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Home » DIY LED Projects » 0.6V to 6V/12V Boost Converter Circuit

0.6V to 6V/12V Boost Converter Circuit

Last Updated on November 24, 2019 by Swagatam 49 Comments

In this post we learn how to make a 0.6V to 6V or 12V boost converter circuit using a single chip MC74VHC1G14, which uses under 1V to operate.

About the IC MC74VHC1G14

Normally, we all know that a silicon transistor would find it difficult functioning below 0.7V, unlike germanium counterparts which are capable of doing it with ease, however nowadays we don't often hear about these devices which have become quite obsolete with time.

The circuit discussed here uses an inexpensive Schmitt trigger NOT gate MC74VHC1G14 from the 74XX TTL  family which are designed to work with voltages well below 0.6V, to be precise even with as low as 0.45V. The device we employ is manufactured by Motorola.

The presented 0.6V to 6V boost converter circuit can be even modified to achieve upto 12V from a 0.6V source.

Referring to the figure below, we see a rather straightforward set up consisting of an oscillator stage using a single NOT gate inverter module as discussed above.


You can also try a Joule Thief Circuit for getting similar results.


Circuit Operation

This NOT gate is very special since it's able to oscillate even at voltage as low as 0.5V which makes it very suitable for the present 0.6V to 6V or 12V boost converter application.

The oscillation frequency here is determined by R1 and C1 which is calculated to be around 100kHz.

The above frequency is fed to the base of an NPN transistor for the required amplification.

C2 makes sure the two IC and the BJT stages are kept isolated from direct contact in order to avoid the low input voltage from dropping below 0.5V

R2 and thee schottky diodes D1 keeps the BJT sufficiently biased for helping an optimal oscillatory response for the transistor.

D2 is another schottky diode which is introduced to keep the charge from C3 disconnected during the switch OFF periods of Q1 otherwise the stored charge inside C3 could get discharged or shorted via Q1.

The IC 7806 at the output is to maintain a fixed 6V irrespective of the boost level created by L1 and the associated converter stages.

L1 must be wound strictly over a ferrite core. The dimension and data of the coil is a matter of some trial and error or it may be procured as a ready made unit for the same.

Circuit Diagram

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About Swagatam

I am an electronic engineer (dipIETE ), hobbyist, inventor, schematic/PCB designer, manufacturer. I am also the founder of the website: https://www.homemade-circuits.com/, where I love sharing my innovative circuit ideas and tutorials.
If you have any circuit related query, you may interact through comments, I'll be most happy to help!

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Reader Interactions

Comments

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  1. Arpan ASR says

    HI bro,
    If i use 7805 inserted of 7806..than it use as a smartphone charger..??

    Reply
    • Swagatam says

      Hi bro, both will work and can be used according to me.

      Reply
      • jindro says

        Sir can u recommend a circuit tha boost li ion bat 3.7 v to 5 v for android phone charger, tnx Sir!

        Reply
        • Swag says

          Jindro, you can use the Joule Thief Circuit as discussed in the following article

          https://www.homemade-circuits.com/make-this-power-bank-circuit-using-37v/

          Reply
  2. Michael Gapasin says

    may i know the code of the diode use here, i am going to try also

    Reply
    • Swagatam says

      you can try BAT41 for the diodes

      Reply
  3. pk94 says

    Hello,
    do you have any recommends for a similar IC ?
    I dont can find and get this IC on a cheap way. Do you have any recommends, does it need to be a Very High Speed CMOS?
    Thanks

    Reply
    • Swagatam says

      hello, I am not sure about an equivalent IC, but a joule thief idea is one option which can be tried for achieving the same results.

      Reply
    • pk94 says

      Does it depend on the NOT gate or the TTL variant ?
      I really want use it, but I can not get this right one.

      Reply
    • Swagatam says

      please check its datasheet.

      Reply
  4. Swagatam says

    thanks neha!

    No it can't be used since a lemon would not produce sufficient current required for the boosting action….

    Reply
  5. Camara Diop says

    How to connect the circuit of 0.6V to 6V/12V Boost Converter
    my mail is: camaradiop001@gmail.com

    Reply
  6. Camara Diop says

    How to connect the circuit of 0.6V to 6V/12V Boost Converter
    my mail is: camaradiop001@gmail.com

    Reply
  7. Camara Diop says

    the scheme of 0.6V to 6V/12V Boost Converter Circuit is complete?

    Reply
  8. Camara Diop says

    how the connection to have 6 v at the output of the system.

    Reply
    • Swagatam says

      the circuit complete, and you must build it exactly as its shown….click on the diagram to enlarge it.

      Reply
  9. Camara Diop says

    Hello. Thanks for the reply. I would like to have a precision compared to al voltage input and sortie.de more I see + 0.5 v at the top of the schema.le less will be connected where.

    Reply
    • Swagatam says

      Hello, the circuit can be used for converting as low as 0.5V into 6V provided the input current is high.

      Reply
  10. Camara Diop says

    What is the number of turns it takes to the coil around the ferrite. If I use 6 v to the entered, what would be the output voltage of the circuit.

    Reply
    • Swagatam says

      for 6V you can use any 555 based boost converter, this circuit is recommended only voltages lower than 2V

      you can also try a joule thief circuit for the same.

      Reply
  11. Uday says

    Hi Swagatham,

    I want a 24VDC to 48VDC boost converter.
    I got a 24DC battery as the voltage source.
    How can I build one. Please suggest.

    Reply
    • Swag says

      Hi Uday,

      you can use any IC 555 based boost converter circuit from this website.

      https://www.homemade-circuits.com/?s=555+boost

      Reply
    • Uday says

      Thank You Swagatham,

      I am need of a circuit where the voltage should decrease gradually over a specified range. As an example it should decrease from 15VDC to 5VDC continuously, but not as in one step, so that I can have control on the rate at which it is decreasing.
      Can you recommend something for this?

      Thanks a lot
      Uday

      Reply
      • Swag says

        Uday, you can probably implement it using a PNP emitter follower BJT circuit, where a base/emitter capacitor would decide the slowly declining voltage across the emitter and positive supply of the BJT

        Reply
      • Uday says

        Thanks Swagtham it worked.
        Thanks a lot!

        Reply
        • Swag says

          You are welcome Uday, happy to help!

          Reply
  12. ABBA says

    Hi swagatam
    which battery do you recommend to be use in the Vin? can we use wrist watch battery 1.5V input if size is of utmost important in a given project? thanks alot.

    Reply
    • Swag says

      Hi Abba, you can try any type of battery, size is not important but the output current will be as per the AH rating of the battery and proportionately reduced depending on boosted value of the output voltage

      Reply
  13. G Daniec says

    Hi,
    I would like a circuit to optimise the power of NiCad cells to drive Ultra Bright Leds.
    I have 3 cell Nicad packs rated at 3.6V which I’d like to use to drive the Ultra Bright Leds.
    To optimise the power available in the NiCad cells, I’d like the cells to continue to drive the Leds with a constant current as the cells voltage drops below the Ultra Bright Leds rated voltage.
    I was considering a Joule Thief Circuit or Voltage Doubler feeding a Constant Current circuit.

    Any suggestions/circuits please ?

    Reply
    • Swag says

      Hi,
      you can try the first circuit from this post:

      https://www.homemade-circuits.com/how-to-make-simple-boost-converter-circuits/

      However current may not remains constant and may also drop as the voltage drops.

      Reply
  14. IRA AISHWARYA says

    Hey,
    Can you please give the link of the website where I can get IC MC74VHC1G14?

    Reply
    • Swagatam says

      Hi, if you do Google “Buy MC74VHC1G14” you will find many reputed online sources who are selling this chip.

      Reply
  15. Amirul says

    Hi Sir. May i know how u calculate the value of capacitors,resistor and inductor needed to boost the input voltage?

    Reply
    • Swagatam says

      Hi Amirul, the basic principle is the same for all boost converters, yu can read it in details in the following link:

      https://www.homemade-circuits.com/how-boost-converters-works/

      Reply
      • Amirul says

        So your calculation for the components rating based on the link above?

        Reply
      • Amirul says

        And may i know what software did you use for this circuit simulation?

        Reply
        • Swagatam says

          I did not use any software, I just built it practically, it was a long time ago.

          Reply
  16. Fayyaz says

    Sir i want a voltage booster circuit capable of delevering 6 vdc 3 amp
    INPUT voltage wouldbe 3 vdc
    kindly guide me

    Reply
    • Swagatam says

      what is input amp?

      Reply
      • Fayyaz says

        Less then.5 amp

        Reply
        • Swagatam says

          you can use the 555 circuit from this article

          https://www.homemade-circuits.com/how-to-make-simple-boost-converter-circuits/

          use 5 turns for the coil, and the IC should be LMC555

          Reply
  17. Eli Sidwell says

    Swagatam, Nice web page !
    I was looking at using a voltage regulator that would buck and boost, I found the following circuit on Wiki and it looks like the zener could be replaced with any value that you wanted to output voltage to be ?
    Also uses a lot of very simple components. I want to conserve as much of the battery as possible.
    Maybe even a voltage divider that would allow you to adjust a pot to any output value say 1 – 7volts.
    https://en.wikipedia.org/wiki/Joule_thief#/media/File:Regulated_Joule_Thief_generalization_and_cleaning.svg

    Thank You.

    Reply
    • Swagatam says

      Thanks Eli,

      yes that’s a simple Joule thief circuit with a feedback link for controlling the output voltage to a specific limit as determined by the zener value.The zener could be replaced with a potential; divider for getting an adjustable output level.

      Reply
      • Eli Sidwell says

        Swagatam, Thank you for the prompt reply.
        I want to know some more about the component selection.

        1. What do those the two dots on the transformer stand for ? And is this a torrid coil ?
        2. I see a lot of designers using all types of transistors, and then others build the entire circuits from 2N2222(s). Do the characteristics of those other transistors that specific ?, or are developers using whats laying around on the workbench ?
        3. Is the LDO really needed ?, Looks like a power waster to me ? (why not just an LC filter?)

        Thanks

        Reply
        • Swagatam says

          Hi Eli, those dots indicate the start an finish orientation of the winding turns. You can ignore and wind the turns anyway round, if it doesn’t work in the circuit, just swap (interchange) the ends of any one of the winding.

          Only the collector current and the collector voltage specs is what really matters for the BJT, which must be higher than the required load V and I specs, est are not critical unless the applications is something very special with special requirements.

          The LDO IC may be necessary if the load involves TTL ICs or any parameter with strict 5 V requirement, otherwise it can be ignored

          Reply
  18. Carlos says

    Hello good afternoon I am a follower of your website since its inception. I need a circuit to convert 3.7vdc / 4vdc to 9vdc to use in the voltmeter with 18650 batteries. A simple and small circuit Thank you very much

    Reply
    • Swagatam says

      Thank you Carlos, for being a dedicated follower of this blog.
      You can use the basic joule thief circuit for your purpose.
      You can adjust the transistor side turns of the coil, or the secondary side until the required level of output voltage is achieved

      Reply
  19. Carlos says

    Hello good afternoon. Thanks for your answer, I like this circuit but I can’t get the Hello good afternoon ic. Thanks for your reply, I like this circuit.. but I can’t get the ic MC74VHC1G14. The question is .. Can I use another IC? Thank you very much

    Reply
    • Swagatam says

      You can use a single gate from the IC 4093 as shown below:

      using a single gate from IC 4093

      However all these ICs require minimum 2 V to operate, so I am not sure how they can be applied to work with 0.6V??

      The article above was referred from another website!

      Reply

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