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Li-ion Emergency Light Circuit

Last Updated on January 1, 2024 by Swagatam 193 Comments

The post presents a simple Li-ion emergency light circuit with over charge and low battery cut off features. The Circuit was requested by Mr. Saeed Abu and Y0f4N.

Table of Contents
  • Technical Requirement
  • The Design

Technical Requirement

Bro thanks for ur reply. Actually im Pharmacist(M.Pharm) & Electronics is my hobby. So i go through ur mentioned link & i dont understand ur suggestion to modify that diagram also about ur mentioned cut off transistor. So would u mind to send me the complete circuit diagram 

My requirement is:(1) Circuit is Operated by Nokia standard cell phone charger

(2) Battery nokia 3.7 volt

(3) Auto ac to dc changeover system when ac fail

(4) Battery overcharge protection system(auto battery full charge cutoff) with LED indicator.I have tried many times to develop such type of circuit but i failed. So Please bro help me urgently. Please design it simple.

The Design

The proposed Li-ion emergency light circuit with over charge and low battery cut off features functioning may be understood with the the following points:

Transistor T6 is basically configured to automatically sense and shut off the LED during the presence of mains AC and vice versa. Here a mobile charger is used for powering the T6 circuit.

As long as the mains input is available, the 1 watt LED stays switched OFF due to the presence of a positive potential at the base of T6,  T6 starts conducting the moment AC mains fails illuminating the connected LED with the help of the attached Li-ion battery power.

T1 and T2 form the low battery detector stage and does the same when the Li-ion battery voltage falls below a certain predetermined level set by P1.

When this happens, T1 just stops conducting forcing T2, T3 to switch ON hard.
T3 passes the battery voltage to the base of T6 choking its conduction thereby shutting off the LED and inhibiting any further loss of voltage under the situation.

T4 and T5 are configured for the opposite function, that is for detecting the full charge of the li-ion battery.

P2 is appropriately set such that T4 conducts fully at this battery voltage.

With T4 fully ON, the base of T5 is unable to acquire the required negative biasing via  R6 and thus is prevented from supplying the charging voltage to the battery, which in turn protects the battery from getting over charged and damaged in due course of time.

The red/green LEDs indicate the relevant states of the battery and the cut off conditions.

li ionbatterycharger

The 10 ohm with the negative of the battery may be eliminated, it's not worth with so many existing protections.

For getting a better response from the over-charge cut-off stage, the above circuit could be modified further with an additional transistor stage T5, as shown below:

Referring to the following circuit, we are able to the see a few crucial additions and removals:

IC 7805 has been added, diode at T6 collector is removed, and D1 position changed. These changes ensure that an exact 4.3V is able to develop across the emitter of T6 and ground, irrespective of the input voltage level.

D5 has been removed in order to provide a better illumination for the LED at the collector of T2.

All high value resistors have now been reduced to 1K for an increased current biasing for the BJTs.

li ionbatterychargercircuit

As suggested by one of the avid readers of this blog Mr. Syed, the above diagram needed some corrections.

The finalized diagram of the Li-ion emergency light circuit with over charge and low battery cut off featurescan be seen below:

transistor2Bemergency2Blamp2Bcircuit

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About Swagatam

I am an electronics engineer with over 15 years of hands-on experience. I am passionate about inventing, designing electronic circuits and PCBs, and helping hobbyists bring their projects to life. That is why I founded homemade-circuits.com, a website where I share innovative circuit ideas and tutorials. Have a circuit related question? Leave a comment.... I guarantee a reply!

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Reader Interactions

Comments

  1. Naresh says

    April 20, 2020 at 8:06 pm

    Hi sir,
    I hope you are doing good.
    I have some LiFe 18650 (4.5 v 2500 mah) batteries which is removed from old laptop battery. I have used it to make emergency light, I used smd leds which is removed from old led buld. When I connected it to the led its glowing very good but heating up very quickly. The led forward voltage is 4v, 50ma. Do I need to use resistor? Pls advise me.

    Reply
    • Swagatam says

      April 21, 2020 at 10:40 am

      Hi Naresh, yes definitely you will need a resistor for the LED to drop the excess 0.5 V.

      The formula is R = (Supply – LED V) / LED Current

      Reply
      • Naresh says

        April 21, 2020 at 7:31 pm

        Hi sir
        I have added a 10 ohm 1/4w resistor in series with battery positive, now the resistor is heating up. What would be the problem sir.

        Reply
        • Swagatam says

          April 21, 2020 at 8:22 pm

          Hi Naresh, please specify what kind of load sre you using, I’ll work out the resistor for you, but 1/4 watt will not do, it must be at least 1 watt.

          Reply
          • Naresh says

            April 24, 2020 at 7:08 am

            Hi sir,
            I am using 4v 50ma smd leds 10nos in parallel.i have tried with 10 ohms 1 watt resistor also but when I use it the brightness is going low.

            Reply
            • Swagatam says

              April 24, 2020 at 10:43 am

              Hi Naresh, for 4 V 50 mA LEDs, and 3.7V Li-ion cell you will not require any series resistor. Simply connect the LEDs in parallel without any resistor.

              Reply
            • Naresh says

              April 24, 2020 at 2:26 pm

              Sir iam using 4.5v 2500mah Life battery not 3.7v

              Reply
              • Swagatam says

                April 24, 2020 at 8:14 pm

                Then 10 ohms is correct, and you should use 10 ohm separately for each LED

                Reply
  2. ABBA says

    March 6, 2018 at 1:54 pm

    hi swagatam
    i have a question, in 3.7v li-ion battery the charging voltage is 4v how about lead acid battery rated at 4v what will be the charging voltage ?

    Reply
    • Swagatam says

      March 6, 2018 at 2:27 pm

      Hi Abba, you can use any type battery as per your preference, Li-ion batt can be charged quickly that’s the only advantage of it

      Reply
  3. Michael says

    October 4, 2017 at 2:49 pm

    Hi, how can I modify this circuit to use it as mobile power bank?

    Reply
    • Swagatam says

      October 4, 2017 at 3:34 pm

      too many modifications might be required, so I would recommend the following concept instead

      https://www.homemade-circuits.com/2013/12/usb-automatic-li-ion-battery-charger.html

      use a cellphone charger for supplying the above linked circuit.

      Reply
  4. Arun Kumar says

    December 24, 2015 at 11:06 am

    I set cut off preset I adjust 4.2v voltage unplug adapter then used the battery voltage is decrease 4.1v connected circuit then not charging I check circuit out voltage 4.1v or 4.2v then adjust cut off preset voltage increase 4.3v or 4.4v then battery charging then over charging again I set cutoff voltage 4.2v again and again I set cutoff voltage I want to parent one time set the cutoff voltage sir please update any mobile charger supportable single ic used low cost circuit diagram please sir

    Reply
    • Swagatam says

      December 24, 2015 at 4:18 pm

      if you are having difficulty with the above design you can try the following more accurate one:

      https://www.homemade-circuits.com/2013/12/usb-automatic-li-ion-battery-charger.html

      Reply
    • Arun Kumar says

      December 26, 2015 at 11:32 am

      This circuit who many voltage used input this circuit cutoff voltage please tell sir

      Reply
    • Swagatam says

      December 27, 2015 at 6:26 am

      5V input is used through the show diodes to finally make it into 4.2V for the battery

      Reply
  5. Arun Kumar says

    December 22, 2015 at 3:59 pm

    charging cut off led glowing in unplug adapter Glowing led then charging led glowing in unplug adapter Glowing led this problem please sir solution

    Reply
    • Swagatam says

      December 23, 2015 at 6:53 am

      remove the battery when unplugged, that's probably the only solution…

      Reply
  6. Arun Kumar says

    October 17, 2015 at 4:17 pm

    How to set cut off voltage p2 & how to set low battery cut off voltage p1 please tell me sir

    Reply
    • Swagatam says

      October 18, 2015 at 11:19 am

      Please see the second comment from top.

      Reply
  7. kamlesh_sexy says

    August 23, 2015 at 12:17 pm

    p1 & p2 is variable resistor in 1st diagram??? I will use 3.7v 1a (Sunca match box size battery) battery to this circuit. so what fixed resister I have to use in place of p1 & p2??

    Reply
    • Swagatam says

      August 23, 2015 at 3:10 pm

      p1, p2 will need to be practically experimented a lot to learn about the required exact fixed value replacement…

      Reply
  8. Saeed Abu says

    May 23, 2015 at 1:14 pm

    dear i have a circuit with birthday tone but how can i convert it as a calling bell?

    Reply
    • Swagatam says

      May 25, 2015 at 2:53 am

      dear I'll post the an amplifier circuit soon which you can use with the tune for implementing a door bell.

      Reply
  9. Saeed Abu says

    May 22, 2015 at 6:18 am

    dear i need temperature controlled AC Fan Dimmer circuit and Birthday song tone Calling Bell circuit diagram.do u have this pleas share it.

    Reply
    • Swagatam says

      May 23, 2015 at 5:55 am

      dear, I have one related circuit posted below:

      https://www.homemade-circuits.com/2013/01/automatic-temperatureclimate-controlled.html

      the birthday song tone calling bell can also be designed but first you'll have to procure the "birthday" tune COB (chip on board) without which the song cannot be implemented.

      Reply
  10. White Dragon says

    April 11, 2015 at 9:46 am

    Ok sir. ill check on breadboard first. Another thing, how do i change the output voltage to 1.5v instead 3.7v? as i want to run a 1.5v (150mA approx) dc motor instead LED.How may i do that?

    Reply
    • Swagatam says

      April 11, 2015 at 11:39 am

      for changing the output to 1.5V you can either change the battery to 1.5V or use 3 nos 1n4007 diodes in series with the output positive

      Reply
    • White Dragon says

      April 12, 2015 at 6:47 am

      sir, if I use 1.5v battery, then what's need to be changed? and on 3.7v battery, you told to use 3 diode in series. Why not a simple 10 ohm resistance? will you kindly explain?

      Reply
    • Swagatam says

      April 12, 2015 at 8:19 am

      add 3 more diodes in series after 7805 while charging the 1.5V batt

      a 10 ohm will affect and reduce current to the load, using 3 diodes will keep current intact, but reduce volts to the preferred limit.

      Reply
  11. White Dragon says

    April 8, 2015 at 8:00 pm

    Dear sir, what will be the input voltage? as there is a 7805, i need more then 5v for that, right? but as schematic, it says to use 5v cell phone charger.what to do?
    Please help!
    Thanks.

    Reply
    • Swagatam says

      April 9, 2015 at 7:33 am

      Dear white dragon, a cellphone charger will normally have a slightly higher voltage than 5V, so it's OK to use a cell phone charger as the input, the 7805 is only for ensuring that the li-ion cell does not get an over voltage due to a wrong high voltage input

      Reply
    • White Dragon says

      April 9, 2015 at 6:15 pm

      Oh i see. i didnt know that. 🙂 thanks for the prompt reply. I am designing a pcb of this schematic. Another thing i don't understand. On 3rd schematic, from the collector of T6 toward emitter of T7, it is shown to use 2 pcs of diode, but shows only one. do i need to add 2 diode parallel or serial to there?
      Thanks.

      Reply
    • Swagatam says

      April 10, 2015 at 3:32 am

      since D2 is introduced, therefore only one diode at the emitter of T7 is sufficient, no need of two diodes here.

      before designing a PCB I would recommend to test it out over a general purpose board for a trial and verification.

      Reply
  12. Jignesh says

    October 8, 2014 at 6:29 am

    hi swagtam,
    i want to ask u that same configuration can be use for 12v battery and 12v charger application….???

    Reply
    • Swagatam says

      October 8, 2014 at 3:59 pm

      hi jignesh, yes the above same circuit can be used for 12V batts also

      Reply
    • Swagatam says

      October 8, 2014 at 4:02 pm

      …7805 will need to be removed, and a precise 14V will need to be applied at the emitter of T6

      Reply
  13. Saeed Abu says

    September 25, 2014 at 6:57 pm

    bro is ur last updated circuit has overcome all of it's drawback? did u test it practically the updated circuit?

    Reply
    • Swagatam says

      September 26, 2014 at 4:53 am

      bro i haven't tested it but it looks perfect because most of the issues have been corrected in the last design and it should work as proposed if it's done exactly as shown.

      Reply
  14. Arun Dev says

    July 18, 2014 at 3:46 pm

    The reason why i am skipping the series config. is that if an LED fails in a branch all the LEDs associated with that LED in that particular branch will be turned off affecting the overall brightness considerably

    Reply
    • Swagatam says

      July 19, 2014 at 5:02 am

      Today all LED lamps depend and use series LED configuration, some street lights even use 50 LEDs in series. Good quality LEDs will never fail no matter how these are configured, as long as everything's done as per the specs.

      Reply
  15. Arun Dev says

    July 18, 2014 at 7:04 am

    Sir,
    I need a simple LED light circuit to fit inside a car….
    I am using 10 no.s of white LEDs… The LEDs are connected in parallel for maximum efficiency… So 10 parallel connections are there… Power for the bank is taken from the Car battery voltage… I need to drop a maximum of 600 mA from the source ( 60 mA for each LED ) for maximum brightness….
    By calculations i have found the following ;

    Resistance needed for a single LED to draw a current of 60 mA is:
    ( 12 – 3.1 ) / 0.06 = 148.33 ohms
    Power rating of that resistance :
    ( 12 – 3.1 ) * 0.06 = 0.534 W
    150 ohm 1W resistance can be safely used…
    So 10 no.s of such resistances have to be used… The main drawback of this config. is, more of the board space is getting utilized.

    Now i am gonna chose for a simplest design which uses only one main resistance instead of placing separate limiting resistances for each LEDs…

    So
    The total current required = 600 mA = 0.6 A
    Voltage = 12V – 3.1V = 8.9 V
    So R = 8.9 / 0.6 = 14.833 ohm
    Power rating of the resistance = 8.9 * 0.6 = 5.34 W

    Are my calculations correct sir ??
    I need your valuable comments on these

    Reply
    • Swagatam says

      July 18, 2014 at 2:22 pm

      Arun, series connection gives more efficient results for LEDs, make two led strings with 3 leds in series on each string, and connect them in parallel.

      the series resistor on each string would be then:

      12 – 9.9/.06 = 35 ohms, 1/4 watt

      Reply
  16. Arun Dev says

    July 17, 2014 at 2:22 pm

    Sir,
    Sorry for disturbing you much…
    All the problems facing by me are due to my carelessness while making out the circuit on BB…
    I got the result of the above circuit in a fruitful way so that i can proceed further…

    Hope you will understand my lack of time in concentrating much on the electronics due to a lot of works related to my profession to be completed …

    Also expecting your valuable help in future projects that i am planning to do..

    Thank you sir

    Reply
    • Swagatam says

      July 18, 2014 at 6:52 am

      Sure Arun, thanks! and keep posting.

      Reply
  17. Arun Dev says

    July 16, 2014 at 7:47 am

    Sir,
    On checking today,
    the diagram i have sent to you via email, when assembled on the bread board, acts as the same in the VERO board..

    The Battery full indicator illuminates even on power failure… also the following points were noted

    – Battery full voltage is 4.7 V

    (1).
    the Base of T7 gets voltage about 6.4 V when a 7.0 V charging source ( to charge the 4 V 1000 Ah battery taken from the mosquito bat ) source is used, thereby the LED bank connected between its collector and ground is not active…
    but when source is disconnected ( power failure ) the base voltage is getting reduced only to 3.8 V not to zero, even-though the LED bank begins to illuminate

    (2).
    The battery full indicator LED continues illuminating even after power failure

    (3).
    Correct adjustment of Higher voltage cut of can't be achieved

    (4).
    Even if the higher voltage cut off is achieved, the charging voltage available for the battery doesn't becomes zero..

    I am expecting better solutions for the mentioned problems in the above points

    Reply
    • Swagatam says

      July 17, 2014 at 4:37 am

      Arun, others have also tried the above circuit they are quite satisfied with it, I am not sure why you are facing so many issues.

      Anyway here are the answers:

      "Battery full" LED will stay illuminated because it's connected with the battery line, so it's fine, you can eliminate this LEd entirely and just keep the red and green LEd for the indications.

      1) This case is also normal, D2 is dropping the 7V to 6.4V, however despite my of repeated suggestions you have not used a 7805 IC that means you will get all the wrong and dangerous results while the battery gets fully charged.

      On power failure T6 gets activated via R7 that's why you see 3.8V at its base, it's due to battery voltage minus the 3.8V which could be 0.6V, which is exactly what a BJT needs to conduct.

      2) i have answered this above.

      3) This is because you have not used 7805 IC and did not take care about making the emitter of T6 exactly equal to the full charge level of the battery.

      4) the answer is same as above

      Reply
  18. Saeed Abu says

    July 15, 2014 at 5:00 am

    bro ur given last circuit is overcome all the drawback of over charge cut off feature which i have faced during build it?

    Reply
    • Swagatam says

      July 15, 2014 at 2:02 pm

      Thanks for the feedback bro, that's great… a small additional refinement could make it more perfect, the emitter of T6 needs to be shifted to the anode of D2 from its existing position, this will make it more reliable in my opinion.

      Reply
    • Swagatam says

      July 15, 2014 at 2:05 pm

      …sorry the above recommendation is not correct, rather another diode needs to be added between the emitter of T6 and the base of T7 so that the battery voltage does not reach the emitter of T6 during backup.

      Reply
  19. Truong HOANG ANH says

    July 14, 2014 at 7:10 am

    Hi Pro! I have done this circuit and it works quite well with the charger plugged in and cut, even with a low battery saver mode also works well. I changed T7 with TIP127 to control parallel 10Led 1w, however when I measure the voltage at the base of the LED light is getting 2.8V, this can happen due to too many connections I Led?. This is my 2nd T6 is used to charge controller TIP127, however after the last TIP127 voltage has been reduced from 5.1V down to 3.96v, so the pressure drop due to TIP127 this?. I tried removing T6 and check the charging mode and charging cut still works well. So according to Pro then need to add back to T6?. I checked voltage charger when the battery is not connected 4.4. I have combined this circuit with controller enabling / disabling of IR and used more direct mode without batteries. Looking forward to the comments of Pro to help achieve the best performance circuits. Thank Pro!

    Reply
    • Swagatam says

      July 15, 2014 at 4:12 am

      Thanks Truong for improving the design, I appreciate your efforts.

      I hope your suggestions will help the interested viewers to learn and modify the circuit as per their personal applications.

      Reply
  20. Arun Dev says

    July 8, 2014 at 6:08 am

    TIP127 didn't make any difference

    Reply
    • Swagatam says

      July 8, 2014 at 12:38 pm

      remove the battery and check the voltage across its collector and ground, it should be 4.2V and the current should be minimum 500mA, if these are satisfied then your batt will get correctly charged.

      Reply
  21. Arun Dev says

    July 8, 2014 at 4:55 am

    But still i am facing a low charging current problem… The 1000 mAh battery doesn't get the minimum chaging current of 100 mA, only 56 mA maximum is available…

    WHAT 2 DO SIR ????

    Reply
    • Swagatam says

      July 8, 2014 at 5:49 am

      did you use TIP127 for T7?

      Reply
  22. Arun Dev says

    July 7, 2014 at 5:49 pm

    Finally i got it Sir. I have included the LDR dark sensor portion to the last diagram…. I have sent the altered diagram to your hitman inbox. Plz check it sir.

    Now..can u suggest a suitable and efficient method to adjust the brightness of LEDs in that circuit ?

    Reply
    • Swagatam says

      July 8, 2014 at 5:51 am

      OK thanks! simply add a 10K pot across base of T7 and battery positive for the dimming feature

      Reply
  23. Arun Dev says

    July 4, 2014 at 7:41 am

    Sir,
    Can you provide a dark sensor which can be used with the last schematics such that the emergency light should only be turned on during night time..

    The dark sensor given in the below schematics is not working since the collector voltage of the BC557 in the DARK SENSOR section doesn't become zero when the LDR faces darkness ( i have confirmed it by testing it many times )..

    2.bp.blogspot.com/-SE0yn6ovpbE/Tyu6Bf2vsLI/AAAAAAAAA10/fKymq5Xk2So/s320/emergency.png

    Plz help me to solve this by obtaining zero volt at the base of T7 when darkness is detected.

    Reply
    • Swagatam says

      July 5, 2014 at 3:54 am

      Arun, you should first learn how PNP devices work. The shown circuit will definitely work
      In the given link, the collector of BC557 should become equal to the battery voltage in order to shut off T1.

      The LDR should get sufficient light to turn off T1, or may be you can try using another BC557 to make a Darlington configuration for increasing sensitivity.

      Reply
    • Swagatam says

      July 5, 2014 at 4:03 am

      …OK sorry, I slightly misunderstood you question.

      At complete darkness any good LDR resistance will reach in Megaohms.

      With 100k across its base/positive, a resistance in Megaohms across its base/ground will have no effect on the BC557 so how can it keep conducting??

      Check the base voltage of BC557 at this position if it doesn't get equal to the battery voltage would indicate a faulty BC557.

      Reply
  24. Arun Dev says

    July 4, 2014 at 4:50 am

    Sir i have sent the mail to your hitman inbox

    Reply
  25. Arun Dev says

    July 3, 2014 at 6:35 pm

    Hellow sir in the circuit about which i was discussing the problem stated in the last comment, the problem persists even after many trial and errors
    Here i am again giving the direct link to the schematics

    4.bp.blogspot.com/-N7x3_I8Ky4s/U6cC7ipSmwI/AAAAAAAAHUo/jZ1znlwGEI0/s1600/li-ion+battery+charger+circuit.png

    The LEDs associated with the high voltage cut off section ( either charging LED or full charging indicator LED ) continues to blink even after power failure ( or retains its state as they were before the power failure occurs ).

    On close examining the circuit i have reached to some conclusions… I am giving those here…. Plz give your valuable opinions about these..

    1).
    Since the diode at the collector of T6 has been removed, the battery voltage during power failure becomes available at this terminal causing an emitter voltage of T6 ( about 2.6 V to 3.0 V for battery full voltage ) .. That emitter voltage is being utilized by the Over voltage protection circuit along with the battery voltage ( by the 47 K pot )… This may be the real reason for those LEDs to illuminate even after power failure….
    I could found this by testing the LEAD terminals of T6 and the problem was solved by placind the diode D3 as before.

    (2).
    Some voltage will also be present as in the first case by shorting the base of the LED driving transistor T7 directly to the voltage rail ( in which the voltage from the mobile charger arrives during charging phase )… So i have used a diode in place of the actual connection with cathode pointed to the base of T7 and anode to the above voltage rail..

    The above said two modifications solved the issue…

    Now the LEDs ( which are causing the problem ) do not illuminate during power failure..

    Check your hitman inbox sir… I have send the altered diagram to it…

    Hoping your reply soon

    Reply
    • Swagatam says

      July 4, 2014 at 4:53 am

      Hello Arun,

      Thanks for the detailed assessment!

      What you have suggested in point 1) is strange because in a PNP device voltage will "flow" from emitter to base/collector, never in the opposite direction, therefore the diode at the collector shouldn't make much of difference.

      However your 2) point makes sense wherein I am assuming that you have shifted the emitter of T6 to the anode of D2 from the existing cathode of D2, right?

      The above correction would be preventing a leakage voltage from T3 collector to reach the emitter of T6 and perhaps this could have been the real issue.

      Try removing the T6 collector diode with your 2) suggestion in place, and see if it reverts to the issue or sustains the present good condition.

      Reply
    • Swagatam says

      July 4, 2014 at 4:54 am

      …I'll check my email ID soon and post the corrected diagram here for others to view…thanks

      Reply
    • Swagatam says

      July 4, 2014 at 4:59 am

      your point 2) modification would be also preventing T7 emitter/base battery voltage from reaching T6 emitter, correcting the discussed issue

      Reply
  26. Arun Dev says

    July 2, 2014 at 10:54 am

    Hai sir,
    In the circuit given in the below link, the Charging LED ( green ) illuminates even during power failure….

    4.bp.blogspot.com/-N7x3_I8Ky4s/U6cC7ipSmwI/AAAAAAAAHUo/jZ1znlwGEI0/s1600/li-ion+battery+charger+circuit.png

    I have placed a 4.7V zener in series with the Green LED with proper position, which solved the issue.
    Green LED turned off when power failure occured.
    But a new problem arised that, the charging current of the battery becomes very less compared to the previous case..

    COULD U PLZ SUGGEST A BETTER REMEDY FOR THIS ??

    Reply
    • Swagatam says

      July 3, 2014 at 4:59 am

      Hi Arun, a zener diode is not required, and there's no way the green LED can illuminate with the input supply switched OFF, because if the emitter of T6 has no voltage from where will the green LED receive power? The battery voltage cannot pass through collector of T6 to the green LED, right? so then from where could the green LED be getting the power if there's no input supply at the emitter of T6?

      You can try disconnecting different links that may be related to the green LED to find the leakage path for troubleshooting the issue.

      Reply
    • Swagatam says

      July 3, 2014 at 5:06 am

      ….you can try the last circuit given in the following link, for achieving a guaranteed and a reliable response:

      https://www.homemade-circuits.com/2013/12/usb-automatic-li-ion-battery-charger.html

      Reply
  27. Arun Dev says

    July 1, 2014 at 8:36 am

    Sir i am using two unknown rechargeable batteries taken from two broken MOSQUITO BATS….
    On searching the internet i found that they might be 4V 1000 mAH batteries.
    One of the battery shows abotu 4.3V and the other one shows 4.1 V..

    (1). So what do you think about the MAXIMUM CHARGING VOLTAGE and MINIMUM
    CHARGING CURRENT of these batteries ?

    (2). Will the criterion 1/10Ah holds the same for this case so that the parallel config. of these
    batteries require 200 mA current as minimum charging current ?

    (3). What config. will be most preferable here ? A Parallel config. or a Series one ?

    (4). What z about the maximum charging voltage ?

    My requirement is to make the present circuit able to provide suitable charging levels ( voltage and current ) to the battery bank and the brightness of the LEDs ( 10 no.s ) should be high enough to make it useful at night….

    On inspecting the working of the present circuit, i came to know that, the charging current supplied by the collector terminal of the T6 is only about 15 to 30 mA which is too low ..
    Also the discharging current is also less so that more than one LEDs can't be used instead of the single one…..

    Hope you will suggest better remedies to solve all these issues….

    Reply
    • Swagatam says

      July 2, 2014 at 4:16 am

      Arun,

      the full charge voltage for most batteries and in your case also would be 16 to 18% of the actual battery voltage rating, so for 4V it would be around 4.8V. Similarly the lower may be calculated as 12% less than the actual battery rating.

      The charging current in the above design can be increased by changing the 2N2907 with TIP127, this will significantly improve the current specs of the design.

      Reply
    • Swagatam says

      July 2, 2014 at 4:19 am

      neither series is good nor parallel, ideally you should charge them separately, but parallel config is better than series according to me.

      1/10th rate will be good if the the batts are Ni-CD type.

      Reply
  28. Arun Dev says

    June 30, 2014 at 6:22 pm

    Sir,
    How to use this circuit to operate on set of 10 white LEDs ?

    Can you plz check your hitman inbox Sir…
    I have sent a mail to it.

    Reply
    • Swagatam says

      July 1, 2014 at 5:32 am

      Hi Arun, if it's with 3.7V, the circuit would be the same as above.

      Reply
  29. Syed Arham says

    June 21, 2014 at 6:08 pm

    Sir,
    i have tune the P1 which is working perfectly.i have tested it.but the problem is that the 1 watt led doesnot off. emitter and the collector of the bc557 is connected with each other as mentioned in all three diagram.
    i have just replace the connection of emittter to the positive of the battery.and it is working perfectly means it cutoff the 1 watt led when the red led glows.
    sir i have a question about p2.When i tune it in that position when the green led is comming to be off and the green is in starting to glow but it does not works it remain in this condition even i connect a full charged batt or a weaker once or the charger.
    When i connect full charged batt and adjust the p2 when the blue led is glowing (just when it start glowing)and then replace the batt with weaker batt ,the blue led is still glowing even when i connect the charger.Then how to set P2??????

    Reply
    • Swagatam says

      June 22, 2014 at 8:53 am

      Syed, yes you are correct, T3 emitter should be connected to the battery positive for the required LED glow cut-off, I misunderstood your previous comment, I thought you were referring to T6.

      As for the P2 high voltage cut-off setting, when you connect a new battery you will need to switch off the whole circuit, then connect the new battery and then switch ON again for initiating the actions afresh….if you don't switch OFF the circuit the transistors will be latched on to the previous conditions due to their high hysteresis characteristics.

      Reply
  30. Syed Arham says

    June 21, 2014 at 7:52 am

    Thanks Sir you have clear my all doubt, now i will tune the p2 and come up with positive result.

    Reply
    • Swagatam says

      June 21, 2014 at 10:23 am

      sure, thanks!

      Reply
    • Syed Arham says

      June 22, 2014 at 11:45 am

      Sir,
      The circuit is working with its all features.
      I have make two changes.
      1) i have connect the emitter of bc557 directly to the battery.
      2)i have replace the connection of R5(1k) to the positive of battery.
      That all ,the circuit is working..

      Reply
    • Swagatam says

      June 22, 2014 at 3:40 pm

      Thank you Syed for the updates, that's interesting.

      the connection of BC557 emitter to batt positive is valid and looks perfect but R5 should work even in the shown position.

      But anyway, if it's working for you let's take it in that way.

      I'll update the modified diagram soon…

      Reply
  31. Syed Arham says

    June 20, 2014 at 4:04 pm

    sir i think that the emitter of bc557 should be connected to the positive of the battery to sense through the for cut off. Please describe the function of T4 and T5 so i can accurately adjust the P2.

    Reply
    • Swagatam says

      June 21, 2014 at 5:22 am

      emitter of T6 is connected with the battery via its own collector. as soon as a discharged battery is connected, the emitter potential will drop and come down to the battery voltage level.

      P2 is set so thst T4 just begins conducting at around 4.1V, when this happens T5 conduction gets interrupted since its base begins getting grounded via T4 collector/emitter.

      With T5 not conducting, T6 is unable to receive the negative potential via T5 collector/emitter, and therefore T6 now begins getting choked and soon stops conducting….the battery thus stops receiving the charging voltage at around 4.2V

      Reply
    • Swagatam says

      June 22, 2014 at 8:45 am

      OK now i got your point, I misunderstood T3 with T6, you were referring to T3 and I mistook it to be T6….you are right T3 emitter must be connected with the battery positive for the cut off, I'll make the corrections soon.

      thanks

      Reply
  32. Arun Dev says

    June 20, 2014 at 5:39 am

    and also how to set the lower cut off limit and upper limit accurately… On tweaking the pots associated with each section, only a gradual change in detection of voltage has been noted, not an abrupt change which means that the higher cut off during charging and the lower cut off during discharging occurs gradually ?

    Reply
    • Swagatam says

      June 20, 2014 at 7:06 am

      yes you will a gradual change not a sudden change because these are crude BJT stages not opamp stages.

      an opamp circuit such as a LM358 circuit can be used for a snappy response….

      a relay can also be used for the same but 3V to 5V relays are not easily available and will make the circuit costlier..

      Reply
  33. Arun Dev says

    June 20, 2014 at 5:35 am

    Sir in this circuit when i am using a 5.0 V battery ( taken from a broken mosquito bat ), only 3.58 V to 4.0 V is available at the collector of T6 ( positive terminal to The LED lamp )…
    What to do sir ?

    Also..
    what are the minimum cut off voltage and maximum cut off limit of such a battery taken from the Mosquito bat ? No signs of voltage or current written on the surface of the battery

    Reply
    • Swagatam says

      June 20, 2014 at 7:02 am

      Arun, in the last circuit, I have removed the diode at the collector of T6 did you remove it in your circuit?

      the minimum cut off could be within 3.7 and 3.5V and the upper cut off from 4 to 4,2V for a 3.7V Li-on battery

      Reply
  34. Syed Arham says

    June 19, 2014 at 5:55 pm

    Sir, i will change my circuit according to new design(3rd Circuit).
    Do you have made this circuit.This one is a best emergency light with all features.Every one want to made this. Please verify that circuit practically.

    Reply
    • Swagatam says

      June 20, 2014 at 4:05 am

      No I did not check it so far, but as you can see everything's very basic and very tight, there's no space for any fault now, especially after adding the 7805 now you don't have to worry about the input voltage level and the voltage corrections at the emitter of T6.

      Do it exactly as per the last diagram, it will surely produce the mentioned results, but the cut-offs may not be as sharp as an IC circuit would do, because this circuit is crude compared to an IC circuit.

      Reply
  35. Syed Arham says

    June 18, 2014 at 7:10 pm

    Sir. I want to ask about the adjustment of P1 and P1 .
    When i connect a weak battery and adjust the P1 the red led(low batt) does not glow at any point.i have the reduced the value of the resistor connected with Low battery led.but it was not glowing and when i connect the charger it glows..
    if the charger has output of 9 or 12v volts, will it effect the components?
    For P2 when i connect full charge battery and charger to adjust, and after adjusting it in that position when the Blue led(full batt) glows i change the battery with weaker once but the led is still glowing.. (O_o) .i have check all the connection these are perfect..
    Please describe the adjustment of P1 and P2 .

    Reply
    • Swagatam says

      June 19, 2014 at 4:51 am

      Syed, remove the diode D5, it's dropping 0.6V and making it difficult for the LED to glow at 3V.

      the voltage across emitter/ground of T6 (in the last diagram) from the adapter should be exactly equal to the full charge specification. this must be first confirmed without connecting any battery. for example if you are using a 4V battery, amke sure the emitter of T6 shows 4.4V initially without any battery connected…9V or 12V is too high

      The amp of the adapter should be 1/2 of the connected battery AH. for 1.2AH, the input amp should not be more than 500mA

      also make all the 33k resistors to 10K for better response

      All these things should be confirmed otherwise the circuit will keep producing wrong results.

      Reply
  36. Syed Arham says

    June 18, 2014 at 7:38 am

    Ok sir,
    but i am in trouble with P1, But i have adjusted P2 ..
    i have seen the above the comment for adjusting this but when i attach a weak battery of about 3.0 volts and adjust the P1 the Red Led does not glow properly but it glow.and my Main Led(600mA) does not Off..

    Reply
    • Swagatam says

      June 19, 2014 at 4:00 am

      You can change the series 10k resistor to 1K and see the response, it should brighten up the LED…

      sorry, i could not understand your last question…." but it glow.and my Main Led(600mA) does not Off".

      Reply
    • Swagatam says

      June 19, 2014 at 4:05 am

      …OK got it now, you mean to say at low voltage, the emergency 1 watt LED lamp does not shut off fully

      what did you use for R4?

      use 1k resistor for R4 and check the response

      Reply
    • Syed Arham says

      June 19, 2014 at 4:32 am

      Ok sir i will try it.

      Reply
    • Syed Arham says

      June 19, 2014 at 4:40 am

      Sir how to set the P1 and P2.
      i have set according to above comments but not successfully set it.Please explain it using multimeter..

      Reply
    • Swagatam says

      June 20, 2014 at 3:41 am

      Syed the setting procedures are very easy, without connecting any battery feed a 3.6V directly at the emitter of T6 through a variable power supply, now adjust P1 such that the red LED just begins to light up.

      Next, increase the above voltage to around 4.2V directly at the emitter of T6.

      Now adjust P2 until the base LED of T6 just shuts off.

      your setting up procedure is complete.

      disconnect the variable power supply and connect a phone charger to the input of 7805, connect the desired battery for getting the intended automatic cut off actions as per the above settings.

      Reply
  37. Syed Arham says

    June 17, 2014 at 6:06 pm

    Hello sir i have made this circuit..
    i want to ask that the circuit will perform well on this configuration.
    i have used tip127 so can i use led upto 5a??but i am using led of 0.6a with 4v 1.2a battery..Battery is not Li-ion battery.

    Reply
    • Swagatam says

      June 18, 2014 at 5:01 am

      Hello Syed, yes it will work, but with a 600mA LEd your battery will become flat quickly, you will need a minimum 4AH battery for getting around 3 to 4 hour backup

      Reply
  38. Saeed Abu says

    June 14, 2014 at 6:06 pm

    Bro i can not get ur point properly.What will be the base voltage of T5/T6 when battery get its full charge?Pls describe it properly so that i can examine this properly.

    Reply
    • Swagatam says

      June 15, 2014 at 6:13 am

      Bro, base of T5 should become zero or near zero at 4.2V, this will force the base of T6 to become 4,2V or near 4.2V….all these should be measured with respect to ground or negative of the supply, while P2 is being adjusted.

      You can do it in the following manner:

      Without connecting any battery first make sure the voltage at T6 emitter and ground is 4.2V.

      At this position (without any battery connected) slowly adjust P2 until just the green LED shuts off or becomes too dim.

      Your circuit is set now, after this you may connect the battery for getting the required over charge cut-off at 4.2V

      make all the LEDs to red for better response.

      Reply
    • Swagatam says

      June 15, 2014 at 2:03 pm

      ,,,,bro, I have made one small change in the above circuits to ensure a better response.

      the upper circuit is now supplied from the emitter of T6, and not from the battery….see the red line it joins with the positive line of the upper circuit.

      also due to the presence of D3 please make sure that the charging voltage from the source at emitter of T6 should be 4.2 + 0.6 = 4.8V this will produce a correct charging voltage of 4.2V for the Li-ion battery after passing the drop through D3.

      Reply
  39. Saeed Abu says

    June 14, 2014 at 9:33 am

    bro u above 2 circuit the battery get charged max. 3.90v.Also with PCM the full charge auto cut off is occurred but no full charged indication by LED. Without PCM no full charge auto cut off is occurred also no full charged indication by LED. However, ur other feature is ok. Bro i think u can add 6v dc relay to fix the problem.Is it possible?

    Reply
    • Swagatam says

      June 14, 2014 at 12:05 pm

      sorry bro with this circuit a relay cannot be used, we'll have to go for an opamp circuit for operating a relay….
      I am 100% sure about the above circuit that it will work just needs to be tweaked by observing the base voltage T5/T6 with a multimeter while adjusting P2.
      unless its not done with a multimeter, the results cannot be confirmed

      If the LEDs are not glowing properly we can change their positions, no issues, but the important thing is to make sure that the base of T6 becomes equal to its emitter voltage when the battery voltage reaches 4.2V

      And for this to happen the input voltage at the emitter of T6 should be precisely 4.2V, if it's more T6 will never shut off.

      Reply
  40. ravindra metri says

    June 6, 2014 at 5:03 am

    https://www.homemade-circuits.com/2013/04/1-watt-led-emergency-lamp-circuit-using.html?m=1 in this circuit

    Reply
  41. ravindra metri says

    June 6, 2014 at 2:01 am

    Thanku for replay but above link there is no battery for emergency for mains fail

    Reply
    • Swagatam says

      June 6, 2014 at 4:44 am

      the SCR circuit which you are presently building also does not have an emergency feature, my suggestion was with reference to the SCR circuit not the above.

      which circuit are you referring to?

      Reply
  42. Saeed Abu says

    June 4, 2014 at 7:24 am

    Dear Bro thanks for trusting on my experiment at last.Though i am Pharmacist electronics is my heart. There is no difference between human body and circuit.So i feel it so much.Actually,The PCM makes the Li-Ion battery superior from others.However i am still working on ur given circuit for better outcome.I will give u feedback ASAP.

    Reply
    • Swagatam says

      June 4, 2014 at 2:00 pm

      You are welcome bro, yes surely we are all just like machines too.

      By the way with a PCM connected you can simply use a 7805 IC for supplying the Li-ion cell, it'll do the job perfectly, no other additional circuits would be required….for getting an LED indication, you may use a few of the above circuit stages

      Reply
    • ravindra metri says

      June 5, 2014 at 4:42 am

      Sir your 1 watt led emargency ac operated circuit . I can under stand BT136 pinout in data sheet there show M1 M2 G . In our city 100uf/225v not aveliable can i use 100uf/160v. And 2uf/400v is it 205/400v ?

      Reply
    • Swagatam says

      June 5, 2014 at 1:55 pm

      Ravindra, don't make the circuit using SCR or triac it could be a lot difficult for you, instead you can try the following:

      2.bp.blogspot.com/-nKF8T8lKIxY/UMg7YDLNQ3I/AAAAAAAAB8U/S1OWTK0cMD4/s1600/Surge+free+transformerless+1+watt+LED+driver+circuit.png

      Reply
  43. ravindra metri says

    June 4, 2014 at 2:07 am

    Sir. Any mosquito repellint circuit ac operated

    Reply
    • Swagatam says

      June 4, 2014 at 2:03 pm

      I don't think these circuits really work, mosquitoes cannot be deterred using electrical frequencies

      Reply
  44. Saeed Abu says

    June 3, 2014 at 3:33 pm

    Dear Bro we call that circuit is PCM=Protection Circuit Module.However u can go through these link:
    1)www.master-instruments.com.au/related_info/PCMs%20for%20Lithium%20Ion/PCMs%20MI%20Offer%20for%20Lithium%20Ion%20and%20Lithium%20Polymer%20batteries.htm
    2)www.slideshare.net/pettersss/about-cell-phone-batteries-use-common-sense-and-charging-techniques

    Which will encourage u to do that experiment.

    Also ur comment ''any battery will stop taking charge after the voltage reaches its maximum charging capacity'' is totally wrong because i have charged a battery with PCM up to 4.25v then it stop to take charge(In that situation the voltage was around 6.5 to 7.5v at the battery with connecting the charger, i have checked it by Digital meter)then i take the same battery removing the PCM it is now charging upto 4.4v and continue to charged and i stop it for explosion risk.

    Now explain me how can differ the full charge voltage between The Battery with PCM and the same battery without PCM???

    Reply
    • Swagatam says

      June 4, 2014 at 3:47 am

      Dear bro, right at the beginning I had asked you provide a link regarding this and you said that no link was required because you had tested it practically. however I wanted to believe it only through reliable source and not your experiments, since now you have provided it now it's very clear what you meant to say.

      Now it makes sense, and it also proves that how sensitive Li-ion batteries are and without a strict charging circuit it could explode or start leaking.

      By the way all Li-ion batteries may not have this built-in protection that's why an external protection is required.

      I did not want to say that ''any battery will stop taking charge after the voltage reaches its maximum charging capacity'' but since you were not agreeing and proving your experiment to be correct without any reliable article by saying that your cell was not taking above 4,25V so I had no choice but to say this. I know that a battery may keep charging to dangerous levels and that's why protection circuit is imperative.

      Still I did not understand your last question.

      My above circuit can be set to any desired cut-off level, you can set it to cut off before the PCM level or the same level….but the PCM will have no connection with the above circuit, they are independent and will not read and react to each others conditions.

      Reply
    • Swagatam says

      June 4, 2014 at 4:10 am

      …..the above circuit will cut-off at the same level every time with PCM or without PCM it won't make any difference. If it's set to cut off at 4.2V then it will cut-off at this voltage even without the PCM connected.

      It's better to test it without a PCM fitted.

      The crucial thing is the input voltage at the emitter of T6, which should be 4.3V so that it can cut off at this voltage.

      Reply
  45. Saeed Abu says

    June 2, 2014 at 5:40 pm

    Dear bro r u saying me that by doing that experiment or not? If not then do it then challenge me that was my wrong experiment.In addition, i have made many times for my many project full charge indication by zener diode using cell phone battery's self over charged protection system feature. So please do that experiment as per my direction.

    Reply
    • Swagatam says

      June 3, 2014 at 6:04 am

      Dear Bro, any battery will stop taking charge after the voltage reaches its maximum charging capacity but that doesn't mean you can keep the charging switched ON…because that would force the chemical reactions to continue inside the cell and start damaging it slowly.

      I'll advise that you should first research online how to charge Li-ion batteries before getting so much confident.

      Reply
  46. Saeed Abu says

    June 2, 2014 at 6:15 am

    Dear bro i have done many experiment on Cell phone battery last 3 to 4 years and still doing.Also i have discussed about it so many mobile technician in my locality.In that way i am running many project by cell phone battery but no problem is raised.So before comments on my experiment u have to do that experiment practically.I hope u will do that and give me feedback ASAP.Also u asked me why do i need an overcharge protection in the above circuit? Because i need a fully automatic feature like Inverter.That built in circuit of battery only covered over charge feature but not covered low cut off and ac to dc change over feature.However i will check that circuit again also ur two new link.i will wait for ur that experiment which i have told u bro.

    Reply
    • Swagatam says

      June 2, 2014 at 3:13 pm

      sorry bro, no battery has such a feature, especially with li-ion batteries we need to follow strict procedures while charging so that they don't get ruined soon and to prolong their working capacity. therefore Li-ion batts are always charged using sophisticated chargers.

      Reply
  47. Saeed Abu says

    June 2, 2014 at 3:20 am

    Dear bro no need to show any article / image to prove this u can easily prove it by yourself.At first:
    1)U have to take a Nokia Battery and a Standard Charger.
    2)Now u simply charge that battery with that charger directly(no use any circuit, just join the anion and cation of the charger directly to the battery anion and cation section).
    3)Wait for the voltage reached at 4.24v of the battery and then connect digital meter on the battery to see the voltage in charging condition.
    4)U will see when voltage reached 4.25v of that battery then it stop to take the charge automatically and the voltage suddenly increased approx. 6.5v to 7.5v which mean that the battery did not take any charge.
    5) Now u remove the top built in circuit of that battery carefully.U will find Anion and cation section and connect to the charger accordingly.Then u have to do same experiment according to my above way.
    6)At last u will share the result of this experiment ASAP.

    Reply
    • Swagatam says

      June 2, 2014 at 3:59 am

      Dear bro, that's a wrong impression you have got, if it works in that way then why do you need an overcharge protection in the above circuit?

      If you continue doing in that way, your battery could bulge after some days and start leaking or even explode.

      The following is the last and final adjustment that I am presenting for the last circuit.

      Without connecting any battery first make sure the voltage at T6 emitter and ground is 4.2V.

      At this position (without any battery connected) slowly adjust P2 until just the green LED shuts off or becomes too dim.

      Your circuit is set now, after this you may connect the battery for getting the required over charge cut-off at 4.2V

      If you find all these difficult there are much sophisticated circuits as given under, you can try them out:

      https://www.homemade-circuits.com/2012/12/li-ion-battery-charger-circuit-using-ic.html

      https://www.homemade-circuits.com/2012/05/make-this-li-ion-battery-charger.html

      Reply
  48. Saeed Abu says

    June 1, 2014 at 12:58 pm

    Bro i mean that the over charged cut off feature of above circuits will work if i connect a battery without it's self over charged protection circuit(circuit which remain on the top of mobile battery) or 4.2v dry cell battery? Please confirm it first then i will share the other problem oh these circuit.

    Reply
    • Swagatam says

      June 1, 2014 at 3:15 pm

      Bro, do you mean the batteries have its own built-in overcharge protection? I have never heard of this before, can you show me an article or image which explains this??

      Reply
  49. ravindra metri says

    June 1, 2014 at 9:29 am

    Blue LED glow so dim

    Reply
  50. ravindra metri says

    June 1, 2014 at 6:32 am

    Plz i want mobile battery charger circuit operat on ac 230 v

    Reply
    • Swagatam says

      June 2, 2014 at 4:08 am

      https://www.homemade-circuits.com/2014/02/220v-smps-cell-phone-charger-circuit.html

      Reply
  51. ravindra metri says

    June 1, 2014 at 4:41 am

    My battery can not charge above 3.96v. i use mobile battery charger is it correct.

    Reply
  52. Saeed Abu says

    June 1, 2014 at 2:43 am

    Bro i go through ur two updated circuit diagram but no positive feedback.At first u have to clear me that ur given circuit is capable for true over charge cut off feature because i have seen that it is only depend on battery's self over charge protection circuit which i have told before many times.If this circuit not then what about this Circuit(https://www.homemade-circuits.com/2013/12/usb-automatic-li-ion-battery-charger.html). Can i use this for my same requested purpose?

    Reply
    • Swagatam says

      June 1, 2014 at 4:00 am

      Bro, i did not understand what you are saying.

      are you using the above circuit with another auto-cut off circuit??

      If it is so then you should remove it and use it only with a simple 5V adapter.

      I suggested you to measure the voltage at the base of T4 while adjusting P2, but you did not do so.

      The above circuit will surely work if it's done as per the rules, not by trial and error.

      anyway you can try the other one which you have asked, but if you could not make this one you wouldn't be able to make that even, because it has a opamp which will require even more knowledge and precise adjustments.

      Reply
  53. ravindra metri says

    June 1, 2014 at 2:02 am

    My battery can not charge above 3.96v. i use mobile battery charger is it correct.? 2N2907 eqvalant or can i use 2N2222 ? I know 2N2907 matal pinout but i want to plastic transistor pinout

    Reply
    • Swagatam says

      June 1, 2014 at 4:10 am

      2N2222 is NPN, not PNP…. moreover it's also a metal can transistor.

      you may use use 8550, or BEL188, or BD140

      Reply
  54. ravindra metri says

    May 31, 2014 at 11:49 am

    Sir plz tell 2N2907 pinout i confused. and any eqvalant

    Reply
    • Swagatam says

      May 31, 2014 at 3:15 pm

      the lead which is close to the small body projection is emitter, center lead is base, the last one is the collector

      1.bp.blogspot.com/-TAriua1lYrg/TyuESv5W6XI/AAAAAAAAA1s/tgwVOMmoAdA/s1600/2n2222.png

      Reply
  55. ravindra metri says

    May 31, 2014 at 9:17 am

    Sir, charging volt show 3.68 battery postive between D3 & D4

    Reply
    • Swagatam says

      June 1, 2014 at 4:08 am

      try only one diode at the input, D1 or D2, remove one of them and check the response

      Reply
  56. ravindra metri says

    May 30, 2014 at 2:23 am

    Sir, please add LDR circuit for LED on when night if day light mains power goan LED OFF only night time LED on

    Reply
    • Swagatam says

      May 31, 2014 at 3:39 am

      OK, I'll try to include it.

      Reply
  57. ravindra metri says

    May 29, 2014 at 11:14 am

    Can i use 2 battery in parallel any change make

    Reply
    • Swagatam says

      May 30, 2014 at 4:09 am

      no changes will be required.

      Reply
  58. ravindra metri says

    May 29, 2014 at 5:25 am

    1 watt led glow dim can i remove 10 ohm and how to check battery charging or not

    Reply
    • Swagatam says

      May 29, 2014 at 6:43 am

      yes you can remove the 10ohm resistor.

      Reply
    • Swagatam says

      May 29, 2014 at 6:43 am

      the green LED indicates battery is charging.

      Reply
    • ravindra metri says

      May 29, 2014 at 10:42 am

      When charger connect green led not glowing

      Reply
    • ravindra metri says

      May 29, 2014 at 10:44 am

      I remove 10ohm resister but led glow dim

      Reply
    • Swagatam says

      May 30, 2014 at 4:08 am

      the presets will need to be correctly adjusted to get a proper response from the circuit.

      Reply
  59. Saeed Abu says

    May 27, 2014 at 5:01 pm

    Dear bro, i have tried again ur revised circuit but problem is still exist, these r:

    1)Ur developed Over charge cut off system is not worked only work in case of battery with self over charge protection circuit which i have told u before.
    2)During low cut off and Over charge cut off stage the charging Green LED is glowing gently (when i disconnect the charger.)
    3)During over charge cut off stage the full charge indicator Yellow LED is glowing gently.If i adjust the P2 to increase the brightness of Yellow LED then Green LED glow gently and vice versa.

    So i am hoping a nice solution of it from u.

    Reply
    • Swagatam says

      May 28, 2014 at 4:49 am

      Sorry Bro, that looks impossible…

      If the blue LEd in the last diagram illuminates it means T4 is conducting.

      If T4 is conducting it would ground the base of T5, stopping it from conducting.

      When T5 is stopped from conducting how will the green LEd glow???

      Because as long as T5 is conducting the green LED is getting its ground through the collector/emitter of T5, once T5 stops conducting this passage is blocked and the green LED also has to stop glowing, resulting in shutting off the 2N2907 transistor completely.

      Check the voltage at the base of T5 when the BLUE LED is glowing. It should be zero and the green LED must stop glowing.

      Please do the above, we'll troubleshoot it right here…..

      Reply
    • Swagatam says

      May 30, 2014 at 4:07 am

      …i did a slight change in the diagram please check it.

      Reply
  60. Saeed Abu says

    May 24, 2014 at 6:33 pm

    Thanks bro I'll wait for ur corrected diagram also i need true over charge cut off circuit which only worked by ur developed circuit not by the battery's self over charge protection circuit.Pls bro update ur circuit ASAP.

    Reply
    • Swagatam says

      May 25, 2014 at 8:16 am

      Thanks bro, I updated it yesterday itself….please check it out.

      Reply
  61. Saeed Abu says

    May 24, 2014 at 4:10 pm

    Pls bro correct the diagram ASAP.I am waiting for this.Also i need true over charge cut off system i mean battery will be over charge cut off by ur circuit not his(battery) self over charge circuit.

    Reply
  62. Saeed Abu says

    May 24, 2014 at 9:53 am

    Dear bro i have tried again ur new circuit as per ur direction but no positive result.The problem is here:

    1) The charging green LED is glowing during charging but no so much glow.
    2)The yellow LED is not glow during battery voltage is 4.25 also i can not glow that by adjusting the P2. At 4.25v the voltage remain in yellow LED is approx. 0.65v.
    3)Also ur developed auto high voltage cutoff circuit (battery over charge protection) system is not working.Only working Battery's self overcharge protection circuit when voltage reaches at 4.25v( I have tested it again by connecting a battery without it's self overcharge protection circuit, it getting charged 4.40v then i disconnect the charger).
    4)But ur other system low battery cutoff and ac to dc change over system is ok.

    Bro what will be the solution of this.I think u have to develop this circuit practically to find out the solution of this.

    Reply
    • Swagatam says

      May 24, 2014 at 12:48 pm

      Dear bro, the second circuit is perfect in every way.

      again I'll say if you do without understanding, you will keep getting problems.

      if T4 and the yellow led are not conducting it means either one of them is faulty or the connections are wrong in your circuit.

      make R5 = 1k (I had suggested this before also)… and check.

      as soon as T4 conducts, T5 will switch OFF and the green LED will also switch OFF

      you can try making the series resistor of green LED to 1k for increasing its current and brightness.

      practical making won't be required because I am sure this circuit is OK.

      Reply
    • Swagatam says

      May 24, 2014 at 12:56 pm

      …bro, i think got the culprit.

      the yellow led should not be placed at the emitter of T4. connect the emitter of T4 directly with ground

      put it at the base of T4….and check.

      the emitter position is not allowing T5 to stop conducting completely.

      I'll correct the diagram soon.

      Reply
  63. Saeed Abu says

    May 22, 2014 at 1:47 pm

    Dear bro, I have tried again as per ur latest direction but i am again failure.here the problems are:

    1)The voltages at the base of T5 cannot make zero from 0.6v by setting up P2.
    2) The green LED keep glow gently at 4.25v of the battery.
    3)Also ur developed auto high voltage cutoff circuit (battery over charge protection) system is not working.Only working Battery's self overcharge protection circuit when voltage reaches at 4.25v( I have tested it again by connecting a battery without it's self overcharge protection circuit).
    4)But ur other system low battery cutoff and ac to dc change over system is ok.

    So bro what can i do now to over come above problem.Please do something.I think u should practically make this circuit then u can easily find out the problem.

    Reply
    • Swagatam says

      May 23, 2014 at 6:48 am

      Dear Bro, I have modified the diagram with an additional stage, please do it as per the new diagram and check the response.

      Reply
  64. Vidyarthi says

    May 14, 2014 at 7:07 pm

    Dear Sir,

    I request you to kindly suggest me a simple circuit to cut off power supply to a 4V-4Ah lead acid battery on full charge (over charging protection) from a 5V mobile charger.

    Reply
    • Swagatam says

      May 15, 2014 at 10:04 am

      Dear Vidyarthi,

      you can use the following design

      https://www.homemade-circuits.com/2013/12/make-this-usb-li-ion-37v-battery.html

      Reply
    • Swagatam says

      May 15, 2014 at 10:28 am

      sorry here's the correct link:

      https://www.homemade-circuits.com/2013/12/usb-automatic-li-ion-battery-charger.html

      Reply
  65. Saeed Abu says

    May 4, 2014 at 4:50 am

    Bro i have tried again as per ur modification guideline but result is not positive.The green LED is not glowing during charging the battery so there is no question of shutoff the green LED When the voltage reaches 4.25V.Also ur developed auto high voltage cutoff circuit (battery over charge protection) system is not working.Only working Battery's self overcharge protection circuit when voltage reaches at 4.25v( I have tested it again by connecting a battery without it's self overcharge protection circuit) .So Bro i think u have to redesign the circuit freshly and upload it again.I am waiting for ur great feedback.

    Reply
    • Swagatam says

      May 4, 2014 at 6:44 am

      Bro, electronics is not easy, you won't get results even from the easiest of the circuits until you do it by understanding it.

      The above circuit is perfect in all respects according to me, however if you can pinpoint the faults in the design then surely we can debate on that.

      Alternatively you can try testing the design by checking the voltages at the base of T5 while setting P2. The base voltage should almost become zero at 4.25V.

      confirm this by disconnecting the emitter of T4, this should revert the T5 into conducting mode again. once confirmed connect it back in position.

      Reply
    • Swagatam says

      May 4, 2014 at 6:49 am

      …check it by putting red prod of the meter on the positive line and black on the base.

      when conducting, it should show near 0.6V, keep adjusting P2 until it drops to zero at 4.25V.

      Reply
    • Swagatam says

      May 4, 2014 at 6:51 am

      also replace all 33k resistors with 1k resistors.

      Reply
  66. Saeed Abu says

    May 2, 2014 at 4:39 pm

    Bro then what will be the P2 condition it will be removed or not?

    Reply
    • Swagatam says

      May 3, 2014 at 8:18 am

      everything else will be as before, even the setting of P2

      Reply
  67. Saeed Abu says

    May 1, 2014 at 5:55 pm

    Bro thanks ur reply.However today i have developed ur circuit as per ur given model and i successfully done auto ac to dc changeover system,battery low voltage cutoff system but i can not success in auto high voltage cutoff(battery over charge protection) system.The problem is here:

    1)The green LED is not glow during battery voltage is 4.25 when charger is connected but when charger is disconnected from circuit then green LED is glow but so dim.

    2)Then i replace R6 into 1k then green LED is glow normally.

    3) I tune P2 very accurately at battery voltage 4.25 but auto high voltage cutoff(battery over charge protection) system is not worked.

    4) Only working Battery's self overcharge protection circuit when voltage raised at 4.25v but not ur given over charge protection circuit that's why the green LED is not glowing.

    5) I have tested it by connecting a battery without it's self overcharge protection circuit with ur circuit.Ur circuit is continued to give charge that battery and battery voltage is raised up to around 4.75 then i stop to give charge my battery.

    So bro it seems to me that in auto high voltage cutoff(battery over charge protection) system there is something wrong.Pls refine it.This circuit is badly needed for me.I have tried to refine it but i failed.

    Reply
    • Swagatam says

      May 2, 2014 at 6:14 am

      Bro, remove the green LED from the shown position, and connect the collector of T4 to directly to positive.

      Now connect the green LED in series with the base of T5, anode to base, cathode to T4 emitter.

      When the voltage reaches 4.25V, this LED will shutoff indicating that T5 has been switched OFF and the battery is receiving no charging voltage.

      ….also reduce R5 to 1K

      please try this and let meknow the results.

      Reply
  68. Saeed Abu says

    April 30, 2014 at 4:45 pm

    bro is R7=1k is needed and why? Also i can not collect TIP 127 in my locality.So am i use BD 140 or any other NPN Transistor?

    Reply
    • Swagatam says

      May 1, 2014 at 3:42 pm

      Bro R7 is for enabling the transistor to conduct when mains is absent, without it the LED will not glow.
      BD140 will do, it's not an NPN, rather a PNP

      Reply
  69. Saeed Abu says

    April 25, 2014 at 12:08 pm

    Bro what is value of R3 and R4? Is R8 is essential for this circuit?

    Reply
    • Swagatam says

      April 26, 2014 at 5:05 am

      R8 may be removed

      Reply
  70. Saeed Abu says

    April 25, 2014 at 11:46 am

    Bro What is the R3 and R4 value?

    Reply
    • Swagatam says

      April 26, 2014 at 4:59 am

      bro, both are 10k

      Reply
  71. roshan ran says

    April 24, 2014 at 5:48 am

    what is R4 value?

    Reply
    • Swagatam says

      April 25, 2014 at 5:40 am

      10k

      Reply
  72. Saeed Abu says

    April 16, 2014 at 2:46 am

    Bro thanks ur reply.Where should i use TIP127 for 5/6 cells(Parallel connection) in above circuit?Also any change is required in Charge section in above circuit for 5/6 cells(Parallel connection) ?

    Reply
    • Swagatam says

      April 16, 2014 at 8:25 am

      TIP127 should be replaced for the 2N2907 transistor.

      no other changes would be required.

      Reply
  73. Saeed Abu says

    April 15, 2014 at 9:28 am

    Bro thanks for ur developing my requesting circuit and also ur so talent on electronics.If i use 5/6 cell in parallel then this circuit will work properly?What is the alternative transistor of 2N 2907?

    Reply
    • Swagatam says

      April 15, 2014 at 4:00 pm

      my pleasure bro, you can use a TIP127 for 5/6 cells.

      but please note that the circuit is not yet tested by me, although i believe it would work

      Reply
  74. Shiraz rizvi says

    April 15, 2014 at 12:05 am

    Swagatam bro hi… maine 3 watt led lagai but transitor hit ho raha h then whai do plz help me

    Reply
    • Swagatam says

      April 15, 2014 at 7:36 am

      bro use 1 watt led, not 3 watt led, for 3 watt use tip127 as the transistor and a 3.7/2ah batt

      Reply
  75. Trilokee KUMAR GUPTA says

    April 9, 2014 at 7:37 pm

    Hello sir,
    Just I wana to make a circuit wich work in such a way that when ac supply is off then dc supply automatically on but when ac supply is on then dc supply automatically off.pls reply me sir ….

    Reply
    • Swagatam says

      April 10, 2014 at 5:48 am

      Trilokee, pls refer to the following article, you can use the transistor stage for your application:

      https://www.homemade-circuits.com/2011/12/how-to-make-efficient-led-emergency.html

      Reply
  76. Gopal Chauhan says

    April 9, 2014 at 6:52 am

    Swagatam,

    What modification should I do in this circuit to support 4 rechargeable pencil cells of 1.2 volts each, at 1000mah. thanks this will be tried out soon, what can i use as the equivalent of BC 547 available.

    Regards
    Gopal

    Reply
    • Swagatam says

      April 9, 2014 at 1:09 pm

      Gopal, No changes would be required, you may use the same configuration.

      Reply
    • Swagatam says

      April 9, 2014 at 1:10 pm

      any general purpose NPN transistor will work in place of BC547

      Reply
  77. Y0f4N says

    April 8, 2014 at 5:36 pm

    Hello Swagatam,
    I just want add some detail for your article at first circuit since use variable resistor. For expert will be no issue to adjusting P1 and P2. As your blog mention, we are here for learning an discussion.
    To setup P1 as use for protection low batt
    – Remove / unplug the input power supply then connect your low battery (can use 3.2 V or 3.0 V) for me prefer 3.2 V.
    – Adjust P1 until red LED was glow and main LED was off
    To Setup P2 as use for protection overcharge
    – Plugin the input with power supply and put batt with full charge. let say about 3.7 V
    – Adjust P2 until green LED are glow
    hope this can help
    Thanks & Rgds,
    Yofan

    Reply
    • Swagatam says

      April 9, 2014 at 4:34 am

      Hello Yofan,

      That's perfect. You've made life easier for those who would want to build this.

      Thanks very much.

      Reply
    • Swagatam says

      April 9, 2014 at 4:40 am

      yofan, the full charge threshold of 3.7 li-ion is 4.2V

      Reply
    • Y0f4N says

      April 10, 2014 at 9:19 am

      Hello Swagatam,
      agree with you 4.2 V ..it's seem I miss set to 3.7 V

      Reply
  78. Y0f4N says

    April 8, 2014 at 12:07 pm

    Hello Swagatam,
    thank you for your fast design.this design more cheap and easy to find for componen at local store.I just modify for LED driver with replacing T6 with BD 139 and adjust R7 with 10 K for 3 Watt. In this design better you remove D1,D2 as T5 already protected the battery. A
    P1 is key to prevent battery to drop to deep and P2 to protect battery from overload.
    Just suggestion for protection battery , when we set 3.2 volt as cutt off battery and full charge about 4.1 Volt, then we can modify P1 and P2 as fixed resistor. as I see R1,P1 and R5,P2 are voltage devider.may be it's not easy to find match resistor
    Thanks & Rgds,
    Yofan

    Reply
    • Swagatam says

      April 8, 2014 at 3:02 pm

      Helo Yofan,

      You are welcome!
      yes, after confirming the exact values, P1/P2 may be appropriately replaced with fixed resistors..it won't be much difficult

      Reply

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