#190121

Thank you very much sir……

#142455

Wanna make a diy 0-60v 0-20 amp power supply using 3055 transistor and lm317

Kindly help for a nice accurate and powerful circuit

Author
#142472

You can try the second last circuit from the following article:

https://www.homemade-circuits.com/lm317-with-outboard-current-boost/

#139803

Dear Mr. Swagatam
I need 53 V input and 12 -15 V output for a 2 lights and webasto diesel heater ( 5 -7 A)
I would like to make circuit as you give us on March 27, 2022
I have 6 nos TIP 2N3055
do i need to make 3 X parallel LM317HV?
If need, how to add 3 x lm317HV in parallel. Just put in parallel with no resistors between
Input is from lifepo4 batteries 48 -53 volts do i need capacitor at the input?
R1 is 240 OHM , how many W
R2 could be a 22k pot.- how many W
Thank you very very much for your help.
Regards, MATJAZ

Author
#139822

Hi Matjaz,
If you are using 2N3055 transistors then adding 317 in parallel is not required. For 7 amp current only 3nos of 2N3055 are enough.
If you want to connect 317 in parallel, first build a single 317 circuit with resistor and pot, then add two more 317 in parallel to the first one.
Make sure to install all the 3 ICs on a single common heatsink.
Capacitor will not be needed at the input.
240 is 1/4 watt
pot can any ordinary pot.

#132731

Hello,

I would like to try your power circuit for a project I am working on, but would like to ask a few questions before I attempt to build the circuit. The input voltage will be input 110/120VAC and I am looking for a variable output of 12VDC – 20VDC 4a-8a. Can you recommend correct components for this?

Author
#132743

Hi, to implement this circuit you will need a 120V to 20 V transformer. After this you can rectify the 20V AC from the transformer and use it as the input DC for the above explained LM317 circuit.
For increasing current you can modify the basic circuit into the following design:

high current LM317 power supply circuit

#132267

Hello sir, I check the circuit but the seller gave me wrong ic instead of lm317, but I got 5.62 at the output. So what could be the actual problem or can it be the tiny wire I used for the circuit.all my connection are correct. My Rc should be 0.6ohm and is not found in my place so I used two 1ohms 1 watts in parallel and 0.22 ohm’s in series with the resistor
as you instructed becausee 0.1 ohm’s is not found, C1= 6800uf 25v, R2=22kpot, R1=240 ohm’s.

Author
#132278

Hello Youngking, that seems strange.
With a 22K pot and 240 ohm resistor the output could be varied from 1.25V to 30V. Something is not right in your circuit. I suspect the IC itself may be faulty.
Instead of 317 you can try a fully transistorized circuit as explained in the following post, which will give you the same results as LM317.

How to Design a Bench Power Supply Circuit

#132172

Good morning sir , sir I built this 0- 60 variable power supply the one using lm317 and bc547, but my output is 0.15 when turn my multi meter to left hand side written 200. But if I still turn it down to 20 my output will be 2.18. my transformer is 12-0-12v, what will be the problem no components is heating up or may be you didn’t indicate the Bc547 pins because the facing is confusing I also attached pictures on the values I get with the multi meter.

Author
#132173

Hello Youngking, this is one of the simplest designs and cannot go wrong. A problem can arise only if there’s a fault in the connection or the IC itself is faulty. The BC547 pins are clearly indicated in the pictorial diagram, the emitter pin is shown connected with the ground.

You can try making the basic design first, and check the response, if still it doesn’t work then either your connections are not correct or the IC itself is faulty.:

317hv 5

#131968

Dear sir,
Please sir, I intend to get 1.5A output from the circuit by removing the Bc 547 stage.

1. What else do I have to do or modify to get the 1.5A output?

2. Can I add filter capacitor at the regulated output?

3. Is the heat dissipation of the lm317 directly proportional to the difference between the input Voltage and output voltage like in the case of 2n3055 in one of your variable power supply circuits you told me about?

Thank you for your help, sir

Author
#131973

Hi Godfrey,
Getting 1.5 amp from LM317 can make it very hot. You can simply replace it with an LM338 for getting 1.5 amps easily.
1) Just replace LM317 with LM338, or use two LM317 in parallel and mount them over a single common heatsink
2) You can add a capacitor at the output
3) Yes, since LM317 is also a linear regulator the heat dissipation will be directly proportional to the difference in the input/output voltages.

#131784

Dear sir,
Please sir, how can the circuit be modified to have two outputs 12V and 5V at 1.5A?

Author
#131787

Hi Godfrey,
you can adjust the pot to get 12V output, and then use a 7805 IC to convert the 12V to 5V. However you cannot get 1.5 V simultaneously from the two outputs. For this you may have to replace the LM317 with a LM338.

#131204

Okey sir, thanks alot. I appreaciate.

Author
#131215

You are welcome!

#131191

I wanted to build a variable power supply but unfortunately I don’t have the voltage regulator lm317hv.
I need 60v 20a output.

So what should I use instead of lm317hv?
For 60v

#140491

LM317HV isn’t available in this place where I live. So can you provide an alternative of this please

Author
#140495

There’s no other easy alternative for LM317HV

Author
#131216

You can try the following concept:

Variable Voltage, Current Power Supply Circuit Using Transistor 2N3055

#131105

Okey sir, thank you for your responses, but the 1 ohm’s will it be 1 watts.

Author
#131148

Yes you can use 1 watt

#129878

Good day sir, I hope you are doing well. My questions is concerning the 0-60v variable power supply that uses lm317H v (1) so if I use transformer of 14v/220 v/amps unknown won’t I get reasonable output of about 30v. (2)- the calculation of getting the RC, let say I go with your calculation which say’s 0.6/1=0.6 ohm’s for the resistor then the wattage is 0.6×1=0.6watt. I know 0.6 ohm’s is not found in my area so any substitution for such ohm’s. Thanks so far for your effort

Author
#130113

Hi Youngking, if you are using a 14V transformer, then the output after rectification and filtration will be 14 x 1.41 = 19.74V
Yes RC will be 0.6 Ohms for a cut off current of 1 amp. Wattage calculation is also correct.
To build the 0.6 ohms you can use two 1 ohms in parallel and then add a 0.1 ohm in series, or you can try some other similar combination.

#128315

Dear Swagatam:
Greetings.
My LiFePO4 battery pack is being designed for 72 volts (nominal) with 23 cells in series and 58 cells in parallel amounting to 25kwH. I will be needing a charger at 230v AC input, and can take care of the demand for 78v at 100 amps. I am unsure if such a circuit can be built as a single unit. Can you help with a circuit, where I can put two or three modules in parallel with each of them at 78v, to arrive at the desired current rating? Thanks in advance.

Author
#128340

Dear Madhav, a charger circuit with auto cut off can be built but you will require a transformer which can convert the 230V into 78V 100 amps for the batteries

#121498

Hi Swagatam;
I have test for LM317; input is 23 V output is 12 V load is 0.32 A. LM317 is overheating. My I have your opinion. Thank and regards

Author
#121523

Hi Suat, yes if the input/output voltage difference is high then any linear regulator will heat up, you can do nothing about it except connect a large heatsink, or do fan cooling. A capacitive current dropper is the best method which can be connected to 23V AC and then rectified for the motor and meter.

#121526

Okey Sir,
then since my source transformer output is 23 AC and it is necessary to place capacitor after the rectifier and then DC output is 33 DC. That is over burden to LM317 or even 7812. As far as I understand your evaluation, I should either change my transformer or lower the AC input source to about 15 V. So I should search the second choice first. Kind Regards

Author
#121530

Hi Suat, yes using a 12V transformer will quickly solve the heating issue.

#121067

Hi Swagatam;
by considering above statement; “C1 above or min. 2200 mF”, let’s use 2200 or 6800 mF then in the aspect of output dc voltage, result would be same or 6800 is would be more effective? Regards

Author
#121072

Hi Suat, the higher the value of C1 the better will be the filtration. 2200uF is a reasonable value, but higher values can be tried for improving the output DC further.

#121152

Hi Again Swagatam;
Sorry just to completely understand the matter let me ask; for instant I have transformer input 220 and output 24 V and 100 VA. (I think app. 4 Amps) When I use 2200 mf capacitor as a filter after diodes I measure about 34 V output. In case I would have used 3300 mF then the gain would be more output voltage or more stable voltage? and also please comment what about the output current would be the same, less or higher?-thanks and kind regards

Author
#121171

Hi Suat, the gain will be more stable voltage at higher loads. Max current will remain 4 amps only, but higher capacitor values will ensure that the output doesn’t drop with increasing loads upto 4 amps.

#121299

Hi Swagatam;
Thanks a lot the above info is highly precious for me. Then please advise if it is possible to place the capacitors as parallel to increase the capacity. For instance to use 2 of them as 2200 mF 35 V plus 3300 mF 63 V. Or capacitors voltage values should be the same too? Regards

Author
#121308

Hi Suat, you can put the capacitors with different voltages in parallel, but the minimum voltage of a capacitor should be at least 1.5 times the DC output of the power supply. Higher voltage values than this will be OK, no issues.

#121423

Thanks Swagatam;
Power supply input 220 AC output is around 22 V DC but after bridge diode and capacitor that arises to 33 V DC. So, then I should consider 22 x 1.5= 33 V or 33 x 1.5= 50 V? For instance I have 35 V capacitor That will be any issue or tolerable? Regards

Author
#121434

Hi Suat, a 35V capacitor can be too risky and might blow off if accidentally the DC across it exceeds above 35V. That is why, for better safety a 1.5 times more value is recommended. So a 50V capacitor is recommended for a 33V supply.

#119636

Please suggest me a circuit diagram of a 60v 30a (1800watt) variable power supply.

And also give a 1800 watt power supply diagram. Because I’m not able to find it nearby

Author
#119645

You can try the following circuit:
https://www.homemade-circuits.com/lm317-variable-switch-mode-power-supply/
replace the Q1 transistor with three IRF9540 mosfets in parallel, mounted over a common heatsink
Also make sure to use very thick wires for the inductor L1.

First test the original low current version, if you succeed with it, only then go for the upgrade

Author
#117344

If you use minimum 4nos of 2N3055 then 20 amp can be achieved.

#117339

And because of I want a output voltage of 60v, should I use lm317hv instead of lm317?

Author
#117343

Yes that’s correct! You must use LM317HV

#117338

Is it capable to give 0-60v and 0-20a output?

Author
#117336

You can do it by implementing the following design:
high current LM317 power supply through 2N3055 emitter follower

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