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How to Connect LM338 IC in Parallel to Increase Output Current

Last Updated on July 26, 2023 by Swagatam 20 Comments

The LM338 is an adjustable 3-terminal positive voltage regulator capable of providing up to 5 amperes of output current. To increase the output current capability, you can connect multiple LM338 ICs in parallel.

When you connect them in parallel, each IC will share the load current, allowing you to achieve higher total current handling capacity.

Here's a step-by-step guide on how to connect IC LM338 in parallel:

Note: When working with electronic components and circuits, always follow proper safety precautions. Double-check the datasheet and specifications of the LM338 IC for your specific application.

Materials Needed:

LM338 voltage regulator ICs (as many as needed for your desired current capacity)

Heat sinks for each LM338 IC

Suitable transformer and rectifier circuit to provide input power

Capacitors for input and output filtering (optional but recommended for stability)

Step 1: Heat Sinks

Ensure that each LM338 IC has an appropriate heat sink to dissipate heat effectively. The heat sink's size and thermal characteristics should be selected based on the maximum current and temperature rise requirements of the LM338 IC.

Step 2: Input Power Supply

Use a suitable input power supply to provide the required voltage and current for the all parallel connected LM338 ICs. This will require a transformer to step down the AC voltage, a bridge rectifier circuit to convert AC to DC, and input filter capacitors to smooth output the voltage.

Step 3: Provide Input and Output Capacitors (Optional)

You may add capacitors to the LM338 IC to improve its performance and maintain the power stable.

Connect one capacitor to the input of each LM338 and a second capacitor to the ground pin of the devices.

Connect another capacitor to the output of each LM338 and the ground pin of the devices. Simply select the capacitor sizes that apply to your device and refer to the datasheet for recommendations.

Step 4: Connect the LM338 ICs in Parallel

To connect the LM338 ICs in parallel, follow these steps in accordance with the following circuit diagram:

how to connect LM338 IC in parallel to get increased current output
  • Connect the Adjust (ADJ) pins of all the LM338 ICs together.
  • Connect the Output (OUT) pins of all the LM338 ICs together.
  • Connect the Input (IN) pins of all the LM338 ICs together.
  • Connect a 120 ohm or 220 Ohm resistor between the outputs of the all the LM338 and the ADJ pin of all the LM338 ICs.
  • Connect a 10 K potentiometer between the ADJ connections of all the LM338 ICs and the common Ground line.

Step 5: Individual Current-Limiting Resistors (Optional)

If you want to balance the load current between the parallel-connected LM338 ICs, you can add small current-limiting resistors in series with the ADJ pins of each IC.

This can help ensure that each IC contributes proportionally to the total output current. The value of the current-limiting resistor can be calculated using Ohm's law based on the desired current-sharing ratio.

Step 6: Mount the LM338 ICs on Heat Sinks

Mount each LM338 IC on its respective heat sink using suitable thermal compound and hardware. Ensure that the heat sinks are properly insulated to avoid any short circuits.

Step 7: Test and Monitor

Before connecting the load, test the parallel connection of LM338 ICs with a low current load and monitor the output voltage and current.

Ensure that the load is within the safe operating limits of each IC and that the output voltage is stable and regulated.

By following these steps, you can connect IC LM338 in parallel to increase the current-handling capability for your application.

Always refer to the LM338 datasheet and application notes for specific guidelines and precautions.

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About Swagatam

I am an electronics engineer with over 15 years of hands-on experience. I am passionate about inventing, designing electronic circuits and PCBs, and helping hobbyists bring their projects to life. That is why I founded homemade-circuits.com, a website where I share innovative circuit ideas and tutorials. Have a circuit related question? Leave a comment.... I guarantee a reply!

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Reader Interactions

Comments

  1. Tom Moszczynski says

    May 9, 2025 at 6:31 pm

    I hate to sound like a moron. But bear with me … send me the pictorial with 3 LM338 connected in parallel showing the resistors connection for 5 amps per regulator.
    You a beautiful color pictorial showing the 3 LM338 in parallel … why can’t you modify that pictorial showing the load sharing resistors as well, Show a value(S) closest to 100% load sharing as possible.

    Reply
    • Swagatam says

      May 10, 2025 at 8:01 am

      I have already sent it to you, please check your previous emails.

      Reply
  2. Tom Moszczynski says

    May 9, 2025 at 5:51 pm

    " rel="ugc">comment image This the schematic I’m referring to on your post. Please reply back with the Adjustment pin resistors that will equalize the current share loading. The schematic you returned ti totally different. Perhaps you can redraw the pictorial schematic showing the adjustment resistors.

    Reply
    • Swagatam says

      May 9, 2025 at 6:08 pm

      You just need to connect a calculated resistor in series with the outputs of the ICs, that’s all…

      Reply
      • Swagatam says

        May 9, 2025 at 6:22 pm

        here’s the diagram:
        " rel="ugc">comment image

        Reply
  3. Tom Moszczynski says

    May 9, 2025 at 5:07 pm

    2nd Request. Please show the schematic of the addition of the resistors in the adjustment pins that would provide load sharing. Just making a comment doesn’t make it obvious.
    For Paralleling 3 LM138K Regulators.

    Reply
    • Swagatam says

      May 9, 2025 at 5:36 pm

      You need to connect the resistor in series with the output of the IC, as shown in the following article:
      https://www.homemade-circuits.com/make-25-amp-solar-battery-charger-power/

      Reply
  4. Tom Moszczynski says

    April 18, 2025 at 2:00 am

    Please show the schematic of the addition of the resistors in the adjustment pins that would provide load sharing. Just making a comment doesn’t make it obvious.

    Reply
  5. Khatib Nzito says

    April 9, 2025 at 11:01 pm

    Can current be adjusted as well? Can we make it provide constant current or voltage?

    Reply
    • Swagatam says

      April 10, 2025 at 8:50 am

      Yes, it can be adjusted by adding a Bc547 current sensing stage, as shown below:
      " rel="ugc">comment image

      Reply
  6. Giuseppe says

    December 21, 2024 at 1:55 am

    Hello from Italy. I have a large toroidal transformer of 225VA and 28.5V output. Can I use this circuit without problems with about 38V DC input? In this case is it better to insert the small resistors in series with the ADJ pins of each IC? Thank you

    Reply
    • Swagatam says

      December 21, 2024 at 7:54 am

      Hello Giuseppe, I won’t recommend using 38V input for an LM338 IC. Instead you can regulate the 38V to 35V using a transistor zener regulator circuit and then supply the fixed 35V to the input of the LM338.
      You can use the following type of of regulator circuit.
      " rel="ugc">comment image

      Reply
      • Giuseppe says

        December 21, 2024 at 3:50 pm

        Thank you very much, a practical solution to not change transformer and effective, Merry Christmas and Happy New Year

        Reply
        • Swagatam says

          December 22, 2024 at 8:07 am

          You are most Welcome…and a Merry Christmas and Happy New Year to you too!!

          Reply
  7. suat says

    October 27, 2024 at 8:53 pm

    Hi Mr. Swagatam;
    If we prefer to use the step 5 condition (using the individual current limiting resistors) then would the 10K pot be remain or removed?

    Reply
    • Swagatam says

      October 28, 2024 at 8:51 am

      Hi Suat,
      The 10k pot is for adjusting the output voltage so it will be always required in the design, it cannot be removed.

      Reply
      • suat says

        October 28, 2024 at 2:13 pm

        Sorry I made a mistake, I thought that this was designed to adjust / control the output current instead of increasing the output current. Thanks anyway.

        Reply
        • Swagatam says

          October 28, 2024 at 5:12 pm

          No problem Suat, Glad it is clear now!

          Reply
  8. Doug Adams says

    August 2, 2023 at 6:06 pm

    Thanks for the interesting article! You say the transformer current rating depends on how many LM338s are connected, but I am not sure how to apply that. Are transformer current ratings based on input or output current? Where in this circuit (input of transformer, output of transformer, after bridge rectifier) would I put a fuse?

    Reply
    • Swagatam says

      August 3, 2023 at 8:39 am

      Each LM338 can handle upto 5 amp current. Suppose you needed 15 amp current output then you would use 3nos of LM338 in parallel. This would also means that the transformer would need to be rated at 15 amps.
      You can put the fuse at the mains AC input side of the transformer.

      Reply

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