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300 Watts PWM Controlled Pure Sine Wave Inverter Circuit

Last Updated on August 3, 2020 by Swagatam 122 Comments

The following article which discusses a 300 watt pure sine wave inverter circuit with automatic output voltage correction, is a modified version of one of my previous posts, and was submitted to me by Mr. Marcelin. I have explained more about the converter implementations.

The Design

The idea was inspired by the design presented in this article by me, however Mr.Marcelin has refined it considerably for better efficiency and reliability.

To me, the modifications and the implementations done  look great and feasible.

So I have explained the design elaborately with the following points:

IC2 and IC3 are specifically configured as the PWM generator stage.

IC2 forms the high frequency generator required for pulsing the PWM waveform which is processed by IC3.

For processing the IC2 pulses, IC3 needs to be fed with a sine wave equivalent information at its pin#5, or the control input.

Since creating sine waveform is a bit complex than a triangular waves, the later was preferred as its easier to make yet performs as good as a sine waveform  counterpart.

IC1 is wired up as the triangular wave generator, whose output is finally fed to pin#5 of IC3 for the generating the required RMS sine equivalent at its pin#3.

However the above processed PWM signals needs to be modulated over a push-pull kind of arrangement so that the waveforms are able to load the transformer with alternately conducting current.

This is necessary for achieving an output mains consisting of both positive and the negative half cycles.

Circuit Operation

The IC 4017 is introduced just for implementing this action.

The IC generates a sequentially running output from its pin#2 to pin#4, to pin #7, to pin#3 and back again to pin#2, in response to every rising pulse edge at pin #14.

This pulse is derived from the output of IC2, which is  set to 200 Hz strictly so that the outputs of IC4017 results in a 50 Hz across the sequencing from the above discussed pin outs.

Pin#4 and pin#3 are purposely skipped, for generating a dead time across the gates triggers of the respective transistors/mosfets connected to the relevant outputs of IC4017.

This dead time makes sure that the devices never conduct together even for a nano second at transition zones, and thus safeguard the health of the devices.

The sequencing positive outputs at pin#2 and 7 trigger the respective devices which in turn force the transformer to saturate with the alternating battery power induced in the respective winding.

This results in the generation of around 330+ V AC at the output of the transformer.

However this voltage would be a square wave with high RMS if it wouldn't be processed with the PWM from IC3.

Transistor T1 along with its collector diode is fed with the PWM pulses such that T1 now conducts and grounds the base trigger voltages of the outputs devices in accordance with the PWM content.

This results in an output that's an exact replica of the the fed PWM optimized input..... creating a perfectly carved pure sine wave AC equivalent.

The circuit has additional features such as a manual output voltage correction circuit.

The two BC108 transistors are stationed for controlling the gate drive voltage levels of the mosfets, the base current of these transistors are derived from a small sensing winding on the transformer which provides the required output voltage level information to the transistors.

If the output voltage goes beyond the expected safe level, the base current of the above transistors may be adjusted and reduced by varying the 5K preset, this in turn brings down the conduction of the mosfets, ultimately correcting the output AC to the required limits.

The BD135 transistor along with its base zener provides a stabilized voltage to the associated electronics for sustaining constant PWM output from the relevant ICs.

With IRF1404 as the mosfets, the inverter would be able to generate anywher around 300 to 5000 watts of pure sine wave output.

 

 

 

Many drawbacks and flaws were detected while assessing the above circuit details. The finalized circuit (hopefully) is presented below.

The above circuit may be further enhanced with an automatic load correction feature as shown below. It is implemented by the inclusion of the LED/LDR opto-coupler stage.

 

For the final verified design of the above circuit please refer to the following post:https://www.homemade-circuits.com/2013/10/modified-sine-wave-inverter-circuit.html

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Filed Under: Inverter Circuits Tagged With: 300, Controlled, Pure, PWM, Sine, watts

About Swagatam

I am an electronics engineer and doing practical hands-on work from more than 15 years now. Building real circuits, testing them and also making PCB layouts by myself. I really love doing all these things like inventing something new, designing electronics and also helping other people like hobby guys who want to make their own cool circuits at home.

And that is the main reason why I started this website homemade-circuits.com, to share different types of circuit ideas..

If you are having any kind of doubt or question related to circuits then just write down your question in the comment box below, I am like always checking, so I guarantee I will reply you for sure!

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Reader Interactions

Comments

Debashees Sikder says:
December 27, 2013 at 7:26 pm

Sir,in our village home the electricity's volts is low(150 -170v) .Can i use a 16 – 0 – 16v 20a transformer for charge a 120a battery?

Reply
Debashees Sikder says:
December 27, 2013 at 7:14 pm

Dear Sir,is it a pure sine wave inverter as like our main electricity?

Reply
Debashees Sikder says:
December 27, 2013 at 6:42 pm

Dear Sir, I made picture-2 but,it is not able to make a pure wave from.In our market (7)555,1mfd and 50pF is not common.I used here ne555,47pF,1.1MFD (BY PAIRING 2p 2.2MFD POLAR CAPACITOR =1.1MFD {pairing each – } BY POLAR CAPACITOR ). Sir, PLEASE HELP ME.

Reply
Swagatam says:
December 28, 2013 at 7:55 am

Dear Deb,

Please refer to the last circuit given in the following design and add one more 555 stage for getting the required results:

https://www.homemade-circuits.com/2013/10/making-3kva-modified-sine-wave-inverter.html

Reply
achilles hector says:
December 15, 2013 at 2:21 am

are you sure its 300 watts ?

Reply
Swagatam says:
October 15, 2013 at 2:53 am

The chopped PWMs have no connection with moset/transformer switching rate.
Because mosfet/trafo are switched with another IC, it may be with a 4017, or with 4047 etc, and this frequency is fixed at 50 or 60Hz.
The PWMs are only used for chopping or breaking up the above 50 Hz conduction of the mosfet so that the average ON time of the mosfets create a voltage equivalent to a standard sine voltage.
We do this by adjusting the duty cycle of the PWM, if we remove the PWM from the mosfet gates, the mosfets would conduct fully, and create voltages upto 350V which could be dangerous for the appliances.
And the transformer here does not act as a filter, it steps-up whatever waveform is induced at the primary and produces it on its secondary

Reply
Swagatam says:
October 14, 2013 at 3:40 pm

Hi Marcelin,

Welcome back!
Nobody have really completed the project, but according to me the proposed designs a full fledged and perfect and would give the intended results as proposed in the article, especially the last diagram which is a simpler version of the previous design.

TIP35 would require a base driver stage, you can connect 8050 transistor with it in Darlington configuration.

Regards.

Reply
Swagatam says:
October 14, 2013 at 4:36 am

a 12v/220v trafo will require 12v pulsing at the 12v winding for producing 220v, but here since PWM is used the average value across the mosfet drain could be much lower than 12v, therefore to compensate this drop we need to use with a trafo having lower input winding voltage, so that the output never gets affected and stays close t0 220V mark

Reply
alex says:
October 12, 2013 at 10:52 pm

hello Mr swagatam is this a PURESINE WAVE output inverter or it is a modified sine wave inverter like your other post please tell us straight because a lot of us want to build it but we want to be certain before we buy the parts. Thank u for ur usual support

Reply
Swagatam says:
October 13, 2013 at 11:13 am

helo Mr. Alex, all pure sine wave inverters in the market are actually modified sine wave inverters….it's just the quality of the modification that differs, some are crudely modified some are perfectly modified.
In the above design, the waves are perfectly modified according to me, so it can be considered as puresine wave.

Reply
hamza says:
October 11, 2013 at 6:52 pm

thanks 4 de circuit can u please give me de description of upto coupler

Reply
Swagatam says:
October 12, 2013 at 10:17 am

I have explained the optocoupler construction in this article, please refer to it:

https://www.homemade-circuits.com/2011/12/how-to-build-simple-electronic.html

Reply
Swagatam says:
October 11, 2013 at 12:19 pm

Hi thanks! yes it's being tried by an interested member of this blog Mr.Robin Peter.
He has submitted some interesting waveform details and corrections regarding the above design, I would hopefully update them all here soon.

Reply
Swagatam says:
October 11, 2013 at 12:08 pm

…yes surely the PWM via the diodes are reducing the RMS of the mosfet conduction thereby reducing the output voltage proportionately…that's why I have suggested the use of 9-0-9 or 6-0-6V trafo and not a rating that may be matching the battery voltage.

Reply
Swagatam says:
October 11, 2013 at 12:04 pm

The above concept that I have presented is impeccable and will surely work, but your suggestion might be also correct due to one issue in the design, the problem may be with the 200Hz at pin14 of 4017 and the same frequency at pin2 of IC2(555).
I think, pin2 of IC2(555) must be raised to many khz for producing correct pwm via the gates diodes.
for this we need to add a separate astable MV for the IC2(555).
I'll think more about it and update the article accordingly soon.

Reply
alex says:
September 18, 2013 at 12:43 am

helloMr Swagatam I noticed u had a modification which u ommited ic1 and some other components but now I do not see it again. did u remove this and used the other circuit that is ther now with the two 555 and the transistor please explain here thank u

Reply
randy stewart says:
September 14, 2013 at 5:22 am

How does optocoupler protect the circuit?

Reply
Swagatam says:
September 16, 2013 at 2:24 pm

By translating input voltage levels into illumination and then to varying PWMs

Reply
Swagatam says:
September 14, 2013 at 2:18 pm

the LED light increases proportionately with increase in 220V output which lowers the LDR resistance thereby lowering the potential at pin#5 of IC2 resulting in proportionate decrease in mosfet conduction and subsequently reduction in the mains 220v out.

Reply
Swagatam says:
September 13, 2013 at 3:08 pm

it may be due to incorrect or low quality transformer or battery not fully charged.

Reply
Swagatam says:
September 13, 2013 at 9:00 am

I think i have answered this question comprehensively, anyway yes it will drive the mosfets fully.

Reply
Swagatam says:
September 9, 2013 at 4:22 am

Yes that's correct, you got the concept right.

Reply
Swagatam says:
September 8, 2013 at 4:10 am

The meter is showing the RMS value or the average value, the peak voltage of the pulses are always 12V or equal to the supply voltage, so the mosets would be conducting fully during those instantaneous peak pulses.

Reply
Swagatam says:
September 6, 2013 at 4:09 am

If you are using a 12V battery then you can directly connect it with the ICs.

Reply
Swagatam says:
September 5, 2013 at 3:36 am

Yes a lower voltage trafo will generate a slightly higher voltage at the output and thus will last longer even when the battery is fully discharged.

Reply
Swagatam says:
September 3, 2013 at 4:39 am

that's correct.

Reply
Swagatam says:
September 2, 2013 at 3:09 pm

with 12V trafo if the mosfets are allowed to push 12V into the trafo then the output would be equal to the rated output voltage.
Using PWM we can reduce the average conduction of the mosfets thereby reducing their average ON time which in turn produces proportionately lower output voltage at the output of the trafo

Reply
Swagatam says:
August 29, 2013 at 7:53 am

Technically it should be equal to the transformer half winding voltage rating, that is if the trafo is 9-0-9V, then you may fix a 9V DC at pin#5 of IC2 for getting the specified output at the trafo output

Reply
Swagatam says:
August 27, 2013 at 2:29 pm

The varying voltage level of the triangle waves determine the output pulse width therefore if the triangle waves are without sufficient peak levels, the result from pin#3 would be proportionately low which in turn will produce lower AC voltage at the output of the trafo.

In the modified diagram I have eliminated the triangle waves because here I have empoyed a fixed average voltage at pin#5 such that the corresponding average PWM matches with the average of a triangle wave.

You can refer to the following post for knowing more about 555 function as a pwm generator.

https://www.homemade-circuits.com/2012/12/how-to-use-ic-555-for-generating-pwm.html

Reply
Swagatam says:
August 27, 2013 at 3:56 am

I have already rejected the first diagram due to many doubtful things hidden in it, so it's no use sending me the diagram.

First of all the triangle waves shown there may not be from zero to peak, secondly the voltage correction stage is doubtful..

The updated diagrams at the bottom are more reasonable and are on the same principles as the first one, except that it does not employ triangle waves which is anyway not crucial, according to me.

Reply
Swagatam says:
August 26, 2013 at 5:06 am

I did not modify the first design because it's unnecessarily complicated, rather I designed my own version, see the last diagram.
Here I have eliminated the triangle waves because according to me the pattern of the waveform is not critical, the RMS needs to be corrected as per the specifications which I have tried to do through the opto circuit.

The shown optocoupler is a hand made assembly made by sealing an LDR and LED face-to-face inside a light proof enclosure.

Reply
Swagatam says:
August 25, 2013 at 5:51 am

The "space" in the mark/space ratio of PWMs are the negative pulses, wider "spaces" would result in lesser voltage while wider "marks" would result in increasing voltages.

I have updated the required design, you can check it out.

Reply
Swagatam says:
August 24, 2013 at 1:56 pm

the present design would reduce the positive PWMs which we don't want, it should be just the opposite, so you are right the modification should be introduced at the gates of the mosfets, I'll correct it accordingly soon.

Reply
Swagatam says:
August 23, 2013 at 1:51 pm

Actually the above modification won't correct a varying output load, so yes may be the modification was not correct, I'll redesign it and publish it soon.

Reply
Swagatam says:
August 23, 2013 at 5:54 am

it can used to control the height ( peak voltage) of the triangle waves resulting in an equivalent control at the output

Reply
Swagatam says:
August 23, 2013 at 5:22 am

in cases where there's no return path for the mosfet gate to discharge then it would be required.

Reply
Swagatam says:
August 23, 2013 at 5:09 am

Thanks Michael,

The resistors are introduced neither for limiting current nor for restricting voltage, it's just a good practice to put a low value resistor at the gate….even if you don't put any resistor the mosfets won't get affected because these are MOS based devices specified with very high gate resistance.

Applying the PWM at the IC pins would blow the 4017 IC.

Reply
Auston says:
August 21, 2013 at 4:41 pm

hello Sir….
what if i increase the frequency of the output pwm IC??(IC3 in first diagram)…

Reply
Swagatam says:
August 23, 2013 at 5:28 am

the output frequency would also increase then.

Reply
Swagatam says:
August 21, 2013 at 1:49 pm

Hi Michael, you are right! Actually I have already addressed this issue to one of the readers who asked the same question a few days back, I can't remember though where it's posted.

Anyway the remedy may be done in the following manner.

another resistor can be introduced in between the IC pinouts and the common gate resistors, and this junction can be used as the PWM and the voltage correction outputs.

The new resistor can be a 1K while the gate resistors can be reduced to 100 ohms.

Reply
Swagatam says:
August 21, 2013 at 6:23 am

correction:

2)just multiply the number of sequence selected for the output of 4017 with 50, that will give you the needed IC1 frequency value, which can be set by adjusting C1

Reply
Swagatam says:
August 21, 2013 at 6:22 am

1) That's correct, however the triangle waveform is not critical, it can be replaced with square waves at pin#2.
2) just divide the number of sequence selected for the output of 4017 and multiply it with 50, that will give you the IC1 frequency value, which can be set by adjusting C1.
3)It may be connected in that way, but having separate resistors for the gates would be better.

Reply
Swagatam says:
August 20, 2013 at 8:33 am

you may incude for better safety, although nowadays the mosfets have them in-built.

I think you've made a good point, the transistor is not required, in-fact it's presence will invert the PWM from the 555 output, resulting in an incorrect stepped-down voltage at the tranfo output.

the common cathodes of the diodes must be directly connected with the 555 output for obtaining correct optimization.

Reply
Swagatam says:
August 20, 2013 at 8:27 am

Actually there's nothing called carrier waves here, one signal determines the frequency of the PWM while the other the duty cycle, together they constitute and produce the required optimized PWM corresponding to the applied sine input.

for example when you apply the two signals at the inputs of an opamp, the output results in a PWM where the ramp (sine or triangle waves) voltage fixes the pulse width while the square waves determines the frequency of the pulses

Reply
Swagatam says:
August 20, 2013 at 6:37 am

Dear Raimund,

The above circuit was designed by one of the interested hobbyists, so it might have some issues with its configuration, you can refer to the last design presented in the following link:

https://www.homemade-circuits.com/2012/12/make-this-ic-556-pure-sine-wave.html

It's simple and as good as the above explained circuits.

Reply
Swagatam says:
August 19, 2013 at 1:38 pm

Everything is correct in your explanation.

The carrier waves decide the frequency of the PWM so it has nothing to do with filtration at the output, the output will be a clean PWM in sync with the sine generated by the "bubba"

The above diagram may have a few discrepancies, please refer to the LAST diagram given in the following link, it's at par with your explanation except that it doesn't employ a sine oscillator:

https://www.homemade-circuits.com/2012/12/make-this-ic-556-pure-sine-wave.html

Reply
Swagatam says:
August 18, 2013 at 1:14 pm

you are welcome Michael!

Reply
Swagatam says:
August 17, 2013 at 6:51 am

the situation here will be just the opposite to BC108s, for BC557 the emitters will go to the mosfet gates, collector as mentioned by you will go to the ground.
emitters will not need any resistors because of the 1k resistors from the IC 4017 relevant pinouts.

Reply
Swagatam says:
August 16, 2013 at 11:32 am

ACTUALLY THE BC108 SECTION IS INCORRECT, I noticed it carefully just now. The situation will not allow the mosfets to conduct at all.

The BC108 must be replaced with PNP transistors such as BC557 which will then work as "emitter followers" and restrict the mosfet voltage exactly to the level which is set at their bases.

To know more regarding the above just Google, "how emitter follower transistor work"

Reply
Swagatam says:
August 16, 2013 at 11:05 am

You will need battery charger unit which you can wire with the relay changeover system shown in the following link:

https://www.homemade-circuits.com/2012/09/automatic-inverter-supply-and-mains.html

It will charge your battery when mains is present and revert the battery to inverter mode when AC fails, also the output to the appliances will be switched from mains to inverter and vice versa.

Reply
Swagatam says:
August 15, 2013 at 4:25 am

You are welcome Michael, your questions are always interesting.

A wattage selector is not required actually, because the inverer does this automatically…..when more load is connected the output starts drawing more current from the battery and vice versa, just like our home electrical system, with more load we are billed more and so on.

Reply
Swagatam says:
August 14, 2013 at 11:48 am

Higher resistance will prevent quick discharge of mosfets internal capacitance making it inefficient.

Reply
Swagatam says:
August 14, 2013 at 5:08 am

The -12V is actually the 0V line or the ground line, a single battery is used for the design.

Reply
Swagatam says:
August 12, 2013 at 1:44 pm

I am sorry Michael, It's difficult to figure out just by visualizing, you will have to check it in scope.

Reply
Swagatam says:
August 9, 2013 at 4:26 pm

The 1K will block this from happening to appreciable limits, only a trivial amount will pass and get grounded inside the pins and will have no affect on the functioning.

Reply
Darlington from Kenya East Africa says:
August 9, 2013 at 9:09 am

Hi Bro, you are such a genius in this things, now can you give us a PCB for this to enable easy building of the project

Reply
Swagatam says:
August 10, 2013 at 2:35 am

Thank you Darlington, However I am sorry to say that it won't be feasible for me to design the PCB due to my busy schedule, yet I'll see if I can do it some time in the future.

Reply
Swagatam says:
August 5, 2013 at 5:03 am

Refer to this circuit, here the low amplitude signals are appropriately amplified at the output for driving the inverter transformer:

https://www.homemade-circuits.com/2013/04/simple-pure-sine-wave-inverter-circuit.html

Reply
Swagatam says:
August 3, 2013 at 7:44 am

Thank you Michael, interesting questions, I think all these can be easily confirmed through practical testes, because doing mind simulations could possibly produce wrong results.

So the best thing to do is take an opamp, feed the proposed signals at the inputs and analyze the readings at the the output over an oscilloscope.

I appreciate your interesting thoughts, keep them coming:)

Reply
Swagatam says:
August 2, 2013 at 7:39 am

That's exactly why the diodes are there. The diodes prevent positive PWMs from entering the N-channel mosfet gates making sure their gate conduction is chopped only through the negative PWMs which would otherwise have no effect on the mosfet conduction.

Reply
Swagatam says:
July 28, 2013 at 12:56 pm

During the PWM high pulses the transistor conducts and grounds the equivalent amount of areas from the mosfet base square waves allowing the mosfet to conduct exactly according to the PWM pattern.

Reply
Swagatam says:
July 26, 2013 at 2:37 pm

4017 will not respond to PWM, it will only follow the high peaks and make it's output jump from one output to the next, it won't reproduce the PWMs.

Reply
Swagatam says:
July 26, 2013 at 2:11 pm

I wish you all the best for the project.

When two waves are fed to an opamp inputs the internal circuitry compares the two voltage peaks and produce the average waveform of the two through varying rectangular waveform and duty cycle. Since the output from the opamp can be either low or high therefore the result is always in the form of rectangular wave and cannot be exponential.

Reply
Swagatam says:
July 21, 2013 at 2:35 pm

I have worked hard to present the concept, and I will request you to simulate it or test it practically so that all others can benefit from it.

Reply
Swagatam says:
July 21, 2013 at 3:22 am

you can use 9-0-9v/25amp transformer.

7805 will not be required with 12v supply

Reply
Swagatam says:
July 21, 2013 at 3:18 am

The voltage will get adjusted by the 5k preset, there's no need of adding 7806 IC, if you add it then the detection might not take place.

Reply
Swagatam says:
July 18, 2013 at 6:14 am

use the following circuit across points a/b.

https://www.homemade-circuits.com/2011/12/cheap-yet-useful-transformerless-power.html

use a 0.22uF capacitor for C1 and don't use the zener diode.

the 5k preset now should be replaced with a 47K preset.

Reply
Swagatam says:
July 17, 2013 at 4:51 am

Which 555 circuit are you referring to? the above one or the linked one.

the linked one will not require an external triangle wave generator, it has a built in.

Reply
Swagatam says:
July 16, 2013 at 7:08 am

…deriving voltage directly from 220v tap would be posible using a 0.22/400v capacitor for dropping the current and then rectified for feeding the shown transistor stage.

Reply
Swagatam says:
July 16, 2013 at 7:04 am

Thanks Michael, I referred you to the new circuit since you had asked for a simplified and a reliable diagram, you can continue with the above diagram if you feel so, no issues.

The 556 will not require any regulation as it can work with any voltage from 5 to 15V and will produce the same results.

By the way the new diagram is RMS controlled and would hopefully produce a constant voltage with varying load conditions.

Also please note that none of these designs have been practically confirmed by me, they are all produced using mind simulation.

Reply
Swagatam says:
July 15, 2013 at 3:57 pm

you can try the last circuit given in the following article:

https://www.homemade-circuits.com/2012/12/make-this-ic-556-pure-sine-wave.html

Reply
Swagatam says:
July 15, 2013 at 4:26 am

yes you can use irf240. first test with single mosftes, if it works then proceed with more nos.

Reply
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