Jun 12, 2013

Compact, Ferrite Core Transformerless Inverter Circuit

The circuit diagram of a compact transformeress inverter using ferrite core inductor is shown in the following article, the image was provided to me by one of the avid readers of this blog Mr. Ritesh. The design is a full fledged configuration with includes most of the features such as ferrite transformer winding details, low voltage indicator stage, output voltage regulation facility etc.




I would appreciate if anybody could help identify the various stages, and explain them in details.

30 comments:

  1. Schematic quality is very poor, can you upload better one??

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  2. hi sir you done a great job ,i want to build one so i need your help the IC im very confuse is it a CD 556 LM556? and if it would be possible for you to send the PCB of it i will be appreciate,thank you looking forward to hear from soon

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    Replies
    1. Thanks Daniel,

      Any 556 IC will do, the initial prefix does not matter.
      I do not have the PCB design for this circuit, so would be unable to provide it to you

      Delete
  3. Hi. Why is the rectifyer at the output? is this not an inverter? is this a DC-DC converter?
    Why not a filter instead of the rectifyer?
    Thanks.

    ReplyDelete
    Replies
    1. the rectified high voltage is again switched back into AC mains at the output for the appliances. see the extreme right hand side section.

      Delete
  4. Transformerless? It has a ferrite core trafo... this is a transformer.

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    Replies
    1. when inverters are discussed, transformers by default refers to heavy bulky iron cored transformers, which is not present here, the small ferrite trafo can be considered as good as an electronic component.

      Delete
  5. Ok, thanks for your clarifications.

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  6. Thanks Mr Swagatam, you such a gift to our generation.
    I want to build this circuit, my problem is the transfo area, do you have the idea of how big the ferrite core will be and the thickness of the wire use
    2. About the circuit in the link below, can you please tell me how to connect it to inverter? As it have Load terminal /- and battery terminal /- How will I connect these terminals
    Thank

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    Replies
    1. Thanks Olaleye

      The ferrite core dimension is given in the diagram itself, please click it to enlarge.

      I cannot see any link in your comment?

      Delete
  7. Thanks for your quick response
    Here is the link : http://www.homemade-circuits.com/2012/05/low-battery-cut-off-and-overload.html , can you please tell me how to connect it to inverter? As it have Load terminal /- and battery terminal /- How will I connect these terminals
    Thank

    ReplyDelete
    Replies
    1. the inverter battery will need to be connected across the points marked "battery"

      and the supply input points of the inverter across the points marked "load"

      Delete
  8. Supply Input point? I don't get it. Do you mean the input of the transfo?
    i.e the point 12-0-12

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    Replies
    1. the (+) and (-) of the inverter which are normally connected with battery terminals

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  9. Thanks for the quick response.
    So u mean the circuit will serve as intermediary between battery and inverter cuicuit?

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  10. Thanks for all the design
    I build the circuit in this with SG3524 IC, I connect the 555 based output to pin 3 of IC 3524 and it works fine when I use it to power 100w bulb although I don't check the wave I don't have instrument to do that but when I connect pin 3 of the third IC 555 with 1N4148 diode to pin 11 and 14 of SG3524 IC as in the circuit below the current flunctuate to the extend that it burn some of my MOSFETs. http://3.bp.blogspot.com/-tjwhhBrw0eQ/VDyxEksqQKI/AAAAAAAAIcs/PIQ-UAsiKqo/s1600/IMAG0209.jpg
    Please where can I connect that output to. I really want to use 555 based oscillator for my design
    Regards

    ReplyDelete
    Replies
    1. you can try employing transistor driver stages and associate the diodes with the base of the transistor as shown in the following circuit, and see if this solution helps

      http://www.homemade-circuits.com/2015/05/simplest-pwm-modified-sine-wave.html

      Delete
  11. Thank you sir
    So you mean I should replace the two 1K resistor with the diode and instead of connecting it to GND, I should connect it to pin 3 of 555, if am correct.

    ReplyDelete
    Replies
    1. yes you can replace those resistors with diodes and connect with pin3 of IC 555 or you can keep the resistors in their positions and use the diodes separately at the bases of the transistors.

      Delete
  12. Thanks for the response so far
    So if I keep the resistors and connect the diodes separately to the base of transistor, do I still need to connect it to pin 3 of IC555?

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    Replies
    1. Olaleye, if you don't connect the diode ends to pin3 of the IC2 then how the PWMs will work? so obviously you will need to connect the diodes ends to pin3 of PWM IC

      Delete
  13. Compliment of the season to you
    I did the correct by making it a transistor driver stage it works fine when I power it with low battery AmP say 12A but when I use battery of 100amp it start to fluntuate and make scaring noise . Pls what else can I do
    2. About the transformerless inverter in this post, I build the circuit without the low battery and overload detection section and it work fine, the problem am having now is which mosfet do I need to add to in other to increase the power. is it IRF740 or RFP50N06?
    Regards

    ReplyDelete
    Replies
    1. amps actually should not have any effect unless the voltage is increased so whether it's 12A or 100Amp shouldn't make a difference as long as the battery voltage are identical? I'm unable to troubleshoot this issue...make sure you have connected protection diodes across the mosfet drain/source.

      The mosfet can be the one which has the I and V rating much higher than the required specification, meaning if your requirement consumes 12V at 50amps then the mosfet should be rated to handle 30V at 70 amps and so on.

      Delete
  14. Thanks for the quick responds
    About the transformerless inverter in this link http://4.bp.blogspot.com/-HVUzC0czONo/Ubggj8LDuUI/AAAAAAAAETI/wP8405k9iyU/s1600/12v 220v.GIF, I build the circuit without the low battery and overload detection section and it work fine, the problem am having now is which mosfet do I need to add to in other to increase the power. is it IRF740 or RFP50N06?

    ReplyDelete
  15. Thanks for been there for me
    Sir I have another problem with my inverter I used SG3524, its work fine on some appliances but when I use it to power small standing fan, the voltmeter just drop a little the is now making hummy noise (the inverter sound is reflecting in the fan) thereby making the fan not to roll @ high speed.
    Pls what can I do to remove to noise from the fan, I've filter the output by connecting 400v 0.22uf capacitor across the output of the transformer
    Thanks in advance

    ReplyDelete
    Replies
    1. If the voltage is dropping that means the fan is consuming more current than the battery can supply, either the battery is underrated for the fan or may be the fan has some problems....try changing one of these and see the response.

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  16. I have change both the fan and battery, I now used 100 amp battery still the same

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    Replies
    1. check the current consumption by connecting an ammeter in series with the battery positive, if it exceeds around 60% of the battery AH then that's too high and that could be the reason of the problem.

      Delete

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