Or at the output of my dimmer made from a triac and which I have rectified, I can put the two components connected in parallel (1M resistor and 1u / 400V capacitor). I mount several 1u / 400V capacitors in parallel until the current is 1.75A?

    Reply
  4. Daoud says

    August 16, 2021 at 12:21 pm

    Hello sir, as there is no 200V zener diode in our region, I used a dimmer to vary the voltage to 200V well rectified but the leds do not shine normally. Is the current insufficient? I assumed that the current for each led is 350mA and that there are 5 lines connected in parallel which constitutes a block of 5 lines connected in parallel, each line has 24 leds connected in parallel we have in total a current of 1 , 75A. As I have 2 blocks which are connected in series. How I can increase or amplify the current so that the leds shine normally

    Reply
    • Swagatam says

      August 16, 2021 at 1:48 pm

      Hello Daoud, you will have to use a transformer based power supply which can supply 200 V 350 ma, or use an SMPS with the same rating. Capacitive method with zener diode will not produce 350 mA.

      Also make sure each LED series has a limiting resistor calculated using the formula suggested in the previous email.

      Reply
  5. Daoud says

    August 16, 2021 at 11:14 am

    Merci beaucoup à l’aide que vous me donnez
    Je vais donc faire comme vous l’avez dit en appliquant une tension de 200V. Merci infiniment

    Reply
  6. Daoud says

    August 15, 2021 at 4:31 am

    Good day, sir. Thank you for your help. In fact the projector of an unrecoverable switching power supply so I wanted to make another power supply. Of course I have already realized but the mosfet heats up a lot this mosfet is mounted in commutation. The led projector is 200W. How to avoid heating this transistor. This projector has 10 lines of 24 leds per line Thank you

    Reply
    • Swagatam says

      August 15, 2021 at 2:37 pm

      Hello Daoud, assuming the LED series/parallel connections are correctly calculated, the heating up issue of the transistor can be simply solved by using a higher rated transistor, whose rating must be much higher than the total power of the LEDs.

      Reply
      • Daoud says

        August 15, 2021 at 2:52 pm

        Hello Sir thank you very much for your response. I used 2 mosfets of 150W with rds 1.2 Ohms resistor, the voltage Vds 900V and the current of 9A but it still heats up you can have an idea for that please. When I limit the current with a resistance of 500 Ohms the transistor does not heat it is the resistance which heats up earlier. Can I send you the diagram please?

        Reply
        • Swagatam says

          August 15, 2021 at 8:36 pm

          You are welcome Daoud, 900 V and 1.2 ohm both don’t look compatible for your application. The VDD and ID can be at the most 1.5 times higher than the V and I specs of the series/parallel LED array. Higher VDD would also mean high RDSon which can cause the FET to heat up…..so try replacing with a MOSFET having specs only 1.5 times higher than the LED specs.

          The limiting resistor must be optimally calculated, higher series resistance would unnecessarily reduce the light output of the LED.

          Reply
          • Daoud says

            August 16, 2021 at 3:16 am

            Thank you very much Sir really I am very proud
            And today I received a 180W led projector. Inside the projector we have 2 blocks of leds and each block contains 5 lines mounted in parallel each line includes 25 leds. Now the first block is mounted in series with the second block. The power supply of this projector is a switching power supply which is defective as components cannot be found on the market. I did a simple rectification then filter I obtain a voltage of 325V and I feed the projector it does not shine well. What can I do to shine well? Thank you for your help

            Reply
            • Swagatam says

              August 16, 2021 at 10:53 am

              Thank you Daoud, the formula for the supply voltage, limiting resistors, and the current is given below: The supply DC must be slightly higher than the total forward drop of the LED series, and LED series current can be equal to the single LED current.

              Limiting Resistor = supply DC – total FWD voltage of the LED series / total LED current

              If the total series LED number is 24 + 24 = 48 and each LED voltage is 3.3 V. Then the total forward (FWD) LED voltage becomes 48 x 3.3 = 158 V, and any DC above this value can be applied or a maximum of 200 V DC can be applied.

              Reply
  7. Charis Young says

    April 21, 2021 at 12:44 pm

    Please sir I need the schematic diagram of CTORCH LED 28W 2520Lm 250mA circuit diagram.AC input of 230-40V.
    Thank you for your guided and kind response.

    Reply
    • Swagatam says

      April 21, 2021 at 4:54 pm

      Charis, I don’t have the mentioned circuit….but you can use the second circuit from the above article, and put 28nos of 1 watt LEDs. The zener diode will be 92 V.

      Reply
  8. Abdul Basit Momin says

    March 28, 2021 at 2:27 am

    Hello sir want to run 25 number of 1 watt led in series wat will be the changes in circuit

    Reply
    • Swagatam says

      March 28, 2021 at 6:30 pm

      Abdul, you can try the last circuit, adjust the voltage to 25 x 3.3 = 82 V

      Reply
  9. Ritesh Kumar Mohanty says

    March 30, 2018 at 10:11 am

    Thank you sir ,sir where i connect +ve input and -ve input ? Is the +ve can be connected in capacitor side? What is the specification of zener diode?

    Reply
    • Swagatam says

      March 30, 2018 at 10:25 am

      Ritesh, sorry actually I have updated the required diagram in the following article, please check it out

      https://www.homemade-circuits.com/make-hundred-watt-led-floodlight/

      Reply
    • shelim mollik says

      December 27, 2020 at 7:32 pm

      dear sir,
      i made a tiktok ring light with 150 leds (1 watt 3.5 vold),27 leds were brightness and 123 leds were not bright,totally 123 leds did not work.it was without zener diod and varistor,please how to solve it?

      Reply
      • Swagatam says

        December 27, 2020 at 9:18 pm

        Hello Shelim, without seeing the schematic I cannot judge the fault, so if possible provide the complete circuit diagram.

        Reply
  10. Ritesh Kumar Mohanty says

    March 22, 2018 at 5:30 pm

    Thanks sir, sir I can you help me by using smps ? Can you provide me that full circuit diagram and all specification of all components? Sir plz help me I am so excited about this project.

    Reply
    • Swagatam says

      March 22, 2018 at 8:45 pm

      Ritesh, please tell me the total number LEDs, and the wattage of the LEDs you want to use for the project.

      Reply
      • Ritesh Kumar Mohanty says

        March 29, 2018 at 5:25 pm

        Thanks Sir,Sir I want to do a 100 watt LED lamp with 1watt LEDs .sir please give me proper circuit diagram and provide me full specification of all components used in this project. Sir plz help me kindly I am so excited to perform this project. Plz sir

        Reply
        • Swagatam says

          March 29, 2018 at 8:38 pm

          Ritesh, I have updated the diagram above…you can check it out

          Reply
  11. Ritesh Kumar Mohanty says

    March 22, 2018 at 3:16 pm

    Thanks sir, Sir I am very excited to do this project sir can you help me? Can you provide the actual practical circuit diagram of this project , with all components and all’s specification. Sir plz can you send me with full description?

    Reply
    • Swagatam says

      March 22, 2018 at 4:43 pm

      Ritesh, I have undated the diagram, but please do it at your own risk, because mains current is always dangerous and you cannot predict it 100%.

      If you want 100% guaranteed results then it is always better to go for an SMPS based power supply or a transformer based power supply.

      Reply
  12. Ritesh Kumar Mohanty says

    March 21, 2018 at 5:26 pm

    Sir,As shown in circuit diagram can I connect the zener diode in parallel with 10uf 400v capacitor ? What’s the specification of zener diode ?where can I connect the heat sink and what’s the specification of heatsink

    Reply
    • Swagatam says

      March 22, 2018 at 1:53 pm

      yes you must connect it in parallel to the 10uF/400V cap. The zener value should be equal to the total forward drop of the LEDs in series. Heatsink will need to be determined through practical experimentation

      Reply
  13. Ritesh Kumar Mohanty says

    March 21, 2018 at 12:25 pm

    Hello Sir, thanks for your support , Sir can I know where the ntc is connected in +ve of input or in -ve of input ?and what is the specification of zener diode? and where I can use to the zener diode?sir plz kindly respond me.plz help me out

    Reply
    • Swagatam says

      March 21, 2018 at 12:55 pm

      Ritesh, NTC can be connected anywhere in the line, either in the positive line or the negative.
      zener diode can be connected parallel to the filter capacitor.
      but make sure to connect a small value resistor, may be a 50 ohm 2 watt in series with the NTC.

      Reply
  14. Nazim says

    March 18, 2018 at 4:00 am

    Thanks Sir

    Reply
  15. Nazim says

    March 13, 2018 at 2:14 pm

    Dear.. how are you sir i hope your healthy n fir ..
    can can you provide me the circuit diagram of *manual heat sealing machine*

    Reply
    • Swagatam says

      March 13, 2018 at 9:37 pm

      Nazim, the procedures involved are purely mechanical so I won’t be able to help you with it, since my expertise is lies only with electronic circuits

      Reply
  16. Nazim says

    October 28, 2017 at 2:39 am

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit.

    1Watt LED
    Forward current: 350mA
    Forward Voltage: 3.2V~3.4V in average (3.3V*93Leds= 306.9V),
    In india we are getting Indian power supply 240V 50Hz then how this circuit working.

    My dought is input voltage is lower around 220V~250V and output Voltage is Higher (3.3V*93Led)=306.9V… how ita working sir

    Reply
    • Swagatam says

      October 28, 2017 at 6:56 am

      Hello Nazim, the 220V is the average value of the AC, alo called the RMS, the peak value of this 220V AC is always around 310V.

      when we rectify this 220V with a bridge and filter capacitor, the 310V is produced and sustained at the output by these components, therefore the output that we get is 310V DC instead of 220V AC.

      Reply
      • Swagatam says

        October 28, 2017 at 6:57 am

        I hope you have a basic digital meter with you to check the voltages, which is a must for any electronic hobbyist.

        Reply
  17. Nazim says

    October 24, 2017 at 3:47 am

    I think 5uf is sufficient for led if the brightness is not getting sufficient then it may b led fault or any other fault in my circuit sir ? Im i correct sir

    Im not get 310v 2watt zener diode in my local market so i let it and only 5uf +1uf again add totall 6uf then the above said situation happen.

    Did zener diode controls the volts or Ampere sir?

    Reply
    • Swagatam says

      October 24, 2017 at 8:15 am

      did you connect a large heatsink with the LEDs? at 300mA the LEDs can get immensely hot and will blow within a minute.

      without a zener the LEDs can burn with a slightest mains fluctuation.

      zener will control voltage and will prevent rise in abnormal current consumption.

      Reply
  18. Nazim says

    October 24, 2017 at 3:36 am

    Dear Swagatam sir,
    If i want to run 1watt 350mA led on 12-0-12 , 5Ampere transformer.
    Q1 :- How can i run 1watt 350ma leds?
    Q2:- What changes i have to done in above 100watt bulb circuit?
    Q3:-how many leds can i operates with 12-0-12 5ampere transformer with out any problem to enter set?

    In the previous 93led circuit i have add one 1uf/400v non polar capacitor then i give supply after some time 5to10mints leds become slowly dim by dim i think “1uf producing 70mA (70*5=350mA)

    Reply
    • Swagatam says

      October 24, 2017 at 8:06 am

      Dear Nazim,

      connect then as shown in the last diagram of this article

      https://www.homemade-circuits.com/make-this-1000-watt-led-flood-light/

      each string will consume .3 x (3.3 x 6) = 6 watts

      your transformer supply is 24 x 5 = 120 watts

      so you can connect 120/6 = 20 such parallel strings

      Reply
      • Dipan shah says

        May 16, 2019 at 12:30 am

        Hello sir,
        I have made this tranformerless circuit using MB10S bridge rectifier. I have used 250v 1.1uf non polorised capacitor and 250v 10uf polorised capacitor with 470 ohm 1 watt resistor at output with series of 52 leds string. But at output i am getting only 37mA. When i need 60mA. When i tried using 250v 2.2uf non polorised capacitor it became so hot. And other thing is i have some size ristrictions for this driver so if i use 400v non polorised capacitor then it will be so big and will not fit in. So can you plesse give me dome solution over this problem?
        Thank you.

        Reply
        • Swagatam says

          May 16, 2019 at 9:56 am

          Dipan, to get 60mA you will need a 2uF/400V capacitor. 400V is required for guaranteed safety to the capacitor so it is a must. For smaller size you can use 250V but that will not ensure a 100% safety for the capacitor.

          Reply
  19. Nazim says

    October 20, 2017 at 2:18 pm

    Dear Swagatam sir

    (Did i need to place between “6uf/400v ….(310b 2watt zener diode ?)…… 10uf/400v) right sir

    Reply
  20. Nazim says

    October 20, 2017 at 2:16 pm

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit.

    (Did i need to place between “6uf/400v ….(310b 2watt zener diode ?)…… 10uf/400v) right sir

    Reply
    • Swagatam says

      October 20, 2017 at 2:31 pm

      Dear Nazim, yes connect ii across the same points where 10uF/400V capacitor leads are connected, anode of zener to minus of capacitor, cathode to plus pin of capacitor.

      Reply
  21. Nazim says

    October 20, 2017 at 1:39 pm

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit.

    310V 2 watt zener
    in the above design circuit where i have to place the zener diode

    waiting for your great replay sir thanks a lot sir. thank you very much sir

    Reply
    • Swagatam says

      October 20, 2017 at 2:12 pm

      you can connect its anode with the negative line (-310V line) and cathode with the positive line (+310V line)

      Reply
  22. Nazim says

    October 20, 2017 at 10:10 am

    Dear Swagatam sir.
    Simplest 100 Watt LED Bulb Circuit,

    Can i get sufficient brightness if i add below two parts to circuit
    part 1:- 1uF 400V Non-Polar Metallized Film Capacitor
    part2:- 310V 2 watt zener (it shoud be add on 1n4007 diode brige im i correct sit and i dnt know how to connect the position )

    Reply
    • Swagatam says

      October 20, 2017 at 11:52 am

      Dear Nazim, obviously if the each LED gets 3.3V at 300mA then all the LeDs will illuminate at optimal brightness.

      dividing 310V with 93 LEDs gives 3.33 which is the right voltage value for each of the LEDs.

      and if a 6uF cap is used it will provide the required 300mA to the whole string. if it doesn’t then the problem could be somewhere in your parts or the connections.

      310V zener is only to make sure the max voltage to the LeDs does not go above 310V, which can otherwise damage the whole string.

      however if the supply voltage drops below 300V DC (210V AC) then the LEDs will become dimmer…at 200V (145V AC) the LEDs will almost off.

      Reply
  23. Nazim says

    October 19, 2017 at 3:21 pm

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit

    1uF/400V capacitor produces around 60mA (as i read in your blog if we add 1 or 2 more capacitors it will produce above 350mA im i correct sir)

    A single 1uF/400V capacitor produces around 60mA current at the above specified 310V DC, therefore for achieving the required 350mA more such capacitors will need to be added in parallel, to be precise a total of 350/60 = 5 capacitors, that could also be a single 5uF/400V but should be a non-polar type.

    Reply
    • Swagatam says

      October 20, 2017 at 2:11 am

      Hello Nazim, yes you can add a couple of more 1uF capacitor to increase current for the LEDs, but this can make the Leds vulnerable to slightest voltage fluctuations and burn them. 1uF will practically give around 50mA…not 60mA which may be true only as per the formula.
      the capacitor should be a non-polar.

      Reply
  24. Nazim says

    October 19, 2017 at 3:00 pm

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit

    If i add “1uf 400v” two more capacitors in my old circuit can get sufficient brightness sir

    Reply
  25. Nazim says

    October 19, 2017 at 11:09 am

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit
    Thanks you very much for give each and every part information finally i have successfully turn on led bulb with my partner jatin thanks a lot “SWAGATAM SIR AND JATIN” but a led not giving sufficient brightness can…

    Can you give information about “Capacitor Based LED Tubelight Circuit Using 1 Watt LEDs” https://www.homemade-circuits.com/2014/07/capacitor-based-led-tubelight-circuit.html

    Is tube light me use kre hue parts ki information dejiye na identify karne k lye plz
    Thanks a lot sir

    Reply
    • Swagatam says

      October 19, 2017 at 12:32 pm

      Thank you dear Nazim, I am glad you could make it successfully….the illumination can be increased by reducing the number of LEDs in series…if you use 93 LEDs, the brightness will be maximum..also the 5uF capacitor will give only 250mA current which is not full current for the 1 watt LEDs…so you can add one more capacitor in parallel to make it 300mA, but this will make the LED more vulnerable to surge currents…

      the details of the other tubelight is discussed in the comment section, please check it in the comment discussion. and also it is given in the last PCB design

      Reply
  26. Nazim says

    October 15, 2017 at 5:47 pm

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit
    below the four parts images from url once see and say me there are correct image of parts sir,

    1.10uf 400v (1 pieces ) ( Image url )
    if i don’t get 10u 400v can i take 10u 450v

    2. 1uf 400v (5 pieces should be connected in parallel series )(Image url )

    3. NTC Details (Image url )
    (if ntc not available in local dealer can i leave it sir)

    4. 1watt 350mA led (image url )

    waiting for your great replay sir thanks a lot sir for proving me each and every information with out hesitating . thank you very much sir

    Reply
    • Swagatam says

      October 16, 2017 at 1:20 am

      Hi Nazim, all those examples are correct, you can go ahead with them.

      the LEDs will require a large heatsink, so please do not forget to mount them on a hetasink.

      Reply
  27. Nazim says

    October 14, 2017 at 10:05 pm

    Dear Swagatam sir
    Simplest 100 Watt LED Bulb Circuit
    Went to local spare parts dealers and show circuit diagram did not understand . All they asked me image or images of parts r types of capacitors and Resistor 1M Watt? And NTC details so i aked you images sir plz help me to success in this making bulp
    1.10uf 400v {image or capacitor type}
    2. 5uf 400v {image or capacitor type}
    3.1M (Resistor Ohms and watt)
    4. NTC Details {image or details }

    Local dealers give me perfect by seeing circuit diagram 1watt led and diode 1n4004 this two item only i have got the above mentioned 4parts asking more details

    Can this bulp run on indian voltage India 240v 50Hz im waiting for your great reply sir thanks a lot sir for providing me a lot of information. Thank you thank a lot

    Reply
    • Swagatam says

      October 15, 2017 at 3:53 am

      Nazim, to make the 100 watt bulb run correctly you will have to make it exactly as suggested in the diagram, any other method will burn your LEDs, yes it is intended for 250V input

      1N4004 will not work…you must use 1N4007 only.

      If you don’t get the NTC then you can use an scr based circuit as shown below:

      https://www.homemade-circuits.com/2016/07/scr-shunt-for-protecting-capacitive-led.html

      just replace the 12V zener with a 300V zener, and replace the 100uF/25V with 10Uf/400V

      Reply
  28. Nazim says

    October 14, 2017 at 1:42 pm

    Simplest 100 Watt LED Bulb Circuit.

    dont mind sir asking too much because i am not a (Electronic & electrical engineering ) Background student im a commerce student ..after seeing your website i plan to work in this circuit design .
    i have bought 1w 350mA leds with heat sink plate
    i need below parts images to work in this

    i need some images of parts
    1. 10uf 400v {image needed}
    2. 5uf 400v {image needed}
    3.1M (Resistor Ohms and watt)
    4. NTC Details {image needed}
    can you provide me sir please sir
    Email: [email protected]

    Reply
    • Swagatam says

      October 15, 2017 at 3:42 am

      Nazim, If I show you the image then you may go strictly as per the image, which can make things more complex so it’s better that you only take the following parts list and show it to the shopkeeper, he will be able to guide you and provide you the materials:

      1) 10uF/400V electrolytic capacitor – 1no
      2) 5uF/400V can be built by putting 5nos of 1uF/400V PPC capacitors in parallel, this capacitor is normally labelled as 105/400V PPC or MKT.
      3) 1M 1/4 watt CFR, – 1 no
      4) NTC = 11mm, 5 ohm type 1no, or any suitable will do.

      Reply
  29. Nazim says

    October 13, 2017 at 12:36 pm

    Hello sir i need a circuit diagram with items details of 96leds {1watt 350mA} could you please help

    Reply
    • Swagatam says

      October 13, 2017 at 3:04 pm

      Nazim, you can use the same design which is explained in the above article.

      Reply
  30. Mircea Raileanu says

    January 3, 2017 at 6:10 pm

    hi sir, can i use this circuit to power up a pair of pc speaker thank you

    Reply
    • Swagatam says

      January 4, 2017 at 3:50 pm

      No, you must use an SMPS, the above is not recommended.

      Reply
  31. KENNY HO says

    October 22, 2016 at 11:06 am

    HI SIR, CAN YOU PLEASE ADVISE ME ON YOUR CIRCUIT?
    IM USING 17X1W LED IN SERIES
    INPUT 230V AC, I CANT GET THERMISTOR AS YOU SUGEST
    CAN I USING THIS CIRCUIT? ANY COMPONENT TO CHANGE??

    Reply
    • Swagatam says

      October 22, 2016 at 11:30 am

      Kenny, you can try the following concept instead

      https://www.homemade-circuits.com/2016/07/scr-shunt-for-protecting-capacitive-led.html

      just replace the zener with a 56V 1 watt zener diode for 17 LEDs and replace the 1K resistors with 10K.

      Reply
    • John Philip Ivan says

      November 9, 2016 at 9:52 am

      Hi sir. Can you gibe a circuit for using drop capacitor to convert my 110v 60hz smart bulbs to 220v 60hz ? what values for Capacitor and Resistor do i need. Regards.

      Reply
    • Swagatam says

      November 9, 2016 at 11:45 am

      Hi John, please specify the wattage of the bulb.

      Reply
  32. Unknown says

    July 6, 2016 at 3:20 pm

    I assembled the above circuit with 83 1w leds and 2 x 225k capacitors and used one inductor coil also in the circuit. It is working superb. Many Thanks for your help. VG KRISHNA from Hyderabad.

    Reply
    • Swagatam says

      July 6, 2016 at 3:35 pm

      I am glad it's serving the purpose, but make sure to add an NTC also to provide additional safety to the LEDs

      Reply
    • VG KRISHNA says

      July 9, 2016 at 9:32 am

      Thank you sir, I will add NTC also.

      Reply
  33. A Prakash Rao says

    April 2, 2016 at 2:30 pm

    Sir, please tell the value of the thermistor to be used in the 100w led circuit.

    Reply
    • Swagatam says

      April 3, 2016 at 2:43 am

      Prakash, you can use a 2 ohm NTC

      Reply
  34. satheesh k Nalluswamy says

    January 24, 2016 at 4:54 am

    Shopkeeper recommended this to me. NTC 10S100L would use this instead of the NTC 5D-11Tell us your advice
    Waiting for your replay thank you sir

    Reply
    • Swagatam says

      January 24, 2016 at 5:49 am

      It should work, it's a 10 ohm NTC a little higher in resistance though…. you can try it.

      Reply
  35. satheesh k Nalluswamy says

    January 23, 2016 at 2:52 pm

    Sir Namaste my sincere thanks for your advice.

    There is another suspect.
    Can I use this NTC 10S100L instead of that you have to NTC 5D-11 . Would it be much safer if I use this?
    Can I use it to circuits in your blog?

    Reply
  36. satheesh k Nalluswamy says

    January 22, 2016 at 11:27 am

    sir,
    Is it possible to 8mm 0.75 Watt Clear White led

    Reply
    • Swagatam says

      January 22, 2016 at 3:18 pm

      It is possible, just reduce the input cap to around 4uF/400V

      Reply
  37. satheesh k Nalluswamy says

    January 22, 2016 at 11:26 am

    Sir,
    In fact am receiving very greatly help from your blog. And most significant article be present you converse with each person who needs proper supervision. I’m so beholden of this blog and you

    Reply
    • Swagatam says

      January 22, 2016 at 3:17 pm

      Thanks Satheesh!! It's my pleasure ….

      Reply
  38. satheesh k Nalluswamy says

    January 19, 2016 at 3:48 am

    Sir,
    Good day to you can i use this if I have to do 25 1WATT LED. If so what changes need to?

    I learned a lot in your blog. Five circuits were successfully accomplished by using your blog. Thank you sir

    Reply
    • Swagatam says

      January 19, 2016 at 10:56 am

      Thanks Satheesh, the number of LEDs should be around 80 to 100….25nos could be risky because its total forward voltage drop may be much lower than the AC level.

      If you intend to have a 25 watt output in that case you can try using lower wattage LEDs so that you can increase their quantity to around 80 to 90 of them.

      Reply
  39. Shekhar Jaiswal says

    December 30, 2015 at 10:08 am

    Hello sir

    I wish to create a light of 3w 30 white leds with ac 220 supply. Ive bought the leds & heatsink( 30 led in series ). Please guide me with the circuit diagram with capacitor, resistors etc & how to go about. Please..i

    Reply
    • Swagatam says

      December 30, 2015 at 2:33 pm

      Hello Shekhar, your wattage requirement is quite big, it's 3 x 30 = 90 watts, so I would suggest an SMPS circuit for driving it for a reliable and a long lasting performance.

      So first buy a 12V/ 8 amps SMPS or a 24V 4 amp smps unit….then I'll tell you how to proceed.

      Reply
    • Shekhar Jaiswal says

      December 31, 2015 at 3:26 am

      The LED heatsink sized (6"x8") which I have is in a series of 30 and it cannot be modified. Please let me know how do I use this?

      Reply
    • Swagatam says

      December 31, 2015 at 6:55 am

      sorry i could not understand, do you mean the LEDs are clamped with this heatsink from the manufacturer??

      Reply
    • Shekhar Jaiswal says

      January 20, 2016 at 9:03 am

      Sir I purchased a 24v 4a smps what in next process.

      Reply
    • Shekhar Jaiswal says

      January 20, 2016 at 7:47 pm

      Sir I purchased 24v 5amp smps for driving 3w 30pcs led. Waiting your reply

      Reply
    • Swagatam says

      January 21, 2016 at 5:56 am

      please tell me the LED voltage specification.

      Reply
    • Shekhar Jaiswal says

      January 21, 2016 at 2:42 pm

      Description
      1.Power: 3W
      2.Work voltage:DC3.0-3.4V
      3.Current :700mA
      4. efficiency:100-120LM/W
      5. Lumens: 180-200lm
      6.View angle: 120degree

      Reply
    • Swagatam says

      January 22, 2016 at 8:28 am

      make 5 strings having 6 LEDs in series with a 7 ohm/3 watt resistor on each series.

      connect their common (+)/(-) terminals with the SMPS.

      if you use a sufficiently large heatsink then you could eliminate the use of a current controller.

      otherwise you may prefer to include the following circuit in the middle of SMPS and the LED

      https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

      Reply
  40. GOPAL KUMAR says

    December 26, 2015 at 10:44 am

    i want to light 18 ( or 20 ) led smd bulbs (10 watt each) in series with direct mains supply (220 volt ac) using rectifier and some resistance.
    each led is rated at 12volt, 1 amp.
    i don't want to use input capacitor (to make it simple).
    i can increase led numbers to reduce heat production.
    can this arrangement run using half wave rectifier ??. if we use half wave rectifier then what is the risk, i have 6A4 MIC RECTIFIER rated at 420 volt 6 amp.

    Reply
    • Swagatam says

      December 26, 2015 at 1:32 pm

      the input capacitor is compulsory, otherwise your LEDs could get damaged instantly anytime. dividing 230 by 12 gives 19 so probably you could use 20nos of 10 watt LEDs in series.

      The input capacitor could be rated at 10uF/400V (non-polar), and the set up should be exactly as shown in the above article.

      half waver rectification will lower the illumination of the LEDs…but there's no risk in it.

      Reply
    • GOPAL KUMAR says

      January 20, 2016 at 1:59 am

      can we use four 2.5uF capacitors (used in ceiling fan) instead of 10uF capacitor.

      Reply
    • Swagatam says

      January 20, 2016 at 5:20 am

      fan capacitors can be too bulky, a 10uF/4000V electrolytic cap will be much compact

      Reply
  41. SURAJ NAIK says

    September 1, 2015 at 6:40 am

    Hi Swagatam Sir,

    This is Suraj. Thanks for yours help. I tried with a 0.68mf input capacitor instead of 0.33mf and now the leds light much brighter than earlier. Thanks.

    Reply
    • Swagatam says

      September 1, 2015 at 12:37 pm

      That's great Suraj, thanks for updating the info.

      Reply
  42. Lord of Blackspot says

    August 24, 2015 at 5:42 am

    Hi Swagatam Sir,
    I'm Shrinivas Mohod, an amateur photographer. I use 1000W halogen sungun to get desire light. Now I want to replace this gun with LED gun. I've enquired in market, it's cost goes very high comparing to halogen sungun. (about Rs. 7k to 8k where halogen falls at Rs. 550) I've made a couple led circuits given on your blog. Now I want to make an LED light exact like as LED street lamp. Is it possible to make it with the 5W LED module (27 nos) on direct mains 220 (I don't want to use heatsink)? Actually I have sent a plot of light on your facebook timeline. Please check it once, please guide me as possible as you can.
    Waiting 4 reply.
    Thank You so much sir.

    Reply
    • Swagatam says

      August 24, 2015 at 1:36 pm

      Hi Srinivas,

      you can use the idea that's explained in the above post and build it for your requirement. I would recommend using 1 watt LEDs instead of 5 watt since 1 watt LEDs are easier to handle.

      But high watt LED will definitely emit significant amount of heat and you would need to install these over a correctly rated heatsink.

      If you are not interested to use heatsink then probably you would have to employ twice as much as LEDs, for example for getting 1000 watt illumination you would require 2000 numbers of 1 watt LEDs to produce an equivalent amount of light without using any heatsink.

      Reply
    • Swagatam says

      August 24, 2015 at 1:37 pm

      …I don't normally get time to visit FB,

      Reply
  43. SURAJ NAIK says

    August 21, 2015 at 8:44 am

    Hi. This is Suraj. Using your circuit diagram I have created a serial light with below specification. All the bulbs in the serial are lighting but they are not as bright as expected. So what further changes I need to do with it. Please help me. Waiting for your reply.

    Power Supply 220volts
    5mm 20mA 3.2v x 95 white leds
    Input Capacitor 334J 400volts POLYESTER TYPE
    470K 0.25w resistor
    2nd Capacitor 10 Mf 400 volts ELECTROLYTE TYPE
    NTC 100 ohms 0.5watt resistor

    Reply
    • Swagatam says

      August 21, 2015 at 1:32 pm

      Hi Suraj,

      334 = 0.33uF which is quite low…

      try a 474 that's 0.47uF…if still it doesn't provide sufficient brightness, increase it to 0.68uF

      Reply
  44. Swagatam says

    July 9, 2015 at 8:27 am

    yes you can, use a 105/400V capacitor

    Reply
  45. Nitesh Agrawal says

    July 8, 2015 at 5:49 am

    can i use this ckt for run 100 led of 8mm ( vf=3.2v) in series.
    what would be input capacitor value for this ?

    Reply
  46. Swagatam says

    May 1, 2015 at 11:49 am

    For all the series you can use 5uF/400V for the input capacitor, since current is same for all of them.

    C2, and NTC are not critical, C2 can be any high uF capacitor rated at 400V, NTC can be a 11mm, 5 ohm NTC as shown below

    https://www.homemade-circuits.com/2013/02/using-ntc-resistor-as-surge-suppressor.html

    use an inductor also in series with the LED string by winding 200 to 500 turns of 0.5mm super enamel copper wire on any iron core, such as an iron bolt or a ferrite core will also do.

    Reply
  47. Dastgir Shikalgar says

    April 23, 2015 at 7:27 pm

    Sir
    I used……LED .5 watt ,3.5V,170ma, 90 no.in series only change is 3uf cap.
    LEDs are glowing but not satisfactory ….less than 40 watt tube light .so arranged 3+2uf cap current increased from 40ma to 50ma….light increased but not up to mark..so added 2uf ..but current is below 60ma….
    Input voltage is 225 to 230 AC…Out put is 320V…….on load 265V
    Voltage across cap is 50V,………and on load it is 27 V AC
    So please help me….whats wrong …..

    Reply
    • Swagatam says

      April 24, 2015 at 5:16 am

      Dastgir,

      connect the ammeter directly across (+)(-) of the supply, this will show you the actual maximum current capacity of the supply.

      if it's not 60mA per 1uF then your capacitors could be of bad quality, you may want to change it in tat case with a god quality ones.

      Reply
  48. basit momin says

    April 9, 2015 at 10:52 am

    Sir can I use aluminum frame for 1 watt led for above circuit as u said for to paint and firmly pressed the LED on frame that process can also be applied for this circuit

    Reply
    • Swagatam says

      April 10, 2015 at 2:39 am

      an aluminum plate can be used as a heatsink with the above circuit, but since the above circuit does not have a current control feature, therefore the heatsink should be sufficiently large and if possible should be operated under a fan

      Reply
  49. basit momin says

    April 6, 2015 at 6:02 pm

    And how much amps led require

    Reply
    • Swagatam says

      April 7, 2015 at 11:22 am

      for 100 watt module, it would be 3amps

      Reply
  50. basit momin says

    April 5, 2015 at 3:27 pm

    Bt sir how I can get 35v through 230v AC main for the LED

    Reply
    • Swagatam says

      April 6, 2015 at 7:41 am

      through an smps adapter

      Reply
  51. Vijay Patil says

    March 23, 2015 at 5:22 pm

    hi Swagatam i m from Badlapur. This is not my comment but can u pls tell me where can i get this type of raw material for led circuits thanks

    Reply
    • Swagatam says

      March 24, 2015 at 5:16 am

      Hi Vijay, you will have to come to Lamington Road in Grant Road (Mumbai) for procuring the above parts or any related electronic part

      Reply
    • Swagatam says

      March 24, 2015 at 5:17 am

      …you can also try the online option for the same…

      Reply
  52. Manoj kumar says

    January 25, 2015 at 6:52 am

    hello swagatam can u plz tel me how can we calculate zener volt and watt?
    i m using 20 led, 40 led ,and 60 led in 3 diffrent circuit…..plz help me with zener value …
    thanks

    Reply
    • Swagatam says

      January 25, 2015 at 2:46 pm

      Hello manj, the zener volt should be a few volts above the total forward voltage of the LEDs and wattage twice that of the LED series wattage.

      If we take the first example in your case, it would be as follows:

      zener voltage = 20 x 3.3 = 66V so it should be 80V.

      zener wattage = 2(wattage of the LED used)

      example if 1 watt LEDs are used then the wattage of the zener would be

      2(1) = 2 watt

      Reply
    • Swagatam says

      January 25, 2015 at 2:55 pm

      ….sorry the zener wattage will be = capacitor max current output x (supply V – LED fwd V)

      if we assume the caapcitor current to be 500mA, then for the 20nos 1 watt LEDs it would be

      0.5(310 – 66) = 122 watts

      to avoid this huge value, the difference between the supply and the LeD fwd voltage should be as small as possible.

      Reply
    • Manoj kumar says

      January 25, 2015 at 9:15 pm

      Thank you so much my friend.

      Reply
  53. Pritam Bhowmik says

    January 11, 2015 at 5:05 pm

    Bro, i understand your explanations. I know that in case of transformerless designs it is preferred that the source voltage and load voltage be identical to avoid the surge issues etc.
    but i wish to drive minimum number of leds with full brightness for ensuring my light efficiency and also the less cost. 50 leds will cost me a lot of money. waiting for your suggestions.

    Reply
    • Swagatam says

      January 12, 2015 at 4:08 pm

      Bro, in that case you will have to go for a SMPS unit, because with a capacitive PS and few LEDs you can never achieve the desired results

      Reply
  54. Pritam Bhowmik says

    January 10, 2015 at 5:07 pm

    Dear swagatam ! u told that 25, 1w leds would not give optimal illumination, but my concern is to replace my old tube light(28w) in my bed room. in that case 30 , 1w leds should give sufficient light in my bedroom only. your concern?? what glue should i use to stick leds on heatsink and how??

    Reply
    • Swagatam says

      January 11, 2015 at 3:30 am

      Dear Pritam,

      for ensuring optimal response the supply AC V spec must be close to the load V spec.

      25 x 3.3 = 82.5V, and the input is 220V so the difference is wide that's why you wouldn't get an optimal output….but adding 5 more LEDs may compensate the inefficiency.

      You can use 40/50 LEDs with a 1uF/400V capacitor, this would provide nearly 25watts of light output without heating the 1 watt LEDs and you wouldn't need to put the aluminum strip.

      Reply
  55. Pritam Bhowmik says

    January 8, 2015 at 12:05 pm

    for heatsink i am using alluminium channel used for glass windows. i am clamping the 1 w led by fevikwik on the alluminium panels.. it should sink all the heat..

    Reply
    • Swagatam says

      January 8, 2015 at 3:03 pm

      sticking with fewikwik is OK but not the recommended method, may just work, press it hard to reduce the film thickness between the LeD base and the aluminum.

      Reply
  56. Pritam Bhowmik says

    January 8, 2015 at 12:01 pm

    hi! i want to drive 25 pcs of 1w led usinf this ckt. just replacing 5uf with 3.3uf, removing ntc, adding 10uf 450v cap at the rectifier o/p and a zener diode of (25*3.3)=82.5v 1w for protection and a 500ma fuse at the i/p.. will it be a safe idea??pls reply

    Reply
    • Swagatam says

      January 8, 2015 at 3:00 pm

      Hi, with 25 nos of LEDs the efficiency of the circuit will drop by a lot and the illumination will not be optimal. for ensuring optimal response the supply AC V spec must be close to the load V spec.

      NTC is a must in any case and must be included, rest of the modifications are OK.

      Reply
  57. sat says

    November 27, 2014 at 5:35 am

    Do I need HEAT SINK for 93x1w LEDs ? Would the current be round 100mA or 350mA ?

    Reply
    • Swagatam says

      November 27, 2014 at 9:04 am

      yes you will need it, a large one, possibly with a cooling fan…the current would be 350mA

      Reply
  58. Mike Zets says

    October 8, 2014 at 3:18 am

    Please help with a very small but important project.
    LED Latching Circuit using Transistor.

    Power Supply: 3 or 6VDC
    Load: 3 or 4 LEDs (I can calculate resistor sizes needed)
    On Switch: Momenatry
    Separate Off Switch, also Momentary

    I'm looking for a SIMPLE transistor circuit that will turn on LEDs when Momentary ON Switch is depressed and STAY lit until the Momentary OFF Switch is depressed. This should be a simple ON/OFF circuit that latches in the ON condition until the OFF Switch interrupts the latched circuit. I have little knowledge in PNP. NPN, MOSFET devices, so I would very much appreciate it if you would select a small, inexpensive transistor for this circuit..

    Reply
    • Swagatam says

      October 8, 2014 at 3:52 pm

      Yes it's possible but I am not sure about the accuracy of a transistorized circuit….just Google transistor flip flop circuit or transistor bistable circuit…you'll probably find many of these circuits.

      However if you implement this using an IC, you would be able to achieve a highly efficient and a reliable design.

      A transistorized design is shown below:

      https://www.homemade-circuits.com/2014/03/transistor-bistable-flip-flop-circuits.html

      and IC circuits can be witnessed below:

      https://www.homemade-circuits.com/2011/12/build-these-simple-flip-flop-circuits.html

      Reply
  59. PRITESH NAIK says

    September 22, 2014 at 5:11 am

    I forgot to mention the voltage in my previous message, which is 220volts . Thanks

    Reply
    • Swagatam says

      September 22, 2014 at 8:53 am

      Hello Pritesh, for 95 LEDs use 0.33uF/400V for the input capacitor, NTC may not be necessary, rest all can be kept as shown in the above diagram.

      Reply
  60. PRITESH NAIK says

    September 22, 2014 at 5:07 am

    Hello sir
    I've created the rope light & is working fine. Thanks to you.
    Now for 95 leds of specification 5mm 20mA 3.2v white what further modification would be required in yours circuit. Will the value of resistors, NTC, etc will also change?
    Waiting for yours reply.

    Reply
  61. PRITESH NAIK says

    September 18, 2014 at 8:29 am

    Hello sir

    I wish to create a rope light of 50 white leds with ac 220 supply. I want to replace all bulbs in the rope light with leds, as bulbs fuse now & then. Ive bought the leds. Please guide me with the circuit diagram with capacitor, resistors etc & how to go about. Please…

    Reply
    • Swagatam says

      September 19, 2014 at 1:25 am

      Hello Pritesh, you can use the same circuit which is shown in the above article, if the LEds are 5mm type then replace the 5uF capacitor with a 0.47uF/400V capacitor. that's all

      connect all the LEDs in series and connect the ends as described in the above article.

      Reply
    • Shekhar Jaiswal says

      December 31, 2015 at 3:21 am

      The LED heatsink which I have is in a series of 30 and it cannot be modified. Please let me know how do I use this ?

      Reply
  62. sunny says

    September 3, 2014 at 3:50 pm

    hello sir,
    please suggest some initial and basic ideas for starting led tube lights and emergency lights production business regarding initial capital manpower space and other requirements as nobody other can not suggest better than you. what basic problems i can face while starting business and setting up it. your suggestions will be very appreciative and beneficial.
    regards
    sunny pawar

    Reply
    • Swagatam says

      September 4, 2014 at 4:01 am

      Hello Sunny,

      I can only suggest suitable LED tube light and driver circuits, I have no idea regarding the business part of the subject.

      Reply
    • sunny says

      September 6, 2014 at 4:47 pm

      Hello sir,
      Its okay sir. Please suggest some efficient and reliable led drivers for tubes and bulbs for business purposes. It will be a great help for me.
      Regards
      Sunny

      Reply
    • Swagatam says

      September 8, 2014 at 4:24 am

      Hello Sunny,

      Here are a couple of designs that you could try:

      https://www.homemade-circuits.com/2014/02/simple-1-watt-to-12-watt-smps-led.html

      The above is cheap, reliable but a mains non-isolated type.

      The following are a little costly but fully isolated from mains:

      https://www.homemade-circuits.com/2012/03/how-to-make-simple-12-v-1-amp-switch.html

      https://www.homemade-circuits.com/2014/02/220v-smps-cell-phone-charger-circuit.html

      Reply
  63. jideofor5050 says

    May 13, 2014 at 9:11 am

    Hi! Sir, it's been a long time. Please sir,i have a question. I checked the datasheet of transistor 2N3055 and it said that Collector current(max)=15A, Collector-emitter voltage(max)=60V, Collector-base voltage(max)=100V and Emitter-base voltage(max)=7V. I want to use one of this transistor to design a class A amplifier circuit that can receive a power supply of 45V. But i want to design the voltage divider that can set its base reference voltage, and i want the output of the voltage divider to be around 35V. But my fear is that the 35V would be greater than the 7V emitter-base maximum voltage rating. Please how can i calculate the R1 and R2 that will form the voltage divider network to produce 35V from the 45V power supply without damaging the transistor? I tried it using a voltage divider that was producing 18V to the base of 2N3055 from a 20V power supply and it worked fine, but nw i want to increase the power supply to 45V and the voltage divider's output set to produce 35V but i want to confirm it is will be right and proberbly the right value to use for R1 and R2 for this result. Please sir, show me in full calculations on how you calculated their values. Thanks!

    Reply
    • Swagatam says

      May 14, 2014 at 3:53 am

      Hi Jideofor, Although I am not sure how and what you are trying to implement, because there are many class A amplifiers circuits online perfectly optimized and tested which you can simply copy.

      7V is the emitter-base voltage, not base-emitter, so please do not confuse them with each other.

      You'll need to take care about base-emiiter saturating voltage which is 1.5V for 2N3055

      The formula for calculating the base resistor of any BJT is given in this article:

      https://www.homemade-circuits.com/2012/01/how-to-make-relay-driver-stage-in.html

      Reply
  64. chaand tatra says

    April 25, 2014 at 6:36 am

    sir ui make the circuit of fm bugger circuit from electronichub site .i sed the values of 47.8uH and 50pF of tank circuit but no result at proteous .canu guide mu?????

    Reply
    • Swagatam says

      April 25, 2014 at 12:11 pm

      chaand, send the diagram to my email ID I'll check it

      Reply
  65. jideofor5050 says

    April 23, 2014 at 12:59 pm

    Sir you are getting it all wrong. I said the Ic 4863's outputs are not ground compatible, and getting the outputs with respect to ground will make the ic to produce 2v instead of 8v, because its speakers are not connected with respect to ground (the outputs of the Ic 4863 is just like the output of TDA7560, non of them came from GND) and it is producing more than enough power to drive the TDA7560(without connection to ground. But from ground, the output will reduce. Just guide me on how to configure the op amp lm324 as preamp

    Reply
    • Swagatam says

      April 24, 2014 at 7:50 am

      Jideofor, single-ended amplifiers will also respond to its output directly. It's important to confirm first whether your amp is alright or not.

      I do not have any idea how to make a LM324 driver stage for it.

      Reply
  66. jideofor5050 says

    April 23, 2014 at 6:41 am

    Ok sir. I measured the output voltage from the Ic 4863 that went to its speakers and it measured upto 8v(while music was playing), but when i measured the ouputs with respect to ground, it would produce at most 2v(while music was playing). And if i integrate a speaker to its output with respect to ground as you suggested, the music is usually low. My question is can i add an op-amp based preamp at its outputs to boost the outputs of the Ic 4863 from 2v to 8v so that the signal coming from its outputs with respect to ground would be the same as the one coming out of it without respect to ground? So that when i feed the 8v to the TDA7560's inputs, it will reach 51w. If it is possible, direct me on how to connect the following pins of the Lm324 to start functioning as the voltage amplifier(non-inverting inputs, inverting inputs and outputs) of all its stages because i want to make use of the whole 4 x op-amp stages inside the lm324 to feed the TDA7560 since its inputs is 4 in number and the outputs of the Ic 4863 with respect to ground is also 4 in number. Please direct me on how to calculate the feedback resistors too for defining the lm324's voltage gain, and finally the right supply voltage to use for the lm324

    Reply
    • Swagatam says

      April 23, 2014 at 12:00 pm

      LM4863 is a powerful audio amp by itself and it's output should be more than enough for driving LM7560…no need of any external stages.

      your construction may be incorrect somewhere, check it properly and as I suggested earlier you should use the recommended PCB for making the amplifier for eliminating any chances of faults and doubts..

      Reply
  67. tonisage says

    April 22, 2014 at 8:00 am

    What if it is DC? Joule thief is more preferable?

    Reply
    • Swagatam says

      April 23, 2014 at 4:29 am

      for low DC applications and if control is not important, joule thief concept may be chosen

      Reply
  68. tonisage says

    April 16, 2014 at 6:33 am

    Hello swagatam…. Its been a while now and that's because I av bin so busy dis year. Pls I need ur help again. I want 2build an LED circuitry that is efficient at consuming very low power of 60w for 11 rooms in a house. Which will b better, a JOULE THIEF or PWM circuit. Thankz

    Reply
    • Swagatam says

      April 16, 2014 at 8:36 am

      Hello tonisage,

      a joule thief or a PWM both are efficient depending upon the dimensions of the intended input/put ranges.
      these are efficient because they do not waste energy while operating, however the input power will be always equal to the output no matter which circuit is used.

      If your application is at mains AC level, you can opt for a PWM driver circuit.

      Reply
  69. jideofor5050 says

    April 13, 2014 at 8:30 am

    Sir i am having a challenge on this: i have an Mp3 with Ic 4863 that is dual channel( two outputs with speakers, rated 3w, 4 ohms) i want to remove the speakers and replace it with any of the input pins of the Ic TDA7560(so that the TDA7560 can amplify it further). But my problem is that the output pins from the Mp3 that went to the 3w, 4 ohms speakers has none that is connected to ground(GND), but the inputs of TDA7560 is ground compatible(ie, its inputs are connected with respect to ground; GND). My question is how can i do this because if i should go ahead and connect it as required by the TDA7560 input schematic labelling it would amount to grounding two of Mp3's output pins wich i think will be harmfuld to its Ic(4863). Please direct me on what to do. Thanks!

    Reply
    • Swagatam says

      April 14, 2014 at 11:52 am

      Jideofor, just make the grounds of the TDA7560 and 4863 common, after this you can simply integrate the inputs of the TDA to any point that may be producing the audio in the MP3 system

      Reply
  70. jideofor5050 says

    April 7, 2014 at 7:53 pm

    Ok. Sir what is the minimum input voltage for the IC TDA7560? I could not find it in its datasheet

    Reply
    • Swagatam says

      April 8, 2014 at 6:42 am

      apply the input through a pot, as a volume control

      Reply
  71. jideofor5050 says

    April 3, 2014 at 8:39 pm

    Please sir, Is it possible to get 4 ohms speaker from connecting 2 x 8 ohms speakers in parallel?[ie, R=(R1)(R2)/R1 + R2 ]. For instance, the IC, TDA7560 can produce 4 x 45w in 4 ohms speaker according to its datasheet. So does it mean that if i connect 2 x 8 ohms speakers in parallel, then connect it at the output of the IC, wil it produce the same 45w power as it would have done in a single 4 ohms speaker? Please help! ThanksPlease sir, Is it possible to get 4 ohms speaker from connecting 2 x 8 ohms speakers in parallel?[ie, R=(R1)(R2)/R1 + R2 ]. For instance, the IC, TDA7560 can produce 4 x 45w in 4 ohms speaker according to its datasheet. So does it mean that if i connect 2 x 8 ohms speakers in parallel, then connect it at the output of the IC, wil it produce the same 45w power as it would have done in a single 4 ohms speaker? Please help! Thanks

    Reply
    • Swagatam says

      April 4, 2014 at 8:15 am

      Yes it's possible to put two 8 ohm speakers in parallel for making a 4 ohm equivalent

      Reply

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