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Super Capacitor Charger Theory and Working

Last Updated on May 17, 2026 by Swagatam 241 Comments

In this post I have explained a super capacitor charger circuit for charging super capacitors which converts a 12V car battery voltage to an elevated 16V for charging a bank of super capacitors. The idea was requested by Miariver.

Table of Contents
  • Super Capacitor for Peak Power Compensation 
  • The Design
    • PWM Control
  • Another Useful Boost Converter Circuit for Charging Super Capacitor Banks from a 12 V Car Battery

Super Capacitor for Peak Power Compensation 

First thanks for keep publishing this blog is very helpful, I have a question and I don't know if this is the right section!!! sorry for any inconvenient.

I am working from my car, running: a laser copier/printer, a die sublimation photo printer, a note book, 2 cellphones, and plus plus.

My inverter is (1500w 12dc-Battery in to 120ac out) a very good one.

after 4 hours of working the battery is getting too low, so the inverter starting to run on protection mode and beeping like crazy. So I decided to run a 6-pack of super capacitor in parallel with the battery to support the (peak moments) the problem is the super capacitor bank need to be charged to 16.2dc volts (6 times 2.7 volts each capacitor)

So do you have any idea how to get 16.2 volts from the 12 volts battery in order to keep the capacitors charged in order to hold the peak load when would be needed.

any idea, advise or circuit, would be highly appreciated.

supercapacitor charger circuit using IC 555 boost converter

The Design

The proposed super capacitor charger circuit for charging super capacitor banks may be witnessed in the above figure.

The entire circuit can be seen wired around the ubiquitous IC 555, configured as a high frequency astable.

High frequency is required in order to drive a compact ferrite coil which becomes responsible for producing the required boosted voltage.

The relatively low current output from the IC is amplified using T1 which switches the connected ferrite inductor at the rate of the fed astable frequency.

The above action induces a calculated boosted voltage across the coil which is appropriately rectified using the attached BA159 fast recovery diode.

The resultant voltage at the cathode of the diode is fed to the associated super capacitors for the intended charging of the devices.

A feedback loop can be seen from the output to the base of T2 which ensures a perfectly stabilized voltage for the super capacitors....in case the voltage tends to rise above the predetermined fixed value, Z1 gets forward biased and switches ON T2 which in turn grounds pin5 of the IC choking the pulse width of the pin3 frequency.

This procedure quickly reduces the output to the safe limits and the cycle keeps switching ensuring that the voltage always stays within the set thresholds.

PWM Control

In the above design, R2 can be replaced with a 100k pot for achieving a PWM output across the load, although it may be not applicable for charging super capacitors, rather for some different relevant application .

The above super capacitor charger circuit was tested and implemented by Miss Claudia who is an avid follower of this blog and a vehement electronic hobbyist, the verified results for the same may be witnessed with the following images, tested by Miss Claudia:

Another Useful Boost Converter Circuit for Charging Super Capacitor Banks from a 12 V Car Battery

Here's a voltage booster circuit which can be used for charging a super capacitor banks from a car lead acid battery.

The boost circuit has an oscillator stage using a BC548 transistor astable.

This transistor astable oscillator generates a high frequency output which drives a MOSFET based boost converter stage.

The circuit also has a feedback circuit stage using the 24 V zener diode which controls the output voltage level by switching the gate of the MOSFET appropriately.

This zener value can be adjusted for getting a customized boosted output voltage for the super capacitors

The inductor can be built by winding 30 turns of 1 mm super enameled copper wire over a 1 cm thick ferrite rod or a ferrite ring.

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Filed Under: Battery Charger Circuits Tagged With: Capacitor, Charger, Super, Theory, Working

About Swagatam

I am an electronics engineer and doing practical hands-on work from more than 15 years now. Building real circuits, testing them and also making PCB layouts by myself. I really love doing all these things like inventing something new, designing electronics and also helping other people like hobby guys who want to make their own cool circuits at home.

And that is the main reason why I started this website homemade-circuits.com, to share different types of circuit ideas..

If you are having any kind of doubt or question related to circuits then just write down your question in the comment box below, I am like always checking, so I guarantee I will reply you for sure!



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Reader Interactions

Questions & Answers

Total Posts: 241
Newest Oldest
Balaram
November 21, 2014 • 12 years ago #27244

Hi Mr Swagatam
I
am a continuous blogger of ur site and I visit your site regularly if I need any circuits for my project I refer to your blog for information …Recently I brought a 100w led from ebay along with a 12volt to 32volt 3.5amps adjustable boost driver for the led but unfortunately the driver failed so I thought of building my own circuit.
kindly post a circuit in the blog which would be greatly appreciated

regards
Balaram

Reply
SwagatamAdmin
November 22, 2014 • 12 years ago #27250

Hi Balaram, thank you for visiting my blog, please refer to the following circuit, I think it's exactly what you may be looking for:

https://www.homemade-circuits.com/2014/09/32-v-3-amp-smps-led-driver-circuit.html

Reply
Balaram
November 22, 2014 • 12 years ago #27257

Hi Mr Swagatam
I have already purchased this Ac to Dc driver but I need it to run on a 12volt dc source like dc to dc boost converter for 100w led…

regards

Reply
SwagatamAdmin
November 24, 2014 • 12 years ago #27265

Hi Balaram, in that you can try the circuit that's shown in the above article, the coil can be easily tweaked to produce rthe required 32 V for your LED tube light

Reply
SwagatamAdmin
December 14, 2014 • 12 years ago #27603

Hi bla, if it's possible I'll surely try to design the same and post it for you.

Reply
Paul
February 13, 2015 • 11 years ago #28771

Super capacitors are supposed to be connected parallel with your battery ( charge it to same voltage first ) . I got 500F cap with max voltage 16.2 V , I never want to go any higher than 15 V .

Reply
SwagatamAdmin
April 15, 2015 • 11 years ago #30067

thanks Paul for the valuable feed back!

Reply
atos
April 15, 2015 • 11 years ago #30066

If one where to use a TEG as a power source the input would be a lot less than 12V, more in the range of 1-2V in my intended application. But this circuit would still work, since it's still above the volt needed to trigger the diode, correct?

Reply
SwagatamAdmin
April 15, 2015 • 11 years ago #30068

the IC 555 will need minimum 4.5V to initiate so I am afraid it won't work with voltages lower than 4.5V….a joule thief circuit might work better:

https://www.homemade-circuits.com/2012/10/1-watt-led-driver-using-joule-thief.html

Reply
Claudia ft Privacy
July 13, 2015 • 11 years ago #32234

Let's go on here 🙂

Ok, i built it as far as with R1, R2=100k pot, c1=0.2nf, c2= 10 nf and 555.

The measuring results are now:

6.76v = 18.82kHz
6.84v = 20kHz
7.87v = 29.2 kHz
9.66v = 33.7 kHz

on pin 3 from IC1. With a light bulp there is a small variable change visual between pin 3 and ground. The battery measure 12.5V

Reply
SwagatamAdmin
July 13, 2015 • 11 years ago #32245

OK, but you must check the bulb illumination by connecting it across a mosfet drain and positive, that will produce a more effective response…..mosfet gate should connect with pin3 of the IC via a 10 ohm resistor

Reply
Claudia ft Privacy
July 13, 2015 • 11 years ago #32250

Done! The values from turning the pot from left to right completely:

12.3v at the bulb, 34.3kHz at pin3
9.82v 28 kHz,
8.72v 20.3 kHz,
8.59v 20 kHz,
8.53v 19 kHz,

Lower then 8.53v it does not come.

Reply
Claudia ft Privacy
July 13, 2015 • 11 years ago #32251

But i do see the bulb getting a bit brighter when turning the pot.

Reply
SwagatamAdmin
July 14, 2015 • 11 years ago #32262

OK, so now you can try putting the coil in the shown position and check the voltage response across it.

remember wind at least 30 turns.

Reply
Claudia ft Privacy
July 14, 2015 • 11 years ago #32272

ok…i did 40 turns and the mofset burned out completely, the coil became also extremely hot and the wires where i connect all with are melted. I have no measurements because it went very fast. I putted the coil in the place of the lightbulb.

Reply
SwagatamAdmin
July 14, 2015 • 11 years ago #32278

the mosfet will burn if there's no frequency.

I have tested this circuit with a TIP122, and I could light up and 20 numbers of 1 watt LEDs in series…that means the circuit could generate about 20 x 3.3 = 66 volts with a coil wound on a ferrite rod with 40 turns, diameter 1.5cm

Reply
Claudia ft Privacy
July 14, 2015 • 11 years ago #32293

Correct. Only the mosfet was damaged and some wires. What happens is that when i turn the pot above the 6.1k ohm, then the frequencie collapse beneath the 30kHz till 4kHz when the potmeter is at 100k. At 0 ohm, the freq is 40kHz. At 10k it is 23.4kHz.

Reply
Claudia ft Privacy
July 14, 2015 • 11 years ago #32294

with a 1k pot the freq is stable on 40.1kHz. But i think the pot is drunk because it goes on pin3 from the 555 after the 10ohm resistor from 9.24v to 9.40v to 9.28v when i turn in the same direction totally. With the coil mounted, the voltage is stable on 12.2v no mater what i turn on the pot meter, and with a radiator the mosfet still get hot like ….cooking time. But i saved the mosfet with a radiator this time. The freq with coil is also 40.1kHz now on the gate.

Reply
SwagatamAdmin
July 15, 2015 • 11 years ago #32307

with R1 at 0 ohm your 555 IC will instantly get damaged, and may be you have already damaged it by now…that's why I warned you not to reduce R1 below 1K in the other comment.

I told you to hear the frequency with a headphone in the other comment.

Reply
Claudia ft Privacy
July 15, 2015 • 11 years ago #32312

no, R1 is 100k, that one i didn't replaced. I replaced the r2 for a 100k pot and last night i changed it for a 1K to avoid that the freq comes beneath the 30kHz. For the headphone i must make a PAD then because that one works with 0.775v unbalanced and 1v balanced audio. But i googled on the article you said, and i found the principle. Is it possible when the diode and load is missing that the coil can't release its power and it heats up the mosfet?

Reply
SwagatamAdmin
July 15, 2015 • 11 years ago #32313

OK, but R2 will not change the frequency by much..R1 is the resistor which will change the frequency quickly and effectively, and also C1.

you can use a 8 ohm speaker through a 10uF capacitor or any capacitor at pin3 for listening to the frequency

yes without load the back emf can damage the mosfet, but in that case the mosfet will not heat up rather get damaged instantly without any indications….moreover mosfets already have in-bult diode so this possibility may not be so serious with mosfets.

to avoid this danger I had advised you to use a bulb, and check whether or not it's dimming and brightening thoroughly with R2 adjusted from min to max.

if it's heating simply means that the coil is nt proper or there's no frequency at its gate.

Reply
Claudia ft Privacy
July 16, 2015 • 11 years ago #32351

At this moment i don't know anymore. I understand the principle but i can't get it working for some reason.

Reply
Claudia ft Privacy
July 16, 2015 • 11 years ago #32357

I think i know why it didnt worked. The VGS from a buz11 needs 10 volts to switch and the output from the pin 3 555 was between the 5v and 8v. So that if i understand it right, the frequentie must regulate to switch the mosfet to make the voltage higher or lower throe the coil. But the voltage must be stable at 10v.

Reply
SwagatamAdmin
July 16, 2015 • 11 years ago #32363

if your supply voltage is 12V, the pin3 voltage will also be approx 12V…what you are measuring is the average voltage caused due to the frequency which is breaking the pin3 voltage into pieces…but the peak voltage is still around 12V…the peak voltage is always stable…the average volt might change while the pot is moved due to the change in the PWM (pulse widths)

Reply
Claudia ft Privacy
July 16, 2015 • 11 years ago #32367

ok, that is possible….then i don't know. I must first buy new mosfets because they all burned out. i am fighting with resistors to get the right frequencies. I reached today 116kHz and 80kHz to 2.2kHz. I will make a picture from the coil, maybe i do something wrong there. Thank you for being so patient with me, i truly appreciate it.

Reply
SwagatamAdmin
July 17, 2015 • 11 years ago #32372

why don't you first try the circuit with a TIP122 transistor, I did it using this transistor twice and during both the occasions I could make it work at the first shot.

Reply
Claudia ft Privacy
July 17, 2015 • 11 years ago #32382

Yea, i will take those tomorrow to with me. It smells like hell, but i better take a bit more from everything :-)))

Reply
Claudia ft Privacy
July 17, 2015 • 11 years ago #32383

https://drive.google.com/file/d/0B8P7WWCVO6NwMF9TYUwtcGN6VFU/view?usp=sharing
https://drive.google.com/file/d/0B8P7WWCVO6NwQjFaLUZzS2xfdWM/view?usp=sharing

Here are the pictures from the coil i made and the test board.

Reply
SwagatamAdmin
July 18, 2015 • 11 years ago #32397

He coil looks OK, and it should work, just make sure your IC is oscillating at some high kHz frequency.

Reply
Claudia ft Privacy
July 18, 2015 • 11 years ago #32418

The trick is r1, r2 and c1 to get those right. where r1 or r2 must be replaced for a pot.

I tried a lot of combinations, with the results that or the freq is stable and don't move but the voltage on pin 3 goes up and down, or the freq goes from 12kHz to 48kHz but then the voltage is stable on 7volt. But i need it to be stable at 10V with a variation from freq. from 30khz to 60kHz?

Reply
SwagatamAdmin
July 19, 2015 • 11 years ago #32424

the above circuit is very straightforward and not so confusing or complicated as you are experiencing….it should have started working in one shot, I am not sure why you are getting so many issues.

Only R2 should be a pot, R1 can be a fixed resistor, because frequency needs to remain fixed.

use 100k for R1 and any capacitor in the pF range for C1, this will enable an appropriate frequency for your ferrite coil.

frequency needs to be constant, only PWM needs to be changed.

I think the issue may be because you are building it on a breadboard…the circuit needs to be soldered on a PCB for getting accurate results.

Reply
Claudia ft Privacy
July 19, 2015 • 11 years ago #32434

I don't know ether why i have such a fight with it, but i am decided i am going to win from this mountain of silicon 😉

Ok, i am going to soldered it like you say and make a picture from it….or a video when it really starts to burn. If you hear nothing anymore, then it has exploded 😀 My family already considers me as a terrorist because i blow up the components.

Reply
SwagatamAdmin
July 20, 2015 • 11 years ago #32442

I appreciate your interest and determination and I am sure you will succeed soon,
yes, solder it on a general purpose pcb and first confirm the frequency and PWM response,
and don't make explosions, otherwise the cops will come knocking on your door, and will be surprised to find a female terr0rist 🙂

Reply
Claudia ft Privacy
July 20, 2015 • 11 years ago #32450

Ow that wouldn't wonder anybody when those would nock on my door while i am testing my electro skills :-)) But i am glad you have trust in me.

Ok, done it and the results i could measure with the multimeter is:

6.28kHz = 8.4v
10.61kHz= 9.9v
13.8kHz= 11.4v
14.07kHz= 11.8v
12.10kHz= 12.38v
11.93kHz= 12.55v

On the drain from the mosfet i putted 2 led's in series with a 100ohm to the +.
It dimmed a lil bit with a 100k pot, i had to look on the seeling to see the differences. With a 1k pot nothing was visual changing. Nothing burned out this time.

Now i have seen a video last night about PWM, and how it changes the signal, but i have not a oscilloscope but just a Hz meter on a multimeter, so i cant see it very exactly….but there is movement.

Reply
SwagatamAdmin
July 21, 2015 • 11 years ago #32461

It seems you are gradually learning and improving, that's good,

actually the dimming should be consistent from almost zero to maximum brightness. and you should connect a 1K resistor in series with the LEDs, a 100 ohm is too low.
a 1K pot will not do anything, it should be above 22k to produce any kind of variations in the PWMs.

you may verify the voltage at pin3 which must change from minimum to max when R2 is altered

Reply
Claudia ft Privacy
July 14, 2015 • 11 years ago #32274

how much henry must the coil be approx? and what resistance?

Reply
SwagatamAdmin
July 14, 2015 • 11 years ago #32279

Inductance value is not important, even a 10 turn coil will start giving a boost voltage at the output.

just Google "555 flyback boost converter circuit" and check those designs for more info

Reply
Claudia ft Privacy
August 2, 2015 • 11 years ago #32828

I am back 🙂

Well, i made a oscilloscope print from Velleman the edu09, so i can see the signal. Don't laugh, but it works good. Now i can see the signal moving that it get wider while the peeks stay max on 12.4v and min on 0.2v. With a variation from between the 1.14KHz and 28 Khz. BUT! when i connect the mosfet and the LED's with the 1k resistor, the dimming is just a little bit at half of the pot meter but further it does not dim. Please don't ask me why the oscilloscope print does work and the PWM not, because the logic is missing to me completely. How are you doing?

Reply
SwagatamAdmin
August 3, 2015 • 11 years ago #32850

that's a great news….however without seeing the images it would be difficult foe me to judge the results.

the range from 12V to 0.2V looks pretty good, it should dim the LEDs to zero.

by the way are you using a transistor as the control device or is it a mosfet?

Reply
Claudia ft Privacy
August 4, 2015 • 11 years ago #32867

https://drive.google.com/file/d/0B8P7WWCVO6NwTERHLWJTRWxJajQ/view?usp=sharing
https://drive.google.com/file/d/0B8P7WWCVO6NwQVpSc3MxOXdjMVE/view?usp=sharing
https://drive.google.com/file/d/0B8P7WWCVO6NwOGdUbU9ZWTJHdUE/view?usp=sharing
https://drive.google.com/file/d/0B8P7WWCVO6NwbkViMEJQd2N4TE0/view?usp=sharing

Here they are. I am now using a mosfet for the LED's But it does not dim so much.

Reply
SwagatamAdmin
August 4, 2015 • 11 years ago #32877

I am afraid, the PWMs appear the same for all the images, it means that you are not getting any modulation across the range…and that's the reason the LED is not dimming

see the following image…it should be in this manner:

learn raspberry pi how pwm works

Reply
Claudia ft Privacy
August 9, 2015 • 11 years ago #32994

Ow, i must add that i didn't used T2, R4 and Z1. And instead of TIP 122 i used the BUZ11.

Reply
SwagatamAdmin
August 9, 2015 • 11 years ago #32998

….so now are you getting the required boost voltage across the coil??

Reply
Claudia ft Privacy
August 9, 2015 • 11 years ago #33004

I don't know that, i have now just the right PWM signal, i didn't connected anything else then the light bulb.

Can i connect the coil as shown above here, but instead of the 100W LED i use a 1 watt 1k resistor to test the voltage?

Reply
Claudia ft Privacy
August 10, 2015 • 11 years ago #33011

welllll…..all went ok, till i connected the coil and then all blew up. It is now a bit smokey so to say. I checked the pwm before i connected the coil, and all looked ok.

Reply
SwagatamAdmin
August 10, 2015 • 11 years ago #33016

I am clueless why it's not working for you…when I built this circuit, I could make it work instantly, in fact I blew a few of my LEDs due to the high voltage from the coil, and because I had no resistor connected in the LED series.

the voltage I could generate was over 70V from a 30 turn coil over a ferrite rod.

Reply
Claudia ft Privacy
August 10, 2015 • 11 years ago #33025

I don't know ether. Maybe i must let the idea go to put those LED's on a 12V battery, it would had been handy but i think i better look to make something from 220v to 38V, but then i get the same problem i think because a dimmer works by default with a pwm? I don't know at the moment, i think those high power LED's are a bigger problem to get them work then i thought it would be.

Reply
Claudia ft Privacy
August 11, 2015 • 11 years ago #33035

What would happen when i put between the s pin from the mosfet and the – a resistor from 1k, to avoid a shortcut from the coil when the mosfet opens? If i calculated it right then the power throe the mosfet would be something like 0.04 Amp. And over the coil i put a light bulb from 220v to see if something will happen and i can measure the voltage?

Reply
SwagatamAdmin
August 11, 2015 • 11 years ago #33046

I wish I could make it for you and show how simple it is…anyway right now there's nothing much I can do.

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Claudia ft Privacy
August 11, 2015 • 11 years ago #33052

hahahahha then i would really feel blond if it is so simple and i am fighting for weeks with it 😉

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SwagatamAdmin
August 12, 2015 • 11 years ago #33073

you enjoy and laugh even after so many failures;-) you seem to be a stubborn candidate (just joking)

Reply
Claudia ft Privacy
August 10, 2015 • 11 years ago #33024

There was a copper lane from the + blown off the PCB, the pwm still works, but on 1.2kHz. I checked the resistors and the capacitors but those are ok, the mosfet also still functions. Is the 555 then damaged? As i see it, is that the coil makes a shortcut that gives a high amp? Must there not be a resistor or something between the mosfet and the – ?

Reply
SwagatamAdmin
August 11, 2015 • 11 years ago #33047

it's not required…however for testing sake only you can try putting a bulb in series with the coil….but not at the source of the mosfet, because the source needs to be connected directly with the ground…

Reply
SwagatamAdmin
August 11, 2015 • 11 years ago #33048

the track blew due to the high current from the coil…the IC could be still fine.

Reply
Claudia ft Privacy
August 11, 2015 • 11 years ago #33053

ok, i will try it with a bulp in series then it shouldn't be able to burn out…..again.

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Claudia ft Privacy
August 12, 2015 • 11 years ago #33067

I just studied the boost principal, and i see it needs the capacitor to be able to function. Without the capacitor, the full load of the coil goes throe the mosfet to minus and it gets smokey. Is that correct?

Reply
SwagatamAdmin
August 12, 2015 • 11 years ago #33074

yes that might be correct, you are supposed to include the capacitor after the diode…although mosfets have a protection diode internally so I am not entirely confident regarding this factor…

Reply
Claudia ft Privacy
August 14, 2015 • 11 years ago #33142

Ok, i think the current is to high.

As i calculate it with the measurments from the osci

Then V out = 12v/ (0.040ms – 0.039) = 12v / 0.001ms = 12000v

I dont know if i calculated this correctly, but if i did then i am not wondered that everythings burns out to me 😀

Reply
SwagatamAdmin
August 15, 2015 • 11 years ago #33165

that's a weird calculation and result 😀 not correct

current can be measured by simply connecting an ammeter in series with the positive supply

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Claudia ft Privacy
August 14, 2015 • 11 years ago #33143

No, it is 12/(4-3.9) = 12/0.1=120volts
Input Voltage / (period – positive with) = output voltage

Reply
SwagatamAdmin
August 15, 2015 • 11 years ago #33166

output voltage will depend on the number of turns of the coil…

Reply
Claudia ft Privacy
August 15, 2015 • 11 years ago #33171

I will build it now first with the fixed resistors to be able to measure the coil.

First the coil was 140uH, and now i reduced it to 48uH. Because something is to big i think.

Reply
SwagatamAdmin
August 16, 2015 • 11 years ago #33190

sure claudia, please go ahead…

Reply
Claudia ft Privacy
August 17, 2015 • 11 years ago #33210

Listen 🙂 Is it an idea to protect the circuit with a PolySwitch Resettable Device 72V 3,75 A between the coil and the BUZ11 ? I mean in my logic the BUZ11 can handle 50v x 30A=1500W. 72V x 3.75A = 270W. Could that save my PWM and BUZ? Because i know i stay slim from running throe the town, but it costs something you know and i would like to protect my circuit to when the LED's are not connected and by accedent the power is turned on.

Reply
SwagatamAdmin
August 17, 2015 • 11 years ago #33217

you mean to say that you want to connect a switch which will make sure that when the LEDs are not connected, the coil also remains disconnected from the FET drain…right?

yes that can be easily done through a DPDT switch.

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Claudia ft Privacy
August 17, 2015 • 11 years ago #33222

Yes, that is my meaning indeed.

Reply
SwagatamAdmin
August 18, 2015 • 11 years ago #33241

a DPDT may not be required…..just connect a high value capacitor as shown in the diagram, that would take care of the reverse EMF and safeguard the mosfet

Reply
Claudia ft Privacy
August 14, 2015 • 11 years ago #33144

And the BUZ 11 can handle till 50V 30A.

Reply
SwagatamAdmin
August 17, 2015 • 11 years ago #33218

did you check its datasheet? i think it can.

Reply
Claudia ft Privacy
August 17, 2015 • 11 years ago #33221

well, that is a bit difficult to check. Because the code on the DPDT is : "XXX 375 A11E" if i google on that i see a lot of things that got absolutly nothing to do with electronic components. 😐

Reply
SwagatamAdmin
August 18, 2015 • 11 years ago #33240

I asked about the BUZ datasheet. not the DPDT….the DPDT does not need a datasheet for the explanation, it's too easy and just about identifying how the 6 pins are positioned and use it accordingly:)

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Claudia ft Privacy
August 17, 2015 • 11 years ago #33229

I don't understand the datasheet completly what they mean. I think they mean that at 3.75Amp it switches off till a voltage from 72volt. Would that protect my BUZ and pwm then you think when i put it in serries with the coil?
http://www.digchip.com/datasheets/parts/datasheet/1721/RXEF375.php

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SwagatamAdmin
August 18, 2015 • 11 years ago #33242

you are making a simple concept extremely confusing and difficult…all these are not required.

there may be something seriously wrong with your circuit, I am not sure what…. but believe me a boost converter is one of the easiest thing to make on this planet….:)

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Claudia ft Privacy
August 18, 2015 • 11 years ago #33245

No, i am kidding, i know i do something wrong and try to find out what but without blowing up my pwm every time again. I almost can make a pwm blind so many times i made it.

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SwagatamAdmin
August 18, 2015 • 11 years ago #33265

lady why don't you just quit and start learning to cook some good recipes?…electronics might not be your cup of tea, it seems 😀

jokes apart…..I have no idea what might be causing so many issues in your circuit, just keep trying and keep your fingers crossed

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Claudia ft Privacy
August 18, 2015 • 11 years ago #33275

hahahhaa i am not good in cooking that burns always worse then my electronic components 😀

Yesssssssssssssssss Sir Swagatam!!!!

I blew up nothing today and i made 19Volts out of 12.1V 😀 😀 😀

With the fixed resistor it worked, but i had put a 1k 1w resistor over the capicitator, and then it was 12V exact. Then i removed the resistor over the capicitator and i got 18.65V and loading up. Then i replaced the fixed resistor for a pot from 10k, when it was up, the capicitator was loading up till 19V and kept loading. And when i moved the pot down, then the capicitator was unloading. This means it is good right??? 😀

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Claudia ft Privacy
August 18, 2015 • 11 years ago #33276

Ow and i used the tip122 instead of the buz11. Because the tip 122 does 100v at 5 amp, and the dpdt secures at 75v at 3.75A. And the buz11 does 50v at 30A. So it was safer to use the tip i thought.

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SwagatamAdmin
August 19, 2015 • 11 years ago #33293

yes TIP122 is a BJT and I have more faith on BJTs because they are not as unpredictable as the mosfes….I had tested these circuits using TIP122 and I could get the results immediately.

a 19V from 12V is a good improvement, however you can still try increasing the number of turns and check whether it multiplies proportionately or not…because the turn ratio determines the voltage level…if this happens then you can be sure of the circuit working correctly.

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Claudia ft Privacy
August 19, 2015 • 11 years ago #33294

Ow, and a request for a topic 😀

Can you make a topic about how to read and understand datasheets please? Because for engineers it might be logic, but for people who try to learn electronics it is a chaos of data.

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SwagatamAdmin
August 19, 2015 • 11 years ago #33305

OK…. I'll surely consider it once I finish my previous pending assignments..:)

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Claudia ft Privacy
August 19, 2015 • 11 years ago #33312

ok, i got 25.3v with 45 windings, but when i move the pot a little bit up then it moves fast to the 60 volts.

measurments are: 10k pot in lowest resistance

20 windings = 47V
25 " " = 40.3V
30 " " = 35.4V
35 " " = 30.1V
45 " " = 25.3V

BUT! "Mumbai!, we got a boost" 😀

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Claudia ft Privacy
September 1, 2015 • 11 years ago #33656

Back from holiday 🙂 Have you missed me? 😉

I made a circuit drawing from what i have builded now and what does not explode, but what gives the above values from august 20th. The 1K resistor is a 1W to replace the future LED.

https://drive.google.com/file/d/0B8P7WWCVO6NwamlaZ2w0NU5Ua3M/view?usp=sharing

Now the meaning is to change something so i have a variable boost from between the 20 and 36 volt without cooking the LED 😀

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SwagatamAdmin
September 1, 2015 • 11 years ago #33667

wow welcome back…yes, I usually miss anybody who may leave my website without an intimation…;-]

that's a great progress…did you try reducing the number of turns to bring down the voltage to the desired limit?? just try it, or alternatively you can use a BC547 stage at pin#5 of the IC as shown in the above article diagram.

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Claudia ft Privacy
September 2, 2015 • 11 years ago #33673

hahaha no i don't leave so quickly, for sure not without thanking somebody who is so patient and helpfull like you. I just saw that you made projects about the Arduino to, there i want to work with after i finished with these LED's. I think when i understand this circuit then i can start to control the light with the Arduino maybe.

Well if i reduce the number of turns then the voltage goes up for some reason. I know it is not logic, but it is what i measure.

I can try to use the BC547 i just need to get the 17v zener for it, because i just have 2v7 zeners. And otherwise i need to bring the frequence up i think to bring the turns down. Is 0.8mm wire enough for a 100Watt LED?

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SwagatamAdmin
September 2, 2015 • 11 years ago #33685

I have not yet mastered Arduino and MCU stuff, so I won't be able to help you with this subject.

you seem to be quite well versed with the boost circuit at the moment…so surely you'll be able to finish it soon…successfully.

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Claudia ft Privacy
September 2, 2015 • 11 years ago #33692

Ow then i wait with the Arduino a bit.

But! I found on a other website an other development from you

http://www.brighthubengineering.com/consumer-appliances-electronics/68396-over-voltage-and-low-voltage-protection-circuits-easy-home-projects/#imgn_1

The "over voltage indicator and cut-off circuit" it is on the middle of the page. Now before i run for the zeners, is it a idea to use that circuit to protect the LED's against over voltage? Because i had to order those LED's in China and have waited for them 3 weeks. So i would like to protect them a bit you know 😀 If with that circuit i can limit it to 37.5 V then i cant blow up the LED's i think.

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SwagatamAdmin
September 3, 2015 • 11 years ago #33700

the over voltage to the LEDs can be simply protected by regulating the boost voltage with the help of the BC547 transistor across pin#5 of the IC 555..

you can replace the BC547 base zener with a preset…the base goes to preset center….the other two leads of the preset go the boost source and the ground respectively.

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Claudia ft Privacy
September 4, 2015 • 11 years ago #33733

ow cool….how much ohms would be good for this preset?

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SwagatamAdmin
September 4, 2015 • 11 years ago #33744

a 10k would be fine…connect its outer leads across the filter capacitor and connect the center lead with the transistor base resistor. The zener could be eliminated in this case

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Claudia ft Privacy
September 7, 2015 • 11 years ago #33792

Done that, then the output voltage gets fixed on 11.6 V. No matter what i do with the pot or the preset, the voltage stay's fixed on 11.6V.

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SwagatamAdmin
September 7, 2015 • 11 years ago #33800

again that's strange (and impossible)…your circuit is a special one with unique outcomes :-D…so I really can't suggest or recommened much because the results are always something unpredictable…??

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Claudia ft Privacy
September 7, 2015 • 11 years ago #33803

hahaha yea i got the idea, i go to measure what is on the base of the BC547. Because i have no freq anymore on pin 3 from the 555…..or it is to fast to measure. It is because i am from venus i think 😉

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SwagatamAdmin
September 8, 2015 • 11 years ago #33816

OK got it…I think if the transistor does not work then we may have to go for an opamp circuit which can be expected to provide a 100% correct results

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Claudia ft Privacy
September 7, 2015 • 11 years ago #33804

On the base of the bc547 there is 0.6volt, at pin 3 from the 555 there is 0 Hz and -0.2v. There is 0v on the collector but the collector emitor is 365ohm from the bc547….does that helps?

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SwagatamAdmin
September 8, 2015 • 11 years ago #33814

Initially keep the preset slider arm completely towards the ground side this will allow the full 70V to be available across the output, after this you may very slowly slide the preset center arm upwards and check the response over the meter.

try using a 100k preset if possible

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SwagatamAdmin
September 8, 2015 • 11 years ago #33815

you may check the voltage at the center lead of the preset….never at the base of the transistor.

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Claudia ft Privacy
September 8, 2015 • 11 years ago #33822

I have put it in the simulator, and i get the same results as what i have measured. So i made a print screen from what i have now. R4 and R5 is the pot, R7 en R8 is the preset. No matter how i change those 4 values, the result stay's the same on 11.4V.

https://drive.google.com/file/d/0B8P7WWCVO6NwYkU2bWs5djJ0eGs/view?usp=sharing

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SwagatamAdmin
September 8, 2015 • 11 years ago #33832

you must use a preset in place of R7/R8, the image shows fixed resistors…I told you to ground the preset slider arm completely initially….in which case the BC547 would be completely off, from there on you can slowly take it up.

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Claudia ft Privacy
September 8, 2015 • 11 years ago #33836

I know, but that program don't have presets or pot's where i can work with to simulate so i use two resistors then instead to test. I really do all you tell me to do, even it doesn't show on the picture 😀

BUT!!!!!!!!!!!

IT WORKS!!!! 😀 😀 😀

I have 36V sharp….without LED balast, but i have 36Volt :-p

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Claudia ft Privacy
September 8, 2015 • 11 years ago #33838

Must i secure some how that there doesn't goes to much current throe the LED?

Because i blew up a BUZ11 again when i turned it back on after dinner, i had left the pot completly open when i turned it off and on again. The DPDT did get warm and disconnected the coil, but the mosfet was history so the DPDT did safed the rest of the pwm. I should had used the TIP i am thinking now. Some how there is a peak voltage at start up maybe? Anyway, i replaced the BUZ and it works again. So i think about to get some fuses for the LED's.

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