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Home - Datasheets and Components - 400V 40A Darlington Power Transistor Datasheet Specifications

400V 40A Darlington Power Transistor Datasheet Specifications

Last Updated on January 1, 2020 by Swagatam 6 Comments

In this post we investigate the datasheet and technical specifications of a 400V, 40A (ampere) power Darlington transistor MJ10022 and MJ10023, and also learn the main features of the device.

Table of Contents
  • Main Features
  • Maximum Absolute Ratings
  • Thermal Dissipation Graph

We mostly find it difficult when it comes to finding a BJT with extreme voltage and current specifications such as with a 400V and 40 Amp limits.

Here's one such device which is rated with extreme V and I specs, yet it is easily accessible across local electronic markets. This power BJT could be applied in all DC high voltage and high current applications

This power transistor becomes even more special since it has an in-built Darlington feature ensuring maximum efficiency and high current gain, which allows the device to be switched with nominal input triggers and operate huge load using voltages upto 400V and current upto 40 amps.

Main Features

The BJT MJ10022 and MJ10023 are Darlington power transistors are designed to work with fast switching high voltage and high current inductive circuits in which the fall time are typically critical, such as in line operated SMPS topologies.

The main features of this device can be summarized as given below:

  • High current and high voltage operations
  • High speed switching
  • Incorporates high-speed base-emitter diode
  • Darlington high Gain output
  • Designed for heavy duty Inductive loads.

Maximum Absolute Ratings

  • Peak Collector-Emitter Voltage (Vcev) = 450V for MJ10022, and 600V for MJ10023
  • Sustained Collector-Emitter Voltage = 350V for MJ10022, and 400V for MJ10023
  • Maximum Emitter-Base Voltage (Vebo) = 8V
  • Peak Collector Current Icm = 80A (ampere)
  • Sustained Collector Current = 40A (ampere)
  • Maximum Base Current (Ib) = 20A (ampere)
  • Maximum Permissible Power Dissipation (Pd) = 250W (watts) at 25 degrees Celsius, and 143W (watts) at 100 degrees Celsius.

Thermal Dissipation Graph

dissipation graph

Pinout Diagram of MJ10022, and MJ120023 (similar to any other TO3 package such as 2N3055)

MJ10023

Actual Image of the Discussed 400V 40A BJT MJ10022/MJ10023

mje

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About Swagatam

I am an electronics engineer with over 15 years of hands-on experience. I am passionate about inventing, designing electronic circuits and PCBs, and helping hobbyists bring their projects to life. That is why I founded homemade-circuits.com, a website where I share innovative circuit ideas and tutorials. Have a circuit related question? Leave a comment.... I guarantee a reply!

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Reader Interactions

Comments

  1. PGV says

    February 1, 2018 at 10:51 pm

    Hello Swagatam,

    I have gone through many circuits you have designed especially Inverter ones. All I am confused is with the Simple Ohm’s Law and the Power Outputs !!!
    If you have time, please go through my concept here :

    We have a 12 Volt (7 AH battery / whatever the current ratings – I simply don’t know)
    Need to make an Inverter to run an Old sewing machine(manual) support motor (90W, 220/230V/0.5A,50/60Hz)
    This motor is in turn mechanically connected to another motor to work as a generator – (I tried one which generates only 150 Volts ac ; Don’t know the current and frequency generated )
    This 150 Volts I need to further use for an inverter to generate more power..
    Do you think this is possible or a bad Idea ??? If possible, I wonder HOW??

    I am also running after the ways of sustainable free Energy..
    I appreciate your valuable time to read this…
    Wish your thoughts to be positive….
    Thank you so much..
    Have a Joyful Time Ahead… 🙂

    Reply
    • Swagatam says

      February 2, 2018 at 9:48 am

      PGV, that can be never possible, if you have seen such concepts on YouTube, consider them as fakes…

      Reply
  2. Waleed Fareed says

    February 1, 2018 at 12:49 am

    Please help me
    I have cnc router spindle with specification:
    3 phase
    Volt = 220 V AC
    Freq. = 400 Hz
    Power = 800 W
    I need low cost driver circuit
    thanks in advance
    Speed = 24000 RPM

    Reply
    • Swagatam says

      February 1, 2018 at 2:40 pm

      the easiest way is to put 3 separate triac based dimmer controllers (regulators) in series with the 3 lines of the 3 phase.

      then synchronize the pots of the 3 dimmers such that when you want to control the speed, all the 3 knobs rotate together in a synchronized manner

      Reply
  3. Nwibo sylvestet says

    January 6, 2018 at 9:50 pm

    Your circuits diagrams are pretty real. I wish to come over to India and run a full electronics course with you.

    Reply
    • Swagatam says

      January 7, 2018 at 11:19 am

      Thank you!!

      Reply

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