#155588

Hello Swagatam

I am now 74 years old, so it has been many years since I studied at a technical academy. (and many years of developing electronic circuits)

Has there since been a change in how voltages are named in a schematic when we talk about voltage that occurs in an electrical circuit?

I have learned:
U = R*I
The value of U is denoted V (Volt)
The value of R is denoted Ohm
The value of I is denoted A (Amp)

So:
U(supply) is 12V
Not V(supply) is 12V

Is it legal today to mix the terms and values as you wish?
Is it me who hasn’t kept up with the times?

Regards Tommy.

#155591

Thank you Tommy, for the insights!
What you are saying is partially correct, however it is completely legal and legit to use the term “V” instead of “U”
If you search for “Ohm’s law triangle”, you will find that V is always used for denoting voltage.
I think “U” is more prevalent in the European countries, while “V” is a common worldwide notation for expressing Voltage.
However, it might not be appropriate to mix the terms in a schematic, if you are using “V” then you must stick with “V” and not mix the terms U and V.

#152534

Hello sir,

I am a hobbyist, and have assembled a 6 phtodiode circuit. I have used Darlington pair [BC547 BJT NPN] for amplification of current. However, the measuremnts are not steady and stable. Can I add another Darlington pair or do I need to add a capacitor in photodiode circuit? I checked on multimeter, sometimes it reads 800 nF or mF [unable to measure].
Please revert.
Regards,
Sanjay

Author
#152540

Hello Sanjay,
A single Darlington should be enough to amplify a signal from photodiodes, no need of adding additional Darlington BJTs, it won’t help.
Please let me know what you are try to build with the photodiodes?
Is it a proximity sensor?…if possible please show the schematic diagram, I will try to solve it for you.

#136952

Can I connect 10 D2012 transistors in parallel, 5 together and the other 5 together and run it with 12volt?

Author
#136953

You can connect them in parallel, however make sure to add a low value emitter resistor in series with each of the transistors as explained in the article, or alternatively, you can mount all the transistors over a common heatsink and very close to each other.
Or you can do both for optimal performance.

#134546

If i should connect two or more transistors is it the collector-emeter current that will increase or it is the watt that will be increased?

Author
#134551

Current and wattage both will increase.

#132442

Hey, I have a maximum base voltage of 3.3V and a max base current available of 15mA (Raspberry pi pico).
I need to power a motor that requires about 3.7A. That’s the maximum it requires lol. It’s a 1ohm motor so I apply a voltage of 3.7V. Which transistors should I use and in what config. Thanks a lot!

Author
#132444

You can use a Darlington transistor built using a 2N2222 and a 2N3055 transistors. The base resistor can be a 1K resistor. Let me know if you have any more doubts.

#132468

Ayee thanks a lot. I tried using what you suggested and it worked wonderfully!!! Though, I found a high hFE transistor – TIP122 – in my city somehow lol. Is there a benefit to using your suggested darlington config, or should I stick to the single BJT TIP122?

Author
#132473

Glad it is working for you.
TIP122 will work but it can become extremely hot at 3 amp current that is why I suggested the 2N2222/2N3055 combination.

#87722

Thanks very much !

#131980

I am trying to make an ultrasound transducer cleaner circuit which requires 200 watts. I keep trying to wire transistors together and it damages it. What can I do?

Author
#131984

Can you please specify how much base voltage, collector voltage and collector load current you are using for the transistor? I will try to help!

#131988

Also, this is the setup:
a variac rated at 2000 watts is connected to a transistor and it passes through the lower voltage side of a transformer and back to the variac. That creates a current on the other side of the transformer with 10 times the voltage, so 5 volts becomes 50 volts, and i am connecting the two ends of the transformer to the two ends of the transducer. It is a 100 watt transducer I got on amazon. As for the base current of the transistor, I have a signal generator which either wire directly to the base of the main transistor, or, in order to amplify the base current, use a variable dc supply set to 5 volts.
It runs fine with this setup. This is not the issue. The issue is that when I try to increase the variac voltage to 10 or 15 volts and then turn it on, the transistors get damaged and so I have to find a way to increase the total power while keeping the transistors intact. As I said, I already tried wiring several transistors in parallel and still it is at the same current

Author
#131991

For a 500mA load a single 2n3055 should be just enough. Parallel connections may not be required. However to increase the gain you can try converting the 2N3055 into a Darlington configuration, by adding another 2N2222 transistor with it, as shown in the following diagram:

increasing transistor gain with a Darlington configuration

#131998

Also, do you know anywhere I can learn more about powering an ultrasound cleaner? Or a cheap amplifier I can buy? Maybe you can make it and I will buy it from you.

Author
#132006

Sorry, I do not have sufficient knowledge about ultrasound cleaners so it can be difficult for me to assist you in this regard

#132028

Furthermore, I tried using a heatsink to pass 50v through the power transistors and after 1/3 of a second the transistor burned out and stopped working. This happened several times. So I need a way to divide the power among a few transistors. Or, use a lower voltage and get more amperage.

Author
#132030

Transistor cannot be used for AC supply and AC loads, it will keep burning. You will have to use a triac instead for an AC load/supply

#132394

How did you come up with a 0.22 ohm resistor? And why do they have to be individual darlingtons?

Author
#132396

Actually 0.22 is incorrect, it should be 5 ohms since the input voltage is 50 V. We want restrict the max current per transistor to less than 10 amps
Using Ohms law R = V/I = 50 / 10 = 5 ohm
Using Darlington for each transistor is more efficient than using a single transistor for all the 2N3055

#132359

https://1drv.ms/u/s!Ajs8vtOrFCHDjh1OzDwdZQOvhFl4?e=OaTggA
That is my circuit. You said I can add 0.22 ohm resistors in parallel with the emitters of each transistor. Is that what you mean as in my circuit?
As I said I am trying to increase the total power. I used 1 ohm resistors at the emitters and also 10 ohm. Is this circuit right?

Author
#132364

Your circuit is not correct. For high current load you must use a Darlington for each transistor and then add them in parallel as shown in the following diagram:

high current transistors in parallel

#132265

https://1drv.ms/u/s!Ajs8vtOrFCHDjhwXmIAa4Y5s1iVO?e=HbueLt

That is the onedrive link for the picture of the circuit. What I mean to say is that just by connecting a battery across the source and drain, it conducts, without any signal on the gate. That is as opposed to the second picture where I show how I would expect it to work, with the battery connected on the gate.
I have IRFZ44N MOSFET’s and it does not matter whether the drain or source are positive or negative, it just conducts without a gate signal. I do not think it is a depletion type mosfet, but even if it is, with a signal at the gate it still conducts.

Author
#132266

First of all you should never connect the supply voltage directly across the drain/source. You must always have an appropriately rated load in series with the supply, otherwise the mosfet could burn.
The gate of the mosfet should never be kept floating. For any mosfet always make sure to have a resistor connected across gate/source, then the mosfet will remain switched OFF by default.
Try adding a 1K resistor across the gate/source and check the response….and make sure you have a load in series with the drain supply.

#132253

Thanks. Is it correct that the TIP142 is not a mosfet but is a BJT? Because I was having trouble connecting mosfets. I wire them the same way I wire a BJT with the common emitter configuration and it starts to conduct from the source to the drain without any gate signal applied? Do you know why that is happening?

Author
#132259

TIP142 is a BJT not a mosfet. MOSFETs will not work properly with 5V gate supply. Without seeing your connection diagram it can be difficult for me to understand and troubleshoot your circuit.

#132214

I rectified the AC Power through a power diode and led that to the transistors. I know how to connect one transistor without it burning, but how do I increase the power, because one transistor cannot tolerate the whole load. So do I connect them in parallel?
My idea is to connect them in parallel and add resistors, then increase the voltage so that the individual transistors have the same wattage through them (due to the resistor power drop) and since they are in parallel they will be adding together as parallel resistances, then lead that to the load. Is that a good idea?

Author
#132224

You can add 2N3055 in parallel with a low value resistor in series with the emitters of each transistor, and mount them over a common single heatsink close to each other. But the problem is that each 2N3055 will require at least 25 to 35 mA base current. How will you supply this base current to each transistor? The solution is to replace the 2N3055 with a Darlington transistor such as TIP142. You can then connect 10nos of TIP142 in parallel with a series emitter resistor for each transistor. The resistor can be a 0.22 ohm 2 watt resistor

#131997

I think I need a current of 40 amps total at 5v to be transformed to 50 volts at 4 amps to power the transducer. Or something along those lines

Author
#132008

But you said you are converting 5V to 50V through a transformer?
Do you have a 50V source for the transducer, or not??

#132027

Yes I have a variable power supply that can do 50v. If I want to increase the wattage from 50v at probably 1A = 50W to say 300W what can I do? It needs to be at a very high power in order to work. A few hundred watts. The messaging comes a little out of order. I am not sure if I can use the DC power supply as a power source since it might be too low of power for this. So that is why I bought a 2000W variac as a power source. So I need to know 1) how to increase the power in general and 2) about using an AC variac for this. For some reason once I increase the power on the variac beyond 10V the transistor starts to conduct current. This does not happen on AC. Why is that? I appreciate your help.
Can you tell me what to do with regards to these issues?

Author
#132029

The power consumption is determined by the load. The load decides how much power it wants to take. If the load is 300 watt then it will consume 300 watts, provided the source is able to supply 300 watts.
However, a transistor can never handle an AC load, it is designed to work with DC loads. So you will have to convert the 50V AC to 50 DC for powering the load. If your load is an AC load then transistor cannot be used, you will have to use a triac instead.

#131996

Ok. But i am trying to say that only 500ma are coming through. At 5v that is 2.5 watts. But I need around 200 watts for my ultrasound cleaner. Can you help me increase the power? Even when I wire the transistors in parallel it gives around the same amount of current as with one transistor. Why is that?

Author
#132005

OK, sorry for the confusion. So you have 5V for the base drive, 50V 200 watts 4 amp for the collector load.
With 50V 4 amps you can easily use a single 2N3055 with 2N2222 in the Darlington configuration, using 5V 1 amp at the base. You can replace the 2N3055 with TIP35 for better performance. You will need a heatsink on the transistors.
Let me know if you have more doubts.

#131987

I tried to use two transistors in parallel but the current went up from 3 amps to only 4.5 amps. I wired 7 more in parallel and for some reason the current became less than the first time about 1.5 amps

#131986

base voltage: 5 volts (tried up to 10 volts)
collector voltage: i am using a variac set to 5 volts (tried up to 10 and 20)
collector current with no load: 3 – 7 amps with load 500 milliamps.
I am using 2N3055(NPN).

#85673

Thanks for the article. I’m designing a constant current circuit for a power supply and was actually thinking of using 2n3055 transistors. I want it to be able to handle at least 25 amps or more, so thought about 2 or even more in parallel. Your article answered my question. I know that I could probably use a single mosfets, but have a good supply of 2n3055s. Can make them very easy to replace if needed also.

Thanks again,
Ken

Author
#85688

Thank you for liking the post, yes you can certainly try that!

#70308

Thank u so much let me try out those ideas ,becoz was stranded with rhat problem of thermo heating of bjts

Author
#70315

Glad it helped Mubiru, thanks for your feedback!

#66480

Good day,

I am new to electronics.
Digikey had an article on connecting NPN transistors in parallel – to avoid thermal runaway. (TIP41C)

I gained a lot of insight from your article.

From the diagram you have in your article I can see an orange box (resistor), connected to the base.

How do we measure this base resistor, if at all it is needed.

What wattage should be the resistors (emitter and/or base )

Author
#66483

Thank you Christopher, Glad you liked my site!

I have updated the info in the article please check it out.

Wattage of the emitter resistor will be V x I, 12 x 10 = 120 watts, that looks too big, but if the load current is at full 10 amps then it will be this big….

Author
#65260

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#65259

Hello sir i would send the cricuit digram into ur facebook id sir…

Author
#65256

send me in facebook

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