In this post we learn how to build a simple yet accurate timer circuit using the IC 4060 and some ordinary passive components.
Main Advantage of using IC 4060 as the Timer IC
I have already discussed this IC comprehensively in one of my previous articles, everything regarding its pin outs have been discussed there in detail. We studied that the IC 4060 is specifically suited for timer applications and also as an oscillator. In this article we’ll study how a simple versatile timer can be built using the IC 4060.
Other than the IC you would require just a couple of resistors, one pot and a capacitor for making this timer.
Referring the figure, the simplicity of the design becomes evident and therefore this circuit is perfectly suited for all electronic newcomers, who can easily build this project and enjoy its useful service.
As explained earlier in one my articles, the IC has an in built oscillator that needs just a few passive external components for making it tick.
Depending upon the values of the external RC components, the oscillation periods can be varied right from a few fractions of a second to many hours.
RC components refer to the values of the external time determining components consisting of a resistor or a pot and a capacitor.
The outputs produce a varied rate of time periods; each output generates time periods that’s exactly double to that of the previous output in a certain order of the IC pin outs.
Since here we want to use this unit as a timer we have selected the pinout which is last in the order as far the length of the time period is concerned, meaning we have selected pin #3 which generates the highest delay period.
The biggest advantage of making a timer using IC 4060 is that the involved timing capacitor can be kept as small as possible by increasing the complementary timing component value, which is the resistor.
This helps to keep the circuit simple, smaller and very sleek, unlike other timer IC like 555 which require high value electrolytic capacitors for generating even ordinary time delays.
How the Circuit is Latched when Time is Elapsed
In the figure you can see a diode being introduced from the output pin #3 to one of the oscillator pin #11. This diode acts as a latching component, which latches the IC once the set time lapses and the output of the IC goes high.
If this diode is not inserted, the output would go freewheeling from logic high to logic low and keep repeating the time delays.
The circuit may be powered from a small 9 volt battery which will last almost for ever.
A buzzer is fitted at the output for the required indications of the timer output after the time delay has elapsed.
How to Reset the Timer
The IC may be reset simply by pressing the reset button or alternatively the circuit gets automatically reset when switched off and powered again.
How to Calculate Frequency or Time Delay of IC 4060 - The Formula
Or Alternatively the following standard formula for calculating the Rt and Ct values is:
f(osc) = 1 / 2.3 x Rt x Ct
2.3 is a constant as per the ICs internal configuration.
Rt will in Ohms and Rt in Farads
PCB Design
Adding a Relay
You can further upgrade the above design by adding a relay control to the output in order to facilitate an external mains AC load switching, as shown in the following image:
Remember the delay interval at pin3 can be increased by increasing the C1 value along with the P1 pot value. Hoover, make sure that the C1 is always a non-polar, hence to increase its value you can connect many number non polar capacitors in parallel. For example you can connect non-polar 1uF capacitor as many numbers as you want for getting a desired long delay.
Understanding the Basic ON/OFF sequence of IC 4060 pinouts
The following video shows how a basic timer circuit may be configured using an IC 4060 and a few supporting passive components.
The schematic for the circuit discussed in the video can be visualized in the following diagrams:
The following image shows how to latch IC 4060 output by adding a diode across the selected output pin and pin#11
As we already know that the timing output or delay across all the shown output pins of the IC 4060 depends on the product of the values of R1 and C1, here pin#3 can be seen going after 32 logic pulses from pin#14 of the IC. Meaning when the LED at pin#14 completes 32 pulses, the LED at pin#3 switches ON, and switches OFF after another 32 pulses from pin#14. Identically you may find different equivalent rates at the other output pins of the IC.
This timing proportion is observed when R2 and C1 are selected to be 10K and 0.1uF respectively.
Simple Timer with Alarm
The next circuit is also designed using the CMOS IC CD4060, that includes a pulse generator and a counter. When power is switched on via S1, a reset voltage is given to the IC through C2. Simultaneously the IC built-in oscillator starts providing pulses to the counter.
Following 213 clocks, the counter output (Q14) goes high, turning on the oscillator across T1 and T2. By doing this a sharp 3 kHz frequency that is emitted through an 8 ohm small loudspeaker. The circuit is powered down simply by turning off S1.
With the indicated R2 and C1, the buzzer will sound approximately An hour after the circuit has been started up. By upgrading R2 with a 1 M adjustable potentiometer, the buzzer time period could be varied from 5 minutes to 214 hours.
The potentiometer scale may be appropriately calibrated for quick setting up. The circuit utilizes hardly any current (0. 2 mA although the counter will be operating with 35 mA when the alarm signal is turned on) thus that a 9 V battery should promise quite an extended life.
PCB Design and Component Layout for the above timer with alarm can be seen below:
I know this is an old video, but here’s hoping someone sees this..
I am trying to somewhat replicate a tea light LED candle that when switched on, stays lit for 6 hrs and then automatically turns off for 18 hrs with the switch remaining in place. All of my research brought me to this video and I was wondering if this 4060 IC is the item I need? I am trying to power one (maybe two) 5 mm white LEDs with a 9V battery while keeping size to a minimum. I know how to do this with an Arduino Nano, but I believe it would be large, drain the battery too fast, and kind of excessive for this small application. I have a soldering iron, some protoboards, the 5 mm white LEDs I want to use and some resistors but can get more supplies if needed. I plan to make several of these setups for gifts 😉
I am brand new to electronics and any help would be greatly appreciated.
Yes you will need the IC 4060 for implementing the desired function, however, two of these will be needed for achieving two separate programmable timings, as explained in the following article;
https://www.homemade-circuits.com/how-to-make-simple-programmable-timer/
Interesting circuit sir, before i try your circuit i read the datasheet of cd 4060, from the tabel it said that max output current is on mA?not depends on current input?so it must be using relay to switching higher load says >500mA such as peltier or batteries?..im i right?pls fix me if iam wrong.
Thank you.
Thanks, yes naturally for switching higher current loads you will have to connect either a transistor such as TIP122 (for DC load) at pin3 or a transistor relay driver if the load is an AC load.
In the last diagrams, you can replace the BC537 with TIP122 and the collector 1K with a high current load. Alternatively, you can replace the 1K at the the collector of the BC547 with a relay. Just make sure the relay coil has a freewheeling diode, and the the green LED has a series 1K for both the above mentioned alternatives.
I note that the 4060 is powered with 3-15 volts of input via pins 8, 12, and 16. It has several outputs, i.e. pins 1,2,3,4,5,6,7,13,14, and 15. At the proper time, depending upon the Resistors and Capacitors attached to pins 9,10, and 11, each of the outputs will go on.
Question 1) What will be the output voltage.
Question 2) Is there a correlation between input and output voltage, i.e. would Vo = k * Vi ?
Question 3) If several of the output pins are on, will that diminish the voltages, and if so how?
Pin#8 and pin#16 are the supply pins of the IC, pin#12 is the reset pin.
All digital ICs or CMOS ICs will always show an output voltage almost equal to the supply voltage applied across their supply pins. So the output is just the switching ON of the applied supply voltage at their Vcc or supply pins.
The outputs will be normally connected through resistors so even if all the outputs are ON, the voltage will not be affected.
Sir…
Pls tell the reason for using capacitor c2 0.1uf…
And tell how to calculate both resistors and capacitor for time delay
Kesav, it is called a decoupling capacitor, this is normally recommended for all CMOS ICs and should be connected directly across their supply pins (Vcc/Vss)…It is required to ensure a healthy functioning of the IC and prevent voltage transients from affecting the IC functioning during power switch ON periods
Hi,
I need to make a timer circuit wich will works with 3 times options (10min 15min and 20min)
It will receive a pulse from differents relays, by the required time.
For example:
If the required time is 10minutes, the correspondent relay of 10 minutes turn on, and the timer need to turn on a DC Motor, count 10 min, then turn off a DC Motor.
The same with the other times (15 minutes, and 20 minutes).
Could you help me?
Hi, to achieve this you can simply build three separate IC555 monostable timer modules with preset level of timing output, and attach the triggers to the respective 555 inputs.
Hi,
I need to make a timer circuit wich will works with 3 times options (10min 15min and 20min)
It will receive a pulse from differents relays, by the required time.
For example:
If the required time is 10minutes, the correspondent relay of 10 minutes turn on, and the timer need to turn on a DC Motor, count 10 min, then turn off a DC Motor.
The Dame with the other times (15 minutes, and 20 minutes).
Could you help me?
Hi, to achieve this you can simply build three separate IC555 monostable timer modules with preset level of timing output, and attach the triggers to the respective 555 inputs.
Is possible in this 4060 to generate nonsymetrical on/off timings. For example 16hours on and 8hours off?
for two unique time sequences, you may have to employ two 4060 IC s instead of one as discussed in the following article
https://homemade-circuits.com/2012/04/how-to-make-simple-programmable-timer.html
Hi sir,
my name is Rishabh. Sir can you please make a timer based on 4060 ic that can turn on and off a relay for 10 to 30 sec twice in 24 hours, once in morning and at evening.
Hi Rishabh, you can try the following circuit
https://homemade-circuits.com/2012/04/how-to-make-simple-programmable-timer.html
Hi swagatam,
I have read this post on cd4060 and other on its pinout, but i am sorry i not understand how it work.
I get it that pinout 9,10,11 set the frequency, but how it can counter the time?
With an capacitor and two resistors i have an frequency signal at these pinout.
Now,this frequency how come used for counter?
I hope that you can to explain this.
Thank you so much and congratulations for your job.
Hi Andrea,
the counting is in the form of pulses generated across the different output pins of the IC…pin#3 generates the pulses at the slowest rate while pin#7 the fastest…others do it at other specified frequency rates.
these rates of frequency are determined by the charging and discharging period of the capacitor, through the internal CMOS gates…however how these different speeds or frequency rates are attributed across the pinouts of the IC is a little complex to understand and will need a thorough study of the internal structure of the IC.
Hi Swagatam,
Thank you for your fast reply.
I need to calculate the 4060 to give a 1 second interval, but have trouble to understand your formula.
Could you please help to get it right with the 2 resistors at pin 10 & 11 and the capacitor at pin 9?
Thank you
Hi Henrik,
for solving the equation for "seconds" you will need to use the T(out) equation which will provide you the ON/OFF delay in seconds from the selected output pin of the IC.
Rt is the resistor involved with pin#10, Ct is the capacitor at pin#9…"n" is the serial number of the preferred output pin which you can find from the datasheet of the IC….for example the first pinout in the sequence is pin#7 (Q3) while the last is pin#3 (Q13)….if you selected pin#3 then N will correspond to "13"
and Ct will be in Fradas
Hi MIke
im looking into building a timer to replicate a broken siren at work for breaks and lunch times.
Will this circuit serv the perpose? I would need it to sound for 30 seconds at 10:00am, 12:00 and 3:00 pm each day of a 5 day work week.
if so can you provide a component rating for me?
thanks
You can try the following design
https://homemade-circuits.com/2012/04/how-to-make-long-duration-timer-circuit.html
and assign the different outputs of the IC2 uniquely for the required intervals.
or probably the following one
https://homemade-circuits.com/2013/11/week-day-programmable-timer-circuit.html
Thanks!!
Can you please say the part list pls..
it's already given in the circuit diagram….all resistors are 1/4 watt rated.
Hi swagatam
I have made circuit using 4060 timer
But getting different on and off timings
M using 470nF capacitor 1M pot Rs-10M
Please help me out
Hi Ron,
check all the outputs of the IC, you'll find the one which is may be most desirable to your need….pin3 will give highest delay, pin7 the lowest between the ON/OFFs
Dear Swagatam, Thank you for considering my circuit. I will wait for the design. However, the transformer that I have has an output of 16 volts ac not 18. Sorry. Hope this will not be too much trouble.
Thank You kind Sir/
Mike
Dear Swagatam, I am trying to build a timer circuit to control an automatic fish feeder.
It needs to operate on 12 volts. It needs to operate two relays. Both need to come on at
the same time. The first relay needs to shut off after 5.2 seconds. The second relay needs to shut off after 7 seconds. Then the process needs to repeat in 24 hours. Also can you convert 18 volts ac into 12 volts dc.
Thank you
Mike
Hi Mike, I'll try to design it soon and post it in this blog, I'll provide you with the link once it's done…please be in touch.
Dear sir,
I want to start a 12v /500mA max dc motor after 40-60secs of switching on and will stop after switching off.
Please refer any ckt.
I wrote u on saturday and also writing u on today. Sir please help……
Thanking you,
k.kausik
Dear Kausik,
you can try the circuit shown in the above link.
remove the shown buzzer and connect a TIP122 base to pin3 of the IC via a 1k resistor, connect its emitter to negative of the supply, and connect one wire of your motor to the collector of the transistor and the other to the positive supply.
Now if you switch ON power, the motor will start after a predetermined period of time depending upon the value of P1
correction: try the circuit that's given in the above article.
I m ok if it can work on 9 volt battery too
you can try the circuit shown in the following link, it's a 10 stage programmable timer, you may reduce the number as per your requirement:
https://homemade-circuits.com/2014/01/programmable-diesel-generator-timer.html
The relay may be replaced with the COB alarm
Dear Swagatam,
If you have time, I would be very grateful if you could help me and design a circuit.
I need a circuit which will allow a speaker to play a Jingle using a COB at a fix or a pre set time, for example i want to set he speaker to play jingle at 9 AM than at 1 PM and so on.
It should work on a 3V Button cell ( 2032 )
regards
Devan.
Dear Devan,
the circuit is possible but it cannot run on 3V, there's no IC that would run comfortably on 3V
Dear Swagatam, my name is Stevan and I spend more than 20 hours on your site, searching for a circuit I need… My knowledge is not enough to figure which circuit I can use and I tried with many of them… If you have time, I would be very grateful if you could help me and design circuit. I need timer circuit which will allow me to chose for how long it will stay ON (3-10 sec) and how many times it will repeit that action during 7 days (1-7 times / once in a week, twice in a week, every day etc). I need it for controling 9-12V electro motor. Thank you very much in advance!
Dear Stevan,
Thanks! I'll try to do it for you soon and post it in this blog.
Thank you so much!!!
Thanks for publishing this circuit. I'm using it on a boat to turn on the illumination for a switch panel, running at 12V. I've replaced the buzzer with a PNP transistor that switches the real load (the panel back lights) when Q14 (pin 3) is low, and turns it off when the pin goes HIGH…and this works just fine.
So, when I push the momentary (reset) button, the lights come on for a period of time, long enough for me to find the panel switch I am interested in and turn it on or off.
Now I am wondering if there is a way of turning off the lights BEFORE the timer expires? What I'd like is a second momentary switch that would drive the Q14 (pin 3) HIGH and keep it HIGH until the first button was pressed again.
Any ideas?
You are welcome!
You can try putting a push-to-on momentary switch across the end terminals of P1/R2.
When you press this, C1 will quickly discharge making pin3 go high and latch the circuit….I think this would work
I've modified the circuit to run off 12 volts and it works just great. Thanks for putting up the post. I am using this to illuminate a switch panel – the idea is that you press a momentary button and the switch panel back lights will turn on for a period of time…enough time to find the switch you want and turn it on/off. I was also thinking of adding another momentary switch that would turn the lights off even if the timer hadn't expired. However, I haven't managed to figure out how to do this. Another way of describing this is that I want the Q14 (pin 3) to go high (and stay high) when I toggle the second switch.
Any ideas on how this could be done?
Hi, thanks,
through trial and error find an appropriate resistor value and replace R2/P1 with it. You can also try higher values for C1, increasing them to some higher level would give you the required timing.
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