• Skip to main content
  • Skip to primary sidebar

Homemade Circuit Projects

Get free circuit help 24/7

New Projects | Privacy Policy | About us | Contact | Disclaimer | Copyright | Videos | Circuits for Beginners | Basic Circuits | Hobby Projects | Transistor Circuits | LED Drivers 

You are here: Home / Inverter Circuits / Grid Mains to Generator Changeover Relay Circuit

Grid Mains to Generator Changeover Relay Circuit

Last Updated on October 8, 2021 by Swagatam 167 Comments

caution electricity can be dangerous

The post explains a simple configuration which can be used as a automatic changeover circuit for switching AC grid mains to generator mains, during power failures or outages.

The explained circuit will effectively switch the connected appliances to the generator mains during power failure however it won't be able to switch start the generator automatically, this will need to be done manually, because most generators involve a difficult mechanical actuation procedure.

How it Works

Referring to the given diagram  we can see a simple circuit comprising of a TP relay (triple pole relay) as shown below, and a transformerless power supply circuit.

The input of the transformerless power supply circuit is connected to the mains 220V or 120V input.

When mains power is present, the connected relay activates with this power and switches ON the load or the appliances via its N/O contacts.

Conversely when mains power fails, the relay deactivates and connects with the N/C contacts which may be wired up with the generator mains.

Now as soon as the generator is pulled started, the mains finds its way through the connected N/O contacts of the relay to the appliances.

The third set of contacts is used for enabling and disabling of the CDI unit of the generator so that when mains is restored, the generator is automatically halted.

Simple yet effective.....

Circuit Diagram

3 Phase Grid to Generator Changeover Circuit

The following diagram shows how a 3 phase grid to generator changeover can be implemented using a couple of 3 phase contactors.

How the Circuit Works

Let's assume mains AC is not available, and generator is switched ON by the left side relay.

In this situation the center relay will be deactivated, and its pole will be connected with its N/C contact, so that the +12V DC from the generator passes through the N/C contact and actuates the bottom/right 3 phase generator contactor.

The top/right grid mains contactor remains switched OFF due to the absence of a +12V DC.

Therefore, the generator AC flows through this bottom/right contactor and operates the connected appliances or load.

Now, suppose the mains grid AC restores.

The left side relay activates and turns OFF the generator. Also, simultaneously the center relay switches ON through the +12V from the grid mains.

The center relay pole now shifts from N/C to N/O, so that the +12V from the mains grid AC passes through the N/O contacts and actuates the top/right contactor. The bottom/right generator contactor is simultaneously switched OFF.

With the top/right contactor switched ON, the grid AC now becomes available to the load.

Again, if the mains AC fails, the left side relay deactivates, switching ON the generator procedures, the center relay connects with its N/C contacts, turning on the generator 3 phase contactors and turning OFF the grid contactors.

If you are unable to get the above 12V electromechanical relay/contactor, you can go for a 3 phase SSR contactor instead, as shown below.

You'll also like:

  • 1.  Inverter Circuit with Feedback Control
  • 2.  5kva Ferrite Core Inverter Circuit – Full Working Diagram with Calculation Details
  • 3.  Grid-tie Inverter (GTI) Circuit Using SCR
  • 4.  Simple 48V Inverter Circuit
  • 5.  How to Design a Solar Inverter Circuit
  • 6.  Solar Boost Charger Circuit with LED Driver Dimmer

About Swagatam

I am an electronic engineer (dipIETE ), hobbyist, inventor, schematic/PCB designer, manufacturer. I am also the founder of the website: https://www.homemade-circuits.com/, where I love sharing my innovative circuit ideas and tutorials.
If you have any circuit related query, you may interact through comments, I'll be most happy to help!

Reader Interactions

Comments

    Have Questions? Please post your comments below for quick replies! Comments should be related to the above artcile Cancel reply

    Your email address will not be published. Required fields are marked *

  1. Moses says

    January 28, 2022

    Good day sir, please I need a circuit that will automatically switch on a generator that has manual start facility when the mains power is off. That is just what I want

    Reply
    • Swagatam says

      January 29, 2022

      Moses, I think you should use a readymade control box which has automatic start and stop facility, building a circuit can be complex because generators cannot be started just by a push of a button

      Reply
  2. Dan Buchan says

    November 30, 2021

    Hi, thanks for your informative page, just what I was looking for. In the first diagram you have a capacitor “474” – 474 what?

    Thanks, Dan

    Reply
    • Dan Buchan says

      November 30, 2021

      I have a suggestion. How difficult would it be to add some sort of timer to the CDI switch output so the generator can run with the mains on, then be switched to when the mains goes off, and then be killed when the mains comes on again? This would allow you to test the switchover from mains to generator.

      Reply
      • Swagatam says

        November 30, 2021

        For delaying the CDI switch in the first diagram, you will have to isolate the CDI switch with a separate relay which must be connected with the main relay. The main relay now becomes DPDT relay and the CDI relay becomes SPDT relay. The timer could be added with this SPDT relay

        Reply
    • Swagatam says

      November 30, 2021

      Hi, the capacitor 474 is equivalent to a 0.47uF/400C PPC capacitor

      Reply
      • Dan Buchan says

        November 30, 2021

        Thanks!

        Reply
  3. Olakunle Roleola says

    October 6, 2021

    Yes, the wiring is very simple. But my fear is if generator is switched on already and suddenly, mains supply becomes available, if your are using AH3-3 delay relay off timer, the pole of the center relay clicks the NO to power mains contactor (while generator runs for few seconds or minutes depending on the set timing to switch off), power supply from generator will still find its way to the mains circuitry via pole to the NO contacts of the center relay which can cause a short circuit.

    Reply
    • Swagatam says

      October 6, 2021

      The operation of the center relay can never keep the two contactors ON at the same instant. When it moves to N/O, the N/C side contactor releases, and vice versa.

      Reply
      • Olakunle Roleola says

        October 7, 2021

        Having gone through the schematic diagram diligently, I ran a simulation on Proteus CAD. These are my observations
        1. Connecting different power supply on the pole of center relay is dangerous should the relay fails.
        2. Mains power supply takes priority over generator that’s why on the center relay, NO contact is for mains, NC- generator and pole, load. It’s best to separate these contacts accordingly.
        3. If you are using a delay-relay timer, the circuit can poise an hazard in that when generator is running and mains supply is available, generator will still be running. After the time interval of the timer lapses, generator stops working. You can see why generator and mains shouldn’t be connected to the pole.

        Resolution
        1. Disconnect generator +12V power supply from pole of center relay and connect pole back to +12V mains power supply (as in your previous schematic diagram before changing it to the present one). Now, disconnect the upper generator contactor coil from NC of center relay and connect it to generator +12V power supply. Since the lower contactor coil of both generator and mains are connected to ground, that forms the interlock. This arrangement is situable if you want to use a delay-relay timer. That coil will be connected to a timer. The moment generator starts, it will be delay the supply like 20secs (depending on the setting) before powering the load. By that time, the generator would have attained its maximum speed.

        2. You can still maintain your previous schematic diagram which is ok.

        Reply
        • Swagatam says

          October 7, 2021

          It seems you did not understand the second schematic, that’s why you have opted for a proteus simulation….

          the wring is so simple it can be simulated in mind to know the results.

          The pole of the relay is connected to 12V DC from the generator and the mains grid AC, and the N/O N/C contacts are connected to the coils of the contactor relay.

          There’s no AC present anywhere on the pole of the center relay.

          The center relay only controls the contactor coils.

          If the center relay fails, at the most there will be no AC to the load….and that’s all…there is absolutely no chance of any hazardous situation.

          The two contactors on the extreme right can NEVER EVER operate at the same time, and therefore there’s absolutely no chance of any electrical hazard.

          Reply
          • Swagatam says

            October 7, 2021

            I have not used any delay relay timer for the contactors, that is your version, and might require a completely different circuit.

            Reply
          • Olakunle Roleola says

            October 8, 2021

            Your diagram, among others is too simple for me not to understand it. Using Proteus has nothing to do with my logic abilities. I use it to simulate all my designs and to also check mate possible features or amendments where necessary. If you say what you did is ok, then no problem. We are all entitled to our opinions.

            Besides, what do you mean by strong 12VDC from generator and mains? I asked you a simple question that where lies the interlock in your connections. But you seem confused not to understand but instead you change the circuit diagram of which the previous diagram is much more better that the present one.

            Reply
            • Swagatam says

              October 8, 2021

              Again, you have neither understood my previous diagram nor the updated one, and yet you jumped to conclusions and opinions, which are misleading and wrong.

              The previous diagram did not have a 12V from the generator, then how could the generator side contactor operate when the center relay contacts connect to the N/C points? To correct this, I added the +12V from the generator.

              If you have used some external delay/relay with my circuit then that’s your problem. I cannot suggest about it since I have not seen the schematic.

              Although not required, a delay feature can be added with the center relay and should be discretely built without depending on external circuits. In fact I have already provided the delay feature by adding a 1000uF capacitor with the center relay coil.

              Proteus is a good software, but it is good only as long as the user has good knowledge of electronics, otherwise the results can be erroneous.

              The bold 12V indicates only a DC is involved to operate the relays, and two DCs create nothing hazardous with the center relay….

              The second diagram is fail-safe, failproof, hazard proof, under all circumstances.

              Reply
            • Swagatam says

              October 8, 2021

              You say you understood the diagrams, and then you ask whether it has an interlock?

              The center relay ensures the interlock feature.

              The center relay ensures that the two contactors can never operate at the same time.

              I think I have already explained this many times, it’s no point discussing the same thing again and again.

              Reply
      • Olakunle Roleola says

        October 18, 2021

        Hi Swagatam, how are you doing? Having gone through the circuit thoroughly, I now realized that I have been mistaken all along. Without void of doubt, the diagram is very much ok. I didn’t do much due diligence on it that resulted to my conclusion. I’m sorry that our last conversation didn’t go well.

        Regards.

        Reply
        • Swagatam says

          October 18, 2021

          Hi Olakunle, I am good, thank you! Not a problem at all! It is just a part of the learning process for all of us! I am glad the confusion is over now! Please keep up the good work!

          Reply
  4. Olakunle Roleola says

    October 5, 2021

    Thank you for that response. Now, how does the relay gets energized (i.e. to supply power to the first contactor) when there is mains supply considering the fact that the pole or (com) of that relay is connected to the generator 12VDC supply?

    Reply
    • Swagatam says

      October 5, 2021

      When mains supply is present the generator will be switched OFF, and the center 12V relay pole will connect with its N/O contacts, and that will allow the Grid mains contactor to energize. The wiring is very simple, please check the 12V path across the relay contacts and the contactor coils….

      Reply
  5. Mike says

    May 14, 2021

    I take it that the control cct is fed from a mains phase ?

    Reply
    • Swagatam says

      May 14, 2021

      yes that’s correct!

      Reply
  6. Vasilis Caravitis says

    December 4, 2020

    I have noticed that all changeover (generator-grid) circuits feature two contactors, one for the generator and one for the grid. Why can’t one contactor, with an array of NO and NC contacts do the job? Possibly extra safety? What can go wrong with a single contactor?
    Thanks in advance.

    Reply
    • Swagatam says

      December 4, 2020

      Can you show me the contactor diagram link? I’ll try to figure it out.

      Reply
      • Vasilis Caravitis says

        December 4, 2020

        The schematic is previously on this page (near the top).

        Reply
        • Swagatam says

          December 5, 2020

          Accommodating all the mechanism inside one unit can make the system congested and cluttered which may not be recommended for high power systems.

          Reply
  7. Olakunle Roleola says

    June 8, 2020

    Hi, I have four questions:

    1. What are the current ratings of the two contactors?

    2. What is the current rating of the relay?

    3. From the above diagram, I guess it can be used for kick starter generator? And if so, why is there no stop wires/terminal to switch off generator manually the way there is start wire in the diagram?

    4. How can a timer and buzzer be incorporated into the diagram?

    I look forward to each of the answers, thank you.

    Reply
    • Swagatam says

      June 8, 2020

      Hi,
      The contactor current rating will be as per your generator specifications
      The 12V relay can be any small 12V 5 amp relay.
      I have only presented a rough idea regarding the changeover stage, for specific applications you may have to add the required adjustments by your own.
      The last circuit already has a timer in the form of the base 1M/100uF components for BC547, buzzer can be added in parallel to the relay coil

      Reply
      • Olakunle Roleola says

        June 8, 2020

        Ok, thank you. A quick one, the circuit doesn’t not incorporate a stop switch, why?
        2. If size of contactors are 100A which, what must be the current rating of the relay? For every application (irrespective of ratings of contactors), must relay be 12V?

        Reply
        • Swagatam says

          June 9, 2020

          The relay coil voltage rating will depend on the supply voltage used for the circuit.

          Reply
          • Olakunle Roleola says

            June 9, 2020

            Thank you. Can a stop switch be incorporated into the circuit and how?

            Reply
            • Swagatam says

              June 9, 2020

              For what function do you want the stop switch?

              Reply
            • Olakunle Roleola says

              June 9, 2020

              The stop switch is to stop the generator manually. From the diagram, I can see “to generator ignition system” which I have assumed to be the start switch.

              Reply
              • Swagatam says

                June 9, 2020

                Yes, if this voltage is interrupted or switched OFF, the generator will stop working, you can add a series switch with this supply positive.

                Reply
            • Olakunle Roleola says

              June 9, 2020

              Ok. At what point in the diagram can the stop switch be placed in series with the positive supply? By convention, stop switch is connected in Normally Closed position while start button Normally Open.

              Reply
              • Swagatam says

                June 10, 2020

                You can connect the mentioned switch in series with the arrow line which connects with the positive line

                Reply
            • Olakunle Roleola says

              June 10, 2020

              Ok, thank you for your time.

              Reply
      • Olakunle Roleola says

        June 10, 2020

        1. What’s the time duration of the timer?
        2. Does the generator switches off automatically when mains power come?
        3. Does the buzzer sounds the moment mains power come?
        4. For every application, what are those components that need to change based on specifications?

        Reply
        • Swagatam says

          June 10, 2020

          The timer delay will need to be tested and tweaked through some practical experimentation.

          I have replaced the old diagram with a new one which has the stop switch and the generator cut off arrangement addressed correctly.

          For momentary buzzer, you will have to add a 22uF/25V capacitor in series with the buzzer, and a 1 M resistor parallel to the capacitor.
          Sorry I have no idea regarding what needs to be for every application.

          Reply
          • Olakunle Roleola says

            June 10, 2020

            Thank you. Lastly,
            1. You need to incorporate a start switch to that diagram to start a generator manually.
            2. If I am to connect 22uF/25V capacitor in series with the buzzer, and a 1 M resistor parallel to the capacitor, I guess they will still be connected to the relay coil?
            3. What are the functions of the cap and resistor to the buzzer?

            Reply
            • Swagatam says

              June 10, 2020

              I have added the stop switch with the left relay.
              The buzzer will be across the relay coil with the suggested capacitor network.
              When relay is powered, the current also passes through the capacitor and sounds the buzzer, but as the capacitor charges, the current reduces and finally shuts down the buzzer. When the relay deenergizes, the 1M discharges the capacitor for the next cycle.

              Reply
            • Olakunle Roleola says

              June 10, 2020

              Ok, that you. From the previous diagram, is starting the generator manually still valid?

              Reply
              • Swagatam says

                June 11, 2020

                The circuit is intended to be fully automatic, so a manual inclusion may spoil the objective of the circuit, so it is not required.

                Reply
            • Olakunle Roleola says

              June 11, 2020

              Thank you so much. I understand the full automation of the circuit. I don’t think the manual inclusion will spoil the circuit. The essence of the manual start and stop buttons is to operate the generator remotely. The automation comes when there’s no mains power, you start the generator by pushing a start button. When mains power is available, the relay transfers power to the mains and after a preset time, the generator switches off automatically. Now, in a situation whereby mains power may not be available say 4 hours, you can manually push a start button to start the generator and when you don’t feel like running the generator (in the absence of mains power) then you also push a stop button to manually switch off the generator. The circuit is flexible enough to incorporate both manual and automatic operations.

              What if in the case of emergency whereby generator contactor fails during operation, won’t there be an emergency stop button to halt the operation? Please, look into this scenario.

              Thank you.

              Reply
              • Swagatam says

                June 11, 2020

                An ON OFF switch has been already provided in series with the left side relay contacts. If you want a bypass switch you can easily put one right across two arrows, which indicates the wires for the generator CDI circuit

                Reply
            • Olakunle Roleola says

              June 12, 2020

              What is CDI?

              Reply
              • Swagatam says

                June 12, 2020

                Capacitive Discharge Ignition used for operating diesel, petrol based engines.

                Reply
            • Olakunle Roleola says

              June 12, 2020

              Thank you

              Reply
            • Olakunle Roleola says

              June 13, 2020

              Hi, do you have this kind of circuit diagram that uses relays instead of contactors?

              Reply
              • Swagatam says

                June 13, 2020

                Hi, you can replace the contactors with two TPTT relays which is shown in the first image.

                Reply
            • Olakunle Roleola says

              June 13, 2020

              Thank you. Could you please help with the circuit diagram of using such a TPTT relay?

              Reply
              • Swagatam says

                June 14, 2020

                You can do it yourself by checking which contacts of the relay close when the relay coil is energized, and then wire those contacts across the 3 phase lines.

                Reply
            • Olakunle Roleola says

              June 14, 2020

              Ok. I have checked the relay. There are two NO contacts, two NC contacts, two Com contacts and of course the coil. If three phase lines are to be connected to the two NC contacts, where will the last line be connected?

              Reply
              • Swagatam says

                June 14, 2020

                There are 3 sets of contacts, not two, 2 is for DPDT relay (double pole double throw), here we are talking about TPTT relay (triple pole triple throw).

                Reply
            • Olakunle Roleola says

              June 15, 2020

              Ok. I’m unable to wire the connections of TPTT relays. Can you help with a schematic diagram, please?

              Reply
              • Swagatam says

                June 15, 2020

                Connect the 3 contacts of the central pole of one relay to mains 3 phase input, and the other relay’s contacts to generator 3 phase input. Next, connect the 3 N/O contacts of both the relays together and use it as the output for the load.

                Reply
            • Olakunle Roleola says

              June 15, 2020

              I still didn’t get it. Like I said before, there are 2 NO contacts, 2 NC contacts and 2 COMs even though you said there are three sets of contacts exclusively the coil. We are saying the same thing. Total contacts are six. You last comment about the connection is confusing maybe you should be more explicit. For example, connect one line on NC contact, another COM etc

              Reply
            • Olakunle Roleola says

              June 16, 2020

              Hi, I made a mistake. Sorry for the error. I was referring to a DPDT relay contacts and not TPTT relays. Please, ignore my mistake.

              Reply
            • Olakunle Roleola says

              June 16, 2020

              Hi, how are you doing?
              1. Is it possible to use one TPTT relay whereby generator will be connected to NO contact, mains NC contact and load (output) to COMs contact instead of two relays?
              2. Can DPDT or SPDT relays be used for single phase application?
              Thank you.

              Reply
              • Swagatam says

                June 17, 2020

                1. Yes it is possible, the main reason of using contactors was to enable high power load switching, which may not be possible using relays.

                2. Yes DPDT relay can be used for single phase changeover operations, here’s an example design:

                https://www.homemade-circuits.com/automatic-inverter-supply-and-mains/

                Reply
            • Olakunle Roleola says

              June 17, 2020

              Thank you.

              Reply
            • Olakunle Roleola says

              June 17, 2020

              Let’s assume that you use 2nos of 12VDC/30A/220VAC relays with the following connections

              Relay 1
              Mains is connected to NC contact and load (output) NO contact

              Relay 2
              Generator is connected to NC contact and load (output) No contact

              Now, both NO contacts are wired together to make a common load (output). Will the total current be 30A or 60A since both NO contacts (output) has been wired together?

              Reply
              • Swagatam says

                June 17, 2020

                If NC contacts have the mains inputs and the load is connected to NO contacts then how will the AC reach the load? The load must be connected with the pole of the relay and in that case it will be 30 amps max from either sources, 60 amp will burn the individual contacts..

                Reply
                • Swagatam says

                  June 17, 2020

                  Sorry, the second condition is not possible, since joining the poles together will short circuit both the ACs.

                  Reply
            • Olakunle Roleola says

              June 17, 2020

              Ok. That means the two relays cannot add up to 60A isn’t it? It will be 30A for each source. I asked that question because someone said that it will add up since the NO (load) are connected together.

              Reply
              • Swagatam says

                June 17, 2020

                If you connect the N/C contacts in parallel, N/O contacts in parallel and poles in parallel, feed grid at N/O, generator on N/C, load on pole then it will support 60 amps…this is for single phase changeover

                Reply
            • Olakunle Roleola says

              June 17, 2020

              Alright, thank you.

              Reply
            • Olakunle Roleola says

              June 17, 2020

              What’s the principle of Capacitive Discharge Ignition and how does it work?

              Reply
              • Swagatam says

                June 18, 2020

                You can read the following article for more info:

                https://www.homemade-circuits.com/how-to-make-capacitive-discharge/

                Reply
            • Olakunle Roleola says

              June 19, 2020

              Hi, according to you, “an ON OFF switch has been already provided in series with the left side relay contacts”. From the diagram, I can only see “generator cut off” which I will assume that it’s a push button to stop generator remotely. What about the On switch in form of a push button to ignite the generator remotely?

              Reply
              • Swagatam says

                June 19, 2020

                The generator ignition system is not included in the above circuit for simplicity sake. You can refer to the following ATS articles to know more about the procedures:

                https://www.homemade-circuits.com/automatic-transfer-switch-ats-circuit/

                https://www.homemade-circuits.com/petrol-to-lpg-ats-using-solenoid/

                Reply
            • Olakunle Roleola says

              June 19, 2020

              Sorry, I meant Generator starter not ignition system.

              Reply
              • Swagatam says

                June 19, 2020

                How does a generator starter work?

                Reply
            • Olakunle Roleola says

              June 19, 2020

              A generator starter or stopper works on the principle of switching on/off a generator remotely. Generator has a key starter with contacts based on the design. Some have between 3 to 5 contacts such as OFF, Battery, ON, Start and Crank respectively. When you kick start a generator, you are sending a signal from the battery to the kick starter (solenoid) till it cranks and the generator start running.

              For example, I’m leaving in 19th floor of a 25 storey building. It’s very impractical for me to come down to the ground floor to kick start my generator should there be loss of mains and still go down again to switch off generator when mains is available.

              I should be able to control the generator remotely from the 19th floor (expect maintenance). This operation does not nulify the automation of the circuit. But there should be room for manual operation.

              Generator starter is wired to the crank/start contact of the generator (depending on generator design while generator key is on ON position) to a NO push button/switch which I will depress in my house to start generator.

              Generator stopper is wired to the OFF contact of the generator (generator key is still on ON position) to a NC push button/switch which I will depress in my house to stop generator in case I want to run the generator for few hours when mains won’t be available for a longer time.

              Reply
              • Swagatam says

                June 19, 2020

                If you want a manual remote controlled start/stop operation, then you can apply the following concept:

                https://www.homemade-circuits.com/remote-controlled-submersible-pump/

                Reply
            • Olakunle Roleola says

              June 19, 2020

              Correct, nice one bro
              Thank you

              Reply
              • Swagatam says

                June 20, 2020

                Thanks, Glad it helped!

                Reply
            • Olakunle Roleola says

              June 21, 2020

              Thank you Swagatam for everything.

              Reply
              • Swagatam says

                June 21, 2020

                You are welcome Olakunle.

                Reply
            • Olakunle Roleola says

              June 28, 2020

              1. Hi, I have added the buzzer as suggested. I have run the circuit simulation on Proteus. The moment the relay coil is energised, the NO contact (mains) powers the load (lamp) via the pole using a single DPDT relay. The challenge is that the buzzer doesn’t stop the sound. What can I do to stop it the moment mains has come?

              2. Another observation what are the functions of transistor BC557 and resistors 1k and 1k? I noticed that on the simulation, the generator (NC) contact takes priority over mains (NO) in the sense that when I run the simulation, the relay does not activate meaning that lamp connect on poles switches on. When I deleted BC557 from the circuit, relay coil was activated the mains (NO) contact connected the lamp via poles and buzzer sounded indicating that mains is present.

              3. Without the capacitor network, the buzzer still sound when relay coil is energised since it is in parallel with it (coil) like I said before as BC557 has been removed from the circuit during simulations.

              Please, kindly look into this three items as bulleted, thank you.

              Reply
              • Swagatam says

                June 28, 2020

                Hi, I have changed the diagram, please check it now.

                Actually the transistor delay was not necessary, because once the grid fails, the complete transistor circuit fails instantly, due to lack of power so the delay effect also becomes ineffective.

                Now the capacitor directly across the relay coil adds the required delay effect

                I have also amended the buzzer section.

                Reply
            • Olakunle Roleola says

              June 29, 2020

              Thank you. I have checked the circuit and it seems ok. On simulation, mains (NO) contact takes priority over generator (NC) when relay coil has been energised. The only setback is that buzzer is not simulating at all.

              You can also simulate it on Proteus CAD.

              Reply
              • Swagatam says

                June 29, 2020

                The buzzer will also work as specified. You can check it practically with a readymade DC piezo buzzer. The current will enter through the capacitor momentarily causing the buzzer to activate for a few seconds. Once the capacitor charges fully, the sound will stop. When mains fails, the capacitor will discharge through the 2 1k so that it is able to repeat the process again when main restores.

                The buzzer will not sound during mains failure.

                Reply
            • Olakunle Roleola says

              June 29, 2020

              Correct

              Reply
            • Olakunle Roleola says

              June 30, 2020

              Hello, what’s the function of the capacitor 1000uf/25V and why is it in parallel with relay coil?

              Reply
              • Swagatam says

                June 30, 2020

                To enable a delayed switch OFF of the relay when mains AC fails. The relay on the left side switches ON instantly to initiate the generator operations, but the changeover relay operates after some delay, possibly after the generator has started fully.

                Reply
            • Olakunle Roleola says

              June 30, 2020

              1. How will the generator switch off after the load has changed over to mains?
              2. Are you saying that the left relay actuates or switches on the generator the moment mains fails?

              Thanks

              Reply
              • Swagatam says

                June 30, 2020

                Yes the left relay controls the generator operations.

                You can use the following recommended start stop circuit with this relay contacts:

                https://www.homemade-circuits.com/wp-content/uploads/2020/06/borewell-automatic-ONOFF.jpg

                You can ignore the reed switches, and connect the 0.22uF capacitor end of the start circuit with the N/C of the relay, and connect the 0.22uF end of the stop circuit with the N/O of the relay.
                The pole of the relay will connect with the ground.
                But make sure all the grounds of all the circuits are joined in common.,

                Reply
          • Olakunle Roleola says

            July 1, 2020

            How do you connect the left relay for generator start and finish operations?
            Thank you

            Reply
            • Swagatam says

              July 1, 2020

              I think I have explained it in the earlier comment, but it is not for remote control rather for direct integration.

              Reply
            • Olakunle Roleola says

              July 1, 2020

              I know you said that. Just that I’m yet to understand the operation of the left relay.

              Reply
              • Swagatam says

                July 1, 2020

                The N/C contact will trigger the “start” button through the IC 555 monostable circuit when mains fails, and the N/O contact will trigger the stop button through the corresponding IC 555 monostable circuit whens mains is restored. Direct integration means connecting with wires and not through wireless modules.

                Reply
            • Olakunle Roleola says

              July 1, 2020

              What do you mean by direct integration?

              Reply
            • Olakunle Roleola says

              July 2, 2020

              Ok. Another observation is that from the left relay you said “generator cut off” in NC position. What does that mean?
              2. Does generator cut negates this information below?

              https://www.homemade-circuits.com/wp-content/uploads/2020/06/borewell-automatic-ONOFF.jpg

              Reply
              • Swagatam says

                July 2, 2020

                The info on the relay was intended for deactivating the CDI system of the generator, not for the start stop contactor box operation, so it is not relevant to start stop application.

                Reply
            • Olakunle Roleola says

              July 10, 2020

              Hi, from this link,

              https://www.homemade-circuits.com/remote-controlled-submersible-pump/

              How can these controls have effect on generator as the relays are connected to the mains? And if mains is absent, how will the relays be actuated?

              Reply
              • Swagatam says

                July 11, 2020

                Hi, that’s correct, in that case you must have a chargeable battery installed with the generator for the initial starting up of the generator, just as we have in motor car ignition systems.

                Reply
      • Olakunle Roleola says

        July 8, 2020

        Hi, how are you doing? How do you connect the generator to start automatically the moment mains is absent when you are home?
        2. How do you install a by pass or off switch to stop the generator from coming on automatically when you are not home?

        Reply
        • Swagatam says

          July 8, 2020

          I have already explained the start/stop connection details with the N/C, N/O points of the relay in one of the the earlier comments.

          Reply
          • Olakunle Roleola says

            July 8, 2020

            Yes. But I’m yet to have a full grasp of it especially the left hand relay.

            Reply
          • Olakunle Roleola says

            July 11, 2020

            Sure, the generator has a rechargeable battery. How can I connect those relay controls? Thank you.

            Reply
            • Swagatam says

              July 11, 2020

              In that case, connect the circuit positive with the battery positive and negative with battery negative, and connect the N/C, and N/O contacts of the left side relay with the Ic 555 pin 2 as explained in my earlier comment

              .

              Reply
            • Olakunle Roleola says

              July 11, 2020

              Ok. As you know that there are two 555 ICs (one for stop and the other for start). How will they fit in on the left relay in terms of NC and NO? Unless there will be two left relays to accommodate the start and stop? What do you think? Thank you.

              Reply
              • Swagatam says

                July 12, 2020

                The pin2 of the IC 555 “start” circuit will connect with N/C. The pin2 of the IC 555 “stop” circuit will connect with N/O.

                The pole of the relay will connect with the ground line, which must be common to the changeover circuit and the IC 555 circuit both.

                The supply to the IC 555 circuit should be from the battery, and the supply to the changeover circuit should be from an AC/DC adapter

                Reply
            • Olakunle Roleola says

              August 15, 2020

              Hi, if I’m to use two SPDT relays in parallel what will be the connections of the coils as Poles, NCs, and NOs contact are joined in pairs?

              Reply
              • Swagatam says

                August 16, 2020

                If you are trying to increase the current handling capacity of the relay by adding two in parallel, then yes that’s possible. You just have to connect all the identical points of the two relays in parallel including the coil. The coil does not have any polarity, can be connected any way round, but the paralleled coils must have a common freewheeling diode to avoid reverse spike dumping from the relay into the circuit.

                Reply
    • Olakunle Roleola says

      August 10, 2020

      Hi Swagatam, how are you doing? It’s been a long time? My question is can AH3-3 delay timer be used in lieu of the capacitor 1000uf/25V to automatically stop generator?

      Reply
      • Swagatam says

        August 10, 2020

        Hi Olakunle, i am good, thanks, the 1000uF is associated with the relay coil as shown in the diagram , I am not sure how the AH3 device could be replaced with it. I have not yet investigated the AH3 delay timer so I can’t comment much on its integration with this circuit at this moment

        Reply
        • Olakunle Roleola says

          August 13, 2020

          Ok, thank you.

          Reply
        • Olakunle Roleola says

          August 28, 2020

          Hi, how are you doing? The AH-3 device is an eight pin DPDT relay delay timer. Pin 7 looped with Pin 8 or Pin 1 is the Live from mains while Pin 2 Neutral. Pins 8 and 1 are the Poles Pins 3 and 6 are NO contacts while Pins 4 and 5 NC contacts. The application of this device is to either delay ON or OFF a load. So if you want the generator to stop when mains is available is called delayed OFF. You connect generator stop wires to NC contact. If you also want generator to automatically start (delay ON) when mains is not available, you connect generator start wires to NO contact.

          Buzzer (if it is AC) too can be connected in the line with generator stop contact. The moment mains is available, buzzer sounds and after a delay, the sound stops along side the generator.

          Reply
          • Swagatam says

            August 28, 2020

            Hi, from your explanation it seems, the AH3 relay could be powered through the N/O contacts of the 12V relay of the second circuit, for the required ON/OFF actions of the generator. In this situation the 1000uF could be removed

            Reply
            • Olakunle Roleola says

              August 28, 2020

              Yes, the capacitor 1000uf/25V and the left relay need to be removed. Because, this kind of timer has dual power supply (220VAC or 12VDC). The diagram above is DC powered so you can select DC from the timer.

              Connect one of the terminals of buzzer and gen stop wires to Pin 5 (NC) and the other terminals to Pin 2 (-ve). Pins 7 and 2 are the coils while Pin 8 (Common or Pole) and Pin 6 (NO). Pins 7 and 8 take positive supply as pin 2 is negative.

              Reply
              • Swagatam says

                August 29, 2020

                Yes I have roughly studied the details of the device by referring the wiring diagram of the unit online, it looks very useful.

                Reply
            • Olakunle Roleola says

              August 29, 2020

              Yes, very useful.

              Reply
      • Olakunle Roleola says

        August 17, 2020

        Hi, thank you. If the coils are in parallel, connecting mains to NO, load to Poles and generator to NC, don’t you think that if relays are energised from mains, won’t they be activated to the same?

        Reply
        • Swagatam says

          August 17, 2020

          Hi, no that won’t happen, you can clearly see the the situation in the first diagram, the N/C and N/O contacts are aloof and the two ACs can never short with each other.

          Reply
    • Olakunle Roleola says

      October 5, 2021

      Hi, how are you doing? Is there any form of interlock between the utility contactor and that of generator for safety purposes?

      Reply
      • Swagatam says

        October 5, 2021

        Hi, yes the two contactors can never operate together at any instant, and therefore are 100% fail proof. I have corrected the second schematic which previously had some faults.

        Reply
  8. Sunday ifeanyi says

    February 28, 2020

    Please help me out I want to design automatic changeover from two main supply Ac mains and generator. With feature that when the main supply is low I can switch to generator. The circuit diagram please. I like your circuit design

    Reply
    • Swagatam says

      February 28, 2020

      If you connect a 150 V zener in series with the relay coil, that will automatically enable the relay to switch OFF at voltages below 160 V

      Reply
      • Olakunle Roleola says

        July 12, 2020

        I understand that, thank you. Is there anything like “automatic choke” to actuate the generator during startup when the start switch is pressed remotely? Have a pleasant day!

        Reply
        • Swagatam says

          July 12, 2020

          Sorry, I do not have any idea about automatic generator chokes.

          Reply
          • Olakunle Roleola says

            July 12, 2020

            1. What I meant by automatic generator choke is that when you pull the generator to starting it, the choke is opened so that the generator can run smoothly.
            2. Back to my previous comment about the 555IC being connected to the left relay by connecting the pin 2 of the IC as you have stated. I used to know that the pin 2 of the start circuit is connected to the generator solenoid while the other terminal is connected to the second wire of solenoid. The pin 2 of stop circuit is connected to off switch of generator while the other terminal is connected to the generator chassis as ground.

            Reply
            • Swagatam says

              July 13, 2020

              2. The suggested connections for the IC 555 are correct, it is already tested for the borewell contactor start/stop unit. The relay contacts ground the pin2 of the IC alternately which cause the relevant 555 IC outputs to switch ON for a few seconds and operate the relevant start/stop contacts.

              Reply
            • Olakunle Roleola says

              July 13, 2020

              Thank you very much. Could you please explain the first circuit diagram and its mode of operation?

              Reply
              • Swagatam says

                July 14, 2020

                Thank you! In the first diagram the AC changeover to the load is automatic but the generator will need to be started manually by pulling the chord whenever the mains fails. If you need a fully automatic design you can try the following circuit:

                2 Simple Automatic Transfer Switch (ATS) Circuits

                Reply
            • Olakunle Roleola says

              July 14, 2020

              Can you please explain the working principle of the first circuit diagram?

              Reply
  9. Bakare Emmanuel says

    September 25, 2017

    i would want to request and upgrade to this system, to include a buzzer (using ic 555 timer set at 1minute ), two led indicator (one for main one for generator) The system will do two main function, switch from main to generator when power fails and switch back to main when power is restored . It will sound an alarm that will automatically go off after a period of time , say 1 minutes.
    It will have some fail safe features, like , circuit breaker (when main is having low current and one needs to use the generator) and fuse ( for over current protection).

    thanks.
    looking forward to your quick response..

    Reply
    • Swagatam says

      September 26, 2017

      I already have many such upgraded circuits, you can type “ATS” in the search box and find them, you may also search by typing “generator changeover” in the search box for the same.

      Reply
      • Bakare Emmanuel says

        September 26, 2017

        sorry to disturb you . none of the ”ATS”, has anything like i requested. being a newbie and yet to be fully capable of design but undergoing training, this idea came to mind and i will want to build it ..
        please help.

        Reply
        • Swagatam says

          September 27, 2017

          Only the LED indicators are not included in my other similar articles, which can be simply done by adding an LED parallel with the existing relay coil. LED must include a 1K series resistor

          alarm can be made using a small ready made buzzer and wiring it again in parallel with the relay coil. however one of the wires of the buzzer must have a series 100uF capacitor, and a 220K resistor in parallel with this capacitor.

          Reply
  10. gbenga comrade says

    October 25, 2016

    hi sir what kind of relay that can be used for this particular change over or i can make use of 3phase contactor to do it

    Reply
    • Swagatam says

      October 26, 2016

      Gbenga, due to low current contactor cannot be used in this circuit, you must use ordinary 400 ohm type relay here….you can probably use the contacts of this relay to operate the contactor and wire the contactor contacts for the overcharge actions

      Reply
    • Swagatam says

      October 26, 2016

      ….it's not "overcharge", it should be "changeover" actions…

      Reply
  11. Nnaka Stanley says

    October 10, 2016

    Sir, great work on the circuit. But please I need a changeover circuit, this time with three different power sources; generator, AC mains and an inverter supply. So far, what I've come up with is a manual changeover using a bypass, I need one which is automatic. Thanks

    Reply
    • Swagatam says

      October 10, 2016

      Hi NNaka, I already have this design in my website, please search it in the following link

      https://www.homemade-circuits.com/search/label/Relay%20Changeovers

      Reply
  12. priti says

    July 4, 2016

    sir, please tell me about power losses by this changeover circuit.

    Reply
    • Swagatam says

      July 4, 2016

      power consumption will be as per the rating of the relay coil, could be around 50mA, which will be consumed from the AC mains

      Reply
  13. priti says

    July 4, 2016

    if this circuit is used for changeover relay, then how much power losses will take place by the circuit.

    Reply
  14. VINCENT MWENDE says

    October 15, 2015

    great work Swagatam,have learned a lot in the past 6 months.

    Reply
    • Swagatam says

      October 15, 2015

      It's my pleasure Vincent!

      Reply
  15. Unknown says

    July 13, 2015

    If not then what I have to change in this circuit

    Reply
  16. Unknown says

    July 13, 2015

    Hi Sir can I use this above circuit for 40 amp and 63 amp single phase/3phase

    Reply
    • Swagatam says

      July 13, 2015

      yes it can be used but the upper DPDT relay will need to be selected appropriately to handle the large amp.

      also for such huge relay, the activation will need to be done through a AC/DC adapter, a capacitive power supply may not be strong enough….

      Reply
  17. FredoRicko says

    June 10, 2015

    What is the maximum load that a 30A 250VAC can accommodate if used in the circuit above?? Can it power a house with all the basic appliances?? Thanks

    Reply
    • Swagatam says

      June 11, 2015

      yes this much power is more than enough for powering a house with basic appliances.

      The relay will need to be appropriately selected for handling 30A, and also the 474 capacitor which also may need to be upgraded

      Reply
  18. Swagatam says

    June 10, 2015

    use a heavy duty relay with low coil resistance, an decrease the value of the input cap to 2.2uF/400V

    Reply
  19. Qaisar Hussain says

    June 10, 2015

    can you tell how it is possible to overcome changeover time.

    Reply
  20. EKEH EMMANUEL CHIJIOKE says

    May 25, 2015

    how many pole contactor is the one used above? can i use the above changeover system for heavy amperage as in to be used for an entire flat that has up to 3 deep freezers and two ac units with other appliances? put me through please

    Reply
    • Swagatam says

      May 26, 2015

      yes you can use the above circuit for any desired high current application, you just need to change the relays as per the ampere rating of the load, and instead of a capacitive power supply you may have to use a 12V AC/DC adapter for powering the relay coils

      Reply
  21. EKEH EMMANUEL CHIJIOKE says

    May 25, 2015

    thanx for the reply and assistance rendered so far. a have a contactor of LC1D09, it has L1 to L3, T1 to T3 and A1 and A2 two NO n NC that are in the opposite sides of the contactor. i dont know how to use it as a changeover for that your circuit. pls how do i go about it. pls i really need your expectrics. pls come to my rescure

    Reply
    • Swagatam says

      May 26, 2015

      the shown diagram uses it's own recommended relays, it's not meant to be used with a contactor.

      I a sorry I won't be able to interpret the details of your contactor.

      If you are interested to build the above circuit then you may have to incorporate separate relays as per the power specs of the connected load.

      Reply
    • Norie Coquilla says

      October 14, 2015

      Mr. EKE. I have a design of ATS using two Contactors. I'll be glad to share it with if you wish.

      Reply
    • EKEH EMMANUEL CHIJIOKE says

      October 18, 2015

      I will be glad if you would share yours with me. I really appreciate your time and support in rendering assistance to me. Thanks alot.

      Reply
  22. EKEH EMMANUEL CHIJIOKE says

    May 24, 2015

    please i really need your assistance to build and automatic changeover switch of 90amps 220 volts single phase and it should have the ability to switch off the generator set once there is power from the grid

    Reply
    • Swagatam says

      May 25, 2015

      you can use the circuit that's shown in the above article, it exactly matches your requirement.

      Reply
  23. RAHUL V C IFS says

    October 2, 2014

    What is the wattage of 1 megaohm resistance

    Reply
    • Swagatam says

      October 3, 2014

      1/4 watt

      Reply
    • RAHUL V C IFS says

      October 3, 2014

      Thanks

      Reply
    • Henry Ndukwe says

      January 21, 2015

      Hi swagatam can a 373j/400v go in place of the 474/400v in the circuit
      thanks

      Reply
    • Swagatam says

      January 22, 2015

      Hi Henry, if your relay is able to trigger comfortably with this cap then it would be fine

      Reply
  24. Adegbite Abdul Lateef says

    April 10, 2014

    Thanks. How do you connect your CDI GND and cdi gnd with relay.

    Reply
  25. Alfred Emasoga says

    March 31, 2014

    Sir, can one use three SPDT relay connected in parallel, in place of a 3P (three pole) relay? Or would series connection of the three individual coils be a better option?

    Reply
    • Swagatam says

      April 1, 2014

      Alfred, it may be done with a parallel connection, series connection would require three times the coil voltage as the input.

      Reply
  26. preston jose says

    November 2, 2013

    If I need it to connect it to an inverter for mains and when the current goes, the inverter would handle
    What will be the modifications ti do?

    Reply
    • Swagatam says

      November 3, 2013

      You will just need a single DPDT relay, the generator AC will get replaced with inverter AC and the lower CDI section will not be required.

      Reply
    • Michael says

      October 20, 2019

      Hi, I think that the second circuit of 3 phase should be upgraded course they will be failure to operate 3 phase motor incase one or two phases trips ( that is; only 1 or 2 phases have voltage). I think that the circuit operations will fail if there is voltage in that phase connected with relay coil and absence of voltage in either one or the other two remaining phase course will neither switch to generator nor operate 3 phase machine. I am I right?

      Reply
      • Swagatam says

        October 21, 2019

        Hi, missing phase is a different issue actually, and to prevent it we can include a single phasing preventor with the existing circuit to operate the relay coil

        Reply

Primary Sidebar

Calculators

  • 3-Phase Power (15)
  • 324 IC Circuits (19)
  • 4017 IC Circuits (52)
  • 4060 IC Circuits (25)
  • 555 IC Circuits (98)
  • 741 IC Circuits (19)
  • Arduino Engineering Projects (83)
  • Audio and Amplifier Projects (114)
  • Battery Chargers (82)
  • Car and Motorcycle (94)
  • Datasheets (46)
  • Decorative Lighting (Diwali, Christmas) (33)
  • Electronic Components (100)
  • Electronic Devices and Circuit Theory (36)
  • Electronics Tutorial (116)
  • Fish Aquarium (5)
  • Free Energy (34)
  • Fun Projects (13)
  • GSM Projects (9)
  • Health Related (20)
  • Heater Controllers (29)
  • Home Electrical Circuits (102)
  • How to Articles (20)
  • Incubator Related (6)
  • Industrial Electronics (28)
  • Infrared (IR) (40)
  • Inverter Circuits (98)
  • Laser Projects (12)
  • LED and Light Effect (93)
  • LM317/LM338 (21)
  • LM3915 IC (25)
  • Meters and Testers (65)
  • Mini Projects (148)
  • Motor Controller (67)
  • MPPT (7)
  • Oscillator Circuits (26)
  • PIR (Passive Infrared) (8)
  • Power Electronics (34)
  • Power Supply Circuits (77)
  • Radio Circuits (10)
  • Remote Control (48)
  • Security and Alarm (61)
  • Sensors and Detectors (120)
  • SG3525 IC (5)
  • Simple Circuits (75)
  • SMPS (29)
  • Solar Controllers (60)
  • Timer and Delay Relay (53)
  • TL494 IC (5)
  • Transformerless Power Supply (8)
  • Transmitter Circuits (40)
  • Ultrasonic Projects (16)
  • Water Level Controller (45)

Calculators

  • AWG to Millimeter Converter
  • Battery Back up Time Calculator
  • Capacitance Reactance Calculator
  • IC 555 Astable Calculator
  • IC 555 Monostable Calculator
  • Inductance Calculator
  • LC Resonance Calculator
  • LM317, LM338, LM396 Calculator
  • Ohm’s Law Calculator
  • Phase Angle Phase Shift Calculator
  • Power Factor (PF) Calculator
  • Reactance Calculator
  • Small Signal Transistor(BJT) and Diode Quick Datasheet
  • Transistor Astable Calculator
  • Transistor base Resistor Calculator
  • Voltage Divider Calculator
  • Wire Current Calculator
  • Zener Diode Calculator

© 2023 · Swagatam Innovations