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Simple Delay Timer Circuits Explained

Last Updated on January 2, 2024 by Swagatam 690 Comments

In this post I have explained the making of simple delay timers using very ordinary components like transistors, capacitors and diodes. All these circuits will produce delay ON or delay OFF time intervals at the output for a predetermined period, from a few seconds to many minutes. All the designs are fully adjustable.

Importance of Delay Timers

In many electronic circuit applications a delay of a few seconds or minutes becomes a crucial requirement for ensuring correct operation of the circuit. Without the specified delay the circuit could malfunction or even get damaged.

Let's analyze the various configurations in details.


You may also want to read about IC 555 based delay timers. Recommended for you!


Using a Single Transistor and Push Button

The first circuit diagram shows how a transistors and a few other passive components may be connected for acquiring the intended delay timing outputs.

The transistor has been provided with the usual base resistor for the current limiting functions.

A LED which is used here just indication purposes behaves like the collector load of the circuit.

A capacitor, which is the crucial part of the circuit gets the specific position in the circuit, we can see that it's been placed at the other end of the base resistor and not directly to the base of the transistor.

A push button is used to initiate the circuit.

On depressing the button momentarily, a positive voltage from the supply line enters the base resistor and switches ON the transistor and subsequently the LED.

However in the course of the above action, the capacitor also gets charged fully.

On releasing the push button, though the power to the base gets disconnected, the transistor continues to conduct with the aid of the stored energy in the capacitor which now starts discharging its stored charge via the transistor.

The LED also stays switched ON until the capacitor gets fully discharged.

Te value of the capacitor determines the time delay or for how long the transistor stays in the conducting mode.

Along with the capacitor, the value of the base resistor also plays an important role in determining the timing for which the transistor remains switched ON after the push button is released.

However the circuit using just one transistor will be able to produce time delays which may range only for a few seconds.

By adding one more transistor stage (next figure) the above time delay range can be increased significantly.

The addition of another transistor stage increases the sensitivity of the circuit, which enables the use of larger values of the timing resistor thereby enhancing the time delay range of the circuit.

PCB Design

simple delay timer with PCB

Video Demonstration

 Using a Triac:

The following image shows how the above delay timer circuit may be integrated with a triac and used for toggling a mains AC operated load

 

The above could be further modified with a self contained power transformerless power supply as shown below:

simple compact transistorized timer circuit

Without a Push-Button

If the above design is intended to be used without a push button, the same may be implemented as indicated in the following diagram:

The above delay OFF effect without a push button can be further improved by using two NPN transistor, and by using the capacitor across base/ground of the left NPN

The following circuit shows how the associated push button may be rendered inactive as soon as it's pressed and while the delay timer is in the activated state.

During this time any further pressing of the push button has no impact on the timer as long as the output is active or until the timer has finished its delay operation.

Delay from an External Trigger

Problem asked by Mr. Glen (one of the dedicated readers of this blog):

I have a situation where I have a pulse of 12V that lasts about 4 seconds (from a rotary switch being turned by a slow motor) but I only want about half a second pulse (to trigger a mechanical bell/chime). 

Is there any way to take a long pulse into a circuit and send a much shorter pulse out? 

The solution to the above problem is provided in the following schematic:

Two Step Sequential Timer

The above circuit can be modified to produce a two step sequential delay generator. This circuit was requested by one of the avid readers of this blog, Mr.Marco.

A simple delay OFF alarm circuit is shown in the following diagram.

The circuit was requested by Dmats.

The following circuit was requested by Fastshack3

Delay Timer with Relay

"I am looking to build a circuit that would control an output relay. This would be done in 12V and the sequence will be initiated by a manual switch.

I will need an adjustable time delay (possibly displayed time) after the switch is released, then the output would go on for an adjustable time (also possibly displayed) before shutting off.

The sequence would not restart until the button was pressed and released again.

The time after the button release would be from 250 milliseconds to 5 seconds. The "on" time for the output to turn on the relay would be from 500 milliseconds to 30 seconds. Let me know if you can offer any insight. Thanks!"

So far we have learned how to make simple delay OFF timers now let us see how we can build a simple delay ON timer circuit which allows the connected load at the output to be switched ON with some predetermined delay after power switch ON.

The explained circuit can be used for all applications which calls for an initial delay ON feature for the connected load after the mains power is switched ON.

Delay ON Timer Circuit Working Details

The shown diagram is pretty straightforward yet provides the necessary actions very impressively, moreover the delay period is variable making the set up extremely useful for the proposed applications.

The functioning can be understood with the following points:

Assuming the load which requires the delay ON action being connected across the relay contacts, when power is switched ON, the 12V DC passes via R2 but is unable to reach the base of T1 because initially, C2 acts as a short across ground.

The voltage thus passes through R2, gets dropped to relevant limits and starts charging C2.

Once C2 charges up to a level which develops a potential of 0.3 to 0.6V (+ zener voltage) at the base of T1, T1 is instantly switched ON, toggling T2, and the relay subsequently....finally the load gets switched ON too.

The above process induces the required delay for switching ON the load.

The delay period may be set by appropriately selecting the values of R2 and C2.

R1 ensures that C2 quickly discharges through it so that the circuit attains the stand by position as soon as possible.

D3 blocks the charge from reaching the base of T1.

Parts List

R1 = 100K (Resistor for Discharging C2 when circuit is switched OFF))
R2 = 330K (Timing Resistor)
R3= 10K
R4 = 10K
D1 = 3V zener diode (Optional, could be replaced with a wire link)
D2 = 1N4007
D3 = 1N4148
T1 = BC547
T2 = BC557
C2 = 33uF/25V (Timing Capacitor)
Relay = SPDT, 12V/400 Ohms

PCB Design

delay ON timer PCB design

Application Note

I have explained how the above delay ON timer circuit becomes applicable for solving the following presented issue by one of the keen followers of this blog, Mr. Nishant.

Circuit Problem:

Hello Sir,

I have a 1KVA automatic voltage stabilizer.It has one defect that when it is switched on, very high voltage is outputted for about 1.5s (therefore cfls and bulb got fused frequently) after that the voltage becomes OK.

I have opened the stabilizer it consist of an auto-transformer,4 24V relay each relay connected to a separate circuit(each consisting of

10K preset,BC547,zener diode,BDX53BFP npn darlington pair transistor IC,220uF/63v capacitor,100uF/40V capacitor ,4 diodes and some resistors).

These circuits are powered by a step down transformer and output of these circuit are taken across corresponding 100uF/40V capacitor and fed to corresponding relay.What to do in order to tackle the problem.please help me.Hand drawn circuit diagram is attached.

Solving the Circuit Problem

The problem in the above circuit might be due to two reasons: one of the relays is switching ON momentarily connecting the wrong contacts with the output, or one of the responsible relays is settling down with the correct voltages a little while after power switch ON.

Since there are more than one relay, tracing out the fault and correcting it can be a bit tedious......the circuit of a delay ON timer explained in the above article could be actually very effective for the discussed purpose.

The connections are rather simple.

Using a 7812 IC, the delay timer can be powered from the existing 24V supply of the stabilizer.
Next, the delay relay N/O contacts may be wired in series with the stabilizer output socket wiring.

The above wiring would instantly take care of the issues as now the output would switch after some time during power witch ONs, allowing enough time for the internal relays to settle down with the correct voltages across their output contacts.

Feedback from Mr. Bill

Hi Swagatam,

I stumbled across your page doing research on the web to make my delay more consistent.Some back ground information first.

I am a bracket drag racer and launch the car on first sight of the 3rd amber bulb as the christmas tree is coming down.

I use a transbrake switch that is depressed to lock the automatic transmission in forward and reverse at the same time.

This allows you to rev up the engine to build power for launch. When the button is released the transmission comes out of reverse and moves the car  forward under high rpm.

This is like popping the clutch on a manual transmission car, anyway my car reacts to quickly and the result is a redlight, leaving to early,  and you lose the race.

In dragracing your reaction time on the launch is everything and it is a game of hundreths-thousanths with the big boys, so I have put the transbrake switch on a relay and put a  1100uf  cap combo across the relay to delay its release.

Because of the car electronics I don't believe there is a precise voltage charging this cap every time I activate this circuit and precision is key so I bought a power stabilizer off of Ebay that takes 8-15 volts in and gives a consistent 12volts out.

This turned my season around but i believe this circuit could be made to be more precise and to vary the delay time in an easier way rather than swap cap combos.

Also should I run a diode in front of the relay, not currently because all that is there is the on off switch- where will the current go? I am not an electrical engineer by any means but do have some knowledge from trouble shooting high end audio for many years.

Would love your thoughts-  thankyou

Bill Korecky

Analyzing and Solving the Circuit

Hi Bill,

I have attached the schematic of an adjustable delay circuit, please check it out. You can use it for the mentioned purpose.

The 100K preset can used and adjusted for acquiring precise short delay periods as per your specifications.

However, please note that, the supply voltage will need to be minimum 11V, for the 12V relay to operate correctly, if this is not fulfilled then the circuit might malfunction.

Regards.

one transistor relay delay ON timer circuit

Simple 5 to 20 Minute Delay Timer

The following section discusses a simple 5 to 20 minute delay timer circuit for a specific industrial application.

The idea was requested by Mr. Jonathan.

Technical Requirements

While trying to figure out a solution to my problem on google, I came across your above posting. 

I'm trying to figure out how to build a better Sous Vide controller. The main problem is that my water bath has a very high hysteresis, and when heating from colder temperatures will overshoot about 7 degrees from the temperature at which power is terminated.

It is also very well insulated, with a gap between the inner and outer vessel which makes it act like a thermos jar, because of this it takes a very long time to decline from any excess temperature. My PID controller has an SSR control output and a relay alarm output.

The alarm can be programmed as a below limit alarm with an offset from the set-point. I can use a five volt supply I already have for my circulation motor to run through the alarm relay and drive the same SSR the control output is driving.

To be on the safe side and protect the PID controller I'll add a diode to both the alarm voltage and the control voltage to prevent one output from feeding back into the other.

I'll then set the alarm to stay on until the temperature rises above the set-point minus 7 degrees. This will allow the PID tuning to be adjusted without having to account for the initial temperature ramp-up.

Because I know that last few degrees will be achieved without any power input, I'd really like a way to delay any recognition of the control signal for about five minutes after the alarm shuts off, as it will still be calling for heat.

This is the part I've yet to figure out the circuitry for. I’m thinking of a normally closed relay in series with the control output, which is held open by the alarm signal.

When the alarm signal is terminated, I need a delay on the order of five minutes before the relay returns to its ‘off’ normally closed state.

I would appreciate help with the delayed off portion of the relay circuit. I like the simplicity of the initial designs on the page, but I get the impression they wouldn’t handle anywhere near five minutes.

Thank you,

Jonathan Lundquist

The Circuit Design

The following circuit design of a simple 5 to 20 minute delay timer circuit can be suitably applied for the above specified application.

The circuit employs the IC4049 for the required NOT gates which are configured as voltage comparators.

The 5 gates in parallel form the sensing section and provides the required time delay trigger to the subsequent buffer and the relay driver stages.

The control input is acquired from the alarm output as indicated in the above description. This input becomes the switching voltage for the proposed timer circuit.

On receiving this trigger, the input of the 5 NOT gates are initially held at logic zero because the capacitor grounds the initial trigger via the 2m2 pot.

Depending upon the 2m2 setting, the capacitor starts charging up and the moment the voltage across the capacitor reaches a recognizable value, the NOT gates revert their output to logic low, which is translated as a logic high at the output of the right single NOT gate.

This instantly triggers the connected transistor and the relay for the required delay output across the relay contacts.

The 2M2 pot may be adjusted for determining the required delays.

Circuit Diagram

simple 10 to 20 minutes delay timer circuit

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Filed Under: Timer and Delay Relay Tagged With: Circuits, Delay, Explained, Simple, Timer

About Swagatam

I am an electronics engineer and doing practical hands-on work from more than 15 years now. Building real circuits, testing them and also making PCB layouts by myself. I really love doing all these things like inventing something new, designing electronics and also helping other people like hobby guys who want to make their own cool circuits at home.

And that is the main reason why I started this website homemade-circuits.com, to share different types of circuit ideas..

If you are having any kind of doubt or question related to circuits then just write down your question in the comment box below, I am like always checking, so I guarantee I will reply you for sure!

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Reader Interactions

Comments

Indra says:
November 21, 2025 at 12:48 pm

hi Mr. Swagatam.
I’m Indra, I have a 3d printer machine. I want to make a timer circuit off with an adjustable time. I am interested in your timer circuit using the Triac BT 36 so it doesn’t use relays or DC voltage. how does the circuit work so that after the button is pressed, the AC voltage on the load will be off at a selectable time.

Reply
Indra says:
November 21, 2025 at 7:55 pm

thanks for your reply..what in left side?vin? mean dc voltage?

Reply
Swagatam says:
November 22, 2025 at 8:05 am

Yes, your DC input through the push button…

Reply
Indra says:
November 22, 2025 at 11:13 am

Thanks for your reply..maybe i will try your circuit with triac bt 36,no DC, no relay, coz i want simplest circuit for off timer. if you have another suggestion for my need..just mail me :)..thanks for your help

Reply
Swagatam says:
November 22, 2025 at 1:56 pm

Ok great, you can definitely use my design using BT136 triac, as given below, let me know if you have any issues with the circuit…:
https://www.homemade-circuits.com/wp-content/uploads/2012/05/triac-timer.png

Reply
Swagatam says:
November 21, 2025 at 6:24 pm

Hi Indra,
For a short delay you can do it quickly and safely by employing the following concept:
https://www.homemade-circuits.com/wp-content/uploads/2025/11/Triac-load-control-with-timer.jpg
If you need relatively longer delays then the LED side might require a BJT based timer stage…

Reply
Richard says:
July 18, 2025 at 10:03 pm

Hi there,

I have been tasked with creating something to allow a button to be pressed, there be a 5 second delay(ideally with a visual countdown) and then power up a light to give one single flash and then reset to be used again. All the products/circuits i seem to find all want to delay and then switch on, not flash. Is such a thing possible ? Or am i fighting a losing battle ?

Even just a yes it’s possible would inspire me to keep reaseaching although its been 20+ years since i’ve worked with circuit boards.

hope you can help.
thanks
Richard

Reply
Swagatam says:
July 21, 2025 at 7:59 am

Hi, there’s one mistake in the previous circuit diagram which i gave you.
Please make sure to add a diode in series with the brown colored wire which connects the collector of the right side BC557 with the base of left side BC557. Cathode towards left side BC557 and anode towards right side BC557…
And also please reduce the positive to base 10k resistor value of the left side BC557 to 4.7k.

Reply
Swagatam says:
July 19, 2025 at 10:01 am

Hi, do you need this circuit using only transistors or an IC will also do? Because an IC can work more efficiently…

Reply
Richard says:
July 19, 2025 at 3:28 pm

Hi there, thank you for responding.
I’m looking for the most reliable and efficient way to do this, so i guess an IC would be better however i would go with whichever way you think is best.

thanks
Richard

Reply
Swagatam says:
July 19, 2025 at 5:46 pm

Ok, I have designed it with transistors, you can check it out below. The right/bottom transistor is BC547, Rx and Cx must be adjusted to get the required 5 second ON time delay.
https://www.homemade-circuits.com/wp-content/uploads/2025/07/single-flash-and-then-reset-to-be-used-again.jpg

Reply
Richard says:
July 19, 2025 at 7:25 pm

Wow, thank you for that. I will start assmbly and let you know how it goes.

Thanks again
Richard

Reply
Swagatam says:
July 20, 2025 at 8:02 am

Sure, no problem, all the best to you…please make and test the stages step-wise.

Reply
AJAY says:
June 9, 2025 at 9:08 am

YOUR WORKS ARE AWESOME BROTHER , AND HELPING OTHERS , ITS WORTH A VISIT

Reply
Swagatam says:
June 9, 2025 at 9:34 am

Thanks bro, I appreciate your kind words and glad you liked this site…

Reply
Yorgos P. says:
June 5, 2025 at 11:30 pm

Dear Sir,
on “Delay ON Timer Circuit Working Details”, C2 is not discharged quickly, so if mains power fails and returns before C2 is discharged, then delay-on time will be shortened.
Any suggestion for the above problem ?
TNX
Yorgos
GREECE

Reply
Swagatam says:
June 6, 2025 at 1:35 pm

Hi Yorgos, please try the following modification, and let me know if it works or not:
https://www.homemade-circuits.com/wp-content/uploads/2025/06/delay-ON-with-quick-discharge.jpg

Reply
Alastair Clark says:
April 27, 2025 at 8:17 am

I am looking for a simple circuit to control a start winding of a compressor motor. The start coil and capacitor are connected in series. And use a common 120v which is shared with the run winding and capacitor in series.

Can you please provide a basic simple circuit which uses a transistor or mosfet to turn off the start winding after a few seconds? Please try and make the circuit as simple as possible only using resistors, diodes, capacitors, and an npn mosfet/transistor.

Reply
Swagatam says:
April 28, 2025 at 8:36 am

Since a compressor motor is an AC system, MOSFETs or BJTs might not work, so you might have to use a triac instead. You can try the following design and see if it works or not:
https://www.homemade-circuits.com/wp-content/uploads/2025/04/capacitor-start-motor-yriac-switching.jpg

Reply
KGy says:
May 14, 2025 at 9:46 pm

Hi Swagatam,
I’ve been looking for a similar solution: a fast spin-up circuit for a “dimmed” universal motor. AKA overshoot at switch-on. It’s a pump and when the pressure drops below a set threshold the motor needs to recover it first (also spinning up and starting to move the water in the pipes as well) then to fall back to the operating power/RPM. It takes about 2..3 secs.
I’ve recognized some parts of this circuit at one of your previous posts: https://www.homemade-circuits.com/simple-triac-triggering-circuits-explained/#:~:text=Figure%202
I haven’t found anything similar to this circuit. Also, I don’t seem to get how a 10uF capacitor could produce efficient delay. Neither I see the purpose of the capacitor at the very top of this schematics.
May I also note that my mains is 240VAC and I already have a BTA06 (I_G=5..50mA, instead of 10..25mA of a BT136) dimmer PCB present, connected to the pump motor.
Any help much appreciated.
Thanks in advance, KGy

Reply
Swagatam says:
May 15, 2025 at 1:46 pm

Thanks KGy,
Are you referring to the following circuit? In this circuit, the delay capacitor is rated at 100uF, and there’s no capacitor at the top…please let me know which diagram you are actually referring to:
https://www.homemade-circuits.com/wp-content/uploads/2021/10/AC-POWER-SWITCH-whose-triac-can-be-triggered-with-line-derived-DC.jpg

Reply
KGy says:
May 15, 2025 at 4:35 pm

Hi Swagatam,
Thank you very much for coming back to me. You are a star.
Yes, that’s the one. The timing cap is electrolytic, not poly. Furthermore, -if I’m right- it delays the switch-on.
What I need is additional circuit to the basic triac dimmer that opens the gate for a full-cycle for a couple of seconds.
Where I see the problem lies is that a delay and a trigger circuits need to work alongside.
My best guess would be to utilize a diode-bridge for this.
There are plenty schematics for soft-starters but I need the opposite, which I believe is more complicated.
I hope with it I managed to clarified my needs / circumstances.
Thank you so much,
KGy
P.S. I believe this line of my comment is ambiguous/needs clarification: > I haven’t found anything similar to this circuit.
I meant the one you’ve posted here/I’m replying to. I didn’t manage to find anything similar on the Internet. Neither using the image nor the keywords “start.winding” “compressor”, etc.

Reply
Swagatam says:
May 15, 2025 at 5:52 pm

Thank you KGy,
Though not 100% sure, I think the following configuration can be used to keep the load dimmed normally, and boost the power only during power switch ON, for a couple of seconds, you can try this and let us know how it goes:
https://www.homemade-circuits.com/wp-content/uploads/2025/05/triac-switch-ON-boost.jpg

Reply
Ashish says:
April 22, 2025 at 5:10 pm

sir mujhe ek 24 volt se chalane wala delay circuit ki jarurat hai jo 5 se 20 secand tak voltage delay kar sake
bina trigar switch ke

Reply
Swagatam says:
April 23, 2025 at 8:42 am

Ashish, you can try the following circuit, just make sure to change the relay coil voltage to 24V
https://www.homemade-circuits.com/wp-content/uploads/2022/04/delay-ON-timer.jpg

Reply
WZ says:
April 12, 2025 at 1:50 pm

Hello.

Thank You for the article. I have very basic electronic knowledge but with the article I was able to make circuit I need.

My case: I have a photographic lamp as a part of my workbench setup. The lamp is electronically controlled with pushbuttons. It have one annoyance, does not remember on/off state when power is cut. Every time I turn on main power switch for whole workbench, I have to grab the lamp and hold a button. First I tried to lock the button pressed, but after few minutes the lamp goes off.

The lamp PCB is made with very small SMD components, but I should be able to hook wires to the button, ground and 5V. Microcontroller is operating on 3.3V and on/off pin is connected to pullup 10k resistor. My delay circuit bypass the button and sets the pin low for a few seconds after power rail goes high. I added transistor for faster circuit reset / capacitor discharge.

I have question about above circuits, I can’t grasp what exactly diodes connected to transistor base and emitter are doing. This two: imgur.com/a/u6PuAE2
The emitter one is making base voltage higher and pulse longer, my guess would be that it should clamp voltage and make transition edge sharp, instead it looks like the diode is changing transistors operating point.
And the base diode doesn’t make much difference, it is only making capacitor discharge longer because current can’t run through transistor, changing it to small current limiting resistor makes the circuit ready for new pulse faster.

Here is my circuit:
imgur.com/a/HRiK1bo

Reply
Swagatam says:
April 14, 2025 at 8:59 am

Hi, I guess you are referring to the following circuit. Your assumption regarding the emitter diode is correct.
However, the base diode is also very important, which ensures that the circuit works only as a “delay ON” timer and not as a “delay OFF” timer. If you remove the base diode, then the circuit will start functioning as both delay ON and delay OFF timer which we don’t want. You image link is not opening in my browser at the current moment.
https://www.homemade-circuits.com/wp-content/uploads/2021/03/double-delay-circuit-compressed.jpg

Reply
WZ says:
April 14, 2025 at 1:23 pm

The base diode have a sens now. Thanks. I haven’t thought about delay off, because in my circuit “off” means power down. I wanted to discharge capacitor quickly to make next pulse ready in case of some interrupted power switching or rare power line flicker.

The image link works if copied and pasted into browser. I don’t see rules for the website comments about pasting links, BB code or html tags, I’ll try paste it again in different form and hopefully the comment wont by automatically removed :).

[url]https://imgur.com/a/HRiK1bo[/url]

Reply
Swagatam says:
April 14, 2025 at 5:55 pm

Unfortunately, there’s no easier way to discharge the capacitor, except using the parallel resistor, which cannot be small.
There’s no rule for posting the links, I can handle and process the links while moderating the comments.
The link still doesn’t open, it gives me the following error:
{“data”:{“error”:”Imgur is temporarily over capacity. Please try again later.”},”success”:false,”status”:403}

Reply
WZ says:
April 17, 2025 at 4:30 am

The circuit image uploaded to different hosting:
https://www.homemade-circuits.com/wp-content/uploads/2025/04/delay-timer.jpg

Reply
Swagatam says:
April 17, 2025 at 9:10 am

To make the BC557 discharge the capacitor at power switch OFF, the R8 must be replaced with the short circuit. Still, the discharging will not be efficient because the moment the charge across the capacitor drops below 0.6V, Q3 will shut down. Also, the R5 must be replaced with the diode.

I can’t figure out the function of Q1, it will simply invert the Q2 “delay ON” feature…

Reply
WZ says:
April 21, 2025 at 7:05 pm

Hello.

I used Your circuit with two transistors as a base for tinkering, that why there are two transistors in my circuit. Here is much simpler, one transistor circuit, which gives enough pulse length for my need. I added diode witch is discharging capacitor in simulation, but I’m not sure if it will work in reality or is it a simulation quirk.

Reply
Swagatam says:
April 22, 2025 at 8:50 am

Thanks for sharing your design,
Single BJT circuit will provide less delay time and require larger part values compared to a two BJT circuit. If a single BJT works for you then it is fine.
The capacitor in your circuit has no chance to discharge once the trigger switch is turned off, you must connect another resistor between the (+) of the capacitor and ground….the diode D1 and R4 has absolutely no role to play in the circuit and must be removed.
https://www.homemade-circuits.com/wp-content/uploads/2025/04/single-BJT-delay.jpg

Reply
Nwabueze Richard says:
April 6, 2025 at 11:14 pm

Thanks sir, your explanations are more comprehensible for newbies like me. However, I have a slightly different challenge for my work. I actually need a workaround in which a dc motor can ONLY be activated in;
– an open circuit after the button is depressed AND RELEASED (it doesn’t how long), or,
– in a CLOSED circuit, after the button is open (again, the intervals won’t matter) and closed again. The supply volts is 12vdc.
Thanks. I hope you do understand what I was trying to explain

Reply
Swagatam says:
April 7, 2025 at 8:18 am

Thanks Richard,
Sorry, I did not understand the operations correctly. What is “Open” and “closed” circuit?

Reply
Swagatam says:
April 7, 2025 at 8:20 am

Please let’s continue the discussion under a “motor” related article:
https://www.homemade-circuits.com/dc-motor-speed-controller-circuits/

Reply
Gelu says:
March 12, 2025 at 11:15 am

Hello sir. I have been following you for a long time, and I have realized many of your projects. At one of the circuits presented by you, can it be done that timing is repeated after a certain period of time automatically? You mean, like, cyclical?Work for 1 minute and stay for 3 minutes?Respectfully.

Reply
Swagatam says:
March 12, 2025 at 1:43 pm

Thank you so much Gelu,
You can try the first circuit from the following article for getting a separately adjustable ON/OFF timing for the load:
https://www.homemade-circuits.com/how-to-use-ic-555-for-generating-pwm/
Make sure to increase the values of the 47uF capacitor and the 5k pot as per your maximum on or off time specifications

Reply
Jeff Carpentier says:
January 25, 2025 at 11:23 pm

Howdy Swagatam,

Great site and very much appreciated even though I have just discovered it. I have been looking for information on designing a very simple timing circuit on a 12vdc system. Timer will be on a grounded side inititially. when circuit is switched on there need s to be a momentary delay of 1-2 seconds before going high, and then again a momentary delay before going back to ground. It shall remain this way until circuit is powered down then it will reset.

Thank you for your time!
JC

Reply
Swagatam says:
January 26, 2025 at 9:11 am

Thank you Jeff, glad you found the site helpful!
I think the following circuit should be able to fulfil your requirement:
https://www.homemade-circuits.com/wp-content/uploads/2025/01/delay-timer-circuit.jpg
Pease let know how it works.
You will have to adjust the relevant RC components appropriately for getting the desired timing outputs.

Reply
Sabri says:
August 19, 2024 at 1:17 am

hi.
I want to control an electric motor with a relay.
I want the relay to close 5 seconds later when the current to the relay coil is cut off.Can you help me with this?
Thank you for everything

Reply
Swagatam says:
August 19, 2024 at 8:37 am

Hi, you can try the 2nd circuit from the above article. Replace the LED/resistor with your relay, and make sure to add a freewheeling diode across the relay coil…Adjust the 2M2 and the 1000uF values to get the desired 5 second delay-off time.

Reply
Gajendra says:
August 17, 2024 at 11:48 am

Hi Swagatam,
I have come across your blog and love it as I have been an enthusiast for long. I don’t design electronics.
I’m making a battery powered drone. I would like to have an on-off control which can be controlled with a tac push button. A 3 second contact to power on the electeonics and 3 seconds press to turn it off.
The current in drone circuit is very high, about 60 amps. Unable to find the solution as weight and space are critical on this small drone.
Should this be software controlled? Can you please help?

Reply
Swagatam says:
August 17, 2024 at 2:02 pm

Thank you Gajendra, for your question!
The circuit can be perhaps designed using a 4017 IC and a 555 IC.
Just wanted to know, is the ON/OFF operations done with a single tact switch?
And, what happens if the switch is not released after 3 seconds, and remains pressed for more 3 seconds?
Kindly clarify the above, I will try to help!

Reply
Wali says:
July 1, 2024 at 2:50 am

Hello,

So, I have an application where I am using a D-type flip-flop to toggle my load using a pushbutton. I want to add a trip functionality, so when a trip signal comes, after 5 seconds will the load be turned off. If the trip signal goes out before 5 seconds, the load stays on. If it goes out after 5 seconds, the load will turn on again.

Reply
Swagatam says:
July 1, 2024 at 7:55 am

Please explain the delay trigger operation with more details, I may try to solve it.

Reply
Wali says:
July 2, 2024 at 7:26 am

So the circuit that starts with the output being high when you power it on. Now, when you give it a high signal through the dry contact input, it waits for 5 seconds. If the input stays high for the whole 5 seconds, the output switches to low. But if the input goes low before the 5 seconds are up, the timer resets, and the output stays high. Once the output goes low after the 5-second delay, it stays low as long as the input is high. And when the input finally goes low, the output immediately goes back to being high.

Reply
Swagatam says:
July 2, 2024 at 1:33 pm

Ok, you can try this circuit:

https://www.homemade-circuits.com/wp-content/uploads/2024/07/customized-timer-using-nand-gate.jpg

Reply
Colin Redway says:
April 26, 2024 at 3:53 am

Thank you

Reply
Swagatam says:
April 24, 2024 at 1:07 pm

RX can be around 33k and CX can be around 100uF, for getting an ON time pulse of 3 seconds.

Reply
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