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Boost Converter Calculator (Non-Isolated)

This calculator will help you to design and find the optimal inductor value for a non-isolated boost (step-up) converter circuit, ensuring that your circuit works with an efficient operation with a 30% ripple current.

Boost Converter Inductor Calculator

Calculates required inductance assuming an ideal converter and a 30% target ripple current.

Results:

Duty Cycle (D): 0 %

Estimated Input Current (Iin): 0 A

Optimal Inductor Value (L): 0 µH

Calculator by homemade-circuits.com

How to Use the Boost Converter Inductor Calculator

Steps to Use:

Enter the Input Voltage (Vin) = The voltage from your power source which you want to boost (e.g lets say 12V).
Enter the Output Voltage (Vout) = The desired boosted voltage value which you want at the output (e.g let us say 220V).
Enter the Switching Frequency (kHz) = The PWM switching frequency of your astable multivibrator circuit (e.g you can set it up to work with 50 kHz).
Enter the Output Current (A) = The expected load current, which you want to supply the connected load at the output (e.g 1A).
Click the "Calculate" Button = The results will then show up in the relevant fields:

  • Duty Cycle (%) = How long the switch stays ON in one cycle.
  • Optimal Inductor Value (µH) = The required inductor size for stable operation.

Example Calculation

Given:

  • Vin = 12 V
  • Vout = 220 V
  • f = 50 kHz = 50,000 Hz
  • Iout = 1 A

Step 1: Duty Cycle (D)

Formula:

D = 1 − (Vin / Vout)

Substituting:

D = 1 − (12 / 220)
= 1 − 0.054545
= 0.945455

Therefore....

D = 94.55%

Step 2: Estimated Input Current (Iin)

Formula:

Iin = Iout / (1 − D)

Substituting:

Iin = 1 / (1 − 0.945455)
= 1 / 0.054545
= 18.33 A

Therefore,

Iin ≈ 18.33 A

Step 3: Ripple Current (ΔIL)

If "Input Current (Recommended)" is selected:

ΔIL = 0.3 × Iin
= 0.3 × 18.33
= 5.50 A

Step 4: Inductor Value

Formula:

L = (Vin × D) / (ΔIL × f)

Substituting:

L = (12 × 0.945455) / (5.50 × 50,000)
= 11.345 / 275,000
= 0.00004125 H

Therefore,

L = 41.25 µH

Final Results (Using Ripple Based on Iin)

  • Duty Cycle: 94.55%
  • Estimated Input Current: 18.33 A
  • Ripple Current: 5.50 A
  • Optimal Inductor: 41.25 µH

As you can see, the duty cycle is so high at 95% which is a bad thing, so boosting voltage with this circuit from 12V to 220V looks like a bad idea.

So better to go with flyback SMPS topology instead.

Reader Interactions

Questions & Answers

Total Posts: 8
Newest Oldest
vyas
July 12, 2025 • 1 year ago #184401

I am not a electronic student and a chemistry student. Hence I asked you to give me circuit schematic so that I could directly jump into my experiments. I have a TV LOT of ferrite core and 28 K V output. More over it has a diode builtin its output. So I thought I will wind some wire on the core and get the required voltage.
SO try to understand my problem and give me solution.
Thanks and best regards.

Reply
SwagatamAdmin
July 12, 2025 • 1 year ago #184402

Vyas, I do not know much about the ferrite core used in TV LOT coil, and have no such calculator to calculate a LOT winding.
If you can use a standard ferrite E-core for your boost converter then I can probably help.

Reply
David
July 14, 2025 • 1 year ago #184448

I can’t find BD31 for sale. Is the part number correct?

Reply
SwagatamAdmin
July 14, 2025 • 1 year ago #184458

The transistor number is not critical, you can try any transistor of your choice by appropriately matching the parameters.

Reply
NgPark
February 17, 2026 • 8 months ago #201221

Hello Mr. Swagatam, thank you so much for everything you do for us. We are becoming increasingly skilled and very confident in this field of electronics thanks to you and your expertise. But currently, my biggest problem is this: I still haven’t managed to properly size the complete winding of a switching power supply.

Reply
SwagatamAdmin
February 17, 2026 • 8 months ago #201226

Hello NgPark,
Thank you for your kind words, I am glad you found my circuits helpful..
Can you please tell me which circuit and topology have you tried, and what kind of difficulties are you facing? I will try my best to sort it for you…please let me know..

Reply
Ola
June 23, 2026 • 3 months ago #208785

Please (1) what is the output voltage of this boost converter circuit and (2) where is the battery negative input voltage terminal,only the battery positive terminal voltage (+5 to 12) is indicated in the circuit.I mean where can I connect battery negative wire to for input voltage

Reply
SwagatamAdmin
June 23, 2026 • 3 months ago #208792

You have to decide what output voltage you want…and then calculate accordingly…
The pin#1 line of IC 555 is the ground line or the battery negative line…

Reply

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