The circuit of a simplest mosfet power inverter explained requires a single IC 555, a couple of the mosfets and a power transformer as the top ingredients.
As shown in the figure, the IC 555 has been wired as usual in the an astable multivibrator form. The resistors R1 and R2 decides the duty cycle of the inverter.
R1 and R2 must be adjusted and calculated precisely for getting a 50% duty cycle, otherwise the inverter output may generate unequal waveform, which may lead to unbalanced AC output, dangerous for the appliances and also the mosfets will tend to dissipate unevenly giving rise to multiple issues in the circuit.
The value of the C1 must be chosen such that the output frequency comes to about 50 Hz for 220V specs and 60 Hz for 120V specs.
The mosfets can be any power mosfets, capable of handling huge currents, may be upto 10 amps or more.
Here since the operation is a push pull type, two batteries will be required instead of one for supplying the ground potential for the transformer and in order to make the transformer secondary winding responsive to both positive and negative cycles from the mosfet operations.
The idea has been designed by me, however it has not been yet tested practically so kindly take this issue into consideration while making it.
Assumably the inverter should be able to handle upto 200 watts of power easily with great efficiency.
The output will be a square wave type.
R1 and R2 = See Text,
C1 = See text,
C2 = 0.01uF
R3 = 470 Ohms, 1 watt,
R4, R5 = 100 Ohms,
D1, D2 = 1N4148
Mosfets = see text.
Z1 = 5.1V 1 watt zener diode.
Transformer = Asper power requirement,
B1, B2 = two 12 volts batteries, AH will be as per preference.
IC = 555