#149008

My generator has a controller, when on auto I just need a dry relay contact to on the generator. That is when the battery voltage is around 30 or 40 percent the relay will switch on and the open dey contact on the relay will switch on the generator and when the battery is at 100 percent it should switch off the relay and the generator will go off.

#149110

Hello boss, I have seen the circuit diagram you sent me. I have some questions to ask. What is the value of D3 and finding small 48volts relay from my area is slightly difficult, how do I convert the relay to either 12 or 24volt relay. Thanks

#149112

Hi Jolly,
D3 is an LED, if you cannot understand an LED symbol then how will you build this complex circuit successfully?
You can modify the circuit in the following manner for using a 12V relay.
48v charger circuit with relay

Author
#149015

I will design the circuit soon and let you know.

#149000

I have a project for a 48volt battery monitor with a relay that will energize when the battery is low and will go off when the battery is full. I want to use the relay to start my generator when the battery is at a low range I will set and the relay should switch off when the battery is full

Author
#149002

How will you use the relay to start the generator? Starting a generator requires a manual effort or a mechanical setup…

#140782

Hi, many thanks for a well written article. I have been trying to build exactly what you have described. A very basic question.. The first circuit, based on 4 x 6.8k registers and 4 x 10 potentiometers. Will that be the same values if fx measuring 10-12.5v or what that need some other calculations? I have tried to make it on bread board, but can’t really get it to work in the voltage range??.

Regard KT

Author
#140788

Hi, I am glad you liked the post.
The first circuit can be used for any voltage between 5 V and 30 V. The presets work like voltage dividers and set the switch ON voltage limits at the non-inverting inputs of the op amps with reference to the 3.3V zener diode value.
When the non-inverting potential increases above the 3.3V value, the output of the relevant op amp becomes high and illuminates the LED. The presets are adjusted to set these switch ON limits for the op amps.

#140799

Many thanks for your reply, its really appreciated!! 🙂
I have just tried to build the circuit on a bread board several times. It still doesnt cope with with me, and I cant figure out why.
All the presents are working, as well do I get output on pin 1,7,8 and 14 when adjusting the presents. I have the circuit connected with a dimmer, and voltage goes to 12.3v.
When adjusting the voltage to e.g. 6v I adjust the #1 present, and #1 diode lights up. I change the voltage to 10v and adjust #2 present and #2 lights up, and #1 diode is off again. I power full up, and adjust #3 present and #3 diode ligths, #2 diode is off.
I think this is how I read the instructions…

But when slowly powering down the voltage, nothing happens – the different diodes doesnt turn off and on. Instead the last diode just dims off for finally to be off when voltage reaches 0. This doesnt seem to be right!!

Do you have a suggestion what it is I do wrong and I see this behaviour?

BR KT

Author
#140806

Yes, all LEDs will not remain illuminated together, as the volatge is incresed, the lower LED will shut off and the upper LEDs will illuminate until only the top most LED is illuminated.

To understand the first circuit, you will have to understand its working.
As you can all are op amps and all the op amps are configured as comparators.
The idea is simple, the output LED will illuminate only when the (+) input of the opamps become higher than the (-) inputs.
The (-) input is referenced at 3.3 V.
That means, as soon as the (+) input pin voltages become higher than 3.3 V then the output LEDs will illuminate.
While increasing the supply voltage check the voltage values at the (+) inputs of the opamps, they should become higher than 3.3 V, only then the output LEDs will illuminate one after the other.
The (+) inputs are pin 3, 5, 10, 12. When voltage on these pins become higher than 3.3 V, the relevant LEDs will light up.

#137730

Hello, I sincerely hope that you are still watching this page. I am creating 2 – 12 volt lithium battery backed lamps. I am running the lamps off of a 600 mA plug in adapter. Each lamp has 2 – 3000 mAh battery packs. The operation is simple, when I loose power, a relay opens and supplies battery power to the single 12 volt / 60 watt lamp. These lamps only use 543 mA of power. I’m using the 600 mA adapter for each lamp because I read that these battery packs need to charge at 1/10 of their rating ((3000 mAh each X .1) X 2 batteries = 600 mA) I want to try to find a way to monitor these batteries and change a switch to allow the adapter to charge the batteries. Can this be done?

Author
#137737

Hi, yes, definitely you can try one of these circuits to solve your application requirement.

#92702

Emmen, the Netherlands, july 22, 2021.

Dear Mr. Swagatam,

After a long search I came across your website. The circuit diagram with 4 leds appeals to me, because I want to make a battery tester that also uses 4 leds. For the record, I’m a complete nitwit when it comes to electronics, so it must remain simple and I have next to no knowledge of circuit diagrams, but working out a wiring diagram in practice is still possible. The battery tester that I want to make has to measure the condition of a battery pack consisting of 2 Li-ion batteries (each 3.7 Volt) that together provide 8.40 Volt fully charged.

By the way, I’m not doing this for myself, but for the Fietsersbond (the Dutch Bicycle Organization). Every autumn, it organizes days on which people can have their bicycle lights repaired by us, the volunteers. We do this for free, customers only have to pay for the parts and materials. And you can do this low budget organization a great service by adapting the Block Diagram for a battery tester that uses a battery pack of nominally 7.4 Volts (fully charged so 8.4 V). I would attach my overview and some photos of the repair days, but that seems impossible 🙁 I look forward to your much appreciated response!

Author
#92706

Thank you Dear A.N. Bakkar, you can definitely use the 4rth circuit for the intended purpose! However, instead of using fixed resistors for R2—-R6, you may have to employ 1 k presets so that the LED illumination levels can be adjusted precisely for the corresponding voltage levels.

However, I would recommend the first circuit which gives a better control over the adjustments for the LEDs.

#87313

Thx, circuit favorited ))

#82141

Hello, I’m Christian and I would like to design a circuit that would allow me to power a sensitive 10A device in 12 Volts directly from a battery. The battery voltage can reach 14.8V so the circuit must limit the voltage to 13V maximum and must have a protection against polarity inversion and short circuits. I would also like to associate a led that flashes as soon as the battery drops below 11.5V and stops flashing after 12.5V (hysteresis). I have already done some research on LDO regulators but they are too limited because only 1A and zener circuits with ballast transistors don’t have any protection against short-circuits. For hysteresis and flashing I plan to use two NE555. Please I need your help.

Author
#82164

Hello, you can probably try the second last circuit from the following article:

https://www.homemade-circuits.com/low-dropout-5v-12v-regulator-circuits-using-transistors/

Q1 can be replaced with a TIP36 transistor

#82190

Thank you

#59767

Dear sir,
I want to design battery level indicator for 48 volt battery with 5 led. Can you send circuit diagram, rating of components used and mathematical calculation

Author
#59776

Dear Amit, you can easily use the first circuit from the above article, and add one more opamp for getting the 5 LED output.

Just make sure to connect the positive pin of the IC with a stabilized 12V, while the preset output may be connected with the 48V, preferably add a 10K resistor in series with each preset.

The presets and the 10K resistors will form a resistive divider and ensure that the sensing voltage at the input is kept well within 12V range.

All resistors will be 1/4 watt rated, opamps can be from any standard opamp IC

#57558

Hello sir Swagatam,
What modifications do I need to make to the above schematic (first one) so as to use it for both battery charging indicator and discharging indicator? I want to use it for both in a project.
Thanks in anticipation.

Author
#57581

Hello Godson,

the first circuit will work for both, as a full charge indicator when the red LED lights up, and a full discharge indicator when all LEDs shut down except the white one which shows the last discharge level of the battery and indicates that the battery needs to be recharged immediately.

Green indicates battery is moderately charged.

#57679

Hello sir Swagatam,
Thanks a lot for the reply. What I actually meant was using the circuit when the LEDs are in the bar mode, i.e when battery is charging, the LEDs turn on one after the other until the last one is lit, meaning that the battery is fully charged, and when the battery is discharging, the LEDs go off one after another until the last one is turned off, meaning that the battery has discharged. Is it possible for the schematic to work that way?

Author
#57685

Hi Godson,

It is possible by connecting the respective LED ends with the ground line instead of the opamp outputs…

#57910

Hello sir Swagatam,
Thanks a lot for the reply. According to the datasheet, LM324 has a maximum supply voltage of 32V. How do I use it on a 48V battery? What modifications do I need to make?

Please sir, could you suggest a schematic for 0-50V variable power supply. I am urgently in need of it. Thanks a lot in anticipation.

Author
#57917

Hello Godson, you can regulate the positive supply pin of the IC with a 24V zener diode. Connect a 4k7 resistor from it Vcc to positive supply line, and a 24V zner from its Vcc pin to the negative line (ground line)

Link for the power supply

https://www.homemade-circuits.com/how-to-make-versatile-variable-voltage/

#53485

Sir i have few doubts…
* For 12v battery zener value 3.3
For 6v battery zener value ?
For 4v battery zener value ?
Pls tell sir….
Low voltage op amp ic also pls tell
sir

* 12v btry 7aH I’m using…if i give directly to IC +ve (pin no 4) voltage source.IC will be damage or i need to connect IN4007 diode ..to reduce the ampere for IC input (pin no 4)..

Author
#53501

Kesav, it is not critical, you can use any value lower than the minimum threshold of the battery…the zener is only for providing a fixed reference based on which the presets are adjusted for the intended cut offs.

for low volatge operation it is better to use a BJT based circuit as given below:

https://www.homemade-circuits.com/2013/05/low-battery-indicator-circuit-using-two.html

the IC can tolerate upto 19v so 12V cannot be a problem, you can connect the batt directly, and a diode is not for reducing current, it’s job is to only block reverse voltage….

#53519

Thank u sir…

If u have LM3914 battery circuit sir…
I find many circuit not working proper sir…
Pls find me the good circuit sir…

Author
#53521

You are welcome Kesav,

all circuits from this website will work but only if it’s done with proper understanding…if you do it without understanding then you will keep struggling even with the simplest of the circuits, ….and anyway electronics is all about understanding and implementing.

You can check the following design which uses LM3915

https://www.homemade-circuits.com/2013/08/3v-45v-6v-9v-12v-24v-automatic-battery.html

#53056

Hello sir Swagatam,
Thank you very much for this schematic. I’ll like to incorporate it in my inverter design. From what i see, it appears to be for 12V battery. If i want to use it for 24V, 36V, 48V, 60V and higher voltages (for higher inverter capacities), what part do i need to change? And please could you tell me the upper and lower threshold voltages for 24V, 36V, 48V, and 60V e.g upper and lower threshold voltage 12V are 14.5V and 10.5V respectively. Thank you sir.

Author
#53062

Hello Godson, you can can easily use it for 24V monitoring also, just change the zener with a 6V or 9V zener diode. For higher than 30V, you can still use the same design but make sure the IC supply pins are supplied with a regulated 24V.

after this you can simply adjust the relevant presets for enabling the LED switch ON at the desired thresholds

#53086

Thank you for the prompt reply sir. When voltage is above 30V and i use a 24V regulator like you said, how will the circuit be able to monitor the fall in voltage since the circuit will keep getting a constant 24V?

Author
#53091

the 24V should be separately fed only to the (+) supply pin of the IC, that is to pin#4 of IC LM324….

#53096

Very well then. So that means that R5 and P4 will now be connected to the positive terminal of the battery in question and the settings will be done. Thank you for the info sir. I want to design mine in a “bar graph” mode and use it to power off the inverter when the last LED turns off. Can i connect a 10K resistor from pin#1 of the IC to the base of an NPN transistor such that a relay-diode assembly will be connected between the collector and positive terminal and the emitter to ground, keeping R1 and the associated LED in their place and then use the relay contacts as the inverter switch?

Author
#53105

Yes that’s correct R5/and the presets can remain connected with the battery voltage.
you can use pin#1 with a 10k/BC547/relay stage for initiating the mentioned operation.

#51324

Sir I need a circuit that can ON a fan if the temperature go up and switch OFF a fan if the temp go down.

Author
#51331

Aminu, you can try the following concept

https://www.homemade-circuits.com/2016/08/incubator-temperature-controller.html

#51280

Secondly, can I replace the relay by connecting the emiter of PNP transistor to the Positive power of the IC SG3524?
So that, the inveter will shot down when the A4 LED gone off.

Author
#51292

Aminu, it can be done, but as far as I know pin#10 of the SG3525 or 3524 requires a positive pulse for shutting down, not a negative pulse….you can do it as shown in the following diagram

2.bp.blogspot.com/-NSrqci3-b-8/U98ih86pV6I/AAAAAAAAH2E/i9tMa4nS-dA/s1600/sg3525+inverter+circuit.png

#51279

Sir, am building an inverter circuit using SG3524 IC.
So, My mind told me that, I can supply the Negative power to the inveter circuit through this LM324 by connecting A4 output of the LM324 to the negative supply to the SG3524. So that, the inverter will shut down if the final LED, that is A4 output short down.
Is this feaseble Sir?

#51277

I did it… It's quite simple.

#51255

My desing is in bar form and I'm operating 12v battery with it. What I need an addintion of relay to the last LED that will turn off together with the relay.
Thanks very much Sir.

Author
#51265

Aminu, you can do it by connecting the base of a PNP transistor such as a BC557 with the output of A1…the relay can be attached across the collector and ground with a diode parallel to the coil.

also make sure to connect a 10k resistor between the base and the A1 output and a 4k7 resistor across base/emitter…emitter will connect with the positive line

#51254

Morning Sir,
I built this circuit since, and my design was working in bar LED mode. Now I want improve it by adding a relay in the last LED (that indicate below 11v level), so that if the last LED turn off relay will turn off too.
Sir how can I add a relay?

#40240

My mistake Mr.Majumdar, i meant to say lm339. It has all 4 opamps…

Thanks again.

Author
#40250

yes LM339 can be used.

Author
#40217

Thanks Dave, yes you can use an LM358 IC, although it has only a couple of opamps.

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