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100 Watt LED Constant Current Driver Circuit Diagram

Last Updated on January 17, 2025 by Swagatam 190 Comments

You might have probably come across these fantastic high power, high efficiency LED modules and wondered how do you make these? Here I have explained how to make a 100 watt LED flashlight out of it?

Introduction

The article revises the datasheet of this LED module and explains a simple driver circuit which can be used for operating it safely for the intended lighting purpose.

So far we have learned about LEDs with rather smaller features and applications. However the present article finds out how a LED module in the order of 100 watts can be actually used for illuminating a house at costs probably 5 times lower than the conventional lighting devices.

 100 Watt LED Module Image

100 watt LED module

We have all studied a great deal about LEDs and about their high-efficiency with power consumption.

The LED technology has helped us to design and incorporate very high intensity light installations at minimal consumptions as compared to the other conventional form of lighting concepts.

Lower power consumption also means low heat emissions, which again is an added feature and helps to keep the crucial issue of global warming at bay when LEDs are utilized.

As days pass by, technology keeps on improving and we are able to witness many incredible and unbelievable results with these outstanding lighting devices.

The 100 watt LED module is one such marvel of modern science which has created a breakthrough in the field of LED lighting.

Not surprisingly, the device is able to generate an astonishing 6500 lumens of light intensity at a consumption of mere 100 watts, but the interesting part is the size, which is barely 40 square mm.

The saving made by these devices is estimated to be five times more than any other form of light producing device and the if we compare the specified intensity of 6500 lumens, that corresponds to an excess of 500 watts light power that might be acquired from a halogen lamp.

Let’s discuss the important specifications of this amazing LED in brief and in such a way that even a layman understands:

100 Watt LED Datasheet

Typically the preferred color is white, as that produces the most favorable and desirable illumination for all applications.

  • The power consumed is 100 watts for optimal performance.
  • The emanated heat for the specified white color is up to 6000 Kelvin.
  • The intensity of light generated with the above specs is a staggering 6500 lumens.
  • Typical operating voltage of the device is around 35 volts.
  • The current required for producing the above light intensity is around 3 Amps.
  • ESD level is safe and very high up to 4000 V.
  • The safe operating temperature level is very wide, ranging from minus 40 to 110 degrees Celsius.
  • The optimum angle of viewing is also wide, up to 120 degree.
  • Dimension of the unit is truely mini, the height being 4.3 mm, length 56 mm and width 40 mm only.

Typical Specifications

  1. LED Type: 100W COB LED
  2. CRI: Ra70-80/ Ra80-85/ Ra90-95 / Ra95-98
  3. IF (Forward Current): 3500mA
  4. VF (Forward Voltage): 29-34volts
  5. Chip Category: Bridgelux
  6. Power Output: 100 Watt
  7. Angle of Beam: 120 degree
  8. Illumination Magnitude: 10000-14000lm
  9. Substrate: high-grade copper
  10. CCT: 3000K, 4000K, 5000K, 6000K.(any CCT can be customized)
  11. Main application areas: Spotlight, Roving head light, light in stage shows, photography, High intensity rescue floodlight, etc

The specification narrated are sufficient for illuminating a 20 square meter space amply, almost at flood light levels ….. baffling.

Main Features of the 100 Watt LED

The advantages include the following:

High power light output without degradation even after long usages.

Highly robust mechanical specifications, involving less wear and tear and high resistance to changing atmospheric hostilities.

The overall performance is consistently optimal throughout the operating life.

Having discussed the above features of the proposed 100 watt LED lamp, it would be interesting to also learn regarding a useful recommended circuit that may be used for driving or operating the device at safe levels.

How to Make a Current Controlled 100 watt LED flood Light Circuit

A simple two transistor, powerful current limiter, LED driver circuit, which can be used for converting the above discussed device into a 100 watt LED flashlight or to be more accurate, a floodlight is described below:

The circuit of a 100 watt LED flood light shown below has been discussed in few of my other articles also, due its versatile and rather straightforward design; the circuit becomes very suitable in places where current limiting at low costs becomes an issue.

Though the discussed designs mostly dealt with low current applications, the present circuit is specifically intended for handling high currents and up to 100 watts and more power.

Circuit Diagram

100 Watt LED Constant Current Driver Circuit diagram

Looking at the figure we can see a couple of transistors are coupled together such that the base of the upper transistor T1 becomes the collector load of the bottom transistor T2.

The upper transistor T1 which actually carries the LED current is quite vulnerable itself, and is not equipped to control the amount of current through itself and the LED.

However since the base current of this transistor decides the amount of collector current that can pass, it simply means that by restricting its base current to some safe specified levels, it might be possible to keep the overall consumption within tolerable limits.

A current sensing resistor connected at the emitter of T1 is used to convert the current consumed, into a potential difference, across it. This potential difference becomes the base trigger for R2.

However as long as this voltage is below 0.6 volts or simply below the minimum forward voltage drop of T2, T2 remains unresponsive, but once it starts exceeding this value, triggers T2 which in turn clamps the base voltage of T1, rendering it inactive.

This instantaneous cut off of the base drive to T1 shuts the LED for some fraction of a second, bringing the current and the potential drop across the current limiting resistor to zero.

This action reverts the circuit to its original stance and the LED is again switched ON.

The process repeats a number of times per second to keep the LED and the current to safe and precisely tolerable limits.

The value of R2 is calculated in such a way that it keeps the potential difference across itself below 0.6 volts until the LED current reaches 100 watts, after which the restricting process begins.

Warning: The LED must be mounted on a correctly optimized heatsink as per the specifications provided in its datasheet..

How to Calculate the Constant Current Limiting Resistor

For calculating R1 you may use the following formula:

R1 = (Us - 0.7)Hfe/Load Current,

where Us = supply voltage, Hfe = T1 forward current gain, Load current = LED current = 100/35 = 2.5 amps

R1 = (35 - 0.7)30/2.5= 410 Ohms,
wattage for the above resistor would be = 35 x (35/410)  = 2.98 or 3 watts

Formula for calculating R2 is:

R2 = 0.7/LED current
R2 = 0.7/2.5 = 0.3 ohms,
wattage may be calculated as = 0.7 x 2.5 = 2 watts

For an SMPS driver circuit please refer to this article

Current Controlled 100 watt LED Lamp complete schematic

100 watt led with driver circuit Diagram using 1 watt LEDs


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Filed Under: Lamps and Lights Tagged With: 100, Constant, Current, Driver, LED, Watt

About Swagatam

I am an electronics engineer and doing practical hands-on work from more than 15 years now. Building real circuits, testing them and also making PCB layouts by myself. I really love doing all these things like inventing something new, designing electronics and also helping other people like hobby guys who want to make their own cool circuits at home.

And that is the main reason why I started this website homemade-circuits.com, to share different types of circuit ideas..

If you are having any kind of doubt or question related to circuits then just write down your question in the comment box below, I am like always checking, so I guarantee I will reply you for sure!

Previous Post: « Making a Pyrometer Circuit
Next Post: 230 Volts Bulb String Light Circuit for Diwali and Christmas »

Reader Interactions

Comments

Unknown says:
December 17, 2016 at 2:07 pm

Hello!

T1;T2 value? Thank you. Great circuit!

Reply
Swagatam says:
December 18, 2016 at 5:31 am

T1 = 2N2222
T2 = 2N3055

Reply
9707a392-a733-11e5-ac1d-d7e256602c6e says:
November 27, 2016 at 3:45 pm

Thankyou Sir!I got it.
I will report the result as soon as I finished it.

Reply
Swagatam says:
November 28, 2016 at 2:30 am

OK, thanks

Reply
9707a392-a733-11e5-ac1d-d7e256602c6e says:
November 21, 2016 at 8:59 pm

Sir!
still i am waiting of the remote module for this circuit.I hope you didnt forgot it.Thanks.

Reply
Swagatam says:
November 24, 2016 at 12:22 pm

I have published the article here

https://www.homemade-circuits.com/2016/11/remote-controlled-solar-lamp-intensity.html

Reply
Swagatam says:
November 22, 2016 at 5:59 am

thank you for the reminder, I'll try to publish it within a couple of days.

Reply
9707a392-a733-11e5-ac1d-d7e256602c6e says:
November 12, 2016 at 10:04 am

Thankyou very much sir!your website complitelly changed my hobby.So i want to learn more and more.That is why i dont want to buy anything.Instead i want to
make it.So i will wait till you publish it.

Reply
Swagatam says:
November 12, 2016 at 1:40 pm

OK thanks very much!!

Reply
Yoram Stein says:
November 6, 2016 at 10:17 pm

What about cooling of both the power transistor and the LED

Reply
Swagatam says:
September 12, 2016 at 5:16 am

you can use a small metal clamp and fix the heatsink with the resistor using screw nuts, make sure the resistor is a wire wound type

Reply
Swagatam says:
September 11, 2016 at 12:32 pm

….because the calculated wattage is the approximate breakdown value, below this value the resistor might start burning, so this value will just safeguard the resistor but not stop from heating

Reply
Swagatam says:
September 11, 2016 at 12:30 pm

yes, Even if you have calculated it correctly it will still dissipate some heat but might not burn out.

to minimize heat you can either double the wattage value, or add a small aluminum plate with it as heatsink.

Reply
beni says:
September 4, 2016 at 8:17 am

Thankyou very much for your quick respond,According to manufacturer data,the LED has 10 wATT AND 700mlamp.So that means,the max. Voltage is around 14v.but even with this one the brightness is not good.so i put the 5 nos in parallel and connect them with the circuit and with SMPS gave 26v,1.5amp.then the brighteness was good.Is it the right way?one more question:-is it necessary to put a limiting R for each LED or not?

Reply
Swagatam says:
September 4, 2016 at 2:04 pm

No it's not the right way…for 5 LEDs in parallel the current input should be equal to 0.7 x 5 = 3.5 amp..or 4 amps

Therefore the input supply source should be rated at 14V 4 amps.

If you use the above explained current limiter circuit then the LEDs will not required individual resistors.

Reply
Swagatam says:
September 3, 2016 at 2:57 am

What is the voltage rating of the LEDs?? if it's 12V then you can put them in parallel and connect the assembly with the above mentioned circuit. The supply will need to be around 12V

Reply
francisco rodriguez says:
August 15, 2016 at 7:23 pm

Hi, i have read a lot this post and called my attention.

I bought a 30w 32-36v red LED light(i have burned a few LEDs before) and i want to make the led power supply. I tried and i can't do a good power supply to have the best performance from LEDs.

I used 2 ideas to make a power supply:

1) I have a 220 to ~36v AC transformer from old printer, and a rectified DC voltage around the 50v. The LED has a consumption of about 950 mA(enough from transformer). Besides i have two 2sc3320 from a bad pc power supply, and a few bc547… i tried using a 2sc3320 to make a simple dimmer(first LED burned) but didn't work.

2)i had the idea to rectify from 220v ac… but i think that i will burn another LED

So… wich idea is better to use? and how i can make a circuit for this LED power supply using the things i have?(except by resistors).

Best Regards

-Francisco

Reply
Swagatam says:
September 12, 2016 at 5:25 am

yes that's possible, actually I have discussed this elaborately in the comments above with one of the members….please go through it for the details.

Reply
francisco rodriguez says:
September 11, 2016 at 11:31 pm

Thank you very much it was helpful. I question arises, you could use the same scheme replacing the transistor by a MOSFET?

Reply
Swagatam says:
August 19, 2016 at 7:09 am

OK, that will do, just calculate the parameters as per the given formula….

Reply
francisco rodriguez says:
August 19, 2016 at 2:34 am

I suposse that my T1 must be the 2sc3320 and my T2 the 2n2222?

Reply
francisco rodriguez says:
August 19, 2016 at 1:59 am

Okay, thanks!
I'll try it, hence I tell how things go 😀

Reply
Swagatam says:
August 17, 2016 at 9:56 am

yes there's no problem, make sure to confirm the current by connecting a 10amp DC ammeter at the points where the LED would be connected….it must not show more than 800mA…..and mount the transistors on large heatsinks.

Reply
francisco rodriguez says:
August 17, 2016 at 4:13 am

I thought I'd ask before try to use the circuit.

So… there is no problem with voltage while the current is limited? I can put the LED safely in 50v dc with current limit to 800mA?

Reply
Swagatam says:
August 16, 2016 at 3:29 am

Hi, did you try the concept explained in the above article?

Once the current is limited, the voltage is bound to drop to the preferred limit.

so I would recommend you to use the above circuit with current limit set to 800mA.

for the lower transistor I would recommend a 2N2222, but you can try 2sc3320 also…

while calculating use the value "1.5" instead of "0.7" if you are using 2sc3320 for the lower transistor.

Reply
Mike Wallace says:
May 24, 2016 at 9:17 pm

Hello, this site is awesome, thank you for it. I have 10 LEDs with a Vf of 3.75V and current handing of 1050mA. I would like to make a few different circuits as follows:

1: run 3 of the LEDs using two 18650 size, 3.7VDC (4.2VDC when fully charged) Li Ion batteries connected in series.

2: run 4 of these LEDs with the same battery setup

3: run 2 of these LEDs using only 1 of the same batteries

4: run 1 of these LEDs using 1 of the same batteries

I would like all 4 of these circuits to maintain the brightness of the LEDs with fully charged batteries all the way through until they need to be charged. I would also prefer these circuits to include reverse polarity protection, battery over-discharge protection and, if possible, thermal protection. I would also like to fit them into a flashlight body if possible (I have a massive assortment of different sized flashlight bodies to choose from). I do have the ability to make and/or order completely custom PCBs and/or flashlight bodies if necessary.

I know this is a lot to ask and I greatly appreciate any assistance you may provide to me.

As always, thank you and have a great day! 🙂
-Mike.

Reply
Swagatam says:
May 25, 2016 at 10:54 am

Hi, I am glad you liked my site!!

Can please you tell me why you need this variable LED light set up? and how do you plan to switch the LEDs, do you prefer to do it manually or should this happen automatically as the voltage drops.

I'll have to address this design through a new article, so please specify the above data.

Reply
Swagatam says:
May 21, 2016 at 1:57 am

yes, it seems there was a mistake while calculating, that's the reason why I suggest everybody to calculate the parameters themselves using the formulas which are explained comprehensively, because I have to attend many many comments together and that can make me prone to mistakes..

your calculations are correct if you did it exactly as explained in the article…

Reply
John says:
May 10, 2016 at 1:03 pm

Hi, I have two TIP102 on hand and was wondering if they could be used with a 34v 3A 100w led. I calculated R1 to be 333ohm 5w. Does this sound about right?

Reply
Swagatam says:
May 11, 2016 at 5:46 am

Hi, yes it's OK to use them for the mentioned purpose.

If you have used the formula exactly as given, by filling the parameters accurately then you can expect a correct answer…I do not have all the data so I am unable to calculate it myself

Reply
Anil Kumar. K says:
May 5, 2016 at 8:40 pm

Hi Swagathm
I have some doubts related with current controlled circuits. Please clarify.

1) If I use a 35v, 2.5A SMPS , can I avoid this transistorised current control circuit ….? If voltage is constant current will also constant.

2) As per your above circuit calculation , at 35v, LED current is 2.5A. Then at eg.30v and 40v what will be the current flow through the LED….?

Thanks in advance.

Reply
Swagatam says:
May 6, 2016 at 8:43 am

Hi Anil,

1) yes if the source current is limited to the safe level then there's no need of using the above circuit, you can directly connect the LED with your power supply.

If the voltage is constant then the current will be also constant that's true but if the LED temperature rises it might start drawing more current from the source even with a constant voltage situation, that's why current limiting is essential.

2) For a 35V LED its current consumption will become proportionately lower at 30V and proportionately higher at 40V….but if the current is restricted from the source then even at 40V the current will not go above 2.5A….

Reply
Keynon Ketcher says:
March 11, 2016 at 12:58 pm

Sir can you please give me the circuit diagram for the above 34V power supply.

Reply
Swagatam says:
March 11, 2016 at 2:07 pm

keynon, please procure a 12-0-12v/3amp transformer first along with 4nos 6A4 diodes and a 2200uF/50V capacitor, then we can discuss further.

Reply
Keynon Ketcher says:
March 7, 2016 at 7:11 am

Swagatam sir can you suggest me a 35v rectifier circuit for operating this driver.

Reply
Swagatam says:
March 11, 2016 at 11:39 am

…converting a 5V to 35V would be unnecessarily lengthy and costly process…so not recommended.

Reply
Swagatam says:
March 11, 2016 at 11:38 am

the best option would be to buy a 12-0-12V transformer and use its end wires with a bridge rectifier and a 2200uF/50V capacitor to get around 34V DC output and then use this output in conjunction with the current limiter circuit explained above to drive your LED

Reply
Keynon Ketcher says:
March 11, 2016 at 7:07 am

Thanx for your response sir. I'm going to used it to drive a 100 watt led. So 6A4 diodes would be suitable. So sir please suggest me a 35v power supply circuit.

Reply
Swagatam says:
March 7, 2016 at 4:43 pm

Hi Keynon, you can use a 1N4007 for the rectifier if the current spec is below 500mA or 1N5408 if the current is below 2amp or 6A4 diodes if the current is below 5 amps

Reply
Marinko Radenovik says:
March 3, 2016 at 10:09 am

dear Swagaram I have power supply from printer epson and gives about 36.4v I want to use for 100w led but am afraid that the led will burn,how can I set the voltage to 34volts can you help me what should I bild before the led chip

Reply
Swagatam says:
March 3, 2016 at 11:17 am

dear marinko, if you restrict the current to a safe level by the procedures explained in the above article then the voltage will automatically settle down to the LED spec…36V will not be an issue once the current is suitably limited.

Reply
Dipin Joseph Vakkathumalil says:
November 11, 2015 at 1:32 pm

Very useful tutorials. I searched the entire net to get a circuit for a 20v smd led. Can you please tell me which transistors and resisters should I use. The led specs. are :

20w white color led
Vf 9-12v DC
If 2000MA
Output lumens 1800-2000lm
Operate voltage 9-12DC

I don't know anything about electronics. Please help if you can 🙂
Thank you

Reply
Swagatam says:
December 6, 2015 at 8:53 am

Dear Marc, did you attach a large heatsink with the LED??

Make sure you do this otherwise your LED will get damaged within a minute

additionally you will need to introduce the above explained current limiter for your LED, or you can also alternatively employ the following current limiter which is much sophisticated than the above.

https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

also make sure to attach large heatsink to the transistors or the LM338 whichever is selected by you

Reply
MARC says:
December 6, 2015 at 6:52 am

dear swagatam sir

we are using 32 watt cob led 12 vdc power supply current 3 amps the power supply is 12 VDC power supply but the led lights are getting hot and buring out the power is 12 vdc we have checked with the multimeter cand u please suggest will this circuit help in this case

Reply
Swagatam says:
November 21, 2015 at 2:18 pm

Please use the formula furnished for calculating the resistors.

Reply
Dipin Joseph Vakkathumalil says:
November 21, 2015 at 8:30 am

Thank you for the quick reply sir. Can I use TIP31 and 2N2222 for T1 and T2, as for 10w Led drive? And what should be the R1 ?

Reply
Swagatam says:
November 12, 2015 at 1:03 pm

Thanks! You can do it by simply by connecting the above explained transistorized current limiter circuit stage with the output of any standard 12 V 2 amp SMPS AC to DC adapter unit, and then connect the LED at the position shown in the diagram…

the value of R2 will be 0.6/2 = 0.3 ohms..2 watt

Reply
Swagatam says:
October 31, 2015 at 2:27 pm

470 ohm is for protecting the transistor base…so it cannot be removed even with a PWM control..

Reply
Unknown says:
October 30, 2015 at 1:38 pm

Can you use pwm to control the input 12v to dim and leave the 470 alone as well?

Reply
Aditya Kadlag says:
October 27, 2015 at 10:43 am

Thankx swagatam ,
All the question and answer clarified all my doubts.
Thankx for the share really very helpfull …
Keep up the good work .

Reply
Swagatam says:
October 28, 2015 at 3:58 am

You are welcome Aditya!

Reply
Thilanka Thilina says:
October 25, 2015 at 9:08 am

hi,
can i have the circuit diagram for 5w / 10w Led's? it would be really helpfull.

Reply
Swagatam says:
October 25, 2015 at 2:19 pm

mains operated or low voltage DC operated?

Reply
Pedro Rodrigues says:
September 28, 2015 at 10:47 pm

Hello, if i need to control a on/off 10W 12v led with a 12v 3.3 battery with a reed switch, where do i need tu put it on the circuit?
thanks

Reply
Swagatam says:
October 8, 2015 at 1:45 pm

1K with the reed will not be required now.

TIP31 and 2n2222 will do for a 10 watt led.

hfe is not critical, it can be any average value within the range of the device.

resistor watt may be calculated as per the explanation given in the above article.

Reply
Pedro Rodrigues says:
October 7, 2015 at 10:09 pm

So in this case i dont need the 1k resistor for reed right?

For my 10w 12v led i will use a 12v 3.3A battery for supply and i will use for T1 TIP31C and for T2 2N2222A, can you tell me wich hfe value from datasheet of TIP31C i will use for R1 calculations?
For this power of led will 1/4 resistor for R1 and R2 are enough?

Finally are my choices forr T1 and T2 correct?

Thanks

Reply
Swagatam says:
October 4, 2015 at 5:03 pm

connect T1 base through the reed to R1, meaning the T1 base should connect to R1 through the reed…that's all.

Reply
Pedro Rodrigues says:
October 4, 2015 at 4:42 pm

But i want the opposite, i want the led to shut off when the reed opens, what do i need do do?

Reply
Swagatam says:
October 2, 2015 at 7:21 am

when the reed closes it activates T2, which in turn grounds T1 base forcing the LED to shut off

Reply
Pedro Rodrigues says:
October 1, 2015 at 6:53 pm

Can you explain theoretically how this will control de circuit if i connect the reed like you said?

Reply
Swagatam says:
September 30, 2015 at 1:46 pm

Do not disconnect the base from its existing position, simply connect the reed to the base of T2 as explained earlier.

Reply
Pedro Rodrigues says:
September 29, 2015 at 12:33 pm

So i disconnect the base of T2 from the circuit and connect the reed like you said, or i leave the circuit like it is and connect the reed like you said?

Reply
Swagatam says:
September 29, 2015 at 9:21 am

you can wire the reed across the positive supply and the base of T2…make sure to include a 1K resistor in series with one of the reed wires…

(+)<——–(reed)—–^^^^^——–>base of T2

Reply
rock.pro. says:
July 29, 2015 at 5:23 pm

hey sir
… your all project is awesome . i am using some circuit . sir i want a new circuit for 10watt LED through AC supply 220VAC (if any option to use 15 watt CFL Kit to make) or making new circuit for 10watt LED … , THANKS FOR READING SIR

Reply
Swagatam says:
July 30, 2015 at 1:01 pm

thanks rock.pro, I am glad you liked them.

You will basically need an SMPS driver circuit for illuminating a 10 watt LED…you can try the following circuit and effectively use it for the same:

https://www.homemade-circuits.com/2012/03/how-to-make-simple-12-v-1-amp-switch.html

Reply
mus tafa says:
July 17, 2015 at 12:25 pm

Hy Swagatam, I am from Indonesia.. can you help me
I want to make adjustable driver circuit for LED 100w (34v 3A) which can adjust the light intensity of 30 to 100%..
Can you indicate what its circuit.?

Reply
Swagatam says:
July 17, 2015 at 12:46 pm

Hi Mustafa,

you can try the following circuit and adjust R6 for obtaining any desired illumination on the LED.

https://www.homemade-circuits.com/2014/09/32-v-3-amp-smps-led-driver-circuit.html

Reply
김기정 says:
July 14, 2015 at 2:45 pm

Hello Swagatam. I have a 20w led (36v and 0.525mA) what are the resistors that i need?
be already in useT1:TIP31C, T2:MMBT3904

Reply
Swagatam says:
July 15, 2015 at 3:10 am

please calculate with the help of the given formulas.

Reply
김기정 says:
July 14, 2015 at 2:42 pm

hello, I have a 36V 20W LED, what resistors that i need?
T1:TIP31C, T2: MMBT3904

Reply
S Elango says:
June 14, 2015 at 7:18 am

I have 12 battery and 12v,10w led bulp 5no's.that bulps are connected in parallel,the bulp takes 2amps,lm338 regulator using but heat is very high,so please give 12v DC to DC constant current and voltage drive circuit.

Reply
Swagatam says:
June 14, 2015 at 1:08 pm

LM338 is the easiest option to go with….an SMPS could be quite difficult to build.

Use a large heatsink with the IC and also with the LEDs, that will take care of the situation.

Heating is a normal phenomenon, there's nothing to worry about it, just use a heatsink with maximum dimensions…

Reply
Vinesh m.k says:
June 9, 2015 at 11:13 am

i want to use the circuit for 50w..what changes should i make

Reply
Swagatam says:
June 10, 2015 at 9:46 am

what are the voltage and amp specs of your LED?

Reply
Swagatam says:
April 21, 2015 at 6:25 am

You are welcome!!

Reply
Swagatam says:
April 20, 2015 at 3:51 am

Hello Mark,

you are right, 10k, 1/4 watt will do.

BC547 is a BJT, and all BJTs require just around 0.7V to trigger across their base/emitter, so 5V is incorrect you might have interpreted something else.

Reply
Swagatam says:
April 13, 2015 at 4:00 pm

The transistors can be TIP3055 for T1, and TIP41 for T2. both on large heatsinks

R2 = 0.7/3 = 0.233 ohms, 3 watts

R1 = 220 ohms, 5 watts

Reply
Raj says:
April 3, 2015 at 3:44 am

Hi Swagatam, excellent tutorials you have made here. I have a confusion. I want to power a 10 Watt LED using a12 volt-3A adapter. In one comment you said
"Make R1 = 40 Ohms and R2 = 0.2 Ohms for using a 10 watt LED @12V supply." and in another comment you said
"T1 and T2 are transistors, for your application you may use TIP31 for T1 and 2N2222 for T2.
As per your LED specs the other component values could be as follows:
R1 = 270 ohms, 1 watt
R2 = 0.7 ohms 1 watt".
Which one is correct? And also is 0.2 or 0.7 ohms resistor available in market?
Can I use TIP41 instead of TIP31? Any alternatives for 2N2222?

Also, I bought a 20W LED floodlight few months back, it is now flickering very much. I measured the LED driver, the voltage is constant 42V but the current is varying for about every 0.2 seconds from 0.1A to 0.9A. The driver has a chip "PL3536", I think that is malfunctioning. Any ideas how I can fix it?

Reply
Swagatam says:
April 4, 2015 at 4:11 am

yes it can be used

Reply
Raj says:
April 3, 2015 at 12:10 pm

Is the LM317 capable of driving a 10watt LED from 12volt?

Reply
Swagatam says:
April 3, 2015 at 11:45 am

Thanks Raj,

The calculations were done as per the given formula, you can calculate the R1, R2 values as per your LED specs and confirm the results.

However the above mentioned design is suitable for higher voltage drivers where an IC regulation may not be available, for your 10watt 12V purpose you can simply use a LM338 current controller as explained here

https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

although for a 42V driver the above circuit may be tried since an IC circuit could be difficult to find

Reply
basit momin says:
April 2, 2015 at 2:29 pm

Sir how can I give 35v to the circuit through 230v AC main

Reply
Swagatam says:
April 3, 2015 at 11:19 am

Basit, you'll need an smps driver for it, as shown here:

https://www.homemade-circuits.com/2014/09/32-v-3-amp-smps-led-driver-circuit.html

Reply
Pinaki Gupta says:
March 14, 2015 at 8:02 pm

Can I put a capacitor between the Vcc and LED junction so that the light does not flicker at all. What would be the calculation method for this capacitor and what would be the type of that capacitor, please give me an idea about it.

Reply
Swagatam says:
March 15, 2015 at 5:59 am

yes you can do it, calculating it is not necessary, the larger the value the better it'll get.

perhaps a 2200uF/50V would be more than sufficient.

Reply
Pinaki Gupta says:
March 1, 2015 at 12:55 pm

Hello,
I'm from India. I will be using 5x100W LED lights as my video light from AC 250v/50Hz source.
I'm currently using Halogen Lamps (Work Light) for my video cameras made by "Simpex" and bulb made by "Halonix". It is 1000W. Best part: It does not create any flicker in my video footage.
If I make a LED video light what will be the modification to the circuit and would it create any flicker in my footage? If it does it would ruin my footage. What about the Heatsink? And I need LED of a colour temperature nearly 2800K to match my Halogen is it possible?

Reply
Swagatam says:
March 3, 2015 at 4:14 am

Mr. Pinaki,

regarding the SMPS you may have inquire in the local electronic market, or you can buy it from any relevant online store

If i get an opportunity I'll surely try out the experiment and let you know about the results.

Reply
Pinaki Gupta says:
March 2, 2015 at 8:25 am

Mr. Swagatam Majumdar, Thanks for your quick reply.
Where can I find such an SMPS in Chandni Market, Calcutta, as I am in Calcutta?
What would be the approximate cost of that SMPS?
I need your assistance for one thing. Please bring a camcorder DV/Digital-8 or any from someone for one day and test different footage with a single 100W white LED and check whether it creates any flicker or not. Warm white would be better since they are nearly halogen like yellowish (3200K) while halogens are a little more yellow, 2800K 18000 lumen.
Be sure to keep the shutter speed at 1/50. Also test whether there is any flicker at a higher shutter speed e.g., 1/100, 1/250, 1/500, 1/1000 etc.
I'm interested in the above circuit since it would be a lot cheaper and a viable alternative to halogen/HID for everyone.
These days halogen based lights are annoyance in an air conditioned conference room, closeup shots, small room, summertime shots. So LEDs are the way to go. Please update me after testing.
Thanks.

Reply
Swagatam says:
March 1, 2015 at 4:01 pm

Since the LED lamp would be run on Dc it would generate zero flicker or interference, so it would work better than a halogen lamp.

The above circuit is s cheaper alternative, although it's reasonably accurate I would recommend you to buy a current controlled 33V / 15 amp SMPS unit for operating the LED modules.

The LEDs would definitely need heatsinks, it would include a back base with appropriate slot to facilitate clamping of the modules with large aluminum plates for the required cooling.

Reply
Gildor Simplice says:
February 12, 2015 at 7:55 pm

I want to power a 10w led using a 12v lipo batter, i wanted to use the 2nd circuit that you mention here: https://www.homemade-circuits.com/2012/11/3-watt-5-watt-led-dc-to-dc-constant.html I want to also make that flash like emergency lights. I saw that you mention on the comments here for a guy to use "IC555 astable circuit" is that what I need to use, if so, how do I hook it up in the circuit, and where do I purchase it, or can I just do a google search for "IC555 astable circuit"
thank you for your help.

Reply
Swagatam says:
February 16, 2015 at 4:13 am

you may refer to this article which is quite identical to your requirement:

https://www.homemade-circuits.com/2012/09/led-emergency-light-circuit-using-boost.html

R1/R2 should be 47k each and C1 = 10uF/25V

the supply points would need to be connected with the output from the LM338 circuit.

L1 could then be replaced with the specified LED

Reply
Gildor Simplice says:
February 15, 2015 at 3:02 am

thank you for your reply, can you tell me what is a BJT, kinda new to this, is there any way you can post a quick wiring diagram of how you are telling me to hoke it up please

Reply
Swagatam says:
February 13, 2015 at 2:53 pm

yes you can use any standard 555 astable flasher circuit and drive the LED from a BJT stage connected at pin3 of the IC…..such as a TIP122…connect its base with pin3 via a 10k resistor, emitter to ground (negative) and the LED across collector of the transistor and positive supply.

The battery poles may be then connected to the input of the LM338 circuit and the output of the LM338 to the pin4/8 (positive) and pin1 (ground) of the astable….positive will also connect to the LED as explained above

Reply
Aaron Atkinson says:
February 6, 2015 at 6:00 pm

Hi, I have a workshop and would like to run 5 x 50w led flood lights in a row,
they would be run from a 240v output genarator.
Can I run them from one driver/transformer or does each LED need a separate supply?
I am out of my depth when it comes to making one so I will have to buy what I need.
Could you please advise me on what I need to get.

Many Thanks

Reply
Swagatam says:
February 7, 2015 at 4:11 am

Hi, you can run all the 5 modules from a single adequately rated power supply unit, preferably an SMPS unit.

In between each LED and the supply you will need to insert a current controller stage as shown in the first diagram of the following post:

https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

LM117 will need to be replaced with LM338

Reply
wolf says:
December 4, 2014 at 3:57 pm

Great blog.

Question: what do u use for T1 and T2? Url? Any heatsink requirements?

Question: are R1 and R2 axial resistors?

Reply
Swagatam says:
February 12, 2015 at 1:24 pm

Hi, thanks

you can use TIP3055 for T1, and TIP31 for T2, these transistors would also work for 50 watt and 200 watt lamps 🙂

Reply
Solder Sam says:
February 12, 2015 at 3:29 am

HI! Like the others; Great site, and thanks for sharing your knowledge! But I wish you could have been a bit more specific this time. An amateur tinkerer like me has no idea what transistors to use. I can build stuff from schematics, and cross reference if I don't have the recommended transistors, but I need to know where to start looking in my scrap box…

I'm experimenting with a similar LED to the one in the picture. I rescued it from a dumpster, so I don't have the specs, but a quick test showed that it works. It has five rows of ten LEDs, and after googeling a bit it seems that that means it's a 100W unit, right? And if so, what would you have used for T1 and T2?

On behalf of noobs the world over, please enlighten us!
(recommendations for 50W and 200W+ setups are also most welcome… 🙂

Reply
Swagatam says:
December 5, 2014 at 8:48 am

thanks, heatsinks will be required for T1/T2 depending on the load dimension.

R1, R2 could be axial or any other variant doesn't make any difference.

Reply
jsingh64 says:
November 10, 2014 at 1:04 am

How can you vary the brightness of 100 watt led?

Reply
Swagatam says:
November 10, 2014 at 4:01 pm

use a variable resistance for R2

Reply
Geo K says:
November 6, 2014 at 1:02 am

By way of the DC boost converter that utilizes the much higher, reversed polarity fly back voltage from its inductors collapsing magnetic field whilst its oscillating at high frequency. That higher then source and presently AC voltage is then rectified back to DC at the desired higher voltage. Pretty simple stuff when you look at the schematics for any boost/buck converters…

Reply
Shekhar Jaiswal says:
October 27, 2014 at 8:39 am

I would like to try a 50 watt version and a 30 watt version, would you change the R value for each curcuit?

Reply
Swagatam says:
October 28, 2014 at 3:56 am

you can take the help of the following article and the given formulas:

https://www.homemade-circuits.com/2013/02/make-this-1000-watt-led-flood-light.html

Reply
Anish says:
September 17, 2014 at 12:45 am

Dear Sir,

Thanks for the setup, could you pls tell the value of T1 and T2. Also in Ebay its advised to give 32 to 35V , Approx 3500mAh. In this stage, i guess 32V is feasible right. Can you please suggest a best transformer-less circuit with best filter with zener protection.

Awaiting for your valuable feedback, thanks in advance.

Reply
Swagatam says:
September 18, 2014 at 8:04 am

Dear Anish, you will have to procure a 32V/3amp SMPS and use it with the above circuit for driving the LED

Reply
malay shah says:
September 8, 2014 at 5:40 am

ckt for 10W LED?

Reply
Jayanath Ranasinghe says:
July 16, 2014 at 2:45 am

ok sir i will do and let u know thanks

Reply
Jayanath Ranasinghe says:
July 14, 2014 at 9:48 am

dear sir i want to flash sequentially/(running mode) 4 to 6 nos of 3w color leds from 12v dc source. request circuit instructions.

Reply
Swagatam says:
July 15, 2014 at 4:38 am

Dear Jayanath, you can try the following design:

https://www.homemade-circuits.com/2011/12/simple-yet-effective-led-strobe-light.html

First construct the shown design successfully using 5mm LEDs, later I'll explain how to modify it for illuminating high watt LEDs

Reply
Miha Černe says:
April 30, 2014 at 5:18 pm

Hello Swagatam, really amazing tutorial.
I am new in the world of electronics and would like to know how to wire a 0,12A cooling fan so that it is powered by the same 12v battery that powers the led.
Thank you for your time.
Best regards.

Reply
Swagatam says:
May 1, 2014 at 3:55 pm

Thanks Miha.

You may do it by simply connecting the motor wires parallel with the battery poles, observing correct polarity

If the motor is rated at a lower voltage, you may use a regulator IC such as 7805, 7806, 7808, 7809 etc whatever may suit your motor.

Reply
harley smith says:
April 29, 2014 at 3:31 pm

Hello Swagatam Majumdar. Very good website and very useful !!!!

I buy one of this 100w led cool white , But I looking at the datasheet, I do not understand WHICH IS BETTER VALUE OF CURRENT AND VOLTAGE for maximum brightness is achieved without damaging the LED (with heatsink and fan).

I read IF= 3,5 A

Min 32

Typ 34

Max 36

I THINK 3,5 IS MUCH CURRENT BECAUSE P=V.I=34V . 3,5 A = 119 W.

THIS I HAVE: i.imgur.com/DBCJNuI.png

I LIKE BUILD A LIMIT CURRENT A OUTPUT VOLTAGE REGULATOR.

COMPONENTS AND VALUES THAT RECOMMENDED BUY ME TO GET THE MAXIMUM LED LIGHTING WITHOUT BREAKING IT???? ( I WILL PUT IT WITH HEATSINK AND FAN)

MY IDEA IS PUT 34V- 3A OR 33V-3.2 A

but i dont know values ​​using of T1, T2 , R1 AND R2 AND POWER OF THESE what can you tell me??

THANK YOU VERY MUCH

REGARDS.

Reply
Swagatam says:
May 1, 2014 at 3:51 pm

Harley, the connections shown in the image are perfect, if the boost converter is able to provide the required current/voltage, everything would work satisfactorily.

I would recommend the IC current limiter over the above transistorized version because it's much sophisticated in all respects.
However if you are interested to go for the above, you may do so.

The calculations that you have made are also correct.

Reply
harley smith says:
May 1, 2014 at 9:02 am

Hello and thanks for your fast response.

I I already bought Power DC-DC Boost Converter 150W 10-32V to 12-35V 6A .

You mean it does not serve me this dc-dc boost.

I have little knowledge and no clear to my this mounting.

IS THIS CORRECT?

i.imgur.com/965TvoC.png

IF I CHOOSE OPTION DOWN THE VALUES ARE TIP3055 for T1, and TIP31 for T2

R1 = (32 – 0.7)30/3

= 313 OHMS

wattage for the above resistor would be = 32 x (32/313) = 3.3 WATTS

Formula for calculating R2 is:

R2 = 0.7/LED current

R2 = 0.7/3 = 0.23 ohms,

wattage may be calculated as = 0.7 x 3 = 2.1 watts

IF I WOULD LIKE THE OPTION 1 CIRCUIT HOW FINDING VALUES?

SORRY FOR MY LITTLE KNOWLEDGE.

REGARDS FRIEND.

Reply
Swagatam says:
April 30, 2014 at 5:45 am

….a 0-24V after rectification would output around 34V, which is just suitable for your application, the rest will be handled by the LM338 circuit

Reply
Swagatam says:
April 30, 2014 at 5:44 am

Hello Harley,

I think you should go for 32V as it looks very optimal, safe and within the reach of an LM338 circuit which I would be referring to you, the above circuit could be relatively crude so I don't recommend it.

You can use a 0-24/5amp transformer, rectify it using a full bridge rectifier and filter the output with a 1000uF/50V cap.

Apply the above output to a LM338 current limiter circuit and use the output from this circuit to illuminate your LED. This would provide an ultimate guarantee to your device….however do not forget about adding a heatsink to the LED.

The LM338 circuit is shown in this link:

https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

use the first design, replace LM117 with LM338 and calculate R1 from the given formula

Reply
Cosma Vergari says:
April 28, 2014 at 11:30 am

Hi there!

I recently bought a 100W LED which has 34V forward voltage and 3A forward current. What kind of transistors should I use in my case?

Reply
Swagatam says:
April 28, 2014 at 2:34 pm

Hi,
you can use TIP3055 for T1, and TIP31 for T2

Reply
Jahangir Bhatti says:
March 4, 2014 at 12:06 pm

I have a 10W LED which has a forward voltage of 9-11V with a max current consumption of 1050mA. Can I run this LED with 7809.

Reply
Swagatam says:
March 4, 2014 at 2:23 pm

yes, you can do it.

Reply
onlineincomestrategy says:
February 20, 2014 at 1:11 pm

hello! i have 6watt led from ebay and data is 9v-12v dc. @ 380mA. each. i want to run 6-12 of this led at a time. What should i use in the circuit? or, can you kindly make a circuit for that? is it possible to run these led with transformerless power supply? please! Help me. Thanks. 🙂

Reply
Swagatam says:
February 22, 2014 at 4:32 am

you an make this circuit:

https://www.homemade-circuits.com/2012/03/how-to-make-simple-12-v-1-amp-switch.html

just upgrade the secondary winding from 1amp to approx 2amps by using two parallel wire instead of one. Wind these two wires simultaneously.

Reply
onlineincomestrategy says:
February 21, 2014 at 10:15 am

Can you show me the mentioned circuit? Please???? I want to make 12v/2amp SMPS. will you kindly show me how?

Reply
Swagatam says:
February 21, 2014 at 4:44 am

capacitive type of power supply will not work with these LEDs.

The easiest way is to procure a good quality 12V/2amp SMPS and drive all the LEDs in parallel with this unit.

Reply
junaid iqbal says:
January 31, 2014 at 11:34 am

I need Constant Current Driver circuit for 12Volt,20Watts and 10watts LEDs kindly share the simple diagram

Reply
Swagatam says:
January 31, 2014 at 2:12 pm

you will have to use an smps for this, there's no simple circuit for it

Reply
Greg Farino says:
January 14, 2014 at 5:42 am

I have a 10W LED flood light that I purchased off Ebay. The manufacturer states that the LED itself has a forward voltage of 9-11V with a max current consumption of 1050mA. I do not want to use it at the full current. I'd like to keep it below the max around 900mA. I'd like to be able to do 2 things with it once it is converted over. 1) Use it as a standard flood light on my vehicle and 2) Have the ability of making it flash like an emergency light. Can I use a 2N2222 for T2 and what resistor values do you recommend ?

Reply
Swagatam says:
January 14, 2014 at 1:55 pm

I think you should use a LM317 IC for your application, the above circuit is crude and should be used only for those applications which does not support the available hi-tech ICs due to high voltage/current parameters.

You can try the first design shown in the following link:

https://www.homemade-circuits.com/2012/11/3-watt-5-watt-led-dc-to-dc-constant.html

For making it flash, you can use a standard IC555 astable circuit and connect its output pin3 to the collector of the 2N2222.
When you switch ON this circuit, will result in flashing of the LEd.

Reply
Abu-Hafss says:
January 11, 2014 at 3:49 pm

Hi Swagatam

I referred to the post wherein you recommended me LM338 for fixed 5A supply from car battery. By the way, what would be wiring of LM338 with car battery?

As for this circuit, will it be possible to use it as variable current controller? If yes, how?

Reply
Swagatam says:
January 12, 2014 at 5:09 am

Hi Abu-Haafss,

I have no idea what happened to that comment, may be due to some kind of glitch in the system.

Please refer to the following article, you can go for the first circuit shown there:

https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

Reply
yantz says:
January 11, 2014 at 2:37 pm

The T1 heat up very quickly …but i only tested at 12v/18A, maybe the low voltage or the high amps cause the T1 to heat up? I used T1,T2 mje3055, R1 390R and R2 0.5R (3w both). Thanks.

Reply
Swagatam says:
January 12, 2014 at 5:06 am

yes, when voltage is low, current will be high, you can try TIP35 with heatsink for getting a better response

Reply
Abu-Hafss says:
January 10, 2014 at 6:07 pm

Hi Swagatam

I could not see my post (in the hobby circuits) as well as your reply, which I have been notified in my mail box!

Anyway, please check and confirm if following components would be okay for supplying fixed 5A to the load from a car battery:

R1 = 68R 2Watts
R2 = 0.14R 3.5Watts
T1 = TIP41 (6A)
T2 = TIP31 (3A)

Reply
Swagatam says:
January 11, 2014 at 6:52 am

Hi Abu-Hafss,

Which posts are you referring to?

Yes the calculations are approximately correct.

Reply
Swagatam says:
September 21, 2013 at 7:59 am

I have not built this circuit yet, but you can try TIP35 for T1 and TIP31 for T2

Reply
Swagatam says:
August 16, 2013 at 12:20 pm

I respectfully request you to explain what's incorrect in the above formula and diagram….if you are unable to do it, you can learn it from me further, don't worry I will apologize you for your above ignorance.

Reply
Swagatam says:
August 7, 2013 at 4:18 am

…a 1% MFR type resistor will do the job.

Reply
Swagatam says:
August 7, 2013 at 4:17 am

Your calculations and assumptions are perfectly correct, in fact I have aready discussed the idea elaborately here, you can refer it for better understanding:

https://www.homemade-circuits.com/2013/06/universal-high-watt-led-current-limiter.html

Reply
Swagatam says:
August 6, 2013 at 6:14 am

Hi, yes it is doable.

T1 and T2 are transistors, for your application you may use TIP31 for T1 and 2N2222 for T2.

As per your LED specs the other component values could be as follows:

R1 = 270 ohms, 1 watt

R2 = 0.7 ohms 1 watt

Reply
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