In this post I have explained an automatic submersible pump start, stop circuit with dry run protection in order to implement an automatic ON/OFF switching of the motor in response to the high/low water levels of the overhead tank.
Circuit Concept
In one of the previous posts I have explained a similar concept which also dealt with an automatic start/stop function of the submersible pump contactor button, however since here the sensors involved float switches, the design looked a bit complex and not suitable for everyone.
Moreover, the dry run protection included in the design relied on the temperature change of the motor for executing the required protection of the motor. This feature too was not too desirable for a layman since installing the heat sensor over the underground motor was not easy.
In this post I have tried to eliminate all these hassles and designed a circuit that is featured to sense the water presence solely through metal sensors immersed in the relevant water sources.
Circuit Operation
So I have explained the proposed Automatic submersible pump start, stop circuit with dry run protection.
A single IC 4049 can be seen engaged for the entire sensing, start stop actions and the dry run protection execution.
The gates involved here are 6 NOT gates from the IC 4049 which are basically rigged as inverters (for inverting the polarity of the fed voltage at its input).
Let's assume the water inside the over head tank goes below the desired lower threshold, as indicated in the above diagram.
The situation removes the positive potential that ws supplied through the water to the input of N1. N1 responds to this by causing a positive to appear at its output pin, which instantly causes C1 to begin charging via R2.
The above condition also allows the positive from the output of N1 to reach the input of N2, which in turn produces a low or a negative at the base of T1 via R3....the associated relay now toggles ON and activates the "START" button of the contactor....however the relay activation is sustained only for a second or so until C1 is fully charged, this length may be set by appropriately tweaking the values of C1/R2.
For the moment let's forget about N5/N6 stage which are positioned for the dry run protection implementation.
Let's assume the pump is running and pouring water into the shown OH tank.
The water now begins filling inside the tank, until the level reaches the brim of the tank "kissing" the sensor corresponding to the N3 input.
This allow a positive through the water to feed the input of N3, enabling its output to go low (negative), which instantly causes C2 to begin charging via R5, but in the process the input of N4 also becomes low and its output inverts to a high prompting the relay driver to activate the relay.
The upper relay instantly activates but only for a second, toggling the "STOP" button of the contactor, and halting the pump motor. The relay timing may be set by appropriately tweaking the values of C2/R5.
The above explanation takes care of the automatic water level control by toggling the submersible start/stop button through the circuit's relays. Now it may be interesting to learn how the dry run protection is designed to prevent a dry run hazard in the absence of water inside the borewell or a underground tank.
Let's go back to the initial situation when the water in the OHT has fallen below the lower threshold and rendered a low at the input of N1....which also renders a low at the input N5.
N5 output turns high due to this and provides a positive supply for C3 so that it can begin charging.
However since the process is also supposed to start the motor, if water is present, the pump may start pouring water in the OHT which is supposed to be detected by the input of N6, causing its output to go low.
With N6 output at low, C3 is inhibited from charging, and the situation stays stalemate...and the motor continues to pump water with no change in the previously explained procedures.
But, suppose the motor experiences a dry run due to an absence of water in the well....as stated above C3 begins charging and the output of N6 never turns negative to stop C3 from charging fully....therefore C3 is able to complete its charging within a predetermined span of time (decided by C3/R8) and finally producing a high (positive) at the input N3.
N3 responds to this in the same way as it would do when the water in the tank is detected at the uppermost threshold....prompting the switching of the upper relay and stopping the motor from running any further.
The dry run protection for the discussed submersible pump start, stop circuit is thus executed.
Parts List
- R1,R4,R9 = 6M8
- R3,R7,R6 = 10K
- R8 = 100K
- R2,R5,C1,C2,C3 = to be dteremined with experimentation
- N1------N6 = IC 4049
- ALL DIODES = 1N4007
- RELAYS = 12V, 10AMP
- T1 = BC557
- T2 = BC547
Comments
Just a note to possibly help reduce frustration: this circuit design shouldn’t be used with RO water
Thank you very much sir .I will try it .
Dear sir , Sorry to say , My doubt is not clearly presented by me . Sir I need Buzzer sound , at the time of
” dry run cutoff Mode ” . Plz advise , How it possible . Thanking you .
Hello Mohamad, if you want perfect results, then you may have to incorporate another IC 4093. Connect all its inputs pins together, connect all its output pin together. Connect the input side with C3/D4 junction, and connect the output with the positive of the buzzer, and connect the negative of the buzzer with the ground line.
Dear Mr . Swagatam . have a nice day . Thank u for your advise and Now the circuit working excellent .
please give me one more advise . I need to indicate dryrun stage by buzzer . how to indicate dryrun stage ? I connecet LED between R7 to D3 anode , it affect C3 charging . and i connect buzzer + to D3 anode – to ground . its also affect
C3 charging . Please advise me .
Glad it is working now Mohammad, the LED or the buzzer should be connected between the +positive line and the common line which connects R7, R8, C3, D3, D4. Increase C3 sufficiently, so that the dry run is detected/activated only after 5 to 10 seconds….
Mr. Swagatam , Thank you for kind reply . C3 is fully charged and 7 v only acroos C3 . this same volt reach input of N3 . at the moment N3 output not low . (near + 5v in N3 output ). I try to decrease the R7 value to 15 k , C3 fully charged and Near +10 v reach to N3 input . still the N3 out put NOT low and Stop relay NOT triggered . I change the IC still the problem continue . PLz refer approx value of C3, R7, R8 , dryrun for 90 seconds in 12 v circuit . plz Advise me where is my fault .
thanking you .
Mr. Mohamed, the 7V was due to wrong potential divider calculation for R7/R8. It became 10 V since you reduced R7, so it is fine.
But, at 10 V at the input of N3, its output should have turned 0 V. Please connect an LED with a 1K series resistor across N3 output and ground. When the N3 input turns 10V, this LEd Must shut off.
Alternatively try replacing the IC with Schmitt trigger NOT gate IC such as IC 40106
https://www.ti.com/lit/ds/symlink/cd40106b.pdf?ts=1596858654249&ref_url=https%253A%252F%252Fwww.google.com%252F
Dear mr ,Swagatam .
I try to assembled the circuit submercible pump start stop circuit . Its on and off working is fine . but the dry run is not working properly . In 12 v circuit when the water absence , the c3 is start charging ,but finaly not producing high volt to N3 input . its only
5v to 7 v reach the N3 input at the moment N3 logic not working and no dryrun cut off . what is the reason ? I used R 7 is 68k and
R8 is 100 k preset . please reply , Thanking you .
Dear Mohammad, when C3 charges fully, a voltage equal to 12 V will be developed across the C3. This voltage will reach the input of N3 through D3, and will prompt N4 to switch the STOP relay.
Please check and verify this voltage across C3, and make sure this reaches at the cathode of D3.
dear Swagatam, i have connect this circuit to 9v battery so it works very good, but when i connect it with 12v 500mA small smps (available in the market) then the ic is damaged.
what to do ?
or how i connect the circuit with small smps (if you have circuit diagram with component list) that deliver proper current to the circuit ?
i have lost 4 number of ic for that reason.
Thanks Sudip, that means your SMPS is not 12 V, because the IC 4049 is rated to handle up to a maximum of 18 V, so 12 V should not be a problem at all. If in doubt you an add a 7812 IC in the middle to make sure nothing burns.
very nice project sir, thanks for the circuit . but i found problem ,
1. when switch on the circuit using 9v bat, the start and stop function work for a msecond.
2. when the lower prob is not connected the motor on – is ok, but forwarding when it touches the lower
prob again the stop signal on for a while.
what to do ?
3. if i am use to power up this circuit with 12vdc 500 mA smps, is it ok with this ?
what r the value of R2,R5,C1,C2,C3 you used
can u send pcb design
Thank you Sudip,
1) I don’t think that’s possible, yet still you can prevent this by connecting 10uF/25V across base/emitter of both the relay transistor. For BC547 capacitor negative lead will go the emitter, for the BC557 the positive lead of the capacitor will connect with the emitter.
2) That again looks impossible, because when the water rises and touches the lower probes, the N5 input will become positive, which will cause its output to turn negative or 0V, this 0V will reach N3 input which is already 0V through R4, thus effectively turning N4 output to be 0V so that BC547 can never conduct.
3) yes 12V is recommended for this circuit with 12V relays.
thanks sir, i have made a mistake , but it is working good.
now i want to know that is this circuit is also capable to run a jet pump also ?
i want it with a single switch, that means when the switch on in either direction the two different function works that is one is for submersible pump and another is for jet pump.
Glad it’s working sudip….two function may not be possible with this circuit unless both have identical start/stop contactor ….then it may be possible…in that case the stat/stop switches could be interchanged for the two operations
Swagatam, Few additional features are required to be added to your circuit, which are as follows:- 1.The start switch contacts of the relay should be marked in green colour as per the switch colour of the control panel, and the stop switch contacts should be red colour. 2.For the start switch a DPDT relay would be required as many of the control panels have DPDT (4 contacts) switches fitted inside. 3.As for the stop switch NC contacts are to be used and the wires are to be connected in series with the stop switch in the control panel.
Thank you Sanjay, I hope the readers will note this and proceed accordingly. Yes the stop switch needs to be a push-to-OFF type, therefore the N/C must be used for deactivation.
Swagatam, I tried the modified uln2003 circuit once again, but with the same result the relay latches on as soon as the power is switched on. This time I powered the circuit without connecting the 2003 section and I connected a 10mf capacitor across the BC547 base & emitter. The relay still latches on as soon as the power is switched on.
Sanjay, first remove the 100K feedback resistor across the collector of BC557 and base of BC547. Check whether the circuit latches or not. If it latches then your transistors may be faulty, if not then your circuit is OK. Now replace this feedback resistor with 1M and check again, with 10uF connected across the base/emitter of BC547.
Swagatam, I tested your modified 2003 waterlevel controller circuit today. The circuit when powered on, the relay just latches on and nothing else works at all I checked and rechecked the project but the result is same. I also connected the 1mf capacitor across the 547 base and emitter, but the result was same. Please help.
Sanjay, The circuit will work 100% no doubt about it. Normally 1uF is enough to prevent power ON latching, I have tested and used this latch circuit in many applications. First check the latch circuit with 1uF but without connecting the ULN2003. If it still latches then increase the 1uF to 10uF and check again.
Swagatam, In submersible pumps, since the high current contacts are controlled by a contacter I feel we can use 5 or 7Amps rated relays for the start and stop switches. Please clarify.
Yes, to operate a contactor you can any low current relay.
Swagatam, some queries relating to the uln2003 circuit, 1.Why do we have to use extra transistors whereas pin 10 can drive the relay easily. I suggest that to switch off the relay at cut off stage use pin 16 out to put pin 7 to low state, so as to switch off the relay. Designing the circuit is beyond my capacity, I leave the job to you. Thanks.
Sanjay, the transistor circuit is for latching the relay, if you connect the relay directly the relay will deactivate as soon as the water level drops even slightly below the top level of the tank.
I have given you the appropriate design, so you can test it now to verify the result.
Please make sure to add a 1uF capacitor across the base and emitter of the BC547 otherwise the relay will latch as soon as the circuit is powered.
Swagatam, can you design a circuit diagram of a waterlevel indicator, where the indication should be on a common cathode 7 segment display. The circuit should also include a pump controller with municipal water supply pipeline sensor and a overflow cutoff with a single relay.
Presently I do not have it, I’ll try to design it and let you know.
Swagatam, Can the relays be replaced with Triacs? if possible please suggest the required changes in this circuit. In another circuit I am using ULN 2803 Ic as waterlevel indicator and relay driver to control the two relays for switching the pump on and off, the circuit is functioning well, I have used pin 11 of the Ic to detect water at sump and switch on the relay and pump, and pin 18 to switch off the Overhead tank relay and pump. Can you suggest some modification to do this using only a single relay?
Sanjay, sorry triacs won’t work as far as I understand. No other option other than relay contacts will work correctly.
For the ULN circuit you can refer to the following link, I have updated the diagram in this post.
https://www.homemade-circuits.com/how-to-make-simple-water-level/
Sagar, that cannot happen unless your C1 is faulty or there’s some other issue in your connections. C1 and R2 can be adjusted to get any delay from 0.1 second to 1 hour.
As soon as the water level goes below the lower contact, the N1 input becomes 0V, its output becomes 12V, which passes through C1 and causes N2 input to become high, and N2 output to turn 0V, activating the PNP and the relay to switch ON….in the meantime, within 1 second C1 charges fully and reverts the situation to switch OFF the relay.
Connect LED/1k at the outputs of N1, and N2, and check the responses yourself.
Make sure that inside the water tank, the +12V supply is 1 or 2 inch close to the sensing contacts
Sorry sir I did a mistake in naming the components in my previous question.
I have figured out the values of
C2=2.2uf
R5= 100k
STOP relay is working fine.
Then after for R2 and C1 , I used capacitors 10uf,2.2uf,1uf and Resistors 100k ,10k in combination with them.
I noticed that as soon as the water decreases from middle level , START relay comes to ON state, and stays in the same position ..until the water crosses the middle level .
In practical we need a delay of 1or 2 sec. But I’m not getting that.
Water from pump takes a minimum of 30secs to reach the tank.
If the START relay stays in ON state for 30sec, the motor pump will be damaged.
Did I missed anything or I have to change the values of R2 and C1.
Sir,did anyone successfully experimented this…to be the exact working project..
If yes,
Please suggest me the values of them Sir.
Hi Sir thanks for replying me everytime.
I have figured out the values of
C2=2.2uf
R2= 100k
STOP relay is working fine.
Then after for R1 and C1 , I used capacitors 10uf,2.2uf,1uf and Resistors 100k ,10k in combination with them.
I noticed that as soon as the water decreases from middle level , START relay comes to ON state, and stays in the same position ..until the water crosses the middle level .
In practical we need a delay of 1or 2 sec. But I’m not getting that.
Water from pump takes a minimum of 30secs to reach the tank.
If the START relay stays in ON state for 30sec, the motor pump will be damaged.
I didn’t understand what to do about dry run detection with some sound alert.
I hope you understand my problem.
Hi sir. As per your suggestion I have used 100k and 10uf capacitors Inthe place of R2,R5 and C1,C2,C,3. I have got the delay time of 10seconds across the Start relay. What should I do to get 2 secs? What values must be used. Please suggest me for exact output
Can we use the same circuit by removing one of the relay for making water pump controller for non contactor type starters (i.e on/off by MCB)? How to modify the circuit diagram for this application
Sir how to connect a buzzer to the dry run terminals ,so that I can get notified easily. Please
Thank you Sagar, The combination of the RC delay network should be as C1/R2, and C2/R5.
For the dry run, connect the buzzer across the positive line and the output of N6.
Hi Sagar, to reduce the delay, reduce the 10uF at C1, C2 to 2.2uF
The above design is intended for momentary ON/OFF, it is not a set/reset type therefore it cannot be used for normal water level control
Sagar, connect the buzzer between the positive line and the output of N6
10M will also work!
Can we use 10M resistors? as 6.8M resistors are not available for me,..
Sir I need the start relay to be ON for 2 sec and STOP relay for 1 sec. Please suggest me the values of capacitors and resistors for the above requirements.
Are the values of R & C Directly proportional to each other or Indirectly proportional to each other?
Sir, Can you please share the circuit diagram you have used to make this project as successful. Please let me know the values of R2,R5,C1,C2,C3. Kindly share the circuit diagram
Sir, Can you please share the circuit diagram you have used to make this project as successful. Please let me know the values of R2,R5,C1,C2,C3. Kindly share the circuit diagram to this mail id
Sagar, you can try 100k, and 10uF for the resistors and capacitors initially, and check the how much delay it generates, and then tweak the values appropriately to decrease or increase the delays…connect an LED with series 1K across the relay coil to see check and adjust the delay time visually
yes They are one and the same..
Sanjay, for 1 hp motor you will need a 30 amp relay, 7 amp will not do.