Lamp Outage Detector Circuit for Car Turn Signal

The O.E.M. turn signal flashing units installed in automobiles have two  basic functions i.e. Flasher and Lamp outage detection.

These flashers  are usually built with an 8-pin IC like U2044B, U6432B etc. which are  specifically made for automotive flashers.

Designed and Written By Abu-Hafss

Circuit Operation

These flashers normally oscillate at about 1.4Hz. When a lamp goes bad,  the oscillation is doubled.

The flasher’s faster clicking sound and the  dashboard indicator’s faster flashing attracts the driver’s attention  that one of the bulbs has gone out.

Here, we discuss a flasher circuit which performs similarly but uses a  555 IC and two comparators.

The circuit consists of two parts – the flashing unit and the lamp  outage detection module. The flashing unit is built around 555 timer  configured as an astable multivibrator.

The resistors R12/R13 and  capacitors C3/C4 sets the required frequency. Note that C3 is connected  in parallel to C4 thru an NPN transistor, acting as a switch.

When there  is positive voltage at the base of the transistor, it conducts and  connects C3 to ground. C3 & C4 in parallel makes the capacitance value  double i.e. 220nF + 220nF = 440nF. This capacitance value together with  R12 and R13 result in frequency of about 1.4Hz.

In the Lamp outage detection module, a shunt resistor (a thick wire)  with a calculated minor resistance (30mΩ) is the key to detect the lamp  outage.

The voltage to lamps is fed thru this shunt. Hence, the shunt is  connected in series to the network of the bulbs which are connected in  parallel.

The inverting input (-input) of the comparator U1 is also  connected to the shunt. The non-inverting input (+input) is connected to  a potential divider providing a reference voltage of 11.90V.

NORMAL OPERATION:

-input = Square wave between 11.89V – 12.0V
+input = 11.9V (reference voltage)

The comparator U1 compares the two voltages and the output is a square  wave between 0-12V. This output is rectified thru diode D1 and filtered thru capacitor C1.

Now, we have a triangular wave form which is fed into  another comparator U2.

+input = Triangular wave between 7V – 8V  -input = 1V (reference voltage)

The comparator U2 compares them; the output is constant 12V which goes  to the base of the NPN transistor.

This switches on the NPN and hence C3  is connected to ground. In result, the 555 timer oscillates at about  1.4Hz.

The output of 555 is connected to relay RLY1 which relays 12V  direct from the battery (thru shunt) to the lamps.

OPERATION WITH A DEFECTIVE LAMP:

When a bulb is defective, there is an increase in the resistance of the  bulb network hence the voltage drop across the shunt is changed. So, in  this case we would have:

-input = Sq. wave between 11.95V – 12V

+input = 11.90V (reference voltage)

The comparator U1 compares them and the output is almost zero volts.  After the diode and the filter network, we finally have a few millivolts  at the +input of U2 which is compared with the reference voltage, 1V.

This results in low output of U2 which ultimately switches off the NPN  and hence C3 is disconnected from the ground.

Now, the timing network of 555 has only C4 to work with, therefore the frequency of the oscillation is doubled. This causes the remaining bulbs to flash at doubled rate.

Circuit Diagram